Some problem that I don't understand

Question

I have the next program
int i = 0;
int j = 0;
String[] pila = new String[10];
String[] pila1 = new String[10];
cadbase = prog2;
dirmemo = prog3[i];
do {
if (cadbase.equals("MVI B")) {
vpc ++;
vciclos = vciclos + 7;
j = i + 1;
cadena2 = cadbase;
regb.setText(" " + cadena2);
regcy.setText(" 0");
regp.setText(" 1");
regac.setText(" 0");
regz.setText(" 0");
regs.setText(" 0");
else if (cadbase.equals("INR B")) {
vpc ++;
vciclos = vciclos + 4;
b = "00" + regb.getText().trim();
cad = b;
for(int k = 0; k < 65535; k++) {
if(datos[k].equals(cad))
vcad = k;
vcad ++;
cad = Integer.toHexString(vcad).toUpperCase();
if (cad.length() == 1)
cad = "0" + cad;
regb.setText(" " + cad);
regcy.setText(" 0");
regp.setText(" 1");
regac.setText(" 0");
regz.setText(" 0");
regs.setText(" 0");
else (cadbase.equals("HLT")) {
vpc ++;
vciclos = vciclos + 5;
regcy.setText(" 0");
regp.setText(" 1");
regac.setText(" 1");
regz.setText(" 1");
regs.setText(" 0");
i = vpc ++;
//Registro PC
cadpc = enteros[vpc];
regpc.setText(" " + cadpc);
cadciclos = enteros[vciclos];
regnciclos.setText(" " + cadciclos);
} while (!(cadbase.equals("HLT")));
When I compile it, compiler tell me that I miss a ";" after (cadbase.equals("HLT")), so someone can tell what's happen ????

Answer 1

your block has syntax error...
else (cadbase.equals("HLT")) {
vpc ++;
vciclos = vciclos + 5;
regcy.setText(" 0");
regp.setText(" 1");
regac.setText(" 1");
regz.setText(" 1");
regs.setText(" 0");
modify 1st line & it should work fine..
else if (cadbase.equals("HLT")) {
vpc ++;
vciclos = vciclos + 5;
regcy.setText(" 0");
regp.setText(" 1");
regac.setText(" 1");
regz.setText(" 1");
regs.setText(" 0");
kamlesh