String tokenizing problem
This suddenly started happening last night and for the life of me, i do not know why.
when i start my applet, everything goes ok until my string tokenizer is called. Then the applet crashes and i get the following in the java console:
java.util.NoSuchElementException
at java.util.StringTokenizer.nextToken(Unknown Source)
at Player.authenticateUser(Player.java:98)
at BlackJack.connect(BlackJack.java:575)
at BlackJack.init(BlackJack.java:182)
at sun.applet.AppletPanel.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)
Now, while i understand what the error means, i don't know why it is happening. The string to be tokenized is in the form: "name: x x id: x". Here's the code that handles it:
while(st.hasMoreTokens())
while(!st.equals("id:"))
if(!st.equals("name:"))
name += st.nextToken();
if(st.equals("id:"))
memID = st.nextToken();
//Test string
System.out.println("input:" + input+"\n");This is so annoying now as i just can't see the problem. Any ideas?
Write down what you think the path through the code should be--how many times through the while, what happens each time, whether the if block is entered, what happens.
Then put in a bunch of print statements so you can see the path your code is following (or use a debugger). When you see what's different between what was expected and what's actually happening, you'll be able to find your logic bug.
Clearly something's wrong with the if and/or the while s.t. it's eating all the tokens and then still asking for more.
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Solved!
Go to Solution.Here. Try this one. It does the same thing and uses exposed functions.
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Attachments:
Parse Message.png 10 KB -
Guys I need some help. String token of a wired message
well this is my code.
code:
import java.*;import java.util.StringTokenizer;import java.io.*; class stringtoken { public static void main(String[] args) { Runnable daemonRunner = new Runnable() { public void run() { while (true) { String red, green, blue, yellow, brown, v6, v7; int ali=42; String origtext = "accaa*b*dzddsf*,.sfsdf,a.a/.d,asd.,fa.a/.,/.**asdasdaadf"; StringTokenizer st = new StringTokenizer(origtext,"*"); try { red = (String)("a" + st.nextToken()); green = (String)(st.nextToken()); blue = (String)(st.nextToken()); yellow = (String)(st.nextToken()); brown = (String)(st.nextToken()); System.out.println("Red : " + red); System.out.println("Green : "+ green); System.out.println("Red : " + blue); System.out.println("Green : "+ yellow); System.out.println("Blue : " + brown); /////////////////////////////////[shaded section]/////////////////// String red1,red2;int ie=41; String aChar1 = new Character((char)ie).toString(); System.out.println("From above : Red" + red + " *** Will token -> " + aChar1); StringTokenizer st1 = new StringTokenizer(red, ")"); try { red1 = (String)("After splitting 1 :" + st.nextToken()); red2 = (String)("After splitting 2 :" + st.nextToken()); System.out.println("Output : " + red1 + "&" + red2 ); } catch (Exception ignored) { // (ERROR STATE) could not parse it } ////////////////////////////////[end of shaded section]/////////////////// int a = 0x41;int i=65; String aChar = new Character((char)i).toString(); System.out.println("Ending : " + aChar); } catch (Exception ignored) { // (ERROR STATE) could not parse it } try { Thread.sleep(1500); } catch (InterruptedException ignored ) { } } } }; Thread daemonThread = new Thread(daemonRunner); daemonThread.setDaemon(false); daemonThread.start(); try { Thread.sleep(1000); } catch (InterruptedException ignored) { } } }
let me explain a lil. The program is actually a daemon. It works fine. In the body run, that's the thingy which did string token. It works fine. But
i am creating something that will split (1a) into 2 piece, and another will spilt the other piece.
The senario, the daemon will receive a string, like "*abcde,1,2,3,hello%"
where * = STX (ASCII 02) and % ETX (ASCII 03)
the first loop will eliminate the STX, then seggregate the text to a loop, for example a=abcde, b=1, c=3, d=hello%.
*what i managed to do is only string token the normal characters, not the ASCII characters
then the final loop will grab strtoken the % char.
i have been trying tht for 1 whole days.. n e ideas guys ?
thanks in advance.
you could also post the edited text to [email protected]I have solve the problem. Thanks guys!
import java.*;
import java.util.StringTokenizer;
import java.io.*;
class stringtoken1 {
public static void main(String[] args) {
Runnable daemonRunner = new Runnable() {
public void run() {
while (true) {
int STX=2, ETX=3, comma=44;
String stx = new Character((char)STX).toString();
String etx = new Character((char)ETX).toString();
String flag= null;
String ID= null;
String date= null;
String location= null;
String mobile= null;
String outtouser= null;
String message1=null;
String message2=null;
String origtext = stx+"1,001,17062005 16:16:16,Rawang, Telekom, Please stand by "+etx;
//System.out.println(origtext);
String throwstx = new Character((char)STX).toString();
StringTokenizer stxthrow1 = new StringTokenizer(origtext, throwstx);
try {
message1 = (String)(stxthrow1.nextToken());
catch (Exception ignoredthrowstx) {System.out.println(ignoredthrowstx);}
String throwetx = new Character((char)ETX).toString();
StringTokenizer etxthrow = new StringTokenizer(message1, throwetx);
try {
message2 = (String)(etxthrow.nextToken());
catch (Exception ignoredthrowstx) {System.out.println(ignoredthrowstx);}
String chomma = new Character((char)comma).toString();
StringTokenizer st = new StringTokenizer(message2,chomma);
try {
flag = (String)(st.nextToken());
ID = (String)(st.nextToken());
date = (String)(st.nextToken());
location = (String)(st.nextToken());
mobile = (String)(st.nextToken());
outtouser = (String)(st.nextToken());
catch (Exception ignoredcomma) {System.out.println(ignoredcomma);}
System.out.println("Original Message : " + origtext);
System.out.println("After STX : " + message1);
System.out.println("After ETX : " + message2);
System.out.println("Filtering");
System.out.println("flag : " + flag);
System.out.println("id : "+ ID);
System.out.println("date : " + date);
System.out.println("location : "+ location);
System.out.println("mobile : " + mobile);
System.out.println("message : " + outtouser);
try {
Thread.sleep(3000);
catch (InterruptedException ignored ) { }
Thread daemonThread = new Thread(daemonRunner); daemonThread.setDaemon(false);
daemonThread.start();
try { Thread.sleep(1000);}
catch (InterruptedException ignored){ }
}for others guys as well :) -
Hello -
I'm able to tokenize w/o any problems, save for when I run into consecutive instances of the character, a comma, that I am using for my delimiter. Here's a sample line:
The,lazy,fox,,jumped,,,over,the,,,moon,,,,,
So, if my string has values for each field that the tokenizer looks at, I have no problems, but if there are two or more commas (delimiters) in sequence, it breaks the tokenizer.
So what I'd like to do barring a better/simpler solution is to print "N/A" or something if there is no data in that token and then continue on to assign each (valid) token to a String variable.
Thanks...Like warnerja suggested/mentioned: try String's
split(...) method:
String s =
"The,lazy,fox,,jumped,,,over,the,,,moon,,,,,";
String[] tokens = s.split(",+");
for(int i = 0; i < tokens.length; i++) {
System.out.println("Token "+(i+1)+" =
"+tokens);
Except get rid of the "+" part, as that just makes it eat the empty tokens. Just use s.split(",") -
Parsing strings - baffling problem
Hello, I have an issue with parsing tokenized strings that I am hoping someone can help me out on:
I'm reading in a file which contains a line of the format n,n,n where n are integers (followed by other stuff.)
I'm using the split() function to tokenize the string into an array of three strings.
When I try to parse the strings to integers, I throw a NumberFormatException, but if I just read out the strings, they look fine.
For example, if I read out the value of tokens[0] via System.out.println(tokens[0]), I get 1000, but ("1000"==tokens[0]) returns false;
When try Integer.parseInt[tokens[0]), or:
Integer.parseInt[tokens[0].trim())
I get the exception, whereas:
String tmp = "1000";
Integer.parseInt[tmp) works fine.
It seems that the two statements are identical. I'm kinda lost.
Any pointers?
Here is the code segment:
{code}
public boolean doOpen(String fName)
File file = new File(fName);
try
String current ="";
String delimiter = ",";
BufferedReader br = new BufferedReader(new FileReader(file));
current = br.readLine();
if(current==null)
return false;
else
System.out.println(current);
String[] tokens = current.split(delimiter);
if(tokens.length!=3)
System.out.println("Incorrect file format");
return false;
int tnX = 0,tnY=0,tN=0;
try
System.out.println("Trying first token: "+tokens[0]+".");
tnX = Integer.parseInt(tokens[0].trim());
System.out.println("Trying second token: "+tokens[1]+".");
tnY = Integer.parseInt(tokens[1]);
System.out.println("Trying third token: "+tokens[2]+".");
tN = Integer.parseInt(tokens[2]);
catch(NumberFormatException e)
System.out.println("Could not parse data: ("+tnX+","+tnY+","+tN+")");
return false;
nX = tnX;
nY = tnY;
grid = new char[nX][nY];
initGrid();
// parse input data and verify correct file
while ((current = br.readLine()) != null)
tokens = current.split(delimiter);
grid[Integer.parseInt(tokens[0])][Integer.parseInt(tokens[1])]=tokens[2].toCharArray()[0];
} // end while
System.out.println("File loaded successfuly");
return true;
catch (IOException e)
e.printStackTrace();
return false;Hi everyone, I've got it figured now.
There indeed was some invisible characters hidden in the string.
When I added the code:
char[] cs = tokens[0].toCharArray();
for(int i = 0;i<cs.length;i++)
System.out.println("Character "+i+": "+Character.getNumericValue(cs));
I get as an output:
*Character 0: -1*
*Character 1: 1*
*Character 2: -1*
*Character 3: 0*
*Character 4: -1*
*Character 5: 0*
*Character 6: -1*
*Character 7: 0*
*Character 8: -1*
This comes from the way that the files are being generated: via a DataOutputStream.
The following code inserts the hidden characters, and I can get around this by using a BufferedWriter
OFFENDING CODE File file = new File(fName);
MapPoint[] points = getMapPoints();
fos = new FileOutputStream(file);
dos = new DataOutputStream(fos);
dos.writeChars(new String(""+wX+","+wY+","+points.length+"\n"));
for(int i = 0;i<points.length;i++)
dos.writeChars(""+points[i].x+","+points[i].y+","+points[i].type+"\n");
Thanks to everybody for all your help!
- Andrew -
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I tried to split it using "-" but that obviously doesnt work, because 234 will be a token, I just want to remove the - from the token.
advice please.endasil wrote:
Implode wrote:
if I want 3-34-565456-4 to be 334565456 so that I can take each digit and do calculations with them, could I just split the string 334565456 using .split(""); which will give me splitArray[0]=3, splitArray[1] = 3, splitArray[2] = 4 etc.
String someStr = "3-34-565456-4";
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for ( char c : numsOnly.toCharArray() ) {
int digit = c - '0';
}Or
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If I say:
String str = "Welcome";
str.concat(" to Java");
System.out.println(str);
The output is: Welcome.
How do I get the output to Welcome to Java??I have this strange Question regarding String concat
If I say:
String str = "Welcome";
str.concat(" to Java");
System.out.println(str);
The output is: Welcome.
How do I get the output to Welcome to Java??
The problem is that String is immutable, The String you have held in str does not change, rather a new Srtring is returned. So all yo have to do is grab the new String
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i know this question might be very simple but i just cannot see what i am doing wrong here.
String stringA, stringB, stringC;
stringA= new String();
stringB= new String();
stringC= new String();
stringA = null;
stringB = "TRUE";
stringC = "Error:";
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thanks muchcould you then please explain the following?
public String concat(String str)Concatenates the
specified string to the end of this string.
If the length of the argument string is 0, thenthis
String object is returned. Otherwise, a new String
object is created, representing a charactersequence
that is the concatenation of the charactersequence
represented by this String object and thecharacter
sequence represented by the argument string.
Examples:
"cares".concat("s") returns "caress"
"to".concat("get").concat("her") returns"together"
Parameters:
tr - the String that is concatenated to the end of
this String.
Returns:
a string that represents the concatenation of this
object's characters followed by the stringargument's
characters.
Throws:
NullPointerException - if str is null.It returns a new String, which you are
throwing away. Change your code like this:
stringA = stringA.concat(stringB);
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i think that will work but my problem is with the description of this
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while ( (dbRecord = dis.readLine()) != null) {
StringTokenizer st = new StringTokenizer(dbRecord, ":", false);
Vector row = new Vector();
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Failing that, presumably you would write something like this (I forget the exact naming standard for the password verify function).
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p_password IN VARCHAR2)
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p_characters IN VARCHAR2)
RETURN BOOLEAN
IS
BEGIN
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Hi ,
I wanted to toknize following string using token "#,"
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i.e i need
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Edit:
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Hi,
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String x = node.getText();
The node.getText() should contain value = "\n\r"
However, it always return me "\r" only.
I checked with the debugger and found that when I change the offset value of x to 0, it can return me "\n". However, the original offset value is always kept as 1. That's the reason why it always return me "\r".
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