Sort in finder by name

I tried even restoring the system but finder is not able to sort the files bey name (by date of creation instead).
An solution?

Are you both arranging and sorting?
You can set both on the View Options, but on the menu and the button, the unmodified click produces the Arrange options and an Option-click producse the Sort options.

Similar Messages

How to find ContentDb Name for any of the service application (e.g. User profile , Managed metadata , etc) programmatically in a farm ?

Hi,
I have a application where i need to display Name for all the service application. Specifically i need to get the size of user profile service application and Managed metadata service application name.
Please guide me. :)
Thanks and Regards:
Sanjay

You can use
http://blogs.technet.com/b/tothesharepoint/archive/2011/12/19/find-active-databases-used-by-sharepoint-server-2010.aspx
Get-SPDatabase | Sort-Object disksizerequired -desc | Format-Table Name”
http://webcache.googleusercontent.com/search?q=cache:kMHQXNGmjcwJ:sharepointstruggle.blogspot.com/2011/08/programmatically-enumerating-databases.html+&cd=1&hl=en&ct=clnk&gl=in
using(SPSitesite
= newSPSite(url))
using(SPWebweb
= site.OpenWeb())
SPFarmf
= site.WebApplication.Farm;
foreach(SPDatabaseServices
inf.Services.OfType<SPDatabaseService>())
Console.WriteLine(string.Format("Found
Database service {0} of type {1}",
s.Name, s.GetType().Name));
foreach(SPDatabaseServiceInstancespdsi
ins.Instances)
Console.WriteLine(string.Format("|-Found
Database Service Instance {0} ({1})",
spdsi.DisplayName, spdsi.Name));
foreach(SPDatabasespdb
inspdsi.Databases)
Console.WriteLine(
string.Format(" |-DB: {0}\r\n |-TYPE: {1}\r\n
|-HOST: {2} ",
spdb.Name.Length
> 70? spdb.Name.Substring(0,
65)
+ "...": spdb.Name,
spdb.GetType().Name, spdb.Server.Name)
http://social.msdn.microsoft.com/Forums/en-US/61e4e56e-e373-4167-ba97-e0f411feefe9/how-can-we-programmatically-find-the-names-of-sharepoint-databases

Sort order of file names in list windows

Why is the sort order of file names in the File > Open File...
list window other than in a normal Finder list window?
Example:
File > Open...:
@@@2Know.pages
@@@2KnowQ.pages
@@@@@2Do.pages
@@@@eBayAmaz.pages
@@@@pws.pages
@@@@Sold-DE.pages
@@@@Sold-UK.pages
Finder Window:
@@@@@2Do.pages
@@@@eBayAmaz.pages
@@@@pws.pages
@@@@Sold-DE.pages
@@@@Sold-UK.pages
@@@2Know.pages
@@@2KnowQ.pages
How could both lists be displayed equal?
Thanks!

Run this short script
set theFolder to choose folder
set theNames to list folder theFolder
set texte to ""
repeat with n in theNames
--set n to n as text
set texte to texte & n & return
repeat with i from 1 to count of n
set texte to texte & (ASCII number of character i of n) & " , "
end repeat
set texte to texte & return
end repeat
set p2d to path to desktop
set rapport to "the characters.txt"
tell application "Finder"
if exists file rapport of p2d then delete file rapport of p2d
set theRapport to (make new file at p2d with properties {name:rapport})
end tell
write texte to (theRapport as alias) starting at 1
navigate to the folder whose list seems curious.
You will get a file named "the characters.txt" on the desktop.
It will show the code of every character embedded in fileNames.
My guess is that there are some control characters which aren't treated the same by the open dialog and by the Finder.
Here is an example:
.DS_Store
46 , 68 , 83 , 95 , 83 , 116 , 111 , 114 , 101 ,
base Kbase - copie 1.cwk
98 , 97 , 115 , 101 , 32 , 75 , 98 , 97 , 115 , 101 , 32 , 45 , 32 , 99 , 111 , 112 , 105 , 101 , 32 , 49 , 46 , 99 , 119 , 107 ,
base Kbase - copie.cwk
98 , 97 , 115 , 101 , 32 , 75 , 98 , 97 , 115 , 101 , 32 , 45 , 32 , 99 , 111 , 112 , 105 , 101 , 46 , 99 , 119 , 107 ,
base Kbase.cwk
98 , 97 , 115 , 101 , 32 , 75 , 98 , 97 , 115 , 101 , 46 , 99 , 119 , 107 ,
exemple wKbase
101 , 120 , 101 , 109 , 112 , 108 , 101 , 32 , 119 , 75 , 98 , 97 , 115 , 101 ,
Icon
73 , 99 , 111 , 110 , 13 ,
safe
115 , 97 , 102 , 101 ,
scripts pour Kbase
115 , 99 , 114 , 105 , 112 , 116 , 115 , 32 , 112 , 111 , 117 , 114 , 32 , 75 , 98 , 97 , 115 , 101 ,
 w_Kbase vers AW.scpt
240 , 32 , 119 , 95 , 75 , 98 , 97 , 115 , 101 , 32 , 118 , 101 , 114 , 115 , 32 , 65 , 87 , 46 , 115 , 99 , 112 , 116 ,
Yvan KOENIG (from FRANCE samedi 7 mars 2009 23:14:15)

Sort podcast by track name - yes or no?

A simple question for which I cannot find an answer. Does iTunes allow sorting PODCASTS by track name? From what I've read in the many convoluted questions and answers, apparently it cannot. Please let me know if I'm wrong.

*Short answer:*
No.
*Longer answer:*
If you make a playlist and drag the podcasts into it then yes, you can sort them on any column that iTunes caters for, but you can't do it in the Podcasts section of your library
*Even longer answer:*
Details of how to reconnect orphaned episodes and reorder tracks within a podcast should be in this older thread:
http://discussions.apple.com/message.jspa?messageID=11054406#11054406
tt2

Sort Preset Bin by Name?

Am I missing something? I've searched the net for this and can not find a way to sort preset bins by name or other. I must be missing somthing. When i add a preset to a custom bin it just goes in random order and that makes it hard to locate and not mix up presets with similar but different names.
Thanks for the help.
Cliff

I don't think you can do a sort like you want. But, you can click and drag a present up or down to change its position

N97 How to sort contacts by company name

Is it possible to sort contacts by company name rather than first name,last name etc?

This is a HUGE shortcoming of Nokia's contacts app, which is still the most awkward and "old style numeric keypad telephone" oriented applications in the Nokia software suite on smartphones.
It's the only reason why I am still sometimes missing my Blackberry. There you find everything so quickly, and not only just typing in the individual's name, nor having to use that Nokia general search tool.
But now that Nokia FINALLY introduced a year ago "finding names typing", without launching the contacts application first I still have the hope that Nokia will release one day a REALLY user friendly, fast and flexible fully integrated agenda suite...

Change sorting in Finder from ascending to descending and keyboard shortcut

Hallo,
can someone point me in the right direction of how to change sorting in Finder from ascending to descending and what are the corresponding keyboard shortcuts?
I am already using the ctrl-cmd+number key shortcuts to modify my sorting, and a Google search produced the answer that I can change from ascending to descending by hitting the key-combination again. But it does not work ...
Any help ;-) ?
Thank you !

Never heard of a keyboard command to toggle the sort sequence from ascending to descending and back.
The usual way to change it is to click the highlighted column name in the Finder window.

WebtopNaming - can not find server name for server ID

We have a LB, and web servers in front of OpenSSO app servers in our environment.
OpenSSO debug log CoreSystem fills up with lot of errors like these:
ERROR: WebtopNaming.getServerFromID() can not find server name for server ID : 07
com.iplanet.services.naming.ServerEntryNotFoundException: Cannot find server.
Sometimes, it even complains about a server id (07 in the following trace) which doesn't even exist in the Site Id Table.
There are no changes in the configuration. DNS is properly configured and all the servers and their connectivity are available. CoreSystem throws these errors even after a restart of opensso app servers.
Any ideas about the root cause?
amNaming:05/13/2011 10:22:37:009 AM PST: Thread[WebContainer : 0,5,main]
Server Id Table -> {%protocol://%host:%port%uri/AssertionManagerServlet/AssertionManagerIF=iplanet-am-naming-samlassertionmanager-url, http://host4.company.com:8080/openSSO=04, com.iplanet.dpro.profile.agent.ProfileService=iplanet-am-naming-profile-class, %protocol://%host:%port%uri/SecurityTokenManagerServlet/SecurityTokenManagerIF=iplanet-am-naming-securitytokenmanager-url, %protocol://%host:%port%uri/authservice=iplanet-am-naming-auth-url, %protocol://%host:%port%uri/sts=sun-naming-sts-url, %protocol://%host:%port%uri/SAMLAwareServlet=iplanet-am-naming-samlawareservlet-url, http://host5.company.com:8080/openSSO=05, com.sun.identity.authentication.server.AuthXMLHandler=iplanet-am-naming-auth-class, com.sun.identity.policy.remote.PolicyRequestHandler=iplanet-am-naming-policy-class, %protocol://%host:%port%uri/loggingservice=iplanet-am-naming-logging-url, %protocol://%host:%port%uri/jaxrpc/=iplanet-am-naming-jaxrpc-url, %protocol://%host:%port%uri/FSAssertionManagerServlet/FSAssertionManagerIF=iplanet-am-naming-fsassertionmanager-url, %protocol://%host:%port%uri/identity/=sun-naming-idsvcs-rest-url, 03,05,04,02|03,01|03=iplanet-am-platform-site-id-list, %protocol://%host:%port%uri/identityservices/=sun-naming-idsvcs-jaxws-url, %protocol://%host:%port%uri/sts/mex=sun-naming-sts-mex-url, %protocol://%host:%port%uri/profileservice=iplanet-am-naming-profile-url, %protocol://%host:%port%uri/SAMLPOSTProfileServlet=iplanet-am-naming-samlpostservlet-url, 02|02,01|01,05|05,04|04=iplanet-am-platform-lb-cookie-value-list, %protocol://%host:%port%uri/SAMLSOAPReceiver=iplanet-am-naming-samlsoapreceiver-url, https://host4.company.com:8443/openSSO=01, com.sun.identity.log.service.LogService=iplanet-am-naming-logging-class, %protocol://%host:%port%uri/sessionservice=iplanet-am-naming-session-url, https://host5.company.com:8443/openSSO=02, %protocol://%host:%port%uri/policyservice=iplanet-am-naming-policy-url, iplanet-am-naming-service=serviceObjectClasses, com.iplanet.dpro.session.service.SessionRequestHandler=iplanet-am-naming-session-class, https://opensso-qa.company.com:443/openSSO=03}
amNaming:05/13/2011 10:22:37:009 AM PST: Thread[WebContainer : 0,5,main]
Site Id Table -> {03=03, 02=03, 01=03, 05=05, 04=04}
amNaming:05/13/2011 10:22:37:009 AM PST: Thread[WebContainer : 0,5,main]
Platform Servers -> [https://opensso-qa.company.com:443/openSSO, https://host5.company.com:8443/openSSO, https://host4.company.com:8443/openSSO, http://host4.company.com:8080/openSSO, http://host5.company.com:8080/openSSO]
amNaming:05/13/2011 10:22:37:009 AM PST: Thread[WebContainer : 0,5,main]
Platform Server IDs -> [03, 02, 01, 04, 05]
amNaming:05/13/2011 10:22:37:010 AM PST: Thread[WebContainer : 0,5,main]
ERROR: WebtopNaming.getServerFromID() can not find server name for server ID : 07
com.iplanet.services.naming.ServerEntryNotFoundException: Cannot find server.
at com.iplanet.services.naming.ServerEntryNotFoundException.<init>(ServerEntryNotFoundException.java:52)
at com.iplanet.services.naming.WebtopNaming.getServerFromID(WebtopNaming.java:709)
at com.iplanet.dpro.session.SessionID.setServerID(SessionID.java:380)
at com.iplanet.dpro.session.SessionID.parseSessionString(SessionID.java:363)
at com.iplanet.dpro.session.SessionID.getSessionServerID(SessionID.java:261)
at com.iplanet.dpro.session.service.SessionService.isLocalSite(SessionService.java:881)
at com.iplanet.dpro.session.Session.getSessionServiceURL(Session.java:1197)
at com.sun.identity.authentication.UI.LoginServlet.initializeRequestContext(LoginServlet.java:153)
at com.iplanet.jato.ApplicationServletBase.processRequest(ApplicationServletBase.java:578)
at com.iplanet.jato.ApplicationServletBase.doGet(ApplicationServletBase.java:459)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:743)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:856)

Thank You for the response.
Here is my site configuration in OpenSSO:
There are 4 servers in the two opensso hosts (2 secure, 2 non secure)
Servers:
http://host4.company.com:8080/openSSO
http://host5.company.com:8080/openSSO
https://host4.company.com:8443/openSSO
https://host5.company.com:8443/openSSO
Only one site with secure URLs is configured
Sites:
site1
Primary URL: https://opensso-qa.company.com:443/openSSO
Assigned Servers:
https://host4.company.com:8443/openSSO
https://host5.company.com:8443/openSSO
From the CoreSystem log, Server ID definitions are:
https://host4.company.com:8443/openSSO=01
https://host5.company.com:8443/openSSO=02
https://opensso-qa.company.com:443/openSSO=03
http://host4.company.com:8080/openSSO=04
http://host5.company.com:8080/openSSO=05
Sometimes it throws an exception with existing server IDs. But sometimes it also complains about non existing server IDs.

Crystal Reports XI and Sun One 6.1 web server SP 5 Error finding JNDI name

I am trying to create a Crystal Reports XI report in a JSP using Sun One 6.1 Web server sp 5.
At this point I am getting the error �Error finding JNDI name� on Sun One
The application will run on Netbeans/Tomcat
I have done the following:
I edited CRConfig.xml
<?xml version="1.0" encoding="utf-8"?>
<CrystalReportEngine-configuration>
�
<DataDriverCommon>
     <JavaDir>C:\Program Files\Java\j2re1.4.2_10\bin</JavaDir>
<Classpath>C:\oracle\product\10.2.0\client_1\jdbc\lib\ojdbc14.jar;�</Classpath>
�
<JDBC>
     <CacheRowSetSize>100</CacheRowSetSize>
     <JDBCURL>jdbc:oracle:thin:@10.10.10.10:1521:dev</JDBCURL>
     <JDBCClassName>oracle.jdbc.driver.OracleDriver</JDBCClassName>
     <JDBCUserName>lab_ro</JDBCUserName>
     <JNDIURL></JNDIURL>
�
</JDBC>
I created a report using JDBC (JNDI) connection and have the JNDI Connection set to the name of DATA.
The report works just fine in Crystal Reports.
Then in Netbeans I created an application and it runs in the Tomcat part of Netbeans
In context.xml I have:
<Context path="/BOEnterpriseTest3">
<Resource name="jdbc/dev" auth="Container" type="javax.sql.DataSource"
driverClassName="oracle.jdbc.driver.OracleDriver" url="jdbc:oracle:thin:@10.10.10.10:1521:dev"
username="theuserid" password="thepassword" maxActive="20" maxIdle="10" maxWait="-1"/>
</Context>
In web.xml I have
<web-app>
<context-param>
<param-name>crystal_image_uri</param-name>
<param-value>crystalreportviewers11</param-value>
</context-param>
�
<taglib>
<taglib-uri>/crystal-tags-reportviewer.tld</taglib-uri>
<taglib-location>/WEB-INF/crystal-tags-reportviewer.tld</taglib-location>
</taglib>
<resource-ref>
<description>jdbc:oracle:thin:@10.10.10.10:1521:dev</description>
<res-ref-name>jdbc/dev10g</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Application</res-auth>
<res-sharing-scope>Shareable</res-sharing-scope>
</resource-ref>
<resource-ref>
<description>jdbc:oracle:thin:@10.10.10.10:1521:dev</description>
<res-ref-name>Data</res-ref-name>
<res-type>javax.sql.DataSource</res-type>
<res-auth>Application</res-auth>
<res-sharing-scope>Shareable</res-sharing-scope>
</resource-ref>
</web-app>
in web-inf\sun-web.xml I have
<sun-web-app>
<resource-ref>
<res-ref-name>jdbc/dev10g</res-ref-name>
<jndi-name>Data</jndi-name>
</resource-ref>
</sun-web-app>
I have copied all of Common Files\Business Objects\3.0\java\lib and Common Files\Business Objects\3.0\java\lib\external to the lib folder
I have copied crystalreportviewers11 to the root of my web application
I have tried to load the JNDI information and display the report
<%@page pageEncoding="UTF-8"
import="com.crystaldecisions.reports.reportengineinterface.*,
com.crystaldecisions.report.web.viewer.*,
javax.naming.*,
javax.sql.*,
java.sql.*"%>
<%
InitialContext initContext = new InitialContext();
DataSource source = (DataSource) initContext.lookup("java:comp/env/jdbc/dev10g");
Context initCtx = new InitialContext();
Context envCtx = (Context) initCtx.lookup("java:comp/env");
try{
     // Look up our data source
DataSource ds = (DataSource)initCtx.lookup("Data");
out.println("found ds under jdbc/Data");
catch ( NamingException e ){
// Look up our data source
DataSource ds = (DataSource) initContext.lookup("java:comp/env/jdbc/dev10g");
initCtx.bind("Data", ds);
out.println("found ds under java:com/env:jdbc/Data - bound into root initial context for Crystal to find");
%>
<%
//Use the relative path to the report; the physical or full qualified URL cannot be used.
String reportName = "useridincluded.rpt";
//Database username and password
String userName = "theuserid";
String password = "thepassword";
//check to see if the Report Source Session Variable already exist
Object reportSource = session.getAttribute("Report1");
// Create a new ConnectionInfos and ConnectionInfo object
com.crystaldecisions.sdk.occa.report.data.ConnectionInfos connectionInfos = new com.crystaldecisions.sdk.occa.report.data.ConnectionInfos();
com.crystaldecisions.sdk.occa.report.data.ConnectionInfo connectionInfo = new com.crystaldecisions.sdk.occa.report.data.ConnectionInfo();
//Set username and password for the report's database
connectionInfo.setUserName(userName);
connectionInfo.setPassword(password);
//Add object to collection
connectionInfos.add(connectionInfo);
//---------- Create a ReportClientDocument -------------
com.crystaldecisions.reports.sdk.ReportClientDocument reportClientDocument = new com.crystaldecisions.reports.sdk.ReportClientDocument();
//---------- Set the path to the location of the report soruce -------------
//Open report.
reportClientDocument.open(reportName, 0);
//Get the report source
reportSource = reportClientDocument.getReportSource();
//---------- Create the viewer and render the report -------------
//create the CrystalReportViewer object
com.crystaldecisions.report.web.viewer.CrystalReportViewer crystalReportViewer = new com.crystaldecisions.report.web.viewer.CrystalReportViewer();
//set the reportsource property of the viewer
crystalReportViewer.setReportSource(reportSource);
//set the DB logon into the viewer
crystalReportViewer.setDatabaseLogonInfos(connectionInfos);
//set viewer attributes
crystalReportViewer.setOwnPage(true);
crystalReportViewer.setOwnForm(true);
crystalReportViewer.refresh();
//set the CrystalReportViewer print mode
//crystalReportViewer.setPrintMode(com.crystaldecisions.report.web.viewer.CrPrintMode.ACTIVEX);
crystalReportViewer.setPrintMode(com.crystaldecisions.report.web.viewer.CrPrintMode.PDF);
//process the report
crystalReportViewer.processHttpRequest(request, response, getServletConfig().getServletContext(), null);
%>
On the Sun One Web server
On the Java Tab
JDBC Connection Pools
Pool Name = dev10g
Class name = oracle.jdbc.pool.OracleDataSource
User id = theuserid
url = 10.10.10.10
password=thepassword
JDBC Resources
JNDI Name=dev10g
Pool = dev10g
I get the error finding JNDI name � how do I tell Sun One where the JNDI is to make Crystal Reports work?

I tried the following to test the JNDI
I am trying to do JNDI in Sun One Web server 6.1 sp 5 but I seem to be missing an important part. I get two different errors based on the JSP code, �Cannot retrieve data source: javax.naming.NamingException: Cannot create resource instance� or �Cannot retrieve data source: javax.naming.NamingException: Cannot create resource instance�.
Context.xml:
<?xml version="1.0" encoding="UTF-8"?>
<Context path="/BOTest">
<Resource name="jdbc/dev10g" auth="Container" type="javax.sql.DataSource"
driverClassName="oracle.jdbc.driver.OracleDriver" url="jdbc:oracle:thin:@10.10.10.10:1521:dev10g"
username="userid" password="password" maxActive="20" maxIdle="10" maxWait="-1"/>
<Resource name="Data" auth="Container" type="javax.sql.DataSource"
driverClassName="oracle.jdbc.driver.OracleDriver" url="jdbc:oracle:thin:@10.10.10.10:1521:dev10g"
username="userid" password="password" maxActive="20" maxIdle="10" maxWait="-1"/>
</Context>Sun-one.xml:
<sun-web-app>
<context-root>BOTest</context-root>
<resource-ref>
<res-ref-name>jdbc/dev10g</res-ref-name>
<jndi-name>jdbc/dev10g</jndi-name>
</resource-ref>
</sun-web-app>web.xml:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE web-app
    PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN"
    "http://java.sun.com/dtd/web-app_2_3.dtd">
<web-app>
    <session-config>
        <session-timeout>
            30
        </session-timeout>
    </session-config>
    <welcome-file-list>
     <welcome-file>
            index.jsp
        </welcome-file>
    </welcome-file-list>
    <resource-ref>
        <description>jdbc:oracle:thin:@10.10.10.10:1521:dev10g</description>
        <res-ref-name>jdbc/dev10g</res-ref-name>
        <res-type>javax.sql.DataSource</res-type>
        <res-auth>Application</res-auth>
        <res-sharing-scope>Shareable</res-sharing-scope>
    </resource-ref>
    <resource-ref>
        <description>jdbc:oracle:thin:@10.10.10.10:1521:dev10g</description>
        <res-ref-name>Data</res-ref-name>
        <res-type>javax.sql.DataSource</res-type>
        <res-auth>Application</res-auth>
        <res-sharing-scope>Shareable</res-sharing-scope>
    </resource-ref>
</web-app>server.xml has:
<RESOURCES>
- <JDBCCONNECTIONPOOL name="dev10g" datasourceclassname="oracle.jdbc.pool.OracleDataSource" steadypoolsize="8" maxpoolsize="32" poolresizequantity="2" idletimeout="300" maxwaittime="60000" connectionvalidationrequired="off" connectionvalidationmethod="auto-commit" validationtablename="" failallconnections="off" transactionisolationlevel="read-uncommitted" isolationlevelguaranteed="off">
<PROPERTY name="URL" value="jdbc:oracle:thin:@10.45.3.197:1521:dev10g" />
<PROPERTY name="User" value="lab_ro" />
<PROPERTY name="Password" value="0asphalt1" />
</JDBCCONNECTIONPOOL>
<JDBCRESOURCE jndiname="jdbc/dev10g" poolname="dev10g" enabled="on" />
<JDBCRESOURCE jndiname="Data" poolname="dev10g" enabled="on" />
- <JDBCCONNECTIONPOOL name="Data" datasourceclassname="oracle.jdbc.pool.OracleDataSource" steadypoolsize="8" maxpoolsize="32" poolresizequantity="2" idletimeout="300" maxwaittime="60000" connectionvalidationrequired="off" connectionvalidationmethod="auto-commit" validationtablename="" failallconnections="off" transactionisolationlevel="read-uncommitted" isolationlevelguaranteed="off">
<PROPERTY name="User" value="lab_ro" />
<PROPERTY name="URL" value="jdbc:oracle:thin:@10.45.3.197:1521:dev10g" />
<PROPERTY name="Password" value="0asphalt1" />
</JDBCCONNECTIONPOOL>
<JDBCRESOURCE jndiname="jdbc/Data" poolname="Data" enabled="on" />
<JDBCRESOURCE jndiname="dev10g" poolname="dev10g" enabled="on" />
</RESOURCES>I am getting the following error: �Cannot retrieve data source: javax.naming.NamingException: Cannot create resource instance�
With the following code:
<%@page
   import="java.io.*,
           javax.sql.*,
           javax.naming.*,
           java.sql.*,
           java.util.*"%>
<%
Context init;
Context ctx;
DataSource datasource;
Connection con;
try
init = new InitialContext();
Context envCtx = (Context) init.lookup("java:comp/env");
datasource = (DataSource) envCtx.lookup("jdbc/dev10g");
catch(NamingException ex)
    out.print("Cannot retrieve data source: " + ex.toString(true));
    return;
try
    con = datasource.getConnection();
catch (Exception e)
out.print("Cannot retrieve connection: " + e.toString());
return;
try
    PreparedStatement pstmt = con.prepareStatement("SELECT PROJNO FROM MATERIALSLAB.VW_ASPHALTHEADERINFO");
    ResultSet results = pstmt.executeQuery();
    while (results.next())
    out.println(results.getString(1));
catch(Exception ex)
out.print("Got connection, can't execute query: " + ex.toString());
return;
%>I get the following error: Cannot retrieve data source: javax.naming.NamingException: Cannot create resource instance
With the following code:
<%@page
   import="java.io.*,
           javax.sql.*,
           javax.naming.*,
           java.sql.*,
           java.util.*"%>
<%
Context init;
Context ctx;
DataSource datasource;
Connection con;
try
    init = new InitialContext();
    ctx = (Context) init.lookup("java:comp/env");
    datasource = (DataSource) ctx.lookup("jdbc/dev10g");
catch(NamingException ex)
    out.print("Cannot retrieve data source: " + ex.toString(true));
    return;
try
    con = datasource.getConnection();
catch (Exception e)
out.print("Cannot retrieve connection: " + e.toString());
return;
try
    PreparedStatement pstmt = con.prepareStatement("SELECT PROJNO FROM MATERIALSLAB.VW_ASPHALTHEADERINFO");
    ResultSet results = pstmt.executeQuery();
    while (results.next())
    out.println(results.getString(1));
catch(Exception ex)
out.print("Got connection, can't execute query: " + ex.toString());
return;
%>

How to find the Names of Most costly Views or Most Time consuming views

Hi All,
I had a database consisting of almost 200 views,as a part of Optimization process i want to find out the most costlier views.How to do that.Actually i want the names of the VIEWS,so that i can optimize that.Can any one help me out?
I had one more doubt in our Database a view is created like view A( which is created by joining several tables).so do i need to add index on this view separately or does it take the index of the tables which i joined? And in our Database i had created
a VIEW which is derived from other views(the Joining objects are views not tables),so while i select recoreds from this views which is derived from other views it is taking a lot of time.Is tehre any problem with that?

Please avoid such double post spread over several forums:
http://social.msdn.microsoft.com/Forums/en-US/bae4042a-10b8-4d12-aa46-88a05ea37a76/how-to-find-the-names-of-most-costly-views-or-most-time-consuming-views?forum=sqldataaccess
Olaf Helper
[ Blog] [ Xing] [ MVP]

How can I find the name of a file I downloaded four months ago?

I downloaded a file on either February 15th or 16th. Embarrassingly, I've lost the file, simply by forgetting its name. I need to be able to search my download history, by date. Does anyone know of a way to do this? I know that the history is kept that long, and that I haven't erased the history. Finding the date that I visited the website was easy using history and an approximate date, but download history is less intuitive.
And, no, revisiting the website doesn't help; the only way to find the name of the file there (it's an ebook) is to buy it again, which is NOT what I wish to do.
This was in Windows 7 Home Premium Edition, with FireFox v. 28.0 (yes, I know it's outdated; I haven't been using that computer much lately). I don't know what version of FireFox was installed at the time of the download -- whatever was most current at the time, as I usually make a practice of installing updates.

The downloads folder in the history manager? I'm not sure what you mean.
When I click on History, I see what I've put in the screenshot. Then it starts telling me where I've been today. Nothing about downloads, per se. I've been getting at those through Tools/Downloads.
I have FireFox set up to ask me where downloads should go, rather than automatically sending them to my Downloads folder in Windows, and even if it had automatically saved to Downloads, it wouldn't still be there now.
In a pinch, I suppose I could skip the first few in the downloads list, and then start right-clicking on individual downloads and selecting Go To Download Page, but I was hoping there might be some way to narrow it down, by getting at the date on downloads. That's fairly easy in History, but I don't see any way to do it in Tools/Downloads.

How to find JSFF name in managed bean

Hi Gurus,
I am new in adf and using 11.1.2.3. How i can find the name of jsff page name in managed bean. For example if i have abc.jsf contains a fragment xyz.jsff. i want when i click on button in jsff page, a pop shows me the name it is xyz.jsff.
Thanks,

Hi,
to get the page name,FacesContext.getCurrentInstance().getViewRoot().getViewId() (returns abc.jsf). If you expose the page fragment through an ADF region, then the call is
ControllerContext.getInstance().getCurrentViewPort().getViewId() (returns xyz if the view activity has the same name as the physical file xyz.jsff)
Frank

Help with using mergesort to sort a list of names alphabetically?

Hi, I'm trying to sort a list of names alphabetically, case-insensitive by using the mergesort technique.
I wrote this code and when I trace it through on paper with an example array of names, it should work, but when I run it with an actual txt file, it's not correctly alphabetical.
I'd appreciate it if someone could take a look at my code and give me some ideas on what my problem might be.
Thanks in advance! (note: I also posted this question to java-forums.org, as I've been working on this little problem for over five hours and am in desperate need of some help!)
public static void mergeSort(String[] names)
        if (names.length >= 2)
            String[] left = new String[names.length/2];
            String[] right = new String[names.length-names.length/2];
            for (int i = 0; i < left.length; i++)
                left[i] = names;
for (int i = 0; i < right.length; i++)
right[i] = names[i + names.length/2];
mergeSort(left);
mergeSort(right);
merge(names, left, right);
// pre : result is empty; list1 is sorted; list2 is sorted
// post: result contains result of merging sorted lists;
// add merge method below
public static void merge(String[] names, String[] left, String[] right)
int i1 = 0;
int i2 = 0;
for (int i = 0; i < names.length; i++)
if (i2 >= right.length || (i1 < left.length && left[i1].compareToIgnoreCase(right[i1])<0))
names[i] = left[i1];
i1++;
} else
names[i] = right[i2];
i2++;

Welcome to the forum.
Please read this to learn hot to format your code (and other things relevant for this forum):
https://forums.oracle.com/forums/ann.jspa?annID=1535
923566 wrote:
Hi, I'm trying to sort a list of names alphabetically, case-insensitive by using the mergesort technique.
I wrote this codeDo you know the <tt>TreeSet</tt> class?
http://docs.oracle.com/javase/7/docs/api/java/util/TreeSet.html
With that sorting Strings is a two liner:
http://www.java2s.com/Code/Java/Collections-Data-Structure/TreeSetDemo.htm
bye
TPD

How to find out name of table for a structure.

hello all,
I want to find out name of table for a structure ADDR1_DATA. can anybody pls tell me how to find out it?
Thanks,
Ashu

Hi Ashu,
You write the structure name in se11
after selecting the database table radio button
click on the where used list button in the application tool bar.
You will find the table name if it is used else where.
Check out the website at:
http://sap-idoc2edi-consulting.com/
Read the blog at:
http://blogs.ittoolbox.com/sap/ehadzipetros
Regards,
Jagadish

Alphabetical sorting of Music Artists [Name of Artist] All Songs?

When I go to Music>Artists>[Name of Artist]>All Songs, it sorts the songs by album, is there a way to have this sorted alphabetically instead, without regard to album? Basically I want a way to view an alphabetical list of songs by a certain artist without making a million playlists. This would only apply to Music>Artists>[Artist]>All Songs, I want everything else to stay as is. This is for a current gen Ipod Classic. Also, would doing this (if it's even possible) mess up the sorting of artists who I only have one album for (I would want these to stay sorted by track number)?

Regarding the playlists, just click on the NAME column within each playlist to sort the list by name. Make sure the shuffle icon is not selected before you do this. Your playlists will be in Track Name order now. (You must do this for EACH playlist)
I believe when choosing an individual artist, then choosing all albums by that artist, the tracks will be sorted by album name then track number per album, so the ALBUMS will be played in alphabetical order, but the songs will play in the track order of each album. There is no way to chage this, as far as I know.
There may be a workaround for this by removing all the track numbers from all of your files. However, this will mess up your album order if you ever wish to listen to individual albums.
To each his own, I know, but hearing all songs in alphabetical order drives me insane.

Sort in finder by name

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