Sort and Delete adjucent...
Hello Every one,
Small query.....in the following code am unable to sort table and delete adjucent
please give me the solution for following code.
Here the itab should be in sort order with out entering duplicates this code is correct but output is not correct.
Please check it out....i want 10,20,30,40,50
TYPES: begin of WA ,
a type i,
b type i,
end of WA.
DATA : ITAB1 TYPE STANDARD TABLE OF WA ."OCCURS 0 WITH HEADER LINE.
DATA ITAB TYPE WA.
itab-a = 10.
itab-b = 10.
append ITAB TO itab1.
itab-a = 10.
itab-b = 10.
append ITAB TO itab1.
itab-a = 20.
itab-b = 20.
append ITAB TO itab1.
itab-a = 50.
itab-b = 50.
append ITAB TO itab1.
itab-a = 50.
itab-b = 50.
append ITAB TO itab1.
itab-a = 20.
itab-b = 20.
append ITAB TO itab1.
itab-a = 40.
itab-b = 40.
append ITAB TO itab1.
itab-a = 40.
itab-b = 40.
append ITAB TO itab1.
itab-a = 30.
itab-b = 30.
append ITAB TO itab1.
itab-a = 30.
itab-b = 30.
append ITAB TO itab1.
sort itab1 BY A B.
loop at itab1 INTO ITAB.
delete adjacent duplicates from itab1.
write:/ itab-a, itab-b.
hi
NO NEED TO PUT LOOP AND ENDLOOP
YOUR SORTING THE INTERNAL TABLE AND THEN DIRECTLY USE DELETE STATEMENT AND THEN USE LOOP AT FOR OUTPUT
*& Report ZNNR_NNR2
REPORT ZNNR_NNR2.
TYPES: begin of WA ,
a type i,
b type i,
end of WA.
DATA : ITAB1 TYPE STANDARD TABLE OF WA ."OCCURS 0 WITH HEADER LINE.
DATA ITAB TYPE WA.
itab-a = 10.
itab-b = 10.
append ITAB TO itab1.
itab-a = 10.
itab-b = 10.
append ITAB TO itab1.
itab-a = 20.
itab-b = 20.
append ITAB TO itab1.
itab-a = 50.
itab-b = 50.
append ITAB TO itab1.
itab-a = 50.
itab-b = 50.
append ITAB TO itab1.
itab-a = 20.
itab-b = 20.
append ITAB TO itab1.
itab-a = 40.
itab-b = 40.
append ITAB TO itab1.
itab-a = 40.
itab-b = 40.
append ITAB TO itab1.
itab-a = 30.
itab-b = 30.
append ITAB TO itab1.
itab-a = 30.
itab-b = 30.
append ITAB TO itab1.
sort itab1 BY A B.
delete adjacent duplicates from itab1.
loop at itab1 INTO ITAB.
write:/ itab-a, itab-b.
ENDLOOP.
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Provide the name of the program you are using so a Moderator may move this message to the correct program forum
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What is your Aperture 3 version?
What kind of duplicates are you asking about?
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My list (from a text file) looks sort of like this...
chereba;verb;to dance;05/02;jon smith;
semrka;verb;to speak;03/01;jim jones;
chersl;verb;to laugh;02/01;nancy doe;
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Chapter c
chersl (verb) to laugh 02/01
nancy doe.
chersl (verb) to laugh 02/01
nancy doe.
chersl (verb) to laugh 02/01
nancy doe.
Chapter s
semrka (verb) to speak 03/01
jim jones.
chereba (verb) to dance 05/02
jon smith.
I think the problem is with the remove method...I don't think that it is doing what it is supposed to do...but I could be way off my rocker and totally missing what the real problem is. Can someone please take a look at this and shove me in the right direction?
import java.util.Vector;
public class neverishDictionary
private Node head;
public neverishDictionary()
head = null;
//begin inner node class
private class Node
private String word, pos, def, date, org;
private Node next;
public Node(String word1, String pos1, String def1, String date1, String org1)
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word = word1;
pos = pos1;
def = def1;
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org = org1;
next = null;
public Node(String word1, String pos1, String def1, String date1, String org1, Node nextNode)
//2nd constructor
word = word1;
pos = pos1;
def = def1;
date = date1;
org = org1;
next = nextNode;
public String getWord()
return word;
public String getPos()
return pos;
public String getDef()
return def;
public String getDate()
return date;
public String getOrg()
return org;
public void setNext(Node nextNode)
next = nextNode;
public Node getNext()
return next;
}//ends the inner class
public boolean isEmpty()
return head == null;
public void addList(String newWord, String newPos, String newDef, String newDate, String newOrg)
Node curr;
Node prev;
Node newNode = new Node (newWord, newPos, newDef, newDate, newOrg);
if(isEmpty())
newNode.setNext(head);
head=newNode;
else
newNode.setNext(head);
head=newNode;
/* else
prev = head;
curr = head;
while (curr != null)
if (newWord.compareTo(curr.getWord())<0)
prev.setNext(newNode);
newNode.setNext(curr);
break;
else
prev = curr;
curr = curr.getNext();
if (curr == null)
prev.setNext(newNode);
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Node prev = head;
Node curr = head;
int x = 0;
while (curr != null)
if (curr.getWord().equals(temp) && curr == head)
String resultWord = curr.getWord();
String resultPos = curr.getPos();
String resultDef = curr.getDef();
String resultDate = curr.getDate();
String resultOrg = curr.getOrg();
head = curr.getNext();
else
if (x == 0)
temp = curr.getWord();
curr = curr.getNext();
else if(curr.getWord().equals(temp))
String resultWord = curr.getWord();
String resultPos = curr.getPos();
String resultDef = curr.getDef();
String resultDate = curr.getDate();
String resultOrg = curr.getOrg();
curr = curr.getNext();
else
curr=curr.getNext();
x++;
public Vector radixSort(Vector vlist)
final int NUMCHARS = 128;
// +----------------+------------------------------------------
// | Public Methods |
// +----------------+
* Sort stuff (a vector of strings) alphabetically.
// Set up the result vector.
Vector result = (Vector) vlist.clone();
// Set up the buckets.
Vector[] buckets = new Vector[NUMCHARS];
for (int i = 0; i < NUMCHARS; i++) {
buckets[i] = new Vector();
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int numStrings = vlist.size();
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int len = 0;
for (int i = 0; i < numStrings; i++) {
String str = (String) result.get(i);
if (str.length() > len) len = str.length();
} // for
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for (int i = 0; i < numStrings; i++) {
String str = (String) result.get(i);
int bucketnum;
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if (str.length() <= pos)
bucketnum = 0;
else
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buckets[bucketnum].add(str);
// Read it back out again, clearing the buckets as we go.
result.clear();
for (int i = 0; i < NUMCHARS; i++) {
result.addAll(buckets);
buckets[i].clear();
} // for(i)
} // for(pos)
putitback (result);//put the vector into the list
// That's it, we're done.
return result;
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public void putitback(Vector result)
String temp = " ";
Node prev = null;
Node curr = head;
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temp = result.remove(x).toString();
if (curr.getWord().equals(temp));
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String def = curr.getDef();
String date = curr.getDate();
String org = curr.getOrg();
remove(temp);
addList(word, pos, def, date, org);
public void displayAll()
//radixSort(vlist);
Node prev = head;
Node curr = head;
String blah = " ";
while (curr != null)
if (blah.compareTo(curr.getWord().substring(0,1)) < 0)
blah = curr.getWord().substring(0,1);
System.out.println("\nChapter " + curr.getWord().substring(0,1));
System.out.println(curr.getWord() + " (" + curr.getPos() + ") " + curr.getDef() + " " + curr.getDate());
System.out.println(" " + curr.getOrg() + ".");
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How can i find and delete duplicate emails on my mac
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An iMessages arrives and is displayed in the App.
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9:54 pm Friday; October 31, 2014
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Since not all systems require all parts there are many rows that have a 0 quantity value, I would like to select these rows and delete them once I have gone through the design phase (checking off required features on a separate sheet).
I like the way the other thread I found will gather all the blank rows at the bottom without changing the order of the rows with data in them.
I don't understand exactly how the formula in the other thread works well enough to modify it to look for a certain column.
I hope I made myself clear enough here, to recap, I would like to sort the rows based on a zero value in one (quantity) column, move them (the zero quantity rows) to the bottom of the sheet, and then delete the rows with a zero quantity (I can delete them manually, but would like to automate the sorting part).
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There is no "this column will be auto-destructing after two minutes"
You will have to use your fingers to delete it.
I wish to add a last comment :
if your boss has the bad habit to look over your shoulder, it's time to find an other one.
As I am really pig headed, it's what I did. I became my own boss so nobody looked over my shoulder.
Yvan KOENIG (VALLAURIS, France) mercredi 13 juillet 2011 20:30:25
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FreshaliciousOne wrote:
I understand that i can manually delete duplicates one by one. Is there a way to automate the process? I have an extensive library that is full of duplicates.
The problem you may face with pursuing automated approaches is that the dupicate check occurs on the basis of song title alone. Automating the removal would have it choosing between different versions of the same song - when you may actually want both since they aren't true duplicates.
Examples:
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Edited by: Thomas Zloch on Mar 3, 2011 2:43 PMIn XK06, flagging Vendor for deletion, I get warning "vendor xxxxx has open items in company code xxxx". Does this mean open Invoice Items, pending payment in FI? Since this is just warning I can hit enter and go ahead and save.
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How can I reset security questions. What is a rescue email.
How can uI reset security questions. What is a rescue email.?