Solution needed for the following Requirement..
Hi Friends,
Need an answer for the following . Its for Voluntary Time Recording...
1) Maintain IT0007 with the percentage of employment for both part time and full time employees.
2) The Max Flexi-time for part-time and full-time employees is 37.5/40 hours per week.
3) Maintain attendance infotype.
4) Notification to be sent to the manager once the flexi-time reaches a limit of +15/-15 hours per week. This has to be done through workflow.
5) For the fulltime employees, the flexitime applicable is only +15 as they will maintain absence quota.
6) Once the request is approved , the flexi-time data has to get save in the database.
7) In the quota overview, the daily view is to be removed. The time accounts detail should not be there. The only relevant columns to be displayed are Key Date(Default is current date), Type(Flexitime) and Current Balance(in hours)
If you can please let me know of the configuration changes and workflow changes too...
Thanks,
Kumar
Moderator message - Please do not post your requirements and ask the forum to do your work for you.
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Need sql for the following requirement
EMP_DT EMP_TYPE emp_id
01/01/2011 3 546
01/03/2011 4 546
01/05/2011 3 546
01/08/2011 3 546
01/09/2011 3 546
01/10/2011 4 546
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Hi All,
I have a table with two columns(emp date and type where date is mm/dd/yyyy type tied to employee).
This data is inserted manually through online application. But behind the scenes I would like keep this date in the following fashion by a delete sql. When run the delete sql it should keep the data in following manner with employe type order 3,4,3,4,3,4 and so on. There shouldn't be any 3 empolyee type rows continuosly. Also when delete the data it should keep the smaller date out of three same employee type dates. example 01/12/2011,01/14/2011,01/16/2011 ---> we will keep the row 01/12/2011 and delete two other dates because they are same type of dates(3).
EMP_DT EMP_TYPE emp_id
01/01/2011 3 546
01/03/2011 4 546
01/05/2011 3 546
01/10/2011 4 546
01/12/2011 3 546
01/18/2011 4 546
01/19/2011 3 546Hi,
So, on each row, you need to know what the value of emp_type was on the previous row. That sounds like a job for LAG.
Here's one way to do that:
WITH got_prev_emp_type AS
SELECT emp_dt, emp_type, emp_id
, LAG (emp_type, 1, -1) OVER ( PARTITION BY emp_id -- Just guessing
ORDER BY emp_dt
) AS prev_emp_type
FROM a_table
-- WHERE ... -- If you need any filtering, put it here
SELECT emp_dt, emp_type, emp_id
FROM got_prev_emp_type
WHERE emp_type != 3
OR prev_emp_type != 3
ORDER BY emp_id
, emp_dt
;This assumes that emp_dt is a DATE (or a TIMESTAMP). If it has some other dattype, convert it to a DATE.
"DELETE" means "permanently remove rows from a table." Is that what you want, or do you just want to exclude some rows from a result set? The query above doesn't actually change the table. If that's what you want to do, you can use the query above as a sub-query in hte WHERE clause of a DELETE statement.
DELETE FROM table_a
WHERE (emp_dt, ,emp_type, emp_id) -- Just guessing
NOT IN (
WITH got_prev_emp_type AS
);This assumes that emp_dt, demp_type and demp_id are never NULL.
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all tables, and also post the results you want from that data.
If you're asking about a DML statement, such as DELETE, the sample data will be the contents of the table(s) before the DML, and the results will be state of the changed table(s) when everything is finished.
Explain, using specific examples, how you get those results from that data.
Always say which version of Oracle you're using. All the code I psoted above assumes you have Oracle 9.1 or higher. -
Please urgent help needed for the following
Hi Everybody!
I desperately need help as soon as possible.
Following is the partial code for the driver program which will use the Employee class Objects(Employee is declared abstract). If you want to see whole code you can take a look at my last two or three posts in this forum.
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calcWeeklyPay();
if(event.getSource() == clearButton)
nameField.setText("");
hoursField.setText("");
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increaseField.setText("");
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currentEmp = empCreated;
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//empData.add(emp.toString());
enterButton.setLabel("add");
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nameField.requestFocus();
//String name = nameField.getText();
double payRate = Double.parseDouble(rateField.getText());
double hours = Double.parseDouble(hoursField.getText());
empArray[empCreated] = new HourlyEmployee(nameField.getText(), payRate, hours);
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looking forward your kindnessVisit YAT-Yet Another Thread this is a discussion using the Sun book Core Java 2
and one part in that book uses an example with Employee class of which I assume you are stealing your class-name from. Anyway, that thread is in the Java forums. -
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day | grpID | pktID
sun | 1 | 001
sun | 1 | 002
sun | 1 | 003
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mon | 1 | 001
mon | 1 | 002
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mon | 2 | 008
mon | 2 | 009
tue | 1 | 001
tue | 1 | 002
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Ex: For Sunday, we have two combination list for grpID=1 is (001,002,003) and for group id = 2 is (007,008,009)
2. We need to get all the available combined pktid for each group id for all the days .
Eg the the expected result that is needed from the above table
(001,002,003)
(007,008,009)
(007,010)SQL> with tbl as
2 (select 'sun' d, 1 grp, '001' pk from dual union all
3 select 'sun' d, 1 grp, '002' pk from dual union all
4 select 'sun' d, 1 grp, '003' pk from dual union all
5 select 'sun' d, 2 grp, '007' pk from dual union all
6 select 'sun' d, 2 grp, '008' pk from dual union all
7 select 'sun' d, 2 grp, '009' pk from dual union all
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9 select 'mon' d, 1 grp, '002' pk from dual union all
10 select 'mon' d, 1 grp, '003' pk from dual union all
11 select 'mon' d, 2 grp, '007' pk from dual union all
12 select 'mon' d, 2 grp, '008' pk from dual union all
13 select 'mon' d, 2 grp, '009' pk from dual union all
14 select 'tue' d, 1 grp, '001' pk from dual union all
15 select 'tue' d, 1 grp, '002' pk from dual union all
16 select 'tue' d, 1 grp, '003' pk from dual union all
17 select 'tue' d, 2 grp, '007' pk from dual union all
18 select 'tue' d, 2 grp, '010' pk from dual) -- end of data sample
19 select distinct '('||ltrim(max(c1) keep (dense_rank last order by lv),',')||')'
20 from (select d,grp,level lv,sys_connect_by_path(pk,',') c1
21 from tbl
22 connect by d=prior d and grp = prior grp and pk > prior pk)
23 group by d,grp;
'('||LTRIM(MAX(C1)KEEP(DENSE_RANKLASTORDERBYLV),',')||')'
(001,002,003)
(007,008,009)
(007,010)
SQL>That works on 9i. Other possiblities on 10g.
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Hi All,
I have procedure in that I am calling a cursor to fetch the records. This query is returning the following data
DI
SZ
DII
CWT
Top
down
9 1/2
9.625
8.921
36
18
1602
13 1/2
13.375
12.515
61
19
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18 1/2
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26
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105
20
103
9 1/2
9.625
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7
7
6.276
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9 1/2
9.625
8.921
36
18
1602
9 1/2
9.625
8.835
40
1602
3858
7
7
6.276
26
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6352
As you can see in these values top and down are overlapping.
I tried several ways to sort the query on the fields and have some logic, but I am always getting one row extra which is not overlapping.
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ThanksBrendanP wrote:
26 AND t.top
"AND t.top....."... what?
Here's another solution, giving the least overlap over the greatest distance...
SQL> ed
Wrote file afiedt.buf
1 with data as (select 1 id , 18 top, 1602 down from dual union all
2 select 2,19, 1962 from dual union all
3 select 3,20, 503 from dual union all
4 select 4,20, 103 from dual union all
5 select 5,1602, 3858 from dual union all
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7 )
8 -- -------------------------------------------------------
9 -- END OF TEST DATA JUST USE QUERY BELOW AGAINST OWN TABLE
10 -- -------------------------------------------------------
11 ,idealpath as (
12 select id, path, idpath
13 from (
14 select id, path, idpath, cmlt_diff, min_diff, cvrg, max_cvrg
15 from (
16 select x.id
17 ,x.path
18 ,idpath
19 ,to_number(y.column_value) as cmlt_diff
20 ,min(to_number(y.column_value)) over (partition by cvrg) as min_diff
21 ,cvrg
22 ,max(cvrg) over () as max_cvrg
23 from (
24 select connect_by_root(id) as id
25 ,down-connect_by_root(top) as cvrg
26 ,ltrim(sys_connect_by_path(prior down-top,'+'),'+') as cmlt_diff
27 ,ltrim(sys_connect_by_path(top||'-'||down,':'),':') as path
28 ,ltrim(sys_connect_by_path(id,':'),':') as idpath
29 from data
30 where connect_by_isleaf = 1
31 connect by nocycle top between prior top and prior down
32 and not down between prior top and prior down
33 ) x
34 ,xmltable(nvl(cmlt_diff,'0')) y
35 )
36 where cvrg = max_cvrg
37 )
38 where cmlt_diff = min_diff
39 )
40 --
41 select d.id, d.top, d.down
42 from data d
43 ,(select level l, to_number(regexp_substr(idpath,'[^:]+',1,level)) as id
44 from idealpath
45 connect by regexp_substr(idpath,'[^:]+',1,level) is not null) bp
46 where bp.id = d.id
47* order by bp.l
SQL> /
ID TOP DOWN
1 18 1602
2 19 1962
6 1683 6352 -
What solutions would be needed for the following scenario
I have a client who operates two companies.
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They also want to automatically contact operators and client about upcoming service dates.
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SD Modules
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PM Modules
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PM Modules
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SD Modules
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MM Module
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CS Module -
Query needed for the below requirement
Hi,
I have three tables structures like below.
tableA - LINE_ID, VENDOR_ID,DEAL_SITE_ID
tableB - LINE_ID, DEAL_SITE_ID
tableC - DEAL_ID,VERSION, DEAL_SITE_ID
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UNION
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Subhadeep
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Like this (untested):
select tablea.vendor_id
from tablea
inner join tablec on (tablea.deal_site_id = tablec.deal_site_id)
where tablec.deal_id = 100001
and tablec.snapshot_ver = 1
union
select tablea.vendor_id
from tablea
inner join tableb on (tableb.line_id = tablea.line_id)
inner join tablec on (tableb.deal_site_id = tablec.deal_site_id)
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this seems to be the realtek card reader, and having gone trough other threads, I have tried 3-4 versions of the realtek card reader drivers. None of them have worked.
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This question was solved.
View Solution.Hi
Please find the link given below select Network and download the driver.
Driver Link
Let us know how it goes!
"I work for HP."
****Click the (purple thumbs up icon in the lower right corner of a post) to say thanks****
****Please mark Accept As Solution if it solves your problem****
Regards
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