Sorting the members of a group

Noticed that while adding a member to a group, is there any way to sort those members?
thanks

Nope.
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How can I query all the members of a group using querbuilder? I cannot find any related properties

How can I query all the members of a group using querbuilder? I cannot find any related properties describing members under /home/groups/s/sample_group in jcr repository.

Hi,
FieldPoint Explorer is no longer used to configure FieldPoint systems. However, I do not think that the configuring your system in FieldPoint Explorer is causing the error.
FieldPoint systems are now setup in Measurement and Automation Explorer (MAX). Information on setting up FieldPoint systems in MAX can be found in the MAX help under: Installed Products>> FieldPoint. Also, I recommend upgrading to the latest FieldPoint driver and version of MAX. The FieldPoint VI's will be slightly different when you upgrade, so there is a good chance that this will eliminate the error.
Regards,
Hal L.

Querying for the members of a group using the PRC

I've been combing through the PRC API for a way to query for the members of a group (not the ACL, but the member users and groups).
I can't find anything that seems to do this for Plumtree 5.0x using the PRC. Am I missing something or is this just not implemented? Seems like a major oversight to me. If any Plumtreevians are listening, can I add a feature request for those methods in your next release of the WS Server?
Thanks!
Chris Bucchere | bdg | [email protected] | http://www.bdg-online.com
Like blogs? Check out http://bdg-plumtree.blogspot.com

If you go into the Calendar section and select the Edit option for that calendar and then change the permissions for that calendar people should be able to subscribe to it.

How to sort the members by alias names

I am trying to create dimension build rule whicl will sort the dimension members in an ascending order, but it has to be based on the alias name instead of the member name.
I have tried both Parent-CHild and Generation reference but it doesn't work.
For example
for the city members PSE ( alias name Purchase), and USALB ( alias Albany) needs to be sorted by alias names
the current order is
PSE(Purchase)
USALB(albany)
but the requirement is to be
USALB( Albany)
PSE(Purchase)

Even with presorting the input, you still have work to do. By default, Essbase will add new members to the bottom of the list of membrers, it does not insert them into an existing hierarchy in the right places. If your trying to update existing hierarchies and are going the SQL route, you will need two rules (or 1 rule and a flat file). You also need to specify remove unspecified as part of the dimension build process.
HAve a dummy input (either sql or file) that gets loaded the first time. IT will basically wipe out all the members of the dimension, then your second rule (or same rule calling your SQL) can reload the dimension sorted in alias order.
IT is important that these two rules be done together (either in MaxL using comasin a single statement) or in a BSO cube in the outline before the outline is saved. Otherwise you will have deleted any data that existed in the database. It would be impartant that your SQL also pulls all members (including any special members)
Edited by: GlennS_2 on Jan 6, 2010 9:48 AM
You say you are going to change the stored procedure. That is not necessary, you could put an order by clause in your sql extract statement

Want to sort the columns while using GROUP BY ROLLUP.

Want to order the below query using by "News' column in descending order and "Email address" column in Ascending order.
Note: Sorting should not bring Total value to top. It is happening now.
{code}
SELECT decode(grouping(NVL(Client, 'NA')),1, 'Totals', NVL(Client, 'NA')) "Email (Login ID)",
Location "Location",
SUM(News) "News",
SUM(Website) "Website",
FROM VW_FX_USERDATA
GROUP BY ROLLUP (((NVL(Client, 'NA')),Location,1, 'Totals', NVL(Client, 'NA')))
{code}
PLease let me know if you need any details.
Edited by: Nagaraja Akkivalli on Sep 23, 2011 4:04 PM

Thanks hm,
Let me explain bit clearly.
Say I am getting resultset as below.When I am executing above mentioned query.
Client*        Location    News      Website       Total
ABC        YD           9     0           4
BCD        HB           12     7           13
CDE        SI           1     18           3
JNM        BI          25     0           4
ZZZ        TI          0     221           77
XYZ        TT          0     1           1
Totals                      47     247           435I want it to as below. Here records are sorted in the descending order of the News Count and then Client*
Client*        Location    News      Website       Total
JNM        BI          25     0           4
BCD        HB           12     7           13
ABC        YD           9     0           4
CDE        SI           1     18           3
XYZ        TT          0     1           1
ZZZ        TI          0     221           77
Totals                      47     247           435If I order the column by News in the descending order, it is taking Totals value to the top. (Since I am using GROUP BY ROLLUP).
Note: Sorting should not be applied to Totals.
Hope this is clear to you. Let me know if you need any details.
Thanks and Regards
Nagaraja Akkivalli.

Powershell to get all the members in about 20 DynamicDistribution group in exchange 2010

I have about 20 DynamicDistribution groups in my exchange 2010 enviroment. I need to run a report to show all the members in each group. How can I accomplish this with powershell ? thanks for all the help

I assume you don't want the output of all 20 groups dumped into one single list. So, you'd just use this:
Use the Shell to preview the list of members of a dynamic distribution
group
This example returns the list of members for the dynamic distribution group Full Time Employees. The first command stores the dynamic distribution group object in the variable $FTE.
The second command uses the Get-Recipient cmdlet to list the recipients that match the criteria defined for the dynamic distribution group.
$FTE = Get-DynamicDistributionGroup "Full Time Employees"
Get-Recipient -RecipientPreviewFilter $FTE.RecipientFilter
For detailed syntax and parameter information, see Get-DynamicDistributionGroup and Get-Recipient.
Mike Crowley | MVP
My Blog --
Baseline Technologies

Lsgrp - list all members of a group

lsgrp is a small and fast utility written in C that does just one thing: it lists the members of a group. It can be used in scripts that need to do something for each user in a group, such as setting up directories or generating per-user configuration files. There is a section on the project page explaining why a new utility was necessary.

I agree, addressing a new message to a group using Address through the Mail program seems to fill in just the first recipient's name.
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Alternately, start your new message and then type the name of the group in the To: line (don't use the Address button at all). You don't have to get all of the name typed in before the group name is identified. When the group name has been properly identified just hit the Return key and all of the group members will be filled in the To: line. This should do what you are hoping for.
Dale

Copy global group members to local groups

I have an AD environment with a lot of global groups, all named G-FG-groupname and I would like to move (or copy) the members of these groups to already existing domain local groups with a similar groupname but
with another prefix which is L-RG-groupname.
Example, in which Testn can be replaced by any name.
Members of domain global group G-FG-Test1 have to be moved or copied to domain local group L-RG-Test1
Members of domain global group G-FG-Test2 have to be moved or copied to domain local group L-RG-Test2
Members of domain global group G-FG-Test3 have to be moved or copied to domain local group L-RG-Test3
etc..
Many thanks!

Hi Hoffer,
as Mike already said, use the Searchbase parameter. Here's an example how it could look like in the previous script:
# Import Module
Import-Module ActiveDirectory
# Get old Groups
$GroupsOld = Get-ADGroup -Filter { name -like "G-FG-*" } -Properties Members -SearchBase "OU=OU TestOU,DC=intra,DC=netzwerker,DC=de"
# Then for each group do ...
foreach ($GroupOld in $GroupsOld)
# Get the name of the new group
$NewName = "L-RG-" + $GroupOld.Name.SubString(5)
# Add Group Members
Add-ADGroupMember -Identity $NewName -Members $GroupOld.Members -ErrorAction 'SilentlyContinue'
# Remove Members from old group
Remove-ADGroupMember -Identity $GroupOld -Members $GroupOld.Members -Confirm:$false
Basically, use the Distinguished name of an Organizational Unit as the searchbase parameter.
If you want to know the Distinguished Name of a given OU, you can either use the AD Console, or use this command (change the name as necessary):
Get-ADOrganizationalUnit -filter { name -eq "OU TestOU" } | Select -ExpandProperty DistinguishedName
Cheers,
Fred
There's no place like 127.0.0.1

Using ios 7.0.4 can a group email be sent either from icloud or iPhone by a means other than selecting the individual Contact, ie; can the group be selected and then an email composed that will send the message to all group members.

Using ios 7.0.4 can a group email be sent either from icloud or iPhone by a means other than selecting the individual Contact, ie; can the group be selected and then an email composed that will send the message to all group members.

Hi Richard,
Thanks for the reply - I think I've sorted it though and there isn't actually an issue.
The whole group wasn't receiving the NDR, only the group manager which I setup a few weeks prior. This is a new feature so it complies with certain RFC's, basically the group manager will recieive the NDR to let them know there is a problem.
Something to do with mass mailing and unsolicited mail.
Ta
Ian

How can I increase the members in the chat groups?

The number of members in the cha groups is limited (3000)
How can I increase the members in the chat groups?

Elaborate.

I've found no way to sort. For example, if I type the group "Rush" into the search bar, I get a list of songs recorded by rush and literally thousands of other songs and artists with the word rush in them. There is; however, no way to sort the results.

I've found no way to sort search results in itunes. For example, if I type the group "Rush" into the search bar, I get a list of songs recorded by rush and literally thousands of other songs and artists with the word rush in them. There is; however, no way to sort the results.

In the Search box click on the black Arrow and UNTICK the Search Entire Library.
Then the Search results in Songs view will be displayed in the main Grid and you can sort them by clicking on the column headers.
You can also turn on the column browser which can help with filtering

Sorting the group creating in selection steps

Hi All,
I have created a new group All which has two values 'Y','N'. While displaying the column in the answer it by default put the All values at the end, event I tried to sort it will just sort Y and N value but not All. I do not see any options to sort the new group in selection steps. Any ideas.
Y                  N
N                  Y
All                All
Desired display
All
N
Y
Thanks,
Sushil

I do not see order by clause in the selection steps when creating the new group. There is only one group All which has two values Y and N. So when the report is run the column shows three values Y, N and All and now able to sort with new group at the top. Sorting in the answer will sort just Y , N.

Can I get the members of Domain Users group (AD specific) with JNDI?

Hi All,
I've found these forums very helpful and full of great information, I've been able to retrieve all members of groups that I search for (from the information on this forum), and get the member's attributes such as email addresses through that.
The question I have is, is there a way to query the Domain Users group, since it's a special group in Active Directory, and retrieve the members of it? So far I have been unsuccessful. Here's a query I found that works on .Net:
(|(&({ClassFilter})(memberOf={GroupDistinguishedName}))(distinguishedName={G
roupDistinguishedName}))
I haven't been able to get it to work with JNDI however. Can anyone point me in the right direction?
thanks,
Matt

It's not so much that the Domain Users is a special group, it's more that because by default, all users have their Primary Group set to Domain Users, that it appears to behave differently.
So the query that you're trying to execute via JNDI, would be something like:String searchFilter = "(&(objectClass=user)(memberOf=CN=Domain Users,CN=Users,DC=Antipodes,DC=Com))";And of course if everything has been left to defaults, it doesn't return any results.
Similarly if you look at the member attribute of Domain Users, it will be empty.
Assuming the defaults, and every user's Primary Group is set to Domain Users, the following query would return all the user's whose primary group is Domain Users:String searchFilter = "(&(objectClass=user)(PrimaryGroupID=513))";Note that 513 is the Relative ID (RID) for Domain Users.
Now if you set a user's Primary Group to be something other than Domain Users, then the Domain Users group would now have a value
for it's member attribute and conversely the respective user would now have Domain Users as one of the values of their memberOf attribute.
So then your query would be something like:
String searchFilter = "(&(objectClass=User)(|(memberOf=CN=Domain Users,CN=Users,DC=Antipodes,DC=Com)(PrimaryGroupID=513))){code}
I guess the fundamental question, is why do you need to determine whuch users are members of Domain Users ?
If this is for usie in an application, where the user has authenticated and you are using group membership to make authorisation decisions, perhaps the constructed tokenGroups attribute may be more useful as it contains the Security Identifiers (SID) for all the groups the user is a member of ?

HT5012 When I try to look at my groups the members are shown but it says cannot find page, can anyone helo please?

When I try to look at my groups it shows the members but says page not found, can anyone help please?

I dont understand the answer
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Cannot see the members of the local group on member server!

Hi all,
I have two Windows Server 2008 member servers in a domain, 1 Exchange Server 2010 and 1 WSUS 3.0. When I open the properties of the local Administrator
group on the WSUS server I only see the Administrator being the member of this group. When I add any group/user from the domain to the local Administrator group, I get the following message:
"Group Name" is already a member of group "Administrator".
However, I do not see any other group/user as a member in the property page of the local Administrator group! This is not the case on the Exchange
server! I removed the WSUS server from the domain and re-join it to the domain but this did not help nor did a restart of the server.
Thanks in advance,
This posting is provided AS-IS with no warranties or guarantees and confers no rights.

Okay,
agree with Awinish.
Also, check if there is a restricted groups policy that is applied. AFAIK, it deletes actual members of the wanted group and adds the members mentioned in the group policy. I am not sure but check it.
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posting is provided "AS IS" with no warranties or guarantees , and confers no rights.
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Sorting the members of a group

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