SQL Join help for multiple values in single field.

Question

Hello All,
I need a help, I have two tables T1 and T2
Content of T2 will be like
T2. ID | T2.USERNAME
ID1 | John
ID2 | Peter
ID3 | Mark
Content of T1 is like
T1.ID
ID1 ID2 ID3
ID2
ID1 ID3
I need to join these two tables and replace the T1.ID values with T2.USERNAME, for eg. Row one of T1 should be changed as John Peter Mark.
Note: ID1 ID2 ID3 is a single value.
Thanks for your help.
Sathish.

Answer 1

At Volder: I have made a slight enhancement. It's the same thing but the other way around as last week's regular expression thread. Remember the "and then the bird flew away"? ;-)
SQL> create table t1
  2  as
  3  select 'ID1 ID2 ID3' id from dual union all
  4  select 'ID2' from dual union all
  5  select 'ID1 ID3' from dual union all
  6  select 'ID11 ID2' from dual
  7  /
Tabel is aangemaakt.
SQL> create table t2
  2  as
  3  select 'ID1' id, 'John' username from dual union all
  4  select 'ID2', 'Peter' from dual union all
  5  select 'ID3', 'Mark' from dual union all
  6  select 'ID11', 'Volder' from dual
  7  /
Tabel is aangemaakt.
SQL> select * from t1
  2   model
  3    reference r on (select t2.*, rownum rn from t2)
  4     dimension by (rn)
  5     measures(id, username)
  6    main m
  7     dimension by (id)
  8     measures(cast(id as varchar(200)) str)
  9     rules iterate(100) until (r.id[iteration_number+1] is null)
10      (str[any] = replace(str[CV()], r.id[iteration_number+1],r.username[iteration_number+1]))
11  /
ID          STR
ID1 ID2 ID3 John Peter Mark
ID2         Peter
ID1 ID3     John Mark
ID11 ID2    John1 Peter
4 rijen zijn geselecteerd.
SQL> select id
  2       , str
  3    from t1
  4   model
  5         reference r on (select id,username,rownum rn from t2)
  6           dimension by (rn)
  7           measures (id, username)
  8         main m
  9           dimension by (id)
10           measures (cast(' ' || id || ' ' as varchar2(200)) str)
11           rules iterate(1000) until (r.id[iteration_number+1] is null)
12           ( str[any] = replace
13             ( str[cv()]
14             , ' ' || r.id[iteration_number+1] || ' '
15             , ' ' || r.username[iteration_number+1] || ' '
16             )
17           )
18  /
ID          STR
ID1 ID2 ID3  John Peter Mark
ID2          Peter
ID1 ID3      John Mark
ID11 ID2     Volder Peter
4 rijen zijn geselecteerd.At Sathish: just look at the queries we have to come up with to do such a simple thing. As said many times before, I would also encourage you to change the design instead of executing the queries presented by Volder and me.
Regards,
Rob.
Message was edited by:
Rob van Wijk
Just noticed I missed a final TRIM function around "str", so please add this.