Taking More Time while inserting into the table (With foriegn key)

Hi All,
I am facing problem while inserting the values into the master table.
The problem,
Table A -- User Master Table (Reg No, Name, etc)
Table B -- Transaction Table (Foreign key reference with Table A).
While inserting the data's in Table B, i need to insert the reg no also in table B which is mandatory. I followed the logic which is mentioned in the SRDemo.
While inserting we need to query the Table A first to have the values in TableABean.java.
final TableA tableA= (TableA )uow.executeQuery("findUser",TableA .class, regNo);
Then, we need to create the instance for TableB
TableB tableB= (TableB)uow.newInstance(TableB.class);
tableB.setID(bean.getID);
tableA.addTableB(tableB); --- this is for to insert the regNo of TableA in TableB.. This line is executing the query "select * from TableB where RegNo = <tableA.getRegNo>".
This query is taking too much time if values are more in the TableB for that particular registrationNo. Because of this its taking more time to insert into the TableB.
For Ex: TableA -- regNo : 101...having less entry in TableB means...inserting record is taking less than 1 sec
regNo : 102...having more entry in TableB means...inserting record is taking more than 2 sec
Time delay is there for different users when they enter transaction in TableB.
I need to avoid this since in future it will take more time...from 2 sec to 10 sec, if volume of data increases mean.
Please help me to resolve this issue...I am facing it now in production.
Thanks & Regards
VB

Hello,
Looks like you have a 1:M relationship from TableA to TableB, with a 1:1 back pointer from TableB to TableA. If triggering the 1:M relationship is causing you delays that you want to avoid there might be two quick ways I can see:
1) Don't map it. Leave the TableA->TableB 1:M unmapped, and instead just query for relationship when you do need it. This means you do not need to call tableA.addTableB(tableB), and instead only need to call tableB.setTableA(tableA), so that the TableB->TableA relation gets set. Might not be the best option, but it depends on your application's usage. It does allow you to potentially page the TableB results or add other query query performance options when you do need the data though.
2) You are currently using Lazy loading for the TableA->TableB relationship - if it is untriggered, don't bother calling tableA.addTableB(tableB), and instead only need to call tableB.setTableA(tableA). This of course requires using TopLink api to a) verify the collection is an IndirectCollection type, and b) that it is hasn't been triggered. If it has been triggered, you will still need to call tableA.addTableB(tableB), but it won't result in a query. Check out the oracle.toplink.indirection.IndirectContainer class and it's isInstantiated() method. This can cause problems though in highly concurrent environments, as other threads may have triggered the indirection before you commit your transaction, so that the A->B collection is not up to date - this might require refreshing the TableA if so.
Change tracking would probably be the best option to use here, and is described in the EclipseLink wiki:
http://wiki.eclipse.org/Introduction_to_EclipseLink_Transactions_(ELUG)#Attribute_Change_Tracking_Policy
Best Regards,
Chris

Similar Messages

Avoiding duplicate records while inserting into the table

Hi
I tried the following insert statement , where i want to avoid the duplicate records while inserting itself
but giving me the errror like invalid identifier, though the column exists in the table
Please let me know Where i'm doing the mistake.
INSERT INTO t_map tm(sn_id,o_id,txt,typ,sn_time)
   SELECT 100,
          sk.obj_id,
          sk.key_txt,
          sk.obj_typ,
          sysdate,
          FROM S_KEY sk
    WHERE     sk.obj_typ = 'AY'
          AND SYSDATE BETWEEN sk.start_date AND sk.end_date
          AND sk.obj_id IN (100170,1001054)
           and   not exists (select 1
                                                               FROM t_map tm1 where tm1.O_ID=tm.o_id
                                                                    and tm1.sn_id=tm.sn_id
                                                                    and tm1.txt=tm.txt
                                                                    and tm1.typ=tm.typ
                                                                    and tm1.sn_time=tm.sn_time )

Then
you have to join the table with alias tml where is that ?do you want like this?
INSERT INTO t_map tm(sn_id,o_id,txt,typ,sn_time)
   SELECT 100,
          sk.obj_id,
          sk.key_txt,
          sk.obj_typ,
          sysdate,
          FROM S_KEY sk
    WHERE     sk.obj_typ = 'AY'
          AND SYSDATE BETWEEN sk.start_date AND sk.end_date
          AND sk.obj_id IN (100170,1001054)
           and   not exists (select 1
                                                               FROM t_map tm where sk.obj_ID=tm.o_id
                                                                    and 100=tm.sn_id
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Problem while inserting into a table which has ManyToOne relation

Problem while inserting into a table *(Files)* which has ManyToOne relation with another table *(Folder)* involving a attribute both in primary key as well as in foreign key in JPA 1.0.
Relevent Code
Entities:
public class Files implements Serializable {
@EmbeddedId
protected FilesPK filesPK;
private String filename;
@JoinColumns({
@JoinColumn(name = "folder_id", referencedColumnName = "folder_id"),
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)})
@ManyToOne(optional = false)
private Folders folders;
public class FilesPK implements Serializable {
private int fileId;
private int uid;
public class Folders implements Serializable {
@EmbeddedId
protected FoldersPK foldersPK;
private String folderName;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "folders")
private Collection<Files> filesCollection;
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)
@ManyToOne(optional = false)
private Users users;
public class FoldersPK implements Serializable {
private int folderId;
private int uid;
public class Users implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer uid;
private String username;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "users")
private Collection<Folders> foldersCollection;
I left out @Basic & @Column annotations for sake of less code.
EJB method
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
FoldersPK folderPk = new FoldersPK(folderID, uid);
// My understanding that it should automatically handle folderId in files table,
// but it is not…
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
It is giving error:
Internal Exception: java.sql.SQLException: Field 'folderid' doesn't have a default value_
Error Code: 1364
Call: INSERT INTO files (filename, uid, fileid) VALUES (?, ?, ?)_
_ bind => [hello.txt, 1, 0]_
It is not even considering folderId while inserting into db.
However it works fine when I add folderId variable in Files entity and changed insertFile like this:
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
file.setFolderId(folderId) // added line
FoldersPK folderPk = new FoldersPK(folderID, uid);
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
My question is that is this behavior expected or it is a bug.
Is it required to add "column_name" variable separately even when an entity has reference to ManyToOne mapping foreign Entity ?
I used Mysql 5.1 for database, then generate entities using toplink, JPA 1.0, glassfish v2.1.
I've also tested this using eclipselink and got same error.
Please provide some pointers.
Thanks

Hello,
What version of EclipseLink did you try? This looks like bug https://bugs.eclipse.org/bugs/show_bug.cgi?id=280436 that was fixed in EclipseLink 2.0, so please try a later version.
You can also try working around the problem by making both fields writable through the reference mapping.
Best Regards,
Chris

Record not inserting into the table through Forms 10g

Hi all,
I have created a form in 10g(10.1.2.0.2) based on just one table that has 4 columns(col1, col2, col3, col4).
Here col1, col2 and col3 are VARCHAR2 and col4 is date and all the columns are not null columns(There are no primary and foriegn key constrains, which means duplicates are allowed).
My form contains 2 blocks where block 1 has one text item (col1) and 3 buttons (Delete, Save, Exit).
And block2 is a database block and has col2,col3,col4 which are in tabluar layout frame displaying 10 records.
When the form is opened the cursor has to be in block1.col1 for querrying. Here i enter a value in col1, and then when I click on col2 in the block2, then I put execute_query in new_block_instance of block2, which displays the records.
The block2 properties are not updatable, insertable and query is allowed.
Everything is working good until here. But here in the block2 when I want to insert another record into the table, by navigating all the way down to the last empty record and entering the new values for col2, col3 and col4 And then Ctrl+S will display the message "*FRM-40400: Transaction complete: 1 record applied and saved.*" But actually the record is not inserted into the table.
I also disabled the col4 by setting the Enabled property to No, since while inserting new record the date have to be populated into it and it shouldnt be changed by the user. And im populating the sysdate into the new record by setting Intial Value property to *$$DATE$$*.
And another requirement which I could not work arround here is that, the col3 also should be populated with the username of the user while inserting.
please help me...

Hi Sarah,
I do not want to update the existing record. So I kept Udate Allowed to No in property palette for the items in block2.
Do I have to do this property at block level also?
I'm inserting a new record here.
Edited by: Charan on Sep 19, 2011 8:48 AM

Record is not inserting into the Table thourgh forms 10g

Hi All,
I have the form built in 10g(10.1.2.0.2).
Basically the form has 2 blocks.
Block 1 with only one item, where we enter some value and hit enter(this will navigate to block2 and execute the query).
Block 2(tabular) will fetch the records. Now this block2 have 3 columns(caseid, userid, date).
Now when I insert a new record, I just need to enter the caseid only. And userid and date have to be automatically populated.
I can populate the USERID and DATE fields.
And when I enter some value in caseid item of block 2, and then do Control+S(to insert the record and Save the transaction),
i get the message saying FRM-40400: Transaction complete: 1 records applied and saved.
But when I query again for the same, I dont se the record inserted into the table.
Why is this happening?
Help please...

@ Inol
There is no promary or foriegn key relation ship. The form is fetching records from just one table. As I said block1 has col1. and Block2 has col2,3,4.
@Andreas
Yes I did select * from table, select count(*) from table in SQL*Plus. Nothing is inserted.
And one thing I have to tall here is, I have a ON-INSERT trigger in block2.
The code in ON-INSERT trigger is
-- :BLOCK2.DATE := TO_DATE(:DATE,'DD-MON-YYYY') ;
/* commented since I was populating date by assigning $$DATETIME$$ to the Initial value property of the data item. */
:BLOCK2.SOURCE_CASE := :BLOCK1.SOURCE_CASEID;Forgot to tell you,
Since I was inserting the record from block2(3 columns), to the table which has 4 columns, there is another item in block 2 which has the visible property No.
So the block 2 has 4 columns. And the hidden column will hold the value that is in the item of block1. This is what i'm pushing in the ON-INSERT trigger.
Edited by: Charan on Sep 20, 2011 1:51 PM

Record not inserting into sap table with connector framework ?

here is the code, but record not being inserting into the table ... but same piece of code working fine while updating ... the record ...
try {
interaction = connection.createInteractionEx();
IInteractionSpec interactionSpec = interaction.getInteractionSpec();
String functionName = "Z_XYZ";
interactionSpec.setPropertyValue("Name", functionName);
String writingTable = "MYTABLE";
RecordFactory rf = interaction.getRecordFactory();
MappedRecord importParams = rf.createMappedRecord("input");
importParams.put("ATTR1", "VALUE1");
importParams.put("ATTR2", "VALUE2");
IFunction function = connection.getFunctionsMetaData().getFunction(functionName);
IStructureFactory sf = interaction.retrieveStructureFactory();
IRecordSet table = (IRecordSet) sf.getStructure(function.getParameter(writingTable).getStructure());
table.insertRow();
table.setString("ATNAME", "VALUE");
table.setString("ATWRT", "VALUE");
importParams.put(writingTable, table);
MappedRecord output = (MappedRecord) interaction.execute(interactionSpec, importParams);
} catch (Exception e) {
any idea?
than ks
MMK

Hi Mohan,
Does a creation through SE37 with the same input work?
Yoav.

Constantly inserting into large table with unique index... Guidance?

Hello all;
So here is my world. We have central to our data monitoring system an oracle database running Oracle Standard One (please don't laugh... I understand it is comical) licensing.
This DB is about 1.7 TB of small record data.
One table in particular (the raw incoming data, 350gb, 8 billion rows, just in the table) is fed millions of rows each day in real time by two to three main "data collectors" or what have you. Data must be available in this table "as fast as possible" once it is received.
This table has 6 columns (one varchar usually empty, a few numerics including a source id, a timestamp and a create time).
The data is collect in chronological order (increasing timestamp) 90% of the time (though sometimes the timestamp may be very old and catch up to current). The other 10% of the time the data can be out of order according to the timestamp.
This table has two indexes, unique (sourceid, timestamp), and a non unique (create time). (FYI, this used to be an IOT until we had to add the second index on create time, at which point a secondary index on create time slowed the IOT to a crawl)
About 80% of this data is removed after it ages beyond 3 months; 20% is retained as "special" long term data (customer pays for longer raw source retention). The data is removed using delete statements. This table is never (99.99% of the time) updated. The indexes are not rebuilt... ever... as a rebuild is about a 20+ hour process, and without online rebuilds since we are standard one, this is just not possible.
Now what we are observing is that the inserts into this table
- Inserts are much slower based on a "wider" cardinality of the "sourceid" of the data being inserted. What I mean is that 10,000 inserts for 10,000 sourceid (regardless of timestamp) is MUCH, MUCH slower than 10,000 inserts for a single sourceid. This makes sense to me, as I understand it that oracle must inspect more branches of the index for uniqueness, and more different physical blocks will be used to store the new index data. There are about 2 million unique sourceId across our system.
- Over time, oracle is requesting more and more ram to satisfy these inserts in a timely matter. My understanding here is that oracle is attempting to hold the leafs of these indexes perpetually buffers. Our system does have a 99% cache hit rate. However, we are seeing oracle requiring roughly 10GB extra ram per quarter to 6 months; we're at about 50gb of ram just for oracle already.
- If I emulate our production load on a brand new, empty table / indexes, performance is easily 10x to 20x faster than what I see when I do the same tests with the large production copies of data.
We have the following assumption: Partitioning this table based on good logical grouping of sourceid, and then timestamp, will help reduce the work required by oracle to verify uniqueness of data, reducing the amount of data that must be cached by oracle, and allow us to handle our "older than 3 month" at a partition level, greatly reducing table and index fragmentation.
Based on our hardware, its going to be about a million dollar hit to upgrade to Enterprise (with partitioning), plus a couple hundred thousand a year in support. Currently I think we pay a whopping 5 grand a year in support, if that, total oracle costs. This is going to be a huge pill for our company to swallow.
What I am looking for guidance / help on, should we really expect partitioning to make a difference here? I want to get that 10x performance difference back we see between a fresh empty system, and our current production system. I also want to limit oracles 10gb / quarter growing need for more buffer cache (the cardinality of sourceid does NOT grow by that much per quarter... maybe 1000s per quarter, out of 2 million).
Also, please I'd appreciate it if there were no mocking comments about using standard one up to this point :) I know it is risky and insane and maybe more than a bit silly, but we make due with what we have. And all the credit in the world to oracle that their "entry" level system has been able to handle everything we've thrown at it so far! :)
Alright all, thank you very much for listening, and I look forward to hear the opinions of the experts.

Hello,
Here is a link to a blog article that will give you the right questions and answers which apply to your case:
http://jonathanlewis.wordpress.com/?s=delete+90%25
As far as you are deleting 80% of your data (old data) based on a timestamp, then don't think at all about using the direct path insert /*+ append */ as suggested by one of the contributors to this thread. The direct path load will not re-use any free space made by the delete. You have two indexes:
(a) unique index (sourceid, timestamp)
(b) index(create time)
Your delete logic (based on arrival time) will smatch your indexes as far as you are always deleting the left hand side of the index; it means you will have what we call a right hand index - In other words, the scattering of the index key per leaf block is certainly catastrophic (there is an oracle iternal function named sys_op_lidbid that will allow you to verify this index information). There is a fairly chance that your two indexes will benefit from a coalesce as already suggested:
           ALTER INDEX indexname COALESCE;This coalesce should be investigated to be done on a regular basis (may be after each 80% delete) You seem to have several sourceid for one timestamp. If the answer is yes you should think about compressing this index
    create index indexname (sourceid, timestamp) compress;
or
    alter index indexname rebuild compress;     You will do it only once. Your index will have a smaller size and may be more efficient than it is actually. The index compression will add an extra CPU work during an insert but it might help improving the overal insert process.
Best Regards
Mohamed Houri

Insert into two tables with a single query (same ID)

Hello,
I want to insert two tables at the same time ( with a single query) provided that both records get inserted with the same id. How do I do this?
Table Movies
id
name
Table Category
movie_id
cat_typea) Insert into first table, retrieve the id (may be by using my_sequence.currval and then insert into another table.
issue: Makes three query to the db, I am also guessing that when multiple people try to insert there will be an issue, I might be wrong.
I don't have any other idea.
Greatly appreciated!

Why don't use multitable insert ? It's available from 9i.
A sequence.nextval will return the same value within the whole instruction
so all records can be inserted with the same id.
Look at this example:
DROP TABLE A;
DROP TABLE B;
drop sequence a_seq;
CREATE TABLE A(
ID NUMBER,
FIRSTNAME VARCHAR2(50)
CREATE TABLE B AS
SELECT id, firstname lastname FROM a;
CREATE SEQUENCE a_seq
START WITH 1;
INSERT ALL
INTO A(ID, FIRSTNAME) VALUES(A_SEQ.NEXTVAL, FNAME)
INTO B(ID, LASTNAME) VALUES(A_SEQ.NEXTVAL, LNAME)
SELECT 'fname ' || LEVEL FNAME, 'lname ' || LEVEL LNAME
FROM DUAL
CONNECT BY LEVEL < 10
COMMIT;
SELECT * FROM A;
SELECT * FROM b;
DROP TABLE A succeeded.
DROP TABLE B succeeded.
drop sequence a_seq succeeded.
CREATE TABLE succeeded.
CREATE TABLE succeeded.
CREATE SEQUENCE succeeded.
18 rows inserted
commited
ID                     FIRSTNAME
3                      fname 1
4                      fname 2
5                      fname 3
6                      fname 4
7                      fname 5
8                      fname 6
9                      fname 7
10                     fname 8
11                     fname 9
9 rows selected
ID                     LASTNAME
3                      lname 1
4                      lname 2
5                      lname 3
6                      lname 4
7                      lname 5
8                      lname 6
9                      lname 7
10                     lname 8
11                     lname 9
9 rows selected

How to insert into a table with a nested table which refer to another table

Hello everybody,
As the title of this thread might not be very understandable, I'm going to explain it :
In a context of a library, I have an object table about Book, and an object table about Subscriber.
In the table Subscriber, I have a nested table modeling the Loan made by the subscriber.
And finally, this nested table refers to the Book table.
Here the code concerning the creation of theses tables :
Book :
create or replace type TBook as object
number int,
title varchar2(50)
Loan :
create or replace type TLoan as object
book ref TBook,
loaning_date date
create or replace type NTLoan as table of TLoan;
Subscriber :
create or replace type TSubscriber as object
sub_id int,
name varchar2(25)
loans NTLoan
Now, my problem is how to insert into a table of TSubscriber... I tried this query, without any success...
insert into OSubscriber values
*(1, 'LEVEQUE', NTLoan(*
select TLoan(ref(b), '10/03/85') from OBook b where b.number = 1)
Of course, there is an occurrence of book in the table OBook with the number attribute 1.
Oracle returned me this error :
SQL error : ORA-00936: missing expression
00936. 00000 - "missing expression"
Thank you for your help

1) NUMBER is a reserved word - you can't use it as identifier:
SQL> create or replace type TBook as object
2 (
3 number int,
4 title varchar2(50)
5 );
6 /
Warning: Type created with compilation errors.
SQL> show err
Errors for TYPE TBOOK:
LINE/COL ERROR
0/0      PL/SQL: Compilation unit analysis terminated
3/1      PLS-00330: invalid use of type name or subtype name2) Subquery must be enclosed in parenthesis:
SQL> create table OSubscriber of TSubscriber
2 nested table loans store as loans
3 /
Table created.
SQL> create table OBook of TBook
2 /
Table created.
SQL> insert
2    into OBook
3    values(
4           1,
5           'No Title'
6          )
7 /
1 row created.
SQL> commit
2 /
Commit complete.
SQL> insert into OSubscriber
2    values(
3           1,
4           'LEVEQUE',
5           NTLoan(
6                  (select TLoan(ref(b),DATE '1985-10-03') from OBook b where b.num = 1)
7                 )
8          )
9 /
1 row created.
SQL> select *
2    from OSubscriber
3 /
    SUB_ID NAME
LOANS(BOOK, LOANING_DATE)
         1 LEVEQUE
NTLOAN(TLOAN(000022020863025C8D48614D708DB5CD98524013DC88599E34C3D34E9B9DBA1418E49F1EB2, '03-OCT-85'))
SQL> SY.

Task is taking more time, while creating more number of jobs in PLSQL.

Hi,
I want to know regarding distributing a task to no. of scheduler jobs. On which basis we should have to define no. of jobs and also what will be advantage or disadvantage of increasing the number of such jobs for a particular task ?

Hello,
Looks like you have a 1:M relationship from TableA to TableB, with a 1:1 back pointer from TableB to TableA. If triggering the 1:M relationship is causing you delays that you want to avoid there might be two quick ways I can see:
1) Don't map it. Leave the TableA->TableB 1:M unmapped, and instead just query for relationship when you do need it. This means you do not need to call tableA.addTableB(tableB), and instead only need to call tableB.setTableA(tableA), so that the TableB->TableA relation gets set. Might not be the best option, but it depends on your application's usage. It does allow you to potentially page the TableB results or add other query query performance options when you do need the data though.
2) You are currently using Lazy loading for the TableA->TableB relationship - if it is untriggered, don't bother calling tableA.addTableB(tableB), and instead only need to call tableB.setTableA(tableA). This of course requires using TopLink api to a) verify the collection is an IndirectCollection type, and b) that it is hasn't been triggered. If it has been triggered, you will still need to call tableA.addTableB(tableB), but it won't result in a query. Check out the oracle.toplink.indirection.IndirectContainer class and it's isInstantiated() method. This can cause problems though in highly concurrent environments, as other threads may have triggered the indirection before you commit your transaction, so that the A->B collection is not up to date - this might require refreshing the TableA if so.
Change tracking would probably be the best option to use here, and is described in the EclipseLink wiki:
http://wiki.eclipse.org/Introduction_to_EclipseLink_Transactions_(ELUG)#Attribute_Change_Tracking_Policy
Best Regards,
Chris

MS SQL Server 2014: Error inserting into Temp table with index and identity field

In this thread, I mentioned a problem with SQL Server 2014:
SQL Server 2014: Bug with IDENTITY INSERT ON
The question was answered, it is a bug. To keep you informed on this issue, I open this discussion.
Problem:
The code below works perfectly fine on MS SQL Server 2008 R2 and MS SQL Server 2012, but gives an error every second time the proc is executed on MS SQL Server 2014. If I do not define any index on the temp table, the problem disappears. Defining the index
after the insert, does not help.
SET NOCOUNT ON
GO
IF EXISTS (SELECT 1 FROM sys.procedures WHERE name = 'usp_Test') DROP PROC dbo.usp_Test;
GO
CREATE PROC dbo.usp_Test AS
BEGIN
SET NOCOUNT ON
CREATE TABLE #Source(ID integer NOT NULL);
INSERT INTO #Source VALUES (1), (2), (3);
CREATE TABLE #Dest (ID integer IDENTITY(1,1) NOT NULL);
CREATE INDEX #IDX_Dest ON #Dest (ID);
PRINT 'Check if the insert might cause an identity crisis';
SELECT 'Source' AS SourceTable, * FROM #Source;
SELECT 'Destination' AS DestTable, * FROM #Dest;
SET IDENTITY_INSERT #Dest ON;
PRINT 'Do the insert';
INSERT INTO #Dest (ID) SELECT ID FROM #Source;
PRINT 'Insert ready';
SET IDENTITY_INSERT #Dest OFF;
SELECT * FROM #Dest;
DROP TABLE #Source;
DROP TABLE #Dest;
END;
GO
PRINT 'First execution of the proc, everything OK';
EXEC dbo.usp_Test;
PRINT '';
PRINT 'Second execution of the proc, the insert fails.';
PRINT 'Removing the index #IDX_Dest causes the error to disappear.';
EXEC dbo.usp_Test;
GO
DROP PROC dbo.usp_Test;
GO

There is some progress. Communication from a former Microsoft employee tells us this:
Shivendra Vishal
Engineer at Microsoft
I am no longer with MS, and I do not have code access, however from the public symbols, I could make out following:
sqlmin!SetidentI2I4+0x1f3:
000007fe`f4d865d3 488b10 mov rdx,qword ptr [rax] ds:00000000`00000000=????????????????
ExceptionAddress: 000007fef4d865d3 (sqlmin!SetidentI2I4+0x00000000000001f3)
ExceptionCode: c0000005 (Access violation)
ExceptionFlags: 00000000
NumberParameters: 2
Parameter[0]: 0000000000000000
Parameter[1]: 0000000000000000
Attempt to read from address 0000000000000000
This is a read AV and from registers it is clear that we were trying to move the value of location pointed by qword of register rax which is not valid:
rax=0000000000000000 rbx=0000000000000038 rcx=0000000000001030
rdx=0000000000000006 rsi=00000001f55def98 rdi=00000000106fd070
rip=000007fef4d865d3 rsp=00000000106fcf40 rbp=00000000106fcfe9
r8=0000000000000000 r9=00000001f55def60 r10=00000001f55defa0
r11=00000000106fcd20 r12=0000000000000000 r13=0000000000000002
r14=00000001f49c3860 r15=00000001f58c0040
iopl=0 nv up ei pl nz na po nc
cs=0033 ss=002b ds=002b es=002b fs=0053 gs=002b efl=00010206
The stack is:
# Child-SP RetAddr Call Site
00 00000000`106fcf40 000007fe`f30c1437 sqlmin!SetidentI2I4+0x1f3
01 00000000`106fd050 000007fe`f474e7ce sqlTsEs!CEsExec::GeneralEval4+0xe7
02 00000000`106fd120 000007fe`f470e6ef sqlmin!CQScanUpdateNew::GetRow+0x43d
03 00000000`106fd1d0 000007fe`f08ff517 sqlmin!CQueryScan::GetRow+0x81
04 00000000`106fd200 000007fe`f091cebe sqllang!CXStmtQuery::ErsqExecuteQuery+0x36d
05 00000000`106fd390 000007fe`f091ccb9 sqllang!CXStmtDML::XretDMLExecute+0x2ee
06 00000000`106fd480 000007fe`f08fa058 sqllang!CXStmtDML::XretExecute+0xad
07 00000000`106fd4b0 000007fe`f08fb66b sqllang!CMsqlExecContext::ExecuteStmts<1,1>+0x427
08 00000000`106fd5f0 000007fe`f08fac2e sqllang!CMsqlExecContext::FExecute+0xa33
09 00000000`106fd7e0 000007fe`f152cfaa sqllang!CSQLSource::Execute+0x86c
0a 00000000`106fd9b0 000007fe`f152c9e8 sqllang!CStmtExecProc::XretLocalExec+0x25a
0b 00000000`106fda30 000007fe`f152a1d8 sqllang!CStmtExecProc::XretExecExecute+0x4e8
0c 00000000`106fe1e0 000007fe`f08fa058 sqllang!CXStmtExecProc::XretExecute+0x38
0d 00000000`106fe220 000007fe`f08fb66b sqllang!CMsqlExecContext::ExecuteStmts<1,1>+0x427
0e 00000000`106fe360 000007fe`f08fac2e sqllang!CMsqlExecContext::FExecute+0xa33
0f 00000000`106fe550 000007fe`f0902267 sqllang!CSQLSource::Execute+0x86c
10 00000000`106fe720 000007fe`f0909087 sqllang!process_request+0xa57
11 00000000`106feee0 000007fe`f2bf49d0 sqllang!process_commands+0x4a3
12 00000000`106ff200 000007fe`f2bf47b4 sqldk!SOS_Task::Param::Execute+0x21e
13 00000000`106ff800 000007fe`f2bf45b6 sqldk!SOS_Scheduler::RunTask+0xa8
14 00000000`106ff870 000007fe`f2c136ff sqldk!SOS_Scheduler::ProcessTasks+0x279
15 00000000`106ff8f0 000007fe`f2c138f0 sqldk!SchedulerManager::WorkerEntryPoint+0x24c
16 00000000`106ff990 000007fe`f2c13246 sqldk!SystemThread::RunWorker+0x8f
17 00000000`106ff9c0 000007fe`f2c13558 sqldk!SystemThreadDispatcher::ProcessWorker+0x3ab
18 00000000`106ffa70 00000000`775d59ed sqldk!SchedulerManager::ThreadEntryPoint+0x226
19 00000000`106ffb10 00000000`7780c541 kernel32!BaseThreadInitThunk+0xd
1a 00000000`106ffb40 00000000`00000000 ntdll!RtlUserThreadStart+0x21
Unassembling the function:
000007fe`f4d8658e 4c8b10 mov r10,qword ptr [rax]
000007fe`f4d86591 4533e4 xor r12d,r12d
000007fe`f4d86594 410fb7d5 movzx edx,r13w
000007fe`f4d86598 4533c9 xor r9d,r9d
000007fe`f4d8659b 4533c0 xor r8d,r8d
000007fe`f4d8659e 488bc8 mov rcx,rax
000007fe`f4d865a1 4489642420 mov dword ptr [rsp+20h],r12d
000007fe`f4d865a6 41ff5230 call qword ptr [r10+30h]
000007fe`f4d865aa 8b5597 mov edx,dword ptr [rbp-69h]
000007fe`f4d865ad 4c8b10 mov r10,qword ptr [rax]
000007fe`f4d865b0 4489642438 mov dword ptr [rsp+38h],r12d
000007fe`f4d865b5 4489642430 mov dword ptr [rsp+30h],r12d
000007fe`f4d865ba 458d442401 lea r8d,[r12+1]
000007fe`f4d865bf 4533c9 xor r9d,r9d
000007fe`f4d865c2 488bc8 mov rcx,rax
000007fe`f4d865c5 c644242801 mov byte ptr [rsp+28h],1
000007fe`f4d865ca 4488642420 mov byte ptr [rsp+20h],r12b
000007fe`f4d865cf 41ff5250 call qword ptr [r10+50h]
000007fe`f4d865d3 488b10 mov rdx,qword ptr [rax] <=================== AV happened over here
000007fe`f4d865d6 488bc8 mov rcx,rax
000007fe`f4d865d9 4c8bf0 mov r14,rax
000007fe`f4d865dc ff5268 call qword ptr [rdx+68h]
000007fe`f4d865df 488d55e7 lea rdx,[rbp-19h]
000007fe`f4d865e3 4c8b00 mov r8,qword ptr [rax]
000007fe`f4d865e6 488bc8 mov rcx,rax
000007fe`f4d865e9 41ff5010 call qword ptr [r8+10h]
000007fe`f4d865ed f6450a04 test byte ptr [rbp+0Ah],4
I remember few issues with scan2ident function, I am not sure if they have fixed it however it appears that this is intoduced to SQL 2014 and we need help from MS to get this resolved as it needs code analysis.
It is not getting simulated for other versions of SQL apart from SQL 2014.
Also to add, interestingly, the value of rax is not visibly changed and it was successfully passed on to rcx, which has a valid value, so something should have changed the value of rax inside call to function using call qword ptr [r10+50h], and looking at this
it appears that it might be a list of functions and we are going at particular offset [50h]. So, bottom line is that the call to function qword ptr [r10+50h], should be changing something in rax, and debugging/analyzing this code might give us some more idea.

Weird problem w. mysql 4.0 when inserting into a table with auto_incremet

Since I upgraded my mysql database from 3.23 to 4.0.1
the following code does not work anymore:
I get this error msg:
<b>"Invalid argument value: Duplicate entry '2147483647' for key 1"</b>
<code>
package mysql4test;
import java.sql.*;
class test {
public test() {
public static void main(String[] args) {
Connection connection = null;
Statement st = null;
try {
Class.forName("org.gjt.mm.mysql.Driver").newInstance();
connection = DriverManager.getConnection
("jdbc:mysql://192.168.0.4/x?user=x&password=");
st = connection.createStatement();
for (int i=1;i<10;i++)
String insert = "insert into x (b) values('hello');";
System.out.println(insert);
st.executeUpdate(insert);
} catch (Exception ex) { System.err.println(ex.getMessage());}
</code>
The table definition of table x is the following:
create table x(a int(11) primary key auto_increment, b varchar(10));
What makes the thing even more mysterious is, that doing the same thing as this programm does manually on an mysql client does not produces any error message.
insert into x (b) values('hello'); works fine on the mysql client deliverd with the server.

Hi eggsurplus!
Yes, I succeeded in different ways to solve the problem. changing the table was one of it. but the problem is that i can't simply change all tables (there are a lot) as the are used in other programms.
The simplest solution that i figured out so far was changing the insert from
insert into x (b) values('hello')
to
insert into x (a,b) values("+i+",'hello')"
But this solution is still not satisfactory as in more complex programs you can't just use the i variable of the for loop, but you have to add a new variable that increments on every insert.
This still means changing a lot of code that i wrote for mysql 3.x.
Besides, i tried also another jdbc driver and it still didn't work.
The same bug was reported in a PHP forum, but without solution

Insert into temp table with sorting not works

Hi,
Am inserting some of the values into temp table . Before going to insert i will be sorting a cloumn in descending order and then i will try insert. But actually inserts in ascending order.Dont know why.
Please find the code
Create table #TempTable( column1 smalldateTime )
Insert into #TempTable
Select distinct(column1) from table1 where cloumn2 = 1 order by column1 desc
When i query the table
select * from #TempTable
shows the dates are in ascending order instead it should in descending
But when i query this Select distinct(column1) from table1 where cloumn2 = 1 order by column1 desc
dates are in descending order which means recent dates fills top

Or use a CTE = Common Table Expression:
CREATE TABLE #test (id int);
INSERT INTO #test
SELECT object_id
FROM sys.objects;
SELECT COUNT(*)
FROM #test;
GO
;WITH cte AS
(SELECT Top 2 *
FROM #test
ORDER BY id desc)
DELETE FROM cte;
GO
SELECT COUNT(*)
FROM #test;
GO
DROP TABLE #test;
Olaf Helper
[ Blog] [ Xing] [ MVP]

How do I insert into the next available primary key

Hello,
I am attempting to insert into an already populated database.
How do I use dreamweaver to get the next available PK record in a
MySQL database.
Thanks

If you do an insert it will go into the next available key.
Is that what
you mean?
Murray --- ICQ 71997575
Adobe Community Expert
(If you *MUST* email me, don't LAUGH when you do so!)
==================
http://www.projectseven.com/go
- DW FAQs, Tutorials & Resources
http://www.dwfaq.com - DW FAQs,
Tutorials & Resources
==================
"Mesh55" <[email protected]> wrote in
message
news:fo2trm$scl$[email protected]..
> Hello,
>
> I am attempting to insert into an already populated
database. How do I
> use dreamweaver to get the next available PK record in a
MySQL database.
>
> Thanks

Insert into two tables with trigger on PK in second table

Hi evereone, ineed help.
I have two tables (organizations, addresses).
On addresses table i have trigger on PK. When i do insert i must get this param and insert into OrganizationTable for reference.
Without ADF i can do insert with returning on addresses, than do insert on organizations with this returning param. How can i do this in ADF business logic using trainTaskFlow?
Thanks all.
Edited by: WaterStream on 15.10.2012 15:10

thanks for reply, but i found solution in this materials:
http://liuwuhua.blogspot.com/2010/11/master-detail-crud-in-adf-bc.html
(on this link anyone can download model and see all params)
but in my project i will get JBO-25030 error.
Solution founded here:
http://vtkrishn.com/2011/02/09/oracle-jbo-invalidownerexception/
Work great!!!

Taking More Time while inserting into the table (With foriegn key)

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