Start Date of Week from Week Number

Hi
i need to get the start date of the week based on the week number e.g the start date of week
1 in 2008 would be 01 Jan and start date for week 2 would be 06 Jan and week 3 would be 13 Jan etc
Any advice would be great
Thanks
David

Checkout the java.util.Calendar API and its get/set/add methods.
An alternative is the great Joda Time API at sourceforge.

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it depends upon client requirement.you must have defined the holiday calender as well.if you select the public holidays in your factory calender.then system will allow you to do your daily transctions on public holidays as well and vice versa.so better go with all options selected .and plz check at your end
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How would I display the Week Start Date and Week Number for a range of dates.
required output:
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11 8/03/04 50
12 15/3/04 100
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Do you have a start and end date and need it expanded to weeks ?
Let's say you have a table that include both the start and end dates
select to_char(ddate,'WW'), ddate
 from (select start_dt + rownum - 1 ddate
 from user_objects,
 (select min( START_DATE ) as start_dt,
 max( END_DATE ) as end_dt
 from MY_TABLE
 WHERE .... )
 where start_dt + rownum <= end_dt ) a
where to_char(ddate,'D') = '1'
/Of course, one of the problems with WEEK is interpretation. Week one does not start until the First Sunday of the year. Which may or may not be what you want

How to get the week start date from ISO week number

Hi,
I have a table with the following stucture
Year    error    Week1     week2   week3 ......week53
2012       error1     2           4         2             1
2012       error2    3          0        1                 1I was hoping to get something like select year, error, week1||'Week start date which is a monday of that week' , week2||'Week start date,again monday',....week53 from table
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Thanks,
Sun

Hi, Sun,
To see when week N started, add 7 * (N - 1) days to the beginning of the year. (By definition, the beginning of the ISO year is the start of week 1 of the ISO year.)
To see when week 22 of the current year started:
SELECT TRUNC (SYSDATE, 'IYYY') + (7 * (22 - 1))
FROM    dual
I hope this answers your question.
If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all the tables involved, and the results you want from that data.
Explain, using specific examples, how you get those results from that data.
Always say what version of Oracle you're using.
See the forum FAQ {message:id=9360002}

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I have a requirement as described below.
Table Name Time:
Columns: Fiscal Year, Fiscal Month and Fiscal Week
above table has join with sales table and it contain sales data on week basis. so least granularity of data at week level.
we have a report with columns fiscal year, actual sales and forcast sales. our requirement is to filter the data with following criteria.
Current Month Filter
Jan fiscal week between 1-18 of current year
Feb fiscal week between 5-23 of current year
March fiscal week between 9-27 of current year
November fiscal week between week 44 of current year and week 10 of next year
December
so with above requirement we need to filter data with rollover 18 weeks starting from week number of current month
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1. Oracle version
2. Sample data (CREATE TABLE / INSERT statements)
3. Expected output
4. Explanation of business rules.
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How to calculate start date of the week based on week number ?

i need to get week number of the current date and based on that i need to calculate start date falling in the same week for last year.
Eg. today is 31st week of year and 31st july date. so what will be the date on the 31st week of last year. i need the start date of that week.
we can calculate the week number by select to_char(sysdate,'ww') from dual.
DO we have a single line query for that or will it require writing a pl/sql block ?

you can try following query
it can be as inline but for more clean look and create it as select with include select
with t as
(select sysdate as dt from dual)
select to_char(prev_year_dt - to_char(prev_year_dt, 'D') + 1, 'DD.MM.YYYY') as start_of_week from (select
-- get day from prev year with the same week number
 case
 when to_number(to_char(add_months(dt, -12), 'WW')) > to_number(to_char(dt, 'WW')) then
 dt - (to_number(to_char(add_months(dt, -12), 'WW')) - to_number(to_char(dt, 'WW'))) * 7
 when to_number(to_char(add_months(dt, -12), 'WW')) < to_number(to_char(dt, 'WW')) then
 dt + (to_number(to_char(dt, 'WW')) - to_number(to_char(add_months(dt, -12), 'WW'))) * 7
 else
 add_months(dt, -12)
 end as prev_year_dt
from t) t1good luck
Sergii
'Monday' is not first day of week in 100% ;)
Edited by: Galbarad on Jul 30, 2012 11:00 PM

How do I change the start date for the week from Monday to Sunday on my iPhone 5?

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Sums up the last 4 weeks from the start date

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Pls tell me how to find the give issue with example
How to write queri in SQL
sums up the last 4 weeks from the start date selected (meaning range of date 1st to 7th) (the 4 weeks should stop on the 31st).
Thanks & Regards

<DIV>
select tstdate, weeks, (sum*7) as sum from (select to_date('&date','dd-mon-rrrr') as
tstdate, 
last_day(to_date('&date','dd-mon-rrrr')) as weeks, 
floor((last_day(to_date('&date','dd-mon-rrrr')) - to_date('&date','dd-mon-rrrr'))
/7) as sum 
from dual)</DIV>

Cannot select a Date in the 2nd week of any month from "Month View"

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Find first & last day of the week from given date

Hi All,
I have the below input query,
WITH TEM AS   ( SELECT '11-JAN-13' DT from dual union   SELECT '16-JUN-12' from dual union   SELECT '04-JUL-12' from dual union   SELECT '09-JAN-13' from dual union   SELECT '10-JAN-13' from dual union   SELECT '04-JAN-13' from dual union   SELECT '07-JAN-13' from dual union   SELECT '04-JUN-13' from dual union   SELECT '08-JAN-13' from dual ) SELECT TO_DATE(DT) D1,'WEEK '||TO_CHAR(TO_DATE(DT),'IW-YYYY') WK from tem;
I would like to get the below output i.e. Starting date of the week(Saturday) & end date of the week(Friday)
DT
WEEK Period
Max Date in this week
Min Date in this week
16-Jun-12
WEEK 24-2012
16-Jun-12
22-Jun-12
04-Jul-12
WEEK 27-2012
30-Jun-12
06-Jul-12
04-Jan-13
WEEK 01-2013
04-Jan-13
29-Dec-12
07-Jan-13
WEEK 02-2013
05-Jan-13
11-Jan-13
08-Jan-13
WEEK 02-2013
05-Jan-13
11-Jan-13
09-Jan-13
WEEK 02-2013
05-Jan-13
11-Jan-13
10-Jan-13
WEEK 02-2013
05-Jan-13
11-Jan-13
11-Jan-13
WEEK 02-2013
05-Jan-13
11-Jan-13
04-Jun-13
WEEK 23-2013
01-Jun-13
07-Jun-13
Also suggest if any function available in oracle for this one.

Like this? I think in your required output, 3rd row data, MAX_DATE should be 29-DEC-12 and MIN_DATE should be 04-JAN-13.
WITH TEM AS
( SELECT '11-JAN-13' DT from dual union
SELECT '16-JUN-12' from dual union
SELECT '04-JUL-12' from dual union
SELECT '09-JAN-13' from dual union
SELECT '10-JAN-13' from dual union
SELECT '04-JAN-13' from dual union
SELECT '07-JAN-13' from dual union
SELECT '04-JUN-13' from dual union
SELECT '08-JAN-13' from dual )
SELECT D1 DT,
       WK WEEK_PERIOD,
       CASE WHEN (TRIM(TO_CHAR(D1,'DAY'))='SATURDAY') THEN D1
             ELSE NEXT_DAY(D1,'SATURDAY')-7
        END AS MAX_DATE_IN_THIS_WEEK,
      CASE WHEN (TRIM(TO_CHAR(D1,'DAY'))='FRIDAY') THEN D1
            ELSE NEXT_DAY(D1,'FRIDAY') END AS MIN_DATE_IN_THIS_WEEK
FROM (
SELECT TO_DATE(DT) D1,'WEEK '||TO_CHAR(TO_DATE(DT),'IW-YYYY') WK from tem)
ORDER BY DT;
OUTPUT:
DT        WEEK_PERIOD MAX_DATE_ MIN_DATE_
16-JUN-12 WEEK 24-2012 16-JUN-12 22-JUN-12
04-JUL-12 WEEK 27-2012 30-JUN-12 06-JUL-12
04-JAN-13 WEEK 01-2013 29-DEC-12 04-JAN-13
07-JAN-13 WEEK 02-2013 05-JAN-13 11-JAN-13
08-JAN-13 WEEK 02-2013 05-JAN-13 11-JAN-13
09-JAN-13 WEEK 02-2013 05-JAN-13 11-JAN-13
10-JAN-13 WEEK 02-2013 05-JAN-13 11-JAN-13
11-JAN-13 WEEK 02-2013 05-JAN-13 11-JAN-13
04-JUN-13 WEEK 23-2013 01-JUN-13 07-JUN-13
9 rows selected.

Calendar week: how to substract a number of calendar weeks from a given one

Hi Experts,
Is there a way to calculate this:
If my calendar week is 01.2009 and I want to calculate the corresponding week 18 weeks ago, is there a FM that calculates this?
I tried 01.2009 - 18 but is giving me the wrong week.
Thanks in advance.
Inma

DATA : GV_MONDAY TYPE D,
       GV_DATES TYPE I,
       GV_WEEK   TYPE KWEEK.
PARAMETERS: P_WEEK TYPE KWEEK DEFAULT '200901',
            P_WEEKS TYPE I.
START-OF-SELECTION.
CALL FUNCTION 'WEEK_GET_FIRST_DAY'
    EXPORTING
      WEEK         = P_WEEK
    IMPORTING
      DATE         = GV_MONDAY
    EXCEPTIONS
      WEEK_INVALID = 1
      OTHERS       = 2.
IF SY-SUBRC 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
GV_DATES = P_WEEKS * 7.
GV_MONDAY = GV_MONDAY - GV_DATES.
CALL FUNCTION 'DATE_GET_WEEK'
    EXPORTING
      DATE              = GV_MONDAY
   IMPORTING
     WEEK               = GV_WEEK
   EXCEPTIONS
     DATE_INVALID       = 1
     OTHERS             = 2
IF SY-SUBRC 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
WRITE :/ P_WEEK, '-', P_WEEKS , ': =', GV_WEEK.
Regards,
Shafivullah Mohammad
Edited by: shafivullah mohammad on Jul 9, 2009 12:44 PM

How to calculate start date and last date for current week

Dear All.
i want to calculate the start of the current week as well as the last date of the current week, our week start from Saturday and ends of Friday i.e. Saturday is the first day of the week and Friday is the last day of the week.
How can i acheive this in universe Designer?.
Please help...

Hi
the formulas in webi will be as follows
for startdate
=RelativeDate(LastDayOfWeek(CurrentDate());-8)
for enddate:
=RelativeDate(LastDayOfWeek(CurrentDate());-2)
Regards,
Ranganath

Get weeks based on start date

Hi ,
i need a query that will determine the weeks based on start date.
if the table consists of:
vDate vAmount
06/25/2007 100
06/27/2007 200
07/04/2007 400
If one enters start date as 6/25/2007 , amounts should be broken out in 7 day increments.
Result should be
week1 300
week2 400
where week1 should be from 6/25/2007 to 07/01/2007,
week2 should be from 07/02/2007 to 07/08/2007
and start date is not always on a Monday or Sunday...
any idea?
thanks in advance

try this...
SQL> with rt as
2 (select 'week'||(trunc(l/7,0)+1) wk_no,to_char(trunc(sysdate)+l,'dd-Mon-yyyy') dt,to_char(trunc(sysdate)+l,'Day') "Day" from
3 (select level-1 l from dual connect by level <= 367) where trunc(sysdate) between trunc(sysdate) and add_months(trunc(sysdate),12)),
4 xx as
5 (select '06/25/2007' vdate, 100 vamount from dual union all
6 select '06/27/2007', 200 from dual union all
7 select '07/04/2007', 400 from dual)
8 select wk_no,sum(vamount) from
9 (select (select wk_no from rt where dt = to_date(vdate,'MM/DD/YYYY')) wk_no,vamount from xx)
10 group by wk_no;
WK_NO SUM(VAMOUNT)
week1 300
week2 400
SQL>
SQL> select 'week'||(trunc(l/7,0)+1) wk_no,to_char(trunc(sysdate)+l,'dd-Mon-yyyy') dt,to_char(trunc(sysdate)+l,'Day') "Day" from
2 (select level-1 l from dual connect by level <= 367) where trunc(sysdate) between trunc(sysdate) and add_months(trunc(sysdate),12);
WK_NO DT Day
week1 25-Jun-2007 Monday
week1 26-Jun-2007 Tuesday
week1 27-Jun-2007 Wednesday
week1 28-Jun-2007 Thursday
week1 29-Jun-2007 Friday
week1 30-Jun-2007 Saturday
week1 01-Jul-2007 Sunday
week2 02-Jul-2007 Monday
week2 03-Jul-2007 Tuesday
week2 04-Jul-2007 Wednesday
week2 05-Jul-2007 Thursday
.

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