[SOLVED] Why are control characters visible in text files??

Hi,
If I direct the output of 'ls' to a file like:
ls > file.txt
and open the file in a editor such as vi, joe or mousepad, it looks like this:
[[01;34m22x22[[0m
[[01;34m24x24[[0m
[[01;34m32x32[[0m
[[0mindex.theme[[0m
[[01;34mscalable[[0m
[[m
I just did the same thing on an old slackware box and no control characters are visible. The same for a recent LFS build. I realize I could probably pipe through dos2unix, but it shouldn't be happening anyway. Any input is appreciated.
Thanks
-Frank
Last edited by fianella (2007-10-24 10:37:00)

at the DOS prompt (sorry, old habits die hard :-) ) type
alias ls
and see what the results are. Compare that against your slackware or lfs builds. You will probably find that the color= option is different - most builds will not include the color ANSI sequences if you pipe the output, but if it says color=always the color codes will be included in the redirected file.
Assuming you find an alias for ls that forces color output, you need to find where that is taking place... in your ~/.bashrc file? in /etc/profile.d? And change that to alias ls='ls --color=tty' or something sensible like that.

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Removing the Control Characters from a text file

Hi,
I am using the java.util.regex.* package to removing the control characters from a text file. I got below programming from the java.sun site.
I am able to successfully compile the file and the when I try to run the file I got the error as
------------------------------------------------------------------------D:\Debi\datamigration>java Control
Exception in thread "main" java.util.regex.PatternSyntaxException: Illegal repet
ition
{cntrl}
at java.util.regex.Pattern.error(Pattern.java:1472)
at java.util.regex.Pattern.closure(Pattern.java:2473)
at java.util.regex.Pattern.sequence(Pattern.java:1597)
at java.util.regex.Pattern.expr(Pattern.java:1489)
at java.util.regex.Pattern.compile(Pattern.java:1257)
at java.util.regex.Pattern.<init>(Pattern.java:1013)
at java.util.regex.Pattern.compile(Pattern.java:760)
at Control.main(Control.java:24)
Please help me on this issue.
Thanks&Regards
Debi
import java.util.regex.*;
import java.io.*;
public class Control {
public static void main(String[] args)
throws Exception {
//Create a file object with the file name
//in the argument:
File fin = new File("fileName1");
File fout = new File("fileName2");
//Open and input and output stream
FileInputStream fis =
new FileInputStream(fin);
FileOutputStream fos =
new FileOutputStream(fout);
BufferedReader in = new BufferedReader(
new InputStreamReader(fis));
BufferedWriter out = new BufferedWriter(
new OutputStreamWriter(fos));
// The pattern matches control characters
Pattern p = Pattern.compile("{cntrl}");
Matcher m = p.matcher("");
String aLine = null;
while((aLine = in.readLine()) != null) {
m.reset(aLine);
//Replaces control characters with an empty
//string.
String result = m.replaceAll("");
out.write(result);
out.newLine();
in.close();
out.close();

Hi,
I used the code below with the \p, but I didn't able to complie the file. It gave me an
D:\Debi\datamigration>javac Control.java
Control.java:24: illegal escape character
Pattern p = Pattern.compile("\p{cntrl}");
^
1 error
Please help me on this issue.
Thanks&Regards
Debi
// The pattern matches control characters
Pattern p = Pattern.compile("\p{cntrl}");
Matcher m = p.matcher("");
String aLine = null;

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* Write an application which scans through a text file, and counts
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No need to get quite so uptight. Anyway I think I am making progress although what I have does not compile as it says I need to add curly braces to lines 28 and 44.
Can someone please tell me why I get this error. Maybe the name of the methods - have tried changing but no luck.
cheers
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* by the user) on each line of the file. Use a method to count the
* occurrences on one line. The specification of the method should be:
* private int countCharacters(String line, char c)
* The method returns the number of �c� characters in the line.
public class TextfileScan2
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          for(int i = 0; i < charArray.length; i++)
               if(charArray[i] == 'c')
                    c++;
          System.out.print("There are " + c + " 'c' characters in line");
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Sir,
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Thanking you,
khurram

Hai,
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Mac GigaBytes wrote:
Anyway, I followed the steps you provided, and changed all of the settings including <-- Settings <-- FaceTime and Settings <-- Messages <-- Use your Apple ID for messages.
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[SOLVED] Why are control characters visible in text files??

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