Successive dates with last day of that month being added to succesive date

Hi ,
I have a piece of code that displays the succuessive dates from the given date to tilll date with a date interval of 30 days. My requirement goes some thing like this. since the given date is '26-nov-08' the next successive date should be the number of days in nov(30) added to '26-nov-08'. that will be around 26-dec-08. For this date it has to add the number of days in December(31) to '26-dec-08' and that turns out to be '26-jan-09'. and this must go on till date.
In the below code i have used 30 for the interval of 30 days but the interval has to the last day of the successive date's month( for dec the interval has to 31 and for january the interval has to be 31 and for february 28)
select to_date('26-nov-08', 'dd-mon-yy') + (level - 1) * 30
from dual
connect by level <= trunc((sysdate-to_date('26-nov-08', 'dd-mon-yy'))/30 )Please advice

hi ,
the query sent by you is correct and could it be in corporated for this query :
SELECT TRUNC(inst_due_date) + (LEVEL-1 ) * (ilpa_term_type),iloan_code,LOAN_AMT,FEE_AMT,
LOAN_DATE,LOAN_STATUS_ID
FROM (
SELECT inst_due_date,sm.iloan_code,LOAN_AMT,
FEE_AMT,
LOAN_DATE,
LOAN_STATUS_ID,
decode(sm.ilp_term_type, 26 ,14,24,15,12,(select to_number(to_char(last_day(inst_due_date),'dd')) from dual)) as ilpa_term_type
FROM ST_IL_SCHEDULE sc,ST_IL_MASTER sm
WHERE sc.iloan_code = sm.iloan_code
AND sc.inst_num = (SELECT MAX(inst_num) FROM ST_IL_SCHEDULE b WHERE b.iloan_code = sc.iloan_code)
AND sc.iloan_code =123456789)
CONNECT BY LEVEL <= TRUNC((TRUNC(SYSDATE)-TRUNC(inst_due_date))/(ilpa_term_type) )
Here we are using the decode concept if ilp_term_type = 26 then 14 but we need to implement the code of adding the number of days to that month in place of this code :
select to_number(to_char(last_day(inst_due_date),'dd')) from dual:
Please advice

Similar Messages

Show data of last day of previous month against any day of current month

Hi,
I have fact table which contains data at date level (we have data for oct-2009 to april-2010). Our requirement is to show data of last day of previous month against any day of current month in obiee 11g. I am facing problem in Feb 2010 its picking data of 28-Jan-2010 instead of 31-jan-2010 and for April its picking data of 30-mar-2010 instead of 31-mar -2010.
Any suggestion ???

You're asking to filter your data set to only include rows between:
1) last day of the previous month
2) any day of the current month
This can be achieved with prompting in OBIEE Answers.
last day of previous month = TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE)) . The problem is you need to make query work within Oracle's Answer syntax.
In the prompt, select the operator type for your date dimension as 'between' and default to 'SQL Results'.
For the 'last day of previous month' , use the query:
SELECT
case when 1=0 then Time."Fiscal Date" else TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))
end
FROM ENTER_YOUR_PRESENTATION_FACT_FOLDER_HERE
For the current date, use the query:
SELECT
case when 1=0 then Time."Fiscal Date" else CURRENT_DATE
end
FROM ENTER_YOUR_PRESENTATION_FACT_FOLDER_HERE
Another option is to create a last_date_pervious_month variable in the RPD and have that as the default value in your prompt.

Last day of previous month for data load

Hi,
I have to load data from the previous month into the psa and then into an infocube. I was wondering as to how to get the last of the previous month to write a code in ABAP. I will be writing the code at the infopackage level in the data selection. I could load data from the 1st of the previous month to the 1st of the current month. This will be an additional load of 30,000 records for the 1st of every month, since I will be loading 30,000 records everyday, I was wondering if I could limit the load from the 1st of every previous month to the last day of that month. This will be a repetitive loading.
DATA: CURR_MM(2) TYPE N,
CURR_YYYY(4) TYPE N,
CURR_DD(2) TYPE N,
PREV_MM(2) TYPE N,
PREV_YYYY(4) TYPE N,
PREV_DD(2) TYPE N,
YYYY_MM(6),
YYYY_MM1(6),
DATE LIKE SY-DATUM.
DATE = SY-DATUM.
CURR_YYYY = DATE+0(4).
CURR_MM = DATE+4(2).
CURR_DD = DATE+6(2).
PREV_DD = 1.
IF CURR_MM = '01'.
PREV_MM = '12'.
PREV_YYYY = CURR_YYYY - 1.
ELSE.
PREV_MM = CURR_MM - 1.
PREV_YYYY = CURR_YYYY.
ENDIF.
concatenate PREV_YYYY PREV_MM PREV_DD into YYYY_MM.
concatenate CURR_YYYY PREV_MM PREV_DD into YYYY_MM1.
read table l_t_range with key
fieldname = 'BLDAT'.
l_idx = sy-tabix.
l_t_range-low = YYYY_MM.
l_t_range-high = YYYY_MM1.
l_t_range-sign = 'I'.
l_t_range-option = 'BT'.
modify l_t_range index l_idx.
p_subrc = 0.
Mind you this code will load data from 1st of the previous month to the 1st of current month. I just don't want to load that extra "1st day" of current month data as I have 30,000 records everyday.
Say for example, I want to load data from 1st Mar to 31st Mar or 1st Feb to 28thFeb. How should I modify the above code.
Is there a formula to get the last date of the previous month. That's all I need. This would solve the problem.

try this routine. it will return a range from 1st day to end of the month.
DATA: l_s_range TYPE rsr_s_rangesid,
 E_T_RANGE TYPE RSR_T_RANGESID.
DATA: year(4) TYPE n,
 month(2) TYPE n,
 day(2) TYPE n,
 ld_keydate TYPE sydatum,
 ld_lastday TYPE sydatum.
REFRESH e_t_range.
CLEAR l_s_range.
year = sy-datum(4).
month = sy-datum+4(2).
*Months with 31 days in year
IF month = '01' OR
 month = '03' OR
 month = '05' OR
 month = '07' OR
 month = '08' OR
 month = '10' OR
 month ='12'.
 day = '31'.
ENDIF.
*check for leap year: provoking sy-sybrc <> 0
IF month = '02'.
 day = '29'.
 MOVE: '02' TO ld_keydate+4(2),
 year TO ld_keydate(4),
 day TO ld_keydate+6(2).
 CALL FUNCTION 'DATE_CHECK_PLAUSIBILITY'
 EXPORTING
 date = ld_keydate
 EXCEPTIONS
 OTHERS = 1.
 IF sy-subrc <> 0.
 day = '28'.
 ENDIF.
ENDIF.
*months with 31 days in year
IF month = '04' OR
 month = '06' OR
 month = '09' OR
 month = '11'.
 day = '30'.
ENDIF.
MOVE: year TO ld_lastday(4),
 month TO ld_lastday+4(2),
 day TO ld_lastday+6(2).
l_s_range-low = sy-datum.
l_s_range-high = ld_lastday.
l_s_range-sign = 'I'.
l_s_range-opt = 'BT'.
APPEND l_s_range TO e_t_range.

Getting last days of several months - Bex Analyzer

Hello, BW experts~
I need to calculate with last days of several months.
For example,
- The sales in July: $100
 -> sales per day in July = $100 / 31
- The sales in last month(June): $100
 -> sales per day in last month(June) = $100 / 30
- The sales in 2 month ago(May): $100
 -> sales per day in 2 month ago = $100 / 31
I used to calculate a last day on a month with a customer exit variable. It works well when executing the BEx query with one month. But, when executing the query with 3 months, it doesn't work well.
For example, when executing the query in July, all last days, which are calculated via customer exit variable, become 31. Only one month.
- Last day -
July: 31
Last month(June): 31
2 month ago(May): 31
They have to be each 31(July), 30(June), 31(May).
I want to get fit last days of several months at a time and one BEx query.
Is it possible? (I wish it's possible.)
Can I do something in CMOD?
Thank you~
Sihyoung Jurn

Hi,
You can get it by creating 3 formula variables with 'customer ext' as processing.
Let us assume user enters the First month by a 'user entry' variable.
In the code of user exit for 1st formula variable you will calculate the last day of the user entered month.
In the code of user exit for 2nd formula variable you will calculate the last day of the (prevoius month to user entered month).
Similarly for 3rd Formula Variable also.
there will be 3 Restricted key figures.
one for sales of user entered month.
2nd one for sales of prevoius month to user entered month.
3nd one for sales of two month to user entered month.
you will have 3 calculated kfs.
in first one you do 1st RKF/Formula variable1.
in second one you do 2nd RKF/Formula variable2.
in third one you do 3rd RKF/Formula variable3.
Hope, you understood my explanation.
With rgds,
Anil Kuamr Sharma .P

BIP eBusiness Suite Dates - How to include the last day of the month?

How can I get my report to include the last day of the month 'without' forcing my users to enter the non-intuitive first of the next month as a parm?
I have a report that will generally be run for a month but can be run for any pair of dates representing the first and last date to be included in the report.
When we pass the dates from Oracle Apps to the report it is truncating the date to midnight. This results in the last date entered 'NOT' being included in the report as the second date is marked as "midnight". When I attempt to simply add "=1" to the end date it fails due to formatting issues in apps (only). I have gotten this to work on our Enterprise edition server that we use for testing (only) but it fails in our apps environment.
In APPs we input the date in the format "01-AUG-2007", and this is how it shows in the parm line before the report is submitted as well as in the "View Details" after the report is executed: http://home.swbell.net/grog1//work/req_details_5607586.jpg
However it is odd in that we in the "View Log" entry it shows the date formatted as "2007/08/01 00:00:00": http://home.swbell.net/grog1/work/view_log_5607586.jpg
Even odder is that under diagnostics, "View XML" the date is formatted third way as: "2007/08/01 00:00:00.0" (note it now includes tenths of a second): http://home.swbell.net/grog1/work/view_xml_5607586.jpg
This of course makes it difficult to perform conversions and calculations on the date in the SQL.
Is APPs doing some sort of 'timestamp' conversion?
How can I get my report to include the last day of the month 'without' forcing my users to enter the non-intuitive first of the next month as a parm?
Any feedback is appreciated,
Scott

No. The problem/error occurs long before the data is formatted into xml for presentation to the format template.
The error occurs in the SQL in the 'data' template when I attempt to add a day to the date. It either does not like the implicit conversion with the "+1" and then the use of the "between" with another date or if I attempt to manually convert it has problems with the format mask.
Scott

Date Functions( first day of a month that is 3 months from now....)

I have recently written my first stored procedure.
Its rather a bunch of SQL statements.
I had to hard code lot of dates. most of them are first day of the current monthe or last day of current month etc.
I thot of parametrizing all the dates, but if a business person has to include all the parameters they could go wrong and get the wrong results.
Now, I want to use date functions to achieve these requirements:
Can any one please throw some insght into this:....
1) First day of current month,
2) last day of current month.
3) first day of previious month
4) last day of previous month
5) first day of a month that is 3 months from now.
6) last day of a month that is 3 months from now.
7).....
Can any one please throw some light on any one of this.. I can try to work from there onwards ....
Thanks a lot in advance,
Ac

Hi there,
1) First day of current month
select trunc(sysdate, 'MM') from dual;
2) last day of current month.
select trunc(add_months(sysdate, 1), 'MM') - 1 from dual;
3) first day of previious month
select trunc(add_months(sysdate, -1), 'MM') from dual;
4) last day of previous month
select trunc(sysdate, 'MM') - 1 from dual;
5) first day of a month that is 3 months from now.
select trunc(add_months(sysdate, 3), 'MM') from dual;
6) last day of a month that is 3 months from now.
select trunc(add_months(sysdate, 4), 'MM') - 1 from dual;cheers,
Anthony

Object date - how to get the last day of the month?

hi all,
I have a date object in which I would like to get the last day of the month. any idea?
eg AUG=31
Feb = 28 (depends if a leap year)
thanks

Use java.util.Calendar
Add 1 month to the day.
Set the day of month to be 1.
Subtract 1 day.
Now you are on the last day of the month you wanted.

Defining last day of previous month in ABAP

All,
I am a BW guy and hardly know ABAP. I have a requirement where I have to calculate last day of previous month and use it in the routines of the transformations.
I have decided to define the Last day of previous month in Start routine and then use the global variable in Transformations to calculate further.
The logic that i have used is outlined below.
         Define G_DATE in global declaration for further use in Transformations.
In the Routine section,
        Assign G_DATE to SY-DATUM
        G_DATE + 6(2) = '01' (Replace last to field of date with '01' to establish first day of the current month)
        G_DATE = G_DATAE - 1 (To get to last day of previous month)
My dilemma is to implement this in ABAP in Start routine of transformations. Please include the exact ABAP code that would be needed in Declarations and Routine section.
Thanks in advance.

Hi..,
Go with the function module: LAST_DAY_OF_MONTHS
So, Just determine the last month from the sy-datum and then use above function module and pick the last date of the month.
Thanks,
Naveen Inuganti.

UDF for last day of week/month

Input is a Date(For example: 2010/03/12) in String format.
I need to extract the last day of that week and return it as a string output.
For example if input is 2010/03/12 and thatu2019s a Thursday my output should be 2010/03/14 i.e Saturdayu2019s date.
Similarly I need to extract last day of month too.
Thanks in advance
Soumen...

Hi,
I did not develop this one... but just use "search" button on roseindia and you will have the answer (I think):
[http://www.roseindia.net/java/beginners/DayOfYearToDayOfWeek.shtml|http://www.roseindia.net/java/beginners/DayOfYearToDayOfWeek.shtml]
and do not forget that Google is your friend...
do a research with : Java last day of week, and you have plenty of examples.
Thanks.
P.S: Say us when you will solved your problem.

If Current Month then use last day, else use month

My cube is setup where the current month is at a daily level and the previous months just contain the last day of data.
I would like to for the last month to only return the last day and return the month level for all previous months. The reason being is our third party software gives us the capability of doing a drillthrough, but when doing it for the latest month, it is
returning every day in that month.
Here is my attempt, but it is only returning the last month, not the rest of the months.
select [Measures].[Current Balance]
on 0, non empty
[Date].[Month].children
on 1
from [MyCube]
where
IIF([Date].[Month].CurrentMember = ClosingPeriod([Date].[Month].[Month]),
TAIL (NonEmpty([Date].[Date].members,[Measures].[Count Of Accounts]),1),
[Date].[Month].CurrentMember)

Hi Dodge,
I’m writing to follow up with you on this post. Was the problem resolved by the above query?
If the issue was solved, I’d like to mark this issue as "Answered". Please also feel free to unmark the issue, with any new findings or concerns you may have.
Thanks,
Charlie Liao
TechNet Community Support

SQL select Statement -first day and last day of the month - 1 year from now

Hi,
I need to write a SQL to get the dates in between first day and last day of the month one year from now.
SELECT last_day(add_months(sysdate,12)) as lastday from dual
What could be the Query to get the first day of the month one year from now..
ie ..Sysdate - 3-DEC-2009
Result - 1-DEC-2010
thank you

Hi,
You can use TRUNC with 2 arguments to get the first DATE in a month, year, quarter, week, hour, minute, ISO year, ...
SELECT TRUNC ( ADD_MONTHS ( SYSDATE
 , 12
 , 'MONTH'
 ) AS first_of_month
FROM dual
;The DATE returned will be in the same month, year, quearter, ... as the first argument.
\We convered the last day of the month in [your previous question|http://forums.oracle.com/forums/message.jspa?messageID=3942939#3942939].
At that time, I warded about using LAST_DAY as a cutoff point; TRUNC is a much better way.
For example, to find all appointment_dates in the current month next year:
SELECT *
FROM appointments
WHERE appointment_date >= TRUNC (ADD_MONTHS (SYSDATE, 12), 'MONTH')
AND appointment_date < TRUNC (ADD_MONTHS (SYSDATE, 13), 'MONTH')Note that
the first part of the WHERE clause calls for dates on or equal to the beginning of the 12th month in the future, but
the second part of the WHERE clause calls for dates before, not equal to , the beginning of the 13th month in the future.

The last day of the month when the report is run

Hi,
I am working on custom outbound idocs for FICO module through INTERFACE Program the third party sytem needs "The last day of the month when the report is run" so is there any sytem field or standard SAP Sytem Table field which can give me that value.plz let me know ASAP.
Other wise should i develop custom logic.

Hi,
Try this way.
Selection-screen
PARAMETERS: p_bldat LIKE bsis-bldat .
INITIALIZATION.
DATA: v_end_date LIKE sy-datum.
CALL FUNCTION 'LAST_DAY_OF_MONTHS'
 EXPORTING
 day_in = sy-datum
 IMPORTING
 last_day_of_month = v_end_date
 EXCEPTIONS
 day_in_no_date = 1
 OTHERS = 2.
IF sy-subrc <> 0.
 MESSAGE ID sy-msgid TYPE sy-msgty NUMBER sy-msgno
 WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
ENDIF.
p_bldat = v_end_date.
Thanks,
Anitha

Display a metric differently only on last day of the month.

Have a Daily transaction fact where unit cost of product is stored at a day/part num /business unit level.
When we drag and drop date column and unit cost in the report like below we will have
Date      cost
Sep29     $10
sep30     $12
Oct1       $12
Oct2       $14
..........ans so on
The source sustem program runs on last day of the month around 8pm for setting up cost to reflect on 1st of every month
But the nighly OBI load ( Runs at 2am every day) when incrementally updating Sep30 data picks up $12 from the erp and populates in OBI.
But actually speaking, on Sep30 the cost was $10.
There is no way of running the ERP program to run afer OBI load. Hence we need an expression in the RPD (not answers) saying
when last day of the month (any month) the standard cost must be a previous day value.All other days the same value should be returned.
Is this possible without impacting report performance ?
So, when we drag and drop date and cost value the above report should change as
Date        Cost
sep29     $10
sep30     $10
Oct1       $12
Oct2       $14
Oct30     $12.5
Oct31     $12.5
Nov1      $13.5

You can achieve the above requirement for current month alone with below steps:
The solution requires to have a union report
First part of the report will have Date and Cost fields with a report level date filter, Date NOT IN (TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_MONTH , 1, TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))))
Second part of the report will have Date and Cost fields with a report level date filter Date IN (TIMESTAMPADD( SQL_TSI_DAY , -(1), TIMESTAMPADD( SQL_TSI_MONTH , 1, TIMESTAMPADD( SQL_TSI_DAY , DAYOFMONTH( CURRENT_DATE) * -(1) + 1, CURRENT_DATE))))In the second part of the report,
Change the column formula for Date to display only Current_Date
Change the column formula for Cost field with FILTER(Cost USING Date = Current_Date-1)
Pls mark if correct/helpful.

How to get the last day of a month?

HI,
I want to know how to get the last day of a month.
In my JClient form, I tried to get it by using oracle.sql.Date method, that is:
lastday=oracle.sql.Date anydate.lastDayOfMonth();
But it does not work. The result is lastday=anydate.
Why?
Stephen

You can use the Calender class...
Calendar c = Calendar.getInstance();
and then something like...
c.add(c.MONTH, 1);
int dayOfMonth = c.get(Calender.MONTH);
c.add(c.DAY_OF_MONTH, - (dayOfMonth-1) );
other usefull functions are:
System.out.println(" YEAR : " + c.get(Calendar.YEAR));
System.out.println(" MONTH : " + c.get(Calendar.MONTH));
System.out.println(" DAY_OF_MONTH : " + c.get(Calendar.DAY_OF_MONTH));
System.out.println(" DAY_OF_WEEK : " + c.get(Calendar.DAY_OF_WEEK));
System.out.println(" DAY_OF_YEAR : " + c.get(Calendar.DAY_OF_YEAR));
System.out.println(" WEEK_OF_YEAR : " + c.get(Calendar.WEEK_OF_YEAR));
System.out.println(" WEEK_OF_MONTH : " + c.get(Calendar.WEEK_OF_MONTH));
System.out.println(" DAY_OF_WEEK_IN_MONTH : " + c.get(Calendar.DAY_OF_WEEK_IN_MONTH));
System.out.println(" HOUR : " + c.get(Calendar.HOUR));
System.out.println(" AM_PM : " + c.get(Calendar.AM_PM));
System.out.println(" HOUR_OF_DAY (24-hour): " + c.get(Calendar.HOUR_OF_DAY));
System.out.println(" MINUTE : " + c.get(Calendar.MINUTE));
System.out.println(" SECOND : " + c.get(Calendar.SECOND));
System.out.println();*/

How to get last day of a month

using pl/sql
What i need is that all members whose birthdate is in the curren month will be included as having had their birthdate regardless of the date of the month. The code i have is:
Select me607.subscriber_id
me607.mbr_dob,
** trunc(months_between (*end of current month*,me607.mbr_dob) / 12) as age
from odw.mbr607_member_expanded me607
The asterixed line is what I need to change. If I put the end of the current month (where I put 'end of current month') then all those whose birthday month is in Feb will show as having had their birthdate. So if run today, folks whose birthdate is 26-feb-2005 will show an age of 5.
When grabbing the last day of the month using visual basic I just use the first day of the subsequent month minus 1. Any assistance is appreciated..

Hi,
This does what you requested:
Select me607.subscriber_id,     -- Don't you need a comma here?
     me607.mbr_dob,
     ROUND ( MONTHS_BETWEEN ( SYSDATE
                            , me607.mbr_dob
           / 12
from    odw.mbr607_member_expanded     me607
WHERE     TO_CHAR (me607.mbr_dob, 'MONTH') =
     TO_CHAR (SYSDATE,      'MONTH')
;If this is run sometime in February, 2010, and mbr_dob is sometime in Febrary, 2005, then the result of MONTHS_BETWEEN will be between 59 and 61. When we divide by 12 convert that to years, that difference of up to one month becomes so small that it will be lost in the rounding.
If this isn't exactly what you need, tthen post a little sample data (CREATE TABLE and INSERT statements) and the results you want from that data.
Edited by: Frank Kulash on Feb 17, 2010 1:32 PM
Added explanation.

Successive dates with last day of that month being added to succesive date

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