Ssh keys and gnupg keys from wiki instructions...

Question

following first the gnupg instructions and then ssh keys I've managed to get several instances of gpg-agent running.
[root@frylock ~]# ps aux | grep agent
root 2764 0.0 0.0 4208 432 ? Ss 11:15 0:00 ssh-agent
xtian 2785 0.0 0.1 3500 972 ? Ss 11:18 0:00
gpg-agent -s --enable-ssh-support --daemon
--write-env-file /home/frylock/xtian/.gnupg/gpg-agent.env
root 2958 0.0 0.0 3168 688 ? Ss 11:39 0:00
gpg-agent -s --enable-ssh-support --daemon
--write-env-file /root/.gnupg/gpg-agent.env
root 3036 0.0 0.0 4740 392 ? Ss 11:43 0:00 gpg-agent --daemon
root 3186 0.0 0.0 4740 388 ? Ss 11:53 0:00 gpg-agent --daemon
root 3299 0.0 0.0 4740 388 ? Ss 11:58 0:00 gpg-agent --daemon
root 3549 0.0 0.0 4740 392 ? Ss 12:54 0:00 gpg-agent --daemon
This I can resolve by going back over the instructions--a fifth time. But what I don't understand, why my user account owner of a running process when I'm only logged in one tty as root?
//EDIT: Clarify the login scenario
// EDIT: the code block is cutting off line
Last edited by xtian (2013-09-07 14:20:00)

Answer 1

xtian wrote:
cfr wrote:For example, I don't include the code in ~/.xinitrc or in /etc/profile.d precisely because I'm starting the agent somewhere else.
That's just it. I'm not starting it somewhere else. According to the wiki, its being called from .xinitrc and that's where the call is made to the script in profile.d, I think. Unless the script in /etc/profile.d is starting the script automatically?? I don't know.
Yes. The script you have in /etc/profile.d will start it automatically. I have a similar script in /etc/kde/env and that is all I use. I don't need anything in ~/.xinitrc (or kde's autostart stuff or whatever).  At least, this is true provided those scripts are sourced. What you definitely do not want is the line you currently have in ~/.xinitrc which does not check to see if an instance of gpg-agent is already running.
This is what I use:
$ cat /etc/kde/env/gpg-agent-startup.sh
#!/bin/sh
# see https://wiki.archlinux.org/index.php/SSH_Keys
GPG_AGENT=/usr/bin/gpg-agent
## Run gpg-agent only if not already running, and available
if [ -x "${GPG_AGENT}" ] ; then
# check validity of GPG_SOCKET (in case of session crash)
GPG_AGENT_INFO_FILE=${HOME}/.gpg-agent-info
if [ -f "${GPG_AGENT_INFO_FILE}" ]; then
GPG_AGENT_PID=`cat ${GPG_AGENT_INFO_FILE} | grep GPG_AGENT_INFO | cut -f2 -d:`
GPG_PID_NAME=`cat /proc/${GPG_AGENT_PID}/comm`
if [ ! "x${GPG_PID_NAME}" = "xgpg-agent" ]; then
rm -f "${GPG_AGENT_INFO_FILE}" 2>&1 >/dev/null
else
GPG_SOCKET=`cat "${GPG_AGENT_INFO_FILE}" | grep GPG_AGENT_INFO | cut -f1 -d: | cut -f2 -d=`
if ! test -S "${GPG_SOCKET}" -a -O "${GPG_SOCKET}" ; then
rm -f "${GPG_AGENT_INFO_FILE}" 2>&1 >/dev/null
fi
fi
unset GPG_AGENT_PID GPG_SOCKET GPG_PID_NAME SSH_AUTH_SOCK
fi
if [ -f "${GPG_AGENT_INFO_FILE}" ]; then
eval "$(cat "${GPG_AGENT_INFO_FILE}")"
eval "$(cut -d= -f 1 "${GPG_AGENT_INFO_FILE}" | xargs echo export)"
export GPG_TTY=$(tty)
else
eval "$(${GPG_AGENT} -s --enable-ssh-support --daemon --pinentry-program /usr/bin/pinentry-qt4 --write-env-file)"
fi
fi
In any case, your script should check for the environment file and only start an instance of the agent if it doesn't exist.
I'ts not my script. I'm not up on BASH scripts. This one is from the wiki page. Isn't this script checking just that in this IF clause:
if test -f "$envfile" && kill -0 $(grep GPG_AGENT_INFO "$envfile" | cut -d: -f 2) 2>/dev/null; then
eval "$(cat "$envfile")"
Yes. But the line you have in ~/.xinitrc does NOT check this. It just starts an instance of gpg-agent as a daemon.