SQL Replace function: errors if replacement text is 8191 characters

Oracle 10.2.0.3.0 Enterprise Edition
I'm working on an application which has a function to generate emails.
We have a template, which gets filled with data from the database depending on the email being sent.
To do this I'm using the Replace function to replace certain parts of the template with the right data.
It seems that if the replacement text (the third argument to the function) is longer than 8191 bytes the function throws a PL/SQL: numeric or value error.
This limitation doesn't appear to be documented anywhere, certainly nowhere that I can find.
Anyone know of a way around this short of building my own replace function?

I've figured out what was going on.
The database column for the replacement text is defined as a clob, but there is a front end limit of 10,000 characters for the field being used.
When using the replace function I was assigning the value to a varchar2(32767) field in the PL/SQL.
So in terms of datatypes the function call is:
varchar2 := replace(varchar2, varchar2, clob)
If the length of the clob is over 8191 characters it errors.
(Presumably because of the bug mentioned in this thread DBMS_LOB.SUBSTR() returning 8191 characters instead of 32767
I've fixed it by simply changing the datatype of the variable to which the value is being assigned to a clob.

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Create Or Replace Function Error

Hello,
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) RETURN NUMBER
AS
BEGIN
RETURN TRUNC((to_date(DATE||' '||TIME, 'DD-MM-YY HH:MM:SS')- to_date('01-JAN-1990','DD-MON-YYYY')) * (86400/2400);
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FUNCTION ssnDate compiled
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Error starting at line 1 in command:
CREATE OR REPLACE VIEW WEBLOG_VIEWS("C_IP", "WEB_LINK", "CS_USER_AGENT", "SESSION")
AS
SELECT ssnDate(LOG_DATE, LOG_TIME) AS 'SESSION',
C_IP,
CS_USER_AGENT,
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Error at Command Line:3 Column:38
Error report:
SQL Error: ORA-00923: FROM keyword not found where expected
00923. 00000 - "FROM keyword not found where expected"
*Cause:
*Action:
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Ok, not sure I really understand, but I posted the query and this is the output I got..
ORA-31603: object "WEBLOG" of type TABLE not found in schema "WEBLOG_TABLE_OWNER_NAME"
ORA-06512: at "SYS.DBMS_METADATA", line 2625
ORA-06512: at "SYS.DBMS_METADATA", line 2668
ORA-06512: at "SYS.DBMS_METADATA", line 2983
ORA-06512: at "SYS.DBMS_METADATA", line 3897
ORA-06512: at "SYS.DBMS_METADATA", line 5678
ORA-06512: at line 1
31603. 00000 - "object \"%s\" of type %s not found in schema \"%s\""
*Cause: The specified object was not found in the database.
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SQL Replace function - error

I am little bit struggling to get the my sql function below, to execute the correct output:
ALTER FUNCTION [dbo].[ReplaceTags](@XML VARCHAR(MAX))
RETURNS VARCHAR(MAX)
AS
BEGIN
SELECT @XML = REPLACE(@XML,[Name],'<a href="<a href="pagename.aspx?tag='+[name]+'">'+[name]+'</a>')
FROM [dbo].[database_tags]
where UploadDate >= '2014-09-01'
RETURN @XML
END
When I call the function (select title, [dbo].[ReplaceTags](XML) from article ), it outputs the following result below, whereas the original data is this - (One is a 1m block of AIREM 2006-1X 2A3,).
Query output:
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Thank you for your help and time.

Hi,
There is no problem do this using CLR in the database side, as well. You can use SQLCLR regular expression function.
In any case your HTML is wrong in the original question. You asked for
SELECT @XML = REPLACE(@XML,[Name],'<a href="<a href="pagename.aspx?tag='+[name]+'">'+[name]+'</a>')
but you need
SELECT @XML = REPLACE(@XML,[Name],'<a href="pagename.aspx?tag='+[name]+'">'+[name]+'</a>')
Please post DDL+DML for the [database_tags] table.
Ronen Ariely
[Personal Site] [Blog] [Facebook]

Error using Replace funciton in java

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ie
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Statement stmt = connection.createStatement();
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Chung 650-505-1876
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ttIsqlCS database_test_R7
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2818: Unknown function REPLACE
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Command> version;
TimesTen Release 11.2.2.4.0
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Hi Guys,
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create or replace function "GetHeirachy" (current VARCHAR2) return VARCHAR2 is
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     parent VARCHAR2(4000);
BEGIN
     LOOP
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parent VARCHAR2(4000);
cur VARCHAR2(4000);
BEGIN
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SELECT PARENT_ITEM_ID, ITEM_NAME INTO parent, name
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WHERE ITEM_ID = cur;
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END IF;
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EXIT WHEN cur IS NULL;
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ih.subs_addr_1
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|| ' '
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|| ' '
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) 1,
50
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Thanks in advance.

Hi Jimmy,
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It was typecasting problem
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Check this out
SQL> declare
2 xmldata clob;
3 Begin
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5 <Transaction>
6 <TransactionType>ORIGINAL</TransactionType>
7 <ControlNumber>60022449779</ControlNumber>
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10 <Contact>.</Contact>
11 <PhoneContact>.</PhoneContact>
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16 <Type>SHIP</Type>
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29 </CargoDimensions>
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34 <CargoId>RW9330P01394AA</CargoId>
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38 <Width>2</Width>
39 </CargoDimensions>
40 </CargoDetail>
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42 <CargoHeader>
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44 <CargoId>RW9330P01322</CargoId>
45 </CargoDetaiW>
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47 <Length>1</Length>
48 <Width>2</Width>
49 </CargoDimensions>
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51 </Cargo>
52 </Transaction>
53 </Message>';
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56 dbms_output.put_line(xmldata);
57 end;
58 /
<Message transaction_log_id="" extraction_date="25/11/09 09:52:03 AM"
version="1.0">
<Transaction>
<TransactionType>ORIGINAL</TransactionType>
<Contro
lNumber>60022449779</ControlNumber>
<BookingHeader>
<PortCodeOriginal>GBSOU</Por
tCodeOriginal>
<Contact>.</Contact>
<PhoneContact>.</PhoneContact>
</BookingHead
er>
<PartyInformation>
<PartyDetails>
<PartyId>10002866</PartyId>
<Type>SHIP</Ty
pe>
<Name1>L
LTD.</Name1>
</PartyDetails>
</PartyInformation>
<Cargo>
<CargoDetail>
<CargoHea
der>
<CargoReceivedSeqNo>600015391790</CargoReceivedSeqNo>
<CargoId>RW9330P01394
8</CargoId>
</CargoHeader>
<CargoDimensions>
<Length>1</Length>
<Width>2</Width>
</CargoDimensions>
</CargoDetail>
<CargoDetail>
<CargoHeader>
<CargoReceivedSeq
No>600015391791</CargoReceivedSeqNo>
<CargoId>RW9330P01394AA</CargoId>
</CargoHe
ader>
<CargoDimensions>
<Length>2</Length>
<Width>2</Width>
</CargoDimensions>
<
/CargoDetail>
<CargoDetail>
<CargoHeader>
<CargoReceivedSeqNo>600015391792</Carg
oReceivedSeqNo>
<CargoId>RW9330P01322</CargoId>
</CargoDetail>
<CargoDimensions>
<Length>1</Length>
<Width>2</Width>
</CargoDimensions>
</CargoDetail>
</Cargo>
</Transaction>
</Message>
PL/SQL procedure successfully completed.
SQL> Twinkle
Edited by: Twinkle on Nov 26, 2009 6:05 PM

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http://asktom.oracle.com/pls/asktom/f?p=100:11:3388795154384573::::P11_QUESTION_ID:1533006062995

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- please mark correct answers

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For every expert, there is an equal and opposite expert. - Becker's Law
My blog
My TechNet articles
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SQL Replace function: errors if replacement text is 8191 characters

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