Still having problem with this sql select... any suggestions! tx

Question

The following code has a result, I need to modify the select somehow which only gives me the rows which are common between all PLSTS.
Any suggestions?
Thank you
SELECT DISTINCT P.PLST, P.MENU, I.PNL, P.ACCESS
FROM AUTHITEM P, I.MENUITEM
WHERE P.MENU = I.MENU
AND P.PNL = I.PNL
AND P.MENU IN ('MSN, CPP')
AND P.ACESS >= 8
AND EXISTS
(SELECT K.PLST,COUNT (*)
FROM AUTHITEM K, J.MENUITEM
WHERE K.MENU = J.MENU
AND K.PNL = J.PNL
AND P.MENU = K.MENU
AND I.PNL = J.PNL
--AND P.PLST !=K.PLST
--HAVING COUNT(*)   =2
GROUP BY P.PLST, PMENU, I.PNL, P.ACCESS)
This is the result with having count (*) = 2 and plst !=plst comment
PLST MENU PNL ACCESS
C001 MSN LNAME 14
C002 MSN LNAME 14
B008 MSN LNAME 14
B005 MSN FNAME 14
M009 MSN LNAME 14
C001 MSN GNAME 14
C002 MSN GNAME 14
B008 MSN LNAME 14
C001 MSN FNAME 14
C002 MSN FNAME 14
k008 CPP MNAME 14
If I add having count (*) = 2, I do not get any results
I need this result
PLST MENU PNL ACCESS
C001 MSN LNAME 14
C002 MSN LNAME 14
C001 MSN GNAME 14
C002 MSN GNAME 14
C001 MSN FNAME 14
C002 MSN FNAME 14
Thank you

Answer 1

  > I need this result
  > PLST MENU PNL   ACCESS
  > C001 MSN  LNAME 14
  > C002 MSN  LNAME 14
  > C001 MSN  GNAME 14
  > C002 MSN  GNAME 14
  > C001 MSN  FNAME 14
  > C002 MSN  FNAME 14
i think based on your original posting what you need on your groupings are the columns MENU, PNL, ACCESS and exclude PLST.
  SELECT DISTINCT P.PLST, P.MENU, I.PNL, P.ACCESS
    FROM AUTHITEM P, I.MENUITEM
   WHERE P.MENU = I.MENU
     AND P.PNL  = I.PNL
     AND P.MENU IN ('MSN, CPP')
     AND P.ACESS >= 8
     AND EXISTS (SELECT 'x'
                   FROM AUTHITEM K, J.MENUITEM
                  WHERE K.MENU = J.MENU
                    AND K.PNL  = J.PNL
                    AND P.MENU = K.MENU
                    AND I.PNL  = J.PNL
                    AND P.PLST !=K.PLST
                 HAVING COUNT(*) = 2
                 GROUP BY PMENU, I.PNL, P.ACCESS)note: untested