Urgent solution needed for the Problem ( get all the combination from table

Question

we are having a table in following format
day | grpID | pktID
sun | 1 | 001
sun | 1 | 002
sun | 1 | 003
sun | 2 | 007
sun | 2 | 008
sun | 2 | 009
mon | 1 | 001
mon | 1 | 002
mon | 1 | 003
mon | 2 | 007
mon | 2 | 008
mon | 2 | 009
tue | 1 | 001
tue | 1 | 002
tue | 1 | 003
tue | 2 | 007
tue | 2 | 010
1. We have a combination of pkdIDs related with a specific grpID, for a particular day.
Ex: For Sunday, we have two combination list for grpID=1 is (001,002,003) and for group id = 2 is (007,008,009)
2. We need to get all the available combined pktid for each group id for all the days .
Eg the the expected result that is needed from the above table
(001,002,003)
(007,008,009)
(007,010)

Answer 1

SQL> with tbl as
  2  (select 'sun' d, 1 grp, '001' pk from dual union all
  3   select 'sun' d, 1 grp, '002' pk from dual union all
  4   select 'sun' d, 1 grp, '003' pk from dual union all
  5   select 'sun' d, 2 grp, '007' pk from dual union all
  6   select 'sun' d, 2 grp, '008' pk from dual union all
  7   select 'sun' d, 2 grp, '009' pk from dual union all
  8   select 'mon' d, 1 grp, '001' pk from dual union all
  9   select 'mon' d, 1 grp, '002' pk from dual union all
10   select 'mon' d, 1 grp, '003' pk from dual union all
11   select 'mon' d, 2 grp, '007' pk from dual union all
12   select 'mon' d, 2 grp, '008' pk from dual union all
13   select 'mon' d, 2 grp, '009' pk from dual union all
14   select 'tue' d, 1 grp, '001' pk from dual union all
15   select 'tue' d, 1 grp, '002' pk from dual union all
16   select 'tue' d, 1 grp, '003' pk from dual union all
17   select 'tue' d, 2 grp, '007' pk from dual union all
18   select 'tue' d, 2 grp, '010' pk from dual) -- end of data sample
19  select distinct '('||ltrim(max(c1) keep (dense_rank last order by lv),',')||')'
20  from   (select d,grp,level lv,sys_connect_by_path(pk,',') c1
21          from   tbl
22          connect by d=prior d and grp = prior grp and pk > prior pk)
23  group by d,grp;
'('||LTRIM(MAX(C1)KEEP(DENSE_RANKLASTORDERBYLV),',')||')'
(001,002,003)
(007,008,009)
(007,010)
SQL>That works on 9i. Other possiblities on 10g.
Nicolas.