Suggestions on DHCP using cascading switches

Is there any reason you can't create a different vlan and create a new scope for that vlan on your current dhcp server along with helper addresses on your switches? It seems you're over complicating things as of right now.

gents,we like to provide a WLAN Network for guests in our Company which is connected through a different Provider than our internal Network.I connected the incoming hardline to one router - providing WLAN #1 with DHCP.I like to route it to two floors, using the LAN environment.I have only ONE line available to get the Provider to our Switch-rack.My idea is to connectthe LAN-port of WLAN-Router #1 to the Switch rack and attach another WLAN-Routers to the other floors.My question is: what is the best way to provideDHCP ?a) Router#1 is doing DHCP and all connected secondary routers are just passing through.b) every Router is doing DHCP for himselfI once read that there could be Problems using cascading Switches/Routers. Any enlightment here?
This topic first appeared in the Spiceworks Community

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Using a Switch statement for Infix to Prefix Expressions

I am stuck on the numeric and operator portion of the switch statement...I have the problem also figured out in an if/else if statement and it works fine, but the requirements were for the following algorithm:
while not end of expression
switch next token of expression
case space:
case left parenthesis:
skip it
case numeric:
push the string onto the stack of operands
case operator:
push the operator onto the stack of operators
case right parenthesis:
pop two operands from operand stack
pop one operator from operator stack
form a string onto operand stack
push the string onto operand stack
pop the final result off the operand stack
I know that typically case/switch statement's can only be done via char and int's. As I said I am stuck and hoping to get some pointers. This is for a homework assignment but I am really hoping for a few pointers. I am using a linked stack class as that was also the requirements. Here is the code that I have:
   import java.io.*;
   import java.util.*;
   import java.lang.*;
/*--------------------------- PUBLIC CLASS INFIXTOPREFIX --------------------------------------*/
/*-------------------------- INFIX TO PREFIX EXPRESSIONS --------------------------------------*/
    public class infixToPrefix {
      private static LinkedStack operators = new LinkedStack();
      private static LinkedStack operands = new LinkedStack();
        // Class variable for keyboard input
      private static BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
         // Repeatedly reads in infix expressions and evaluates them
       public static void main(String[] args) throws IOException {
      // variables
         String expression, response = "y";
      // obtain input of infix expression from user
         while (response.charAt(0) == 'y') {
            System.out.println("Enter a parenthesized infix expression.");          // prompt the user
            System.out.println("Example: ( ( 13 + 2 ) * ( 10 + ( 8 / 3 ) ) )");
            System.out.print("Or as: ((13+2)*(10+(8/3))): ");
            expression = stdin.readLine();     // read input from the user
         // output prefix expression and ask user if they would like to continue
            System.out.println("The Prefix expression is: " + prefix(expression));     // output expression
            System.out.println("Evaluate another? y or n: ");          // check with user for anymore expressions
            response = stdin.readLine();     // read input from user
            if (response.charAt(0) == 'n') {          // is user chooses n, output the statement
               System.out.println("Thank you and have a great day!");
            }     // end if statement
         }     // end while statement
      }     // end method main
   /*------------- CONVERSION OF AN INFIX EXPRESSION TO A PREFIX EXPRESSION ------------*/
   /*--------------------------- USING A SWITCH STATEMENT ------------------------------*/
       private static String prefix(String expression) {
            // variables
         String symbol, operandA, operandB, operator, stringA, outcome;
           // initialize tokenizer
         StringTokenizer tokenizer = new StringTokenizer(expression, " +-*/() ", true);
         while (tokenizer.hasMoreTokens()) {
            symbol = tokenizer.nextToken();     // initialize symbol
            switch (expression) {
               case ' ':
                  break;     // accounting for spaces
               case '(':
                  break;     // skipping the left parenthesis
               case (Character.isDigit(symbol.charAt(0))):      // case numeric
                  operands.push(symbol);                                   // push the string onto the stack of operands
                  break;
               case (!symbol.equals(" ") && !symbol.equals("(")):     // case operator
                  operators.push(symbol);                                             // push the operator onto the stack of operators
                  break;
               case ')':
                  operandA = (String)operands.pop();     // pop off first operand
                  operandB = (String)operands.pop();     // pop off second operand
                  operator = (String)operators.pop();     // pop off operator
                  stringA = operator + " " + operandB + " " + operandA;          // form the new string
                  operands.push(stringA);
                  break;
            }     // end switch statement
         }     // end while statement
         outcome = (String)operands.pop();     // pop off the outcome
         return outcome;     // return outcome
      }     // end method prefix
   }     // end class infixToPrefixAny help would be greatly appreciated!

so, i did what flounder suggested:
         char e = expression.charAt(0);
         while (tokenizer.hasMoreTokens()) {
            symbol = tokenizer.nextToken();     // initialize symbol
            switch (e) {
               case ' ':
                  break;     // accounting for spaces
               case '(':
                  break;     // skipping the left parenthesis
               case '0':
               case '1':
               case '2':
               case '3':
               case '4':
               case '5':
               case '6':
               case '7':
               case '8':
               case '9':
                  operands.push(symbol);     // push the string onto the stack of operands
                  break;                               // case numeric
               case '+':
               case '-':
               case '*':
               case '/':
                  operators.push(symbol);     // push the operator onto the stack of operators
                  break;                               // case operator
               case ')':
                  operandA = (String)operands.pop();     // pop off first operand
                  operandB = (String)operands.pop();     // pop off second operand
                  operator = (String)operators.pop();     // pop off operator
                  stringA = operator + " " + operandB + " " + operandA;          // form the new string
                  operands.push(stringA);
                  break;
               default:
            }     // end switch statement
         }     // end while statement
         outcome = (String)operands.pop();     // pop off the outcome
         return outcome;     // return outcomeafter this, I am able to compile the code free of errors and I am able to enter the infix expression, however, the moment enter is hit it provides the following errors:
Exception in thread "main" java.lang.NullPointerException
     at LinkedStack$Node.access$100(LinkedStack.java:11)
     at LinkedStack.pop(LinkedStack.java:44)
     at infixToPrefix.prefix(infixToPrefix.java:119)
     at infixToPrefix.main(infixToPrefix.java:59)
Any ideas as to why? I am still looking through seeing if I can't figure it out, but any suggestions? Here is the linked stack code:
    public class LinkedStack {
   /*--------------- LINKED LIST NODE ---------------*/
       private class Node {
         private Object data;
         private Node previous;
      }     // end class node
   /*-------------- VARIABLES --------------*/
      private Node top;
/*-- Push Method: pushes object onto LinkedStack --*/
       public void push(Object data) {
         Node newTop = new Node();
         newTop.data = data;
         newTop.previous = top;
         top = newTop;
      }     // end function push
   /*--- Pop Method: pop obejct off of LinkedStack ---*/
       public Object pop()      {
         Object data = top.data;
         top = top.previous;
         return data;
      }     // end function pop
   } // end class linked stackEdited by: drmsndrgns on Mar 12, 2008 8:10 AM
Edited by: drmsndrgns on Mar 12, 2008 8:14 AM
Edited by: drmsndrgns on Mar 12, 2008 8:26 AM

Can not connect with dhcp - renew dhcp lease will switch directly to manuel

If have the following problem
I us apple Airport extreme to connect to internet.
I have 5 Macs, all connecting with airport . They work fine with DHCP. Since 2 weeks I have a problem that one computer – a mac book pro with 10.5.6 will not connect.
When I switch to dhcp and select renew dhcp lease it switch directly back to manuell. I have no chance to connect with dhcp.
Has anyone a suggestion?
Thanks

Wonder why Apple hasn't chimed in on this one...
Whenever you have an issue like this where it's fine, then DHCP stops working for any reason.... Reset the PRAM.
How to:
Apple Logo -> Restart.
After the screen goes black -> Hold down all 4 keys until you hear the third Bong.
"Option"+[Apple Logo OR key to the left of the space bar]"P""R"
After the third BONG or Apple Chime whatever you want to call it. The system's Parameter Ram or to the PC Crowd the CMOS has been reset. This resets your clock, brightness, volume, etc.... So things will get reset along the way but it also resets the IRQ and DMA stats on the logic board. Ala, reseting your Airport's Connection to the logic board, Controllers, etc.

HELP -menu using a switch statement

Hello to all. I'm new to the Java world, but currently taking my first Java class online. Not sure if this is the right place, but I need some help. In short I need to write a program that gives the user a menu to chose from using a switch statement. The switch statement should include a while statement so the user can make more than one selection on the menu and provide an option to exit the program.
With in the program I am to give an output of all counting numbers (6 numbers per line).
Can anyone help me with this?? If I'm not asking the right question please let me know or point me in the direction that can help me out.
Thanks in advance.
Here is what I have so far:
import java.util.*;
public class DoWhileDemo
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          int count, number;
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          number = keyboard.nextInt();
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               count++;
          }while (count <= 32);
          System.out.println();
          System.out.println("Buckle my shoe.");
}

Thanks for the reply. I will tk a look at the link that was provided. However, I have started working on the problem, but can't get the 6 numbers per line. I am trying to figure out the problem in parts. Right now I'm working on the numbers, then the menu, and so on.
Should I tk this approach or another?
Again, thanks for the reply.

On my Macbook pro 15 2011, System Profiler is suggesting that it uses SATA III for the hard drive and SATA II for the Optical Drive. Is that true?

On my Macbook pro 15, 2011, System Profiler is suggesting that it uses SATA III for the hard drive and SATA II for the Optical Drive. Is that true?

That is correct. The tech specs indicate:
Hard Drive Interface
6.0 Gbps Serial ATA (SATA)
Optical Drive Interface
3.0 or 6.0 Gbps Serial ATA (SATA)

I created a playlist with 100 songs. I want those 100 songs played using the shuffle option. This no longer works in iTunes version 11.1.5.5 How can I get an entire playlist to paly one song after another by using the switch option?

I created a playlist with 100 songs. I want those 100 songs played using the shuffle option. This no longer works in iTunes version 11.1.5.5 How can I get an entire playlist to paly one song after another by using the switch option?

You're welcome.
Going back to your original post:
5) Tried running Itunes in 'safe mode', running itunes as an administrator..nothing.
Was that iTunes' safe mode as opposed to Windows' safe mode? iTunes safe mode is invoked by holding down CTRL+SHIFT immediately after clicking the icon to launch iTunes and continuing to hold until this message pops up:
Click continue, then close iTunes and reopen. With luck iTunes now opens normally every time.
tt2

Apex 3.1.2, unable to use cascaded lovs

Hi all,
am using apex 3.1.2
trying to use cascaded select lists.
but when trying it, am not able to do it.
it was working fine till two days back.
two items,
1) p14_soft
select distinct SOFTWARE display_value, SOFTWARE return_value
from REQUEST_TYPE
order by 1
display as : select list
on changing soft need to populate problem type.
2) p14_prob
select REQUEST display_value, REQUEST return_value
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any help..,
regards,
littlefoot
Edited by: Little Foot on Jun 26, 2012 11:00 PM

Welcome to Oracle Forums !
Please acquaint yourself with the FAQs , if you have not done so already.
When posting take care of the following:
<ul>
<li>Post you Apex version</li>
<li>DB edition and version</li>
<li>Webserver beng used</li>
</ul>
Other norms to follow:
a. Never highjack someone else's thread. Start your own if you have a question
b. Mark responses Helpful/ Correct, as the case may be
Responding because this is your first post.
>
I followed the example at the link you've posted here but couldn't make it work for me. I would really appreciate if you could answer the following 2 questions regarding the same example.
(1) In the cursors inside the 2 application processes, I'm not fetching anything that's of type number. In that case, what should I change the following line to:
HTP.prn ('<option value="' || c.empno || '">' || c.ename || '</option>');
From what I understand, the <b>"c.empname" in the above line has to be of type number</b>. However, the table I'm querying doesn't have anything of type number.
>
Not sure why you started thinking that c.empname has to be number. In fact, it is not a number but a string. And so is the attribute value. The value attribute is the return value while the text in the tag, c.ename, is the display value ,
See http://www.w3schools.com/tags/att_option_value.asp
>
(2) Do the cursors in the 2 applications processes have to be the exact same replicas of the definitions of the 2 select lists? That's how it looks like from the example:
Select List 2 Definition:
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FROM (SELECT ename, empno, deptno
FROM emp
WHERE empno IN (SELECT mgr
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WHERE deptno = :p119_deptno
Cursor in CASCADING_SELECT_LIST1:
SELECT ename, empno
FROM (SELECT ename, empno, deptno
FROM emp
WHERE empno IN (SELECT mgr
FROM emp))
WHERE deptno = :cascading_selectlist_item_1
>
The example has *3* select lists. The first, top level parent, is defined as a normal LoV on the Page. Only the child and grand child are created through application processes.
The second select list, CASCADING_SELECT_LIST1, is related to the Dept LoV on the page (Top level).
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When i buy a song, i no longer get "similar" suggestions. I used to, and now don't. I liked that feature, how do i get it back on?

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Hi! It was a library book and I first downloaded it to my computer, then tranferred it to my Ipod via USB cable.
It appears on my Ipod menu under Music - Audiobooks and also under Playlists where the book title appears with 10 songs under the name.
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Using multiple lines of query in sqlcmd using -q switch

Hello
I am trying to use sqlcmd to run a set of sql statements. If I use -i switch and input a file with sql statements, it is working fine, but I am trying to use the sql statements using -q to avoid the creation of the input file. But I am not having luck with
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A simple restore command like below. If I use the whole restore command in single line it works fine like below:
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to 'E:\Program Files\Microsoft SQL Server\MSSQL.1\MSSQL\DATA\bestst_test_log.ldf' "
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Well actually there is a way, in command prompt you can you the carat character (^) to indicate that there is more lines. So in your restore case:
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"restore database bestst_test from disk='E:\Backup\test\bestst\bestst_20101222.bak' ^
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move 'BESMgmt415_log' to 'E:\Program Files\Microsoft SQL Server\MSSQL.1\MSSQL\DATA\bestst_test_log.ldf' "
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Thank you
Lucas

Using Cascading Dropdown Boxes

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how to using Cascading Dropdown Boxes in visual composer?

not clearly understand what i mean?
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How to create Auto suggestion component by using of ADF tag

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Try this forum:
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The software switch is in the task bar at the bottom. Double tap the home button and swipe to the right in the bottom of the screen. The speaker icon on the left would be where the software switch would be.
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Using cascade -- Help

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Connecting 300 IP Cameras using Cisco Switches

Require help on a Case study. (Can only use Cisco switch)
Description:
This is a setup required for 300 security cameras.
So availability and redundancy is important.
I have calculate the bandwidth using [URL="http://www.jvsg.com/download/IPDesignToolSetup.zip"]this software[/URL].
If each camera is set to 5MP and H.264-10, Bandwidth is 12.08Mbit
So 300 cameras will require at least 3624.96Mbits in total.
(correct me if i am wrong)
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It will be just connecting within a LAN.
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Design 2:
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Hello Chun,
you need to accomodate 300 cameras and 32 ports for each network video recorder.
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48 * 12,08 = ?? in any case less then < 1 Gbps
You can deploy a hierarchical network design with an access layer made of switches with fixed configuration 48 ports and GE uplinks like a C3750 with 48 ports or a 2960 with 48 ports (if it exists)
Each access layer switch needs to have two uplinks to distribution switches
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Distribution switches should be two and should be able to connect to access layer switches and to NVR that requires 32 ports each.
Different solutions are possible:
instead od deploying 7 standalone switches with 48 ports each you could use two modular C4507 equipped with WS-4548 48 10/100/1000 linecards
the distribution switches can be two C3750 E, eventually configured and connected as a stack, to allow to use both uplinks of each access layer switch
Hope to help
Giuseppe

Suggestions on DHCP using cascading switches

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