How to split a string with regular expression

Hi.
I need to split a string with a regular expression.
Example
String = "this is; a test";rune haavik;12345;
And I want the output to be:
"this is; a test"
rune haavik
12345
If I use this code:
private void test1()
String str = "\"this is; a test\";rune haavik;12345;";
int i=0;
String[] tmp = str.split(";");
while(i<tmp.length)
System.out.println(tmp);
i++;
Then it splits also in the "" text.
Regards
Rune haavik

Rune haavik:
The most effective way to achieve the end result is, I believe, to read the characters one by one, using a flag that indicates if we are inside quotation or not.
Well, if we are in a mind game, then the following should do.
String[] tmp = str.split(";(?![^\"]*\";)");

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This forum is for VB.NET, please check the following resources
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http://social.msdn.microsoft.com/Forums/vstudio/en-US/6a0719fe-14af-47f7-9f51-a8ea2b9c8d6b/where-to-post-your-vb-6-questions?forum=vbgeneral
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How to split a string around "." expression

My code is:
public String removeExtn(String resource){
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Hi mansi,
I had a same kind of problem a few days back.
What I learned was the split() method has a string expression in it, which is usually noted as regex .
'Regex' is just a short form for 'regular expression'
You may directly use the string variable you would split around in some cases or may want to use a '\\' before some of the characters.
I can't place whole information here .So, let me give you that sun site link I read it from.
This link deals with the whole string class.
You may want to ctrl+F and split to read on split method.
http://java.sun.com/j2se/1.4.2/docs/api/java/lang/String.htmlThis link talks about the regular expressions
http://java.sun.com/j2se/1.4.2/docs/api/java/util/regex/Pattern.html#sumI got his for you from that link :
\p{Punct} Punctuation: For One of !"#$%&'()*+,-./:;<=>?@[\]^_`{|}~ This is for your knowledge.
And if you want a quick fix just for your code...
that'ld be using a
split(\p{.}) in place where u used a split(.)I have not tried that ...but u may want to!
Hope that helps.
Message was edited by:
Kishorei20
Message was edited by:
Kishorei20

Replace string with regular expression

I am new to the regular expression. I am just trying to remove double quotes from a string.
My sample string is sql statement(SELECT "SCHEMA"."TABLE1"."COLUMN1", "SCHEMA"."TABLE1"."COLUMN2" FROM "SCHEMA"."TABLE1", "SCHEMA"."TABLE2" WHERE "SCHEMA"."TABLE1"."COLUMN1" = "SCHEMA"."TABLE2"."COLUMN1" );
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String s = query.replaceAll("\\.\"", ".").replaceAll("\"\\.", ".").replaceAll("\\s\"", " ").replaceAll("\\s\"", " ").replaceAll("\",", ",").replaceAll("\"\\s", " ");
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Could anybody tell me how to call replaceAll once with using regular expression instead of calling replaceAll multiple times? Some table or column names can have double quotes, so I want to remove the double quotes without replacing the double quotes which is part of the table or column name.
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caesarkim1 wrote:
I am new to the regular expression. I am just trying to remove double quotes from a string.
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This is what I came up with.
String s = query.replaceAll("\\.\"", ".").replaceAll("\"\\.", ".").replaceAll("\\s\"", " ").replaceAll("\\s\"", " ").replaceAll("\",", ",").replaceAll("\"\\s", " ");
...Note that the following two lines are equivalent:
s = s.replaceAll("a","").replaceAll("b","");
s = s.replaceAll("a|b","");

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Hi ABAP Guru's,
Can you please help me out? How can I split a string into two which has a space in between?
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With best regards,
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Hi
Try like this
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Hello everyone
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abc
def
ghi jkl mno
pqr
stu
what my regular expression should be

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Hi Friends
I am Using Following Code to Split one String.
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wdComponentApi.getMessageManager.reportSuccess(str[0]);
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when i am using following code its working fine.
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wdComponentApi.getMessageManager.reportSuccess(str[1]);
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Jeetendra

"." is a special character.
Use
str.split("\\.");
Regards
Benjamin
Edited by: Benjamin Hansen on Dec 29, 2009 7:52 AM

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</ul>
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OK out and use "Return results containing" to pick a "Match ..." requirement or Boolean.
To become familiar with query syntax, for Acrobat, it is good to review Acrobat Help.
http://help.adobe.com/en_US/Acrobat/9.0/Professional/WS58a04a822e3e50102bd615109794195ff-7 c4b.w.html
Be well...

Extract values with Regular Expression

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user11118871 wrote:
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Hi BluShadow, can you explain what this is doing!?
ThanksSure.
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                     /------------\   /\       (the first thing backreferenced in the search string)
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How to split this string(char1)char2(char3)char4 into (char1)char2 , .. etc

how to split this string (char1)char2(char3)char4 into (char1)char2 , (char3)char4?
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(any charactors except round brace)any charactors except round brace(any charactors except round brace)any charactors except round brace
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iamjhkang wrote:
especially on
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Grouping & Back-references with regular expressions on Replace Text window

I really appreciate the inclusion of the Regular Expressions in the search & replace feature. One thing I am missing is back-references in the replacement expression. For instance, in the unix tools vi or sed, I might do something like this:
s/$firstPart$ $secondPart$ $oldThirdPart$/\2 \1 newThirdPart/g
which would allow me to switch the places of firstPart and secondPart, and totally replace thirdPart. If grouping and back-references are already present in the Replace Text window, how does one correctly invoke them?

duplicate of Grouping & Back-references with regular expressions on Replace Text window

How to split the string by datetime in sql

Hi,
How to split the string by datetime in sql, I've a table with comments column stores comments by datetime, while selecting I want to split and show as in rows by each jobref.
can anyone help me in this please.
Thanks,

declare @callcentre table (comments varchar(max),lbiref varchar(200))
insert into @callcentre
select '(28/10/2014 14:56:14) xyz ..... call logged (28/10/2014 14:56:58) xyz ..... call updated (28/10/2014 14:57:41)xyz ..... call updated','Vi2910201'
insert into @callcentre
select '(29/10/2014 14:56:14) xyz ..... call logged (29/10/2014 14:56:58) xyz ..... call updated (29/10/2014 14:57:41)xyz ..... call updated','Vi2910202'
insert into @callcentre
select '(30/10/2014 14:56:14) xyz ..... call logged (30/10/2014 14:56:58) xyz ..... call updated
output:
1) 28/10/2014 14:56:14, (28/10/2014 14:56:14) xyz ..... call logged ,'Vi2910201'
2) 28/10/2014 14:56:58 ,(28/10/2014 14:56:58) xyz ..... call updated ,'Vi2910201'
3) 28/10/2014 14:57:41, (28/10/2014 14:57:41)xyz ..... call updated,'Vi2910201'
4) 28/10/2014 14:56:14, (28/10/2014 14:56:14) xyz ..... call logged ,'Vi2910202'
5) 28/10/2014 14:56:58 ,(28/10/2014 14:56:58) xyz ..... call updated ,'Vi2910202'
6) 28/10/2014 14:57:41, (28/10/2014 14:57:41)xyz ..... call updated,'Vi2910202'
7) 28/10/2014 14:56:14, (28/10/2014 14:56:14) xyz ..... call logged ,'Vi2910203'
8) 28/10/2014 14:56:58 ,(28/10/2014 14:56:58) xyz ..... call updated ,'Vi2910203'
Thanks,
See this illustration
declare @callcentre table (comments varchar(max),lbiref varchar(200))
insert into @callcentre
select '(28/10/2014 14:56:14) xyz ..... call logged (28/10/2014 14:56:58) xyz ..... call updated (28/10/2014 14:57:41)xyz ..... call updated','Vi2910201'
insert into @callcentre
select '(29/10/2014 14:56:14) xyz ..... call logged (29/10/2014 14:56:58) xyz ..... call updated (29/10/2014 14:57:41)xyz ..... call updated','Vi2910202'
insert into @callcentre
select '(30/10/2014 14:56:14) xyz ..... call logged (30/10/2014 14:56:58) xyz ..... call updated','Vi2910203'
SELECT LEFT(p.u.value('.[1]','varchar(max)'),CHARINDEX(')',p.u.value('.[1]','varchar(max)'))-1) AS [Date],
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lbiref
FROM
SELECT lbiref,CAST('<Root>' + STUFF(REPLACE(comments,'(','</Data><Data>'),1,7,'') + '</Data></Root>' AS XML) AS x
FROM @callcentre c
)t
CROSS APPLY x.nodes('/Root/Data')p(u)
and the output
Date comments lbiref
28/10/2014 14:56:14 (28/10/2014 14:56:14) xyz ..... call logged Vi2910201
28/10/2014 14:56:58 (28/10/2014 14:56:58) xyz ..... call updated Vi2910201
28/10/2014 14:57:41 (28/10/2014 14:57:41)xyz ..... call updated Vi2910201
29/10/2014 14:56:14 (29/10/2014 14:56:14) xyz ..... call logged Vi2910202
29/10/2014 14:56:58 (29/10/2014 14:56:58) xyz ..... call updated Vi2910202
29/10/2014 14:57:41 (29/10/2014 14:57:41)xyz ..... call updated Vi2910202
30/10/2014 14:56:14 (30/10/2014 14:56:14) xyz ..... call logged Vi2910203
30/10/2014 14:56:58 (30/10/2014 14:56:58) xyz ..... call updated Vi2910203
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Dumbfounded by Scanner processing String using regular expression

I was reading Bruce Eckel's book when I came across something interesting: extending Scanner with regular expressions. Unfortunately, I was confronted with an issue that doesn't make much sense to me: if the String that I am scanning contains a hyphen, the Scanner doesn't produce anything. As soon as I take it out, it all works like a charm. Here is my example:
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Thanks for your prompt reply.
I have figured out what was wrong with my code, by the way. Since a single quote is not a word character, it does not match w+. And as the very first input token does not match, the scanner stops immediately. I rewrote my regex to "[a-z].*" and now it does work.

How to split a string with regular expression

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