Splitting of records into different rows

Question

Hi,
I have a table 'test' which has three columns :
ID varchar2(10), Product varchar2(100), source varchar2(100).
I have provided two sample records below :
ID PRODUCT SOURCE
ID1 | P1,P2 | S1,S2
ID2 | P1,P3 | S2,S3
I need to split the product and source values (they are comma separated) and make different rows out of them. The result set required looks like below :
ID PRODUCT SOURCE
ID1 | P1 | S1
ID1 | P1 | S2
ID1 | P2 | S1
ID1 | P2 | S2
ID2 | P1 | S2
ID2 | P1 | S3
ID2 | P3 | S2
ID2 | P3 | S3
Could someone help me regarding this ? The number of comma separated values will be dynamic and we can have null between two commas too.
Kind regards,
Mainak
Edited by: user11183570 on Jul 14, 2011 4:43 AM

Answer 1

SQL> CREATE TABLE test (ID varchar2(10), Product varchar2(100), source varchar2(100));
Table created.
SQL> insert into test values ('id1','P1,P2','S1,S2');
1 row created.
SQL> insert into test values('id2','P1,P3','S2,S3');
1 row created.
SQL> commit;
Commit complete.
SQL> WITH tbl AS
  ( SELECT DISTINCT id col1,
    regexp_substr (product, '[^,]+', 1, level) col2 ,
    source col3
  FROM test
    CONNECT BY level <= LENGTH (regexp_replace (product, '[^,]+')) + 1
SELECT DISTINCT col1,
  col2,
  regexp_substr (col3, '[^,]+', 1, level) col3
FROM tbl
  CONNECT BY level <= LENGTH (regexp_replace (col3, '[^,]+')) + 1
ORDER BY 1;  2    3    4    5    6    7    8    9   10   11   12   13