String.split() regular expression

Regular expression escapes me. I have a line of a CSV file that looks like this:
1,,3,2,45.00,"This & That, LLC",0
I want the string split by commas but the problem with the line above is there's a comma in the name of the company...I obviously don't want the company name split in half...what would the regular expression be that I would provide to the split method to ensure that only commas not found in between double quotes are used to split the string into an array of Strings? is this possible?
Thanks in advance!
Rob

Telling someone to google might be deserved, but it is mean and unhelpful.
If you want to find a regex for CSV's see O'Reilly's "Mastering Regular Expressions" Section 8.4.4.3. Either buy the book - it's worth it - or subscribe to safari.

Similar Messages

How to split a string with regular expression

Hi.
I need to split a string with a regular expression.
Example
String = "this is; a test";rune haavik;12345;
And I want the output to be:
"this is; a test"
rune haavik
12345
If I use this code:
private void test1()
String str = "\"this is; a test\";rune haavik;12345;";
int i=0;
String[] tmp = str.split(";");
while(i<tmp.length)
System.out.println(tmp);
i++;
Then it splits also in the "" text.
Regards
Rune haavik

Rune haavik:
The most effective way to achieve the end result is, I believe, to read the characters one by one, using a flag that indicates if we are inside quotation or not.
Well, if we are in a mind game, then the following should do.
String[] tmp = str.split(";(?![^\"]*\";)");

Spliting a large string using regular expression which contain special char

I have huge sting(xml) containing normal character a-z,A-Z and 0-9 as well as special char( <,>,?,&,',",;,/ etc.)
I need to split this sting where it ends with </document>
for e.g.
Original String:
<document>
<item>sdf</item>
<item><text>sd</text</item>
</document>
<document>hi</document>
The above sting has to be splited in to two parts since it is having two document tag.
Can any body help me to resolve this issue. I can use StringTokenizer,String split method or Regular expression api too.

manas589 wrote:
I used DOM and sax parser and got few exception. Again i don't have right to change xml. so i thought to go with RegularExpression or some other way where i can do my job.If the file actually comes in lines like what you posted, you should just be able to compare the contents of each line to see if it contains "</document>" or whatever you're looking for. I wouldn't use regex unless I needed another problem.
I got excpetion like: Caused by: org.xml.sax.SAXParseException: The entity "nbsp" was referenced, but not declared.
     at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source)
     at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source)
     at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source)So then it isn't even XML.
Edit: sorry, I just realized why you're considering all of these heavy-duty ideas. It's just that you don't know how to break the string into lines. You do it like this:
BufferedReader br = new BufferedReader(new StringReader(theNotXMLString));

-Split Regular expression pattern

Hi all,
I came across the below example in Lee Holmes' PowerShell Cookbook 3rd editon:
"Hello World" -split "He(ll.*o)r(ld)"
and the output is:
llo Wold
Even though I do understand Regular Expressions to some degree (where I can comfortably write a reasonably simple pattern for -replace operator or Select-String cmdlet for example), I am struggling to understand the RE pattern above and what it's trying
to achieve in the -split context. What are the 2 groupings trying to achieve here while splitting a text? What I want to know is the literal translation of the pattern above in clear English words.
Any thoughts?

I guess that explains it clearly now. In fact that's what I wrote above yesterday. So parenthesis in -split operator pattern is not a grouping construct, instead a 'preserving' construct, saving it from consumption by the split operation.
Therefore, following -match operator pattern-semantics to understand -split operator will mislead us here.
But then again, I have troubles understanding the below pattern
"Hello World" -split "(He(ll.*o)r(ld))"Hello World
llo Wo
ld
However, I think I will leave it at this stage. The main thing I wanted to know was what those parenthesis were there for and now I have the answer. It did not really makes sense to group a pattern for -split operator hence I started this thread.
I think that's all I wanted to know. Thank you.

Format string using Regular Expression

Input string output format...
SELECT q'<select ab_c "ABC", efg "EFG" from dual>' str FROM DUAL
Output:
STR
select ab_c "ABC", efg "EFG" from dual
Required output format using regular expression...
STR
select 'ab_c' "ABC", 'efg' "EFG" from dual

Regular expressions have many limitations as parsing tools, and you didn't specify the rules you wanted. This expression puts quotes around the non blank string before a quoted string:
SELECT regexp_replace(q'<select ab_c "ABC", efg "EFG" from dual>',
                      '([^" ]+)( +"[^ ]*")' , '''\1''\2' ) str FROM DUAL;
STR
select 'ab_c' "ABC", 'efg' "EFG" from dual
{code}
It is not robust - a missing " will confuse it, and you should be using bind variables anyway.

Filter String using Regular Expression

Hello,
I have an application that monitors serial communication between a PC and device. The message protocol is a byte stream that I convert to a string to parse into pretty messages. The start of the string is always "10 02", but if the string is preceded with another "10" like this "10 10 02" it is part of a message. I've been trying to use a regular expression with the Search and Replace VI. My regex is "[^10]\s10\s02" which almost works but it cuts off part of the message:
Before:
10 03 10 02
After:
10 0 <= missing the "3"
10 02
Here's what I'm doing:
Any ideas on what I'm missing? I've attached a simple example.
Thanks
Message Edited by Derek Price on 02-14-2008 08:37 PM
Attachments:
Filter Beginning Message1.vi ‏14 KB
FilterMessageRegex1.png ‏7 KB

Try this approach.
Do search and replace on '10\s02' and replace with '\r\n10\s20'
Then do another search and replace on '10\r\n\10\s20' with '10\s10\s20'
See attached.
Randall Pursley
Attachments:
Message Filter.PNG ‏18 KB

Dumbfounded by Scanner processing String using regular expression

I was reading Bruce Eckel's book when I came across something interesting: extending Scanner with regular expressions. Unfortunately, I was confronted with an issue that doesn't make much sense to me: if the String that I am scanning contains a hyphen, the Scanner doesn't produce anything. As soon as I take it out, it all works like a charm. Here is my example:
import java.util.Scanner;
import java.util.regex.*;
public class StringScan {
public static void main (String [] args){
     String input = "there's one caveat when scanning with regular expressions";
     Scanner scanner = new Scanner (input);
     String pattern = "[a-z]\\w+";
     while (scanner.hasNext(pattern)){
          scanner.next(pattern);
          MatchResult match = scanner.match();
          String output = match.group();
          System.out.println(output);
}What could be the reason? I imagined it could be because the hyphen for some reason gets given a special meaning but when I tried escaping it, it still didn't work.

Thanks for your prompt reply.
I have figured out what was wrong with my code, by the way. Since a single quote is not a word character, it does not match w+. And as the very first input token does not match, the scanner stops immediately. I rewrote my regex to "[a-z].*" and now it does work.

ReplaceAll string by regular expression not work for this case.

I will delete all tag and want "pure text" but the output is delete all.
String content = "<aaa>pure text<fff>";
content = content.replaceAll("<.*>","");Content has output is blank because reqular expression match from begin and end of string
But when i change
String content = "<aaa>pure text<fff";
content = content.replaceAll("<.*>","");The output is ==> pure text<fff
How make req match in sequential
Please lead me to solution

peterdog1234 wrote:
Thank you very much.
I know '?' is a Quantifiers.
I do not understand using ?
Please lead me againSee the paragraph "Laziness Instead of Greediness" from [http://www.regular-expressions.info/repeat.html].

Multi-line String - Match Regular Expression

I am trying to figure out the format of a regular expression in order to pull select lines out of a multi-line string and populate those lines as individual elements of a string array while using Match Regular Expression. The overall length of the multi-line string can vary as well as the text contained within the string. The string can contain letters, numbers, and special characters. I have attached an example VI. Within the example VI I only want to return the lines beginning with "Device #" into the array. The number of lines beginning with "Device #" can vary but I want to capture them all.
Or is there a better function to use instead of Match Regular Expression that will give me the desired outcome?
Solved!
Go to Solution.
Attachments:
MultiLine Regular Expression.vi ‏22 KB

aaronb wrote:
I am trying to figure out the format of a regular expression in order to pull select lines out of a multi-line string and populate those lines as individual elements of a string array while using Match Regular Expression. The overall length of the multi-line string can vary as well as the text contained within the string. The string can contain letters, numbers, and special characters. I have attached an example VI. Within the example VI I only want to return the lines beginning with "Device #" into the array. The number of lines beginning with "Device #" can vary but I want to capture them all.
Or is there a better function to use instead of Match Regular Expression that will give me the desired outcome?
Match Regular Expression works well for this.
Ben64

Replace string with regular expression

I am new to the regular expression. I am just trying to remove double quotes from a string.
My sample string is sql statement(SELECT "SCHEMA"."TABLE1"."COLUMN1", "SCHEMA"."TABLE1"."COLUMN2" FROM "SCHEMA"."TABLE1", "SCHEMA"."TABLE2" WHERE "SCHEMA"."TABLE1"."COLUMN1" = "SCHEMA"."TABLE2"."COLUMN1" );
This is what I came up with.
String s = query.replaceAll("\\.\"", ".").replaceAll("\"\\.", ".").replaceAll("\\s\"", " ").replaceAll("\\s\"", " ").replaceAll("\",", ",").replaceAll("\"\\s", " ");
But I want to optimize this line.
Could anybody tell me how to call replaceAll once with using regular expression instead of calling replaceAll multiple times? Some table or column names can have double quotes, so I want to remove the double quotes without replacing the double quotes which is part of the table or column name.
I'd appreciated it.

caesarkim1 wrote:
I am new to the regular expression. I am just trying to remove double quotes from a string.
My sample string is sql statement(SELECT "SCHEMA"."TABLE1"."COLUMN1", "SCHEMA"."TABLE1"."COLUMN2" FROM "SCHEMA"."TABLE1", "SCHEMA"."TABLE2" WHERE "SCHEMA"."TABLE1"."COLUMN1" = "SCHEMA"."TABLE2"."COLUMN1" );
This is what I came up with.
String s = query.replaceAll("\\.\"", ".").replaceAll("\"\\.", ".").replaceAll("\\s\"", " ").replaceAll("\\s\"", " ").replaceAll("\",", ",").replaceAll("\"\\s", " ");
...Note that the following two lines are equivalent:
s = s.replaceAll("a","").replaceAll("b","");
s = s.replaceAll("a|b","");

Replace a string using regular expression from powershell

I want to replace the following:
'browserName': 'firefox'
with :
'browserName': 'chrome'
then I tried this:
(get-content $conffile) -replace "^('browserName': ')\S+","browserName': 'chrome' |set-content $conffile
But nothing happened.
Could someboby tell me how to write the regular expression here? Thanks a lot.

Second person today with the same question.
get-content $conffile |%{$_ -replace "'browserName':\s+'firefox'","'browserName': 'chrome'" | set-content $conffile
\_(ツ)_/

How to Capture Multiple Line String using Regular Expression?

Hi,
I have a simple program like this:
What I want to accomplish is to capture everything between >>start and >>end using a single Match Regular Expression node. It seems that setting multiple? to True or False does not help.
I am using LabVIEW 2012.
If it is impossible to capture it using a single node, that is fine. But I want to make sure that I can make full use of this node without combining serveral others.
Thank you!
TailOfGon
Certified LabVIEW Architect 2013
Solved!
Go to Solution.

Thank you for the fast response! Your solution worked in the example case
After I saw your post, I was finally able to step forward. But I still wanted to make use of dot notation due to the limitation of characters that match with \w.
I made some more modification to your regular expression then now it seems working for all characters:
>>start((?:\s|.)*)>>end
Thanks!
TailOfGon
Certified LabVIEW Architect 2013

Getting non numeric strings using regular expression

Hi Guys ,
I want to get list of string values in table which contains no numeric values .....
I have a string column name A and table name B .
I have written following code , but it seems it is incorrect .
Plz help me out .....
SELECT
A FROM
B
WHERE
regexp_like(A, '([^[:digit:]])'
Thanks in advance ....

96097f0e-f165-463a-a0a2-3d15214c8a3d wrote:
Hi Guys ,
I want to get list of string values in table which contains no numeric values .....
I have a string column name A and table name B .
I have written following code , but it seems it is incorrect .
Plz help me out .....
SELECT
A FROM
B
WHERE
regexp_like(A, '([^[:digit:]])'
Thanks in advance ....
That will give you every one that has at least one non-numeric character, if you want ones which contain no numeric characters then it should be
regexp_like(A,'^[^0-9]*$')

Not understanding the String matches (regular Expression)

Everytime I search I do not find any examples of java String's matches function.
I am reading an input file and just want to print if it matches the pattern
/thisdirectory/source_code/*.cc
I even tried to test by doing
if( line.matches("[a-z]") ){
System.out.println("IT MATCHES");
Which should just test if there is any letter a to z, which there is in the file but it never comes back as true that it fines a to z in the line.

I totally understand what you are going through, maybe someone could shed some light on my problem as well.
In my code the getText() method is pulling the text from a form being filled out. I am checking for validation of fields: But the problem is that my code wont compile with matches method inside these lines of code.:
else if ( !firstTextField.getText().matches( "[A-Z][a-zA-Z]*" ) )
          JOptionPane.showMessageDialog(this, "Invalid First Name");
          else if(!lastTextField.getText().matches("[A-Z][a-zA-Z]*" ) )
                    JOptionPane.showMessageDialog(this, "Invalid Last Name");
          else if(!addressTextField.getText().matches("\\d+\\s+([a-zA-Z]+\\s[a-zA-Z]+") )
                    JOptionPane.showMessageDialog(this, "Invalid Address");
          else if(!cityTextField.getText().matches("[a-zA-Z]+|[a-zA-Z]+\\s[a-zA-Z]+") )
                    JOptionPane.showMessageDialog(this, "Invalid City");
          else if(!stateTextField.getText().matches("[a-zA-Z]+|[a-zA-Z]+\\s[a-zA-Z]+") )
                    JOptionPane.showMessageDialog(this, "Invalid State");
          else if(!zipTextField.getText().matches("\\d{5}") )
                    JOptionPane.showMessageDialog(this, "Invalid ZipCode");
          else if(!phoneTextField.getText().matches("[1-9\\d{2}-[1-9]\\d{2}-\\d{4}") )
                    JOptionPane.showMessageDialog(this, "Invalid Phone number. Please enter phone number in format 1-111-111-1111");
The error I am receiving is:
The method matches(String) is undefined for the type String.
What gives?

Filter Strings using regular expressions

Requirements.
1.I have a table with different names.
2.I input a word(string) through a text box.
3.I filter table using the input string through text box using the code
((DefaultRowSorter)table_customer.getRowSorter()).setRowFilter(RowFilter.regexFilter(regex, indices));
4.regex is obtained as follows.
String regex = "";
String text = txtFilterText.getText();
regex = "^(?i)"text".*"; //for starts with filter
regex = "." + text + ".";//for contains filter
regex = "(?i)["text".*]";//for doesnt start with filter
regex =".*(?i)"text"$";//for end with filter
I need help for doesnt contain and doesnt end with filters.Plz help me out..
Anees

h2. {color:ff0000}Double post{color}
Reply here: http://forum.java.sun.com/thread.jspa?threadID=5231406

String.split() regular expression

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