Sql query to calculate order completion time

Question

Hello,
This is probably a textbook example, but I was wondering if someone could show me the technique to answer the following question based on the sample data:
Show all orders from the orders table where completion time (defined as difference between time the order was completed and received). is > 5 hours
Order_id
Action
Time
1
Received
1/11/2014 10:12:00
1
Logged
1/11/2014 10:15:00
1
Sent
1/11/2014 15:15:00
1
Complete
1/11/2014 16:15:00
2
Received
31/10/2014 8:10
2
Logged
31/10/2014 8:28
2
Sent
31/10/2014 10:11
2
Complete
31/10/2014 12:13
3
Received
30/10/2014 13:10
3
Logged
30/10/2014 15:10
3
Sent
30/10/2014 16:10
3
Complete
30/10/2014 17:10
Thanks

Answer 1

create table orders (order_id int, action varchar(50), [time] datetime)
insert into orders values(1,'Received','1/11/2014 10:12'),(1,'Logged','1/11/2014 10:15'),(1,'Sent','1/11/2014 15:15'),(1,'Complete','1/11/2014 16:15'),
(2,'Received','10/31/2014 08:10'),(2,'Logged','10/31/2014 08:28'),(2,'Sent','10/31/2014 10:11'),(2,'Complete','10/31/2014 12:13'),
(3,'Received','10/30/2014 13:10'),(3,'Logged','10/30/2014 15:10'),(3,'Sent','10/30/2014 16:10'),(3,'Complete','10/30/2014 17:10')
select order_id from (
select *, datediff(hour,lag([time],1) Over(partition by order_id Order by [time]),[time]) diff
from orders WHERE action IN ('Complete','Received')) t
WHERE diff>=5
drop table orders