[SOLVED] howto unzip multipart zipfiles?

Hi all, I have a problem that is driving me crazy, I downloaded some app I need and its a multipart zip file, In windows I should just unzip the file regularly and all went good, whoever the unzip linux utility refuses to do so.
I do have a virtual machine and can just uncompress the file there, but why linux doesn't want to unzip the file?
I tried the instructions provided here http://www.hendra-k.net/how-to-extract- … files.html to no avail, the -F option doesnt work (even if I inputthe --out operand and specify and different zip file, it doesn't work also with -FF option.
Any help will be appreciated.
thanks in advance
Last edited by 655321 (2010-09-24 21:00:21)

Ashren wrote:
Just a crazy idea ... Try joining them like this:
cat *.z* > newfile.zip
And then unzip the resulting file.
It probably won't work.
That's what he's trying to do, as the linked article suggested:
hendra-k@server $ cat zipfiles.* > zipfiles-full.zip
hendra-k@server $ zip -F zipfiles-full.zip
hendra-k@server $ unzip zipfiles-full.zip

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Cheers
n4v33n
Edited by: n4v33n on Dec 8, 2008 7:53 AM

Thanks a lot for the suggestion bro. that took me a step further,
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Wolfgang
"Flex Travel - Higo Rocha Cidario" <[email protected]> wrote in message
news:oE0uh.7409$[email protected]..
> Hi,
>
> I am trying to unzip a file from php.
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>
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ZipEntry anEntry;
anEntry = new ZipEntry(name);
zipout.putNextEntry(anEntry);
zipout.closeEntry();
zipDir(filePath, zipout, name);
else
ZipEntry anEntry;
if (!relativeDir.endsWith("/"))
relativeDir += "/";
anEntry = new ZipEntry(relativeDir + name);
zipout.putNextEntry(anEntry);
zipDir(filePath, zipout, relativeDir + name);
// Loop again.s
continue;
// Create a FileInputStream on top of f.
FileInputStream fis = new FileInputStream(f);
ZipEntry anEntry;
if ((!relativeDir.endsWith("/")) && (!relativeDir.equals("")))
relativeDir += "/";
if (!relativeDir.equals(""))
anEntry = new ZipEntry(relativeDir + f.getName());
else
anEntry = new ZipEntry(f.getName());
// Place the zip entry in the ZipOutputStream object.
zipout.putNextEntry(anEntry);
zipEntries.put(anEntry.getName(), anEntry.getName());
// Now write the content of the file to the ZipOutputStream.
while ((bytesIn = fis.read(readBuffer)) != -1)
zipout.write(readBuffer, 0, bytesIn);
// Close the Stream.
zipout.closeEntry();
fis.close();
This the code I use to unzip:
        try
            ZipFile zip = new ZipFile(zipFile);
            Enumeration zipEnum = zip.entries();
            zipEnum = zip.entries();
            while (zipEnum.hasMoreElements())
                ZipEntry item = (ZipEntry) zipEnum.nextElement();
                // Directory case.
                if (item.isDirectory())
                    File newdir = new File(unzippedFilesDir + "/" + item.getName());
                    newdir.mkdir();
                // File case.
                else
                    String newfile = unzippedFilesDir + "/" + item.getName();
                    InputStream is = zip.getInputStream(item);
                    FileOutputStream fos = new FileOutputStream(newfile);
                    int ch;
                    while ((ch = is.read()) != -1)
                        fos.write(ch);
                    is.close();
                    fos.close();
            zip.close();
        catch (Exception e)
            System.out.println(e);
            e.printStackTrace();
        }The exception is thrown on the line:
ZipFile zip = new ZipFile(zipFile);Do you see something weird in my code..?
I'm working on this problem for several days, and I'm losing hope...
Thanks,
Phil

This looks wierd:
ZipFile zip = new ZipFile(zipFile);
Enumeration zipEnum = zip.entries();
zipEnum = zip.entries();

[SOLVED] howto unzip multipart zipfiles?

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