SQL LOGIN with weak password

I need to create a SQL LOGIN with weak password.
Is there a way to change the password policy or bypass for a specific LOGIN ?
I've tried this:

Is there a way to change the password policy or bypass for a specific LOGIN ?
SQL Azure doesn't allow the CHECK_POLCY clause. See
https://msdn.microsoft.com/en-us/library/ms189751.aspx
Why would you want to create a weak password? I think the CHECK_POLICY option is intended only for legacy applications.
Dan Guzman, SQL Server MVP, http://www.dbdelta.com

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[http://support.mozilla.com/en-US/kb/Safe+Mode] <br />
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[http://support.mozilla.com/en-US/kb/troubleshooting+extensions+and+themes]

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AND name NOT LIKE '%\SQLServer2005MSFTEUser$%$%'
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--Server roles for logins:
SELECT 'EXEC sp_addsrvrolemember ' + QUOTENAME(L.name) + ', ' +
QUOTENAME(R.name)
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JOIN sys.server_principals R
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AND L.name NOT LIKE '%\SQLServer2005SQLAgentUser$%$%'
AND L.name NOT LIKE '%\SQLServer2005MSFTEUser$%$%'
AND L.name NOT IN ('BUILTIN\Administrators', 'NT AUTHORITY\SYSTEM', 'sa');
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
MS SQL optimization: MS SQL Development and Optimization
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for the data source account, it will fail login. If I change the account for the data source to "domain.net\ReportDataSourceUser", then it logs in successfully. However, ConfigMgr complains that it cannot find the login for "domain.net\ReportDataSourceUser".
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This is nothing I am familiar with, but I don't have a domain to play with here.
I'm starting to think that the issue is with the ConfigMgr application. There may be a problem with the account used there. I have two versions there - one with the format "DOMAIN-NET\ReportDataSourceUser" (Which doesn't work)
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SQL Login "disabled" flag does not work with asymmetric key??

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ALTER LOGIN MyUser DISABLE
will prevent anyone from logging in with this MyUser login.
However if I create a SQL login FROM ASYMMETRIC KEY, the Disabled flag for the login seems to have no effect. For example, assemblies in executable files from which the asymmetric key was created can still be used even if the login is "disabled".
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It would seem to me that if a login is disabled, no rights granted to that login should be accessible, including "GRANT EXTERNAL ACCESS ASSEMBLY TO ..." and "GRANT UNSAFE ASSEMBLY TO..."
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Can someone please comment on this behavior?

Disabling a Login has no effect on Permissions.
The only thing it prevents, is the interactive process of “logging in”.
That Login can still be impersonated also. – And this is in fact important to know(!).
That’s also in BOL (ALTER LOGIN):
http://technet.microsoft.com/en-us/library/ms189828.aspx
Andreas Wolter | Microsoft Certified Master SQL Server
Blog: www.insidesql.org/blogs/andreaswolter
Web: www.andreas-wolter.com

Password change fails in SQL Developer with verify function...

A couple of months ago I enforced a password verify function on our 11.2.0.3 databases and also one legacy 10.2.0.4 database.
At the time I tested on my account (which had elevated privileges...doh!).   Now some users are hitting expiry, they can't change it via SQL Developer.
If I create a user with 'create session' privilege and set their profile to one that uses the verify function (see both below), I then log in to SQL Developer (we have tried with versions 3.1 (Windows) and 3.2 (Linux) with same failure results.
BTW,.. the password verify function enforces the following:
password must be minimum of 8 characters
password must not be the same as the user name, or user name (1-100)
password must contain at least a single digit
password must contain at least a single character
1. Works = I log into the local server and run command line SQLPlus, type 'password' and update.   I can successfully change my password.
2. Fails = I log into the local server and run command line SQLPlus, type 'alter user <me> identified by <newpwd>;' I get:
TEST: SUTEMP > alter user sutemp identified by carport9999;
alter user sutemp identified by carport9999
ERROR at line 1:
ORA-28221: REPLACE not specified
This error is because the account does not have the 'alter user' privilege.   I'm okay with this, as I don't want our users having this privilege.
3. I start SQL Developer 3.2, type 'alter user <me> identified by <newpwd>;' I get the same ORA-28221 error as above.   That is fine, and as expected.
4. Now in SQL Developer, I type 'password', set a valid password, but I get 'Failed to change password' in the Script Output tab.
I have a database 'after servererror on database' trigger set, and querying the database table it is logging into, I see a record with a date stamp matching my failure with a server_error=28221 (the same as above).
So I'm wondering if I'm doing something wrong here, or if this is a bug in SQL Developer.   I don't want standard users having 'alter user' privileges, but I do want to enforce password verification.
I get the same result on three 11.2.0.3 databases (haven't tried any more but suspect same results for others) and one legacy 10.2.0.4 database, and using SQL Developer 3.1 and 3.2.
DBA_PROFILE used:
PROFILE
RESOURCE_NAME
RESOURCE LIMIT
CTRU
COMPOSITE_LIMIT
KERNEL     DEFAULT
CTRU
SESSIONS_PER_USER
KERNEL     10
CTRU
CPU_PER_SESSION
KERNEL     DEFAULT
CTRU
CPU_PER_CALL
KERNEL     DEFAULT
CTRU
LOGICAL_READS_PER_SESSION    KERNEL     DEFAULT
CTRU
LOGICAL_READS_PER_CALL
KERNEL     DEFAULT
CTRU
IDLE_TIME
KERNEL     DEFAULT
CTRU
CONNECT_TIME
KERNEL     DEFAULT
CTRU
PRIVATE_SGA
KERNEL     DEFAULT
CTRU
FAILED_LOGIN_ATTEMPTS
PASSWORD 10
CTRU
PASSWORD_LIFE_TIME
PASSWORD 180
CTRU
PASSWORD_REUSE_TIME
PASSWORD DEFAULT
CTRU
PASSWORD_REUSE_MAX
PASSWORD 5
CTRU
PASSWORD_VERIFY_FUNCTION     PASSWORD VERIFY_FUNCTION_11G
CTRU
PASSWORD_LOCK_TIME
PASSWORD .002
CTRU
PASSWORD_GRACE_TIME
PASSWORD 21
16 rows selected.
Verify Function used:
$ cat utlpwdmg.sql
Rem
Rem $Header: utlpwdmg.sql 02-aug-2006.08:18:05 asurpur Exp $
Rem
Rem utlpwdmg.sql
Rem
Rem Copyright (c) 2006, Oracle. All rights reserved.
Rem
Rem    NAME
Rem      utlpwdmg.sql - script for Default Password Resource Limits
Rem
Rem    DESCRIPTION
Rem      This is a script for enabling the password management features
Rem      by setting the default password resource limits.
Rem
Rem    NOTES
Rem      This file contains a function for minimum checking of password
Rem      complexity. This is more of a sample function that the customer
Rem      can use to develop the function for actual complexity checks that the
Rem      customer wants to make on the new password.
Rem
Rem    MODIFIED   (MM/DD/YY)
Rem    suren       05/09/13 - customise for NIHI use
Rem    asurpur     05/30/06 - fix - 5246666 beef up password complexity check
Rem    nireland    08/31/00 - Improve check for username=password. #1390553
Rem    nireland    06/28/00 - Fix null old password test. #1341892
Rem    asurpur     04/17/97 - Fix for bug479763
Rem    asurpur     12/12/96 - Changing the name of password_verify_function
Rem    asurpur     05/30/96 - New script for default password management
Rem    asurpur     05/30/96 - Created
Rem
-- This script sets the default password resource parameters
-- This script needs to be run to enable the password features.
-- However the default resource parameters can be changed based
-- on the need.
-- A default password complexity function is also provided.
-- This function makes the minimum complexity checks like
-- the minimum length of the password, password not same as the
-- username, etc. The user may enhance this function according to
-- the need.
-- This function must be created in SYS schema.
-- connect sys/<password> as sysdba before running the script
CREATE OR REPLACE FUNCTION verify_function_11G
(username varchar2,
password varchar2,
old_password varchar2)
RETURN boolean IS
   n boolean;
   m integer;
   differ integer;
   isdigit boolean;
   ischar boolean;
   ispunct boolean;
   db_name varchar2(40);
   digitarray varchar2(20);
   punctarray varchar2(25);
   chararray varchar2(52);
   i_char varchar2(10);
   simple_password varchar2(10);
   reverse_user varchar2(32);
BEGIN
   digitarray:= '0123456789';
   chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
   -- Check for the minimum length of the password
   IF length(password) < 8 THEN
      raise_application_error(-20001, 'Password length less than 8');
   END IF;
   -- Check if the password is same as the username or username(1-100)
   IF NLS_LOWER(password) = NLS_LOWER(username) THEN
     raise_application_error(-20002, 'Password same as or similar to user');
   END IF;
   FOR i IN 1..100 LOOP
      i_char := to_char(i);
      if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN
        raise_application_error(-20005, 'Password same as or similar to user name ');
      END IF;
    END LOOP;
   -- Check if the password contains at least one letter, one digit
   -- 1. Check for the digit
   isdigit:=FALSE;
   m := length(password);
   FOR i IN 1..10 LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(digitarray,i,1) THEN
            isdigit:=TRUE;
             GOTO findchar;
         END IF;
      END LOOP;
   END LOOP;
   IF isdigit = FALSE THEN
      raise_application_error(-20008, 'Password must contain at least one digit, one character');
   END IF;
   -- 2. Check for the character
   <<findchar>>
   ischar:=FALSE;
   FOR i IN 1..length(chararray) LOOP
      FOR j IN 1..m LOOP
         IF substr(password,j,1) = substr(chararray,i,1) THEN
            ischar:=TRUE;
             GOTO endsearch;
         END IF;
      END LOOP;
   END LOOP;
   IF ischar = FALSE THEN
      raise_application_error(-20009, 'Password must contain at least one digit, and one character');
   END IF;
   <<endsearch>>
   -- Check if the password differs from the previous password by at least
   -- 3 letters
   IF old_password IS NOT NULL THEN
     differ := length(old_password) - length(password);
     differ := abs(differ);
     IF differ < 3 THEN
       IF length(password) < length(old_password) THEN
         m := length(password);
       ELSE
         m := length(old_password);
       END IF;
       FOR i IN 1..m LOOP
         IF substr(password,i,1) != substr(old_password,i,1) THEN
           differ := differ + 1;
         END IF;
       END LOOP;
       IF differ < 3 THEN
         raise_application_error(-20011, 'Password should differ from the old password by at least 3 characters');
       END IF;
     END IF;
   END IF;
   -- Everything is fine; return TRUE ;
   RETURN(TRUE);
END;
alter profile ctru limit password_verify_function verify_function_11g;
alter profile default limit password_verify_function verify_function_11g;
alter profile web_and_it limit password_verify_function verify_function_11g;

okay,... I just saw another website which shows I should put in the 'replace <oldpwd>' clause in.
This works in SQL Developer:     alter user sutemp identified by carport999 replace garage999;
So why does the 'password' command fail?     (Developers: it would also be helpful to have the ORA- error displayed as opposed to 'Failed to change password')

While send/receive email, I have received an error message "Sending of password d"? However with same login details, I am able to login with other application.

While send/receive email, I have received an error message "Sending of password d"?
However with same login details, I am able to login with other application.
I have changed password still the issue remains as it is.

https://support.mozilla.org/en-US/kb/cannot-send-messages

I AM A CREATIVE CLOUD MEMBER FOR SOMETIME BUT NOW WHEN I LOGIN WITH THE CORRECT PASSWORD I STILL GET SIGNED OUT MESSAGE AND THEN WHEN TRIED THE SOLUTION GIVEN BY HELP THAT IS TO DELETE OPM.DB FILE OR SECOND SOLUTION INSTALL A FRESH CREATIVE CLOUD FOR DESK

I AM A CREATIVE CLOUD MEMBER FOR SOMETIME BUT NOW WHEN I LOGIN WITH THE CORRECT PASSWORD I STILL GET SIGNED OUT MESSAGE AND THEN WHEN TRIED THE SOLUTION GIVEN BY HELP THAT IS TO DELETE OPM.DB FILE OR SECOND SOLUTION INSTALL A FRESH CREATIVE CLOUD FOR DESKTOP APP OR EVEN SOLUTION OF RUN OF IMSLIBREPLACER IM STIILL NOT ABLE TO LOGIN TO MY CREATIVE CLOUD FOR DEKTOP APP . PLEASE HELP ME AS I NEED TO GET IN AND EXPLORE MORE OF MY DOWNLOADED S/W
I HAVE TRIED ALL POSSIBLE SOLUTION BUT AM AMAZED HOW THIS IS HAPPENING TO ME.
PLEASE PLEASE HELP ME .Creative Cloud Connection

Hi Alfred,
I would like to know the exact error message when you sign in, in the meanwhile please try the following steps assuming its Windows, let me know if its a MAC:
1) Go to Start button>> Control panel>> Uninstall a program.
2) Check if you see Browser safeguard there, if yes then uninstall it.
3) Open Internet explorer>> Tools>> Internet options>> Connections>> Lan Settings>> and it should be like this.
-Ankit

SQL LOGIN with weak password

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