Test for visible GUI

I want to test (in a shell script) whether my GUI is visible. The test should return false if I’m not logged in, or the screen saver is running, the login window is showing, another user has the display, etc. How can I do this?

I found a hack that accomplishes the goal, but it's not a very good solution. There must be a much better way.
The hack uses the screencapture utility. If the login window is showing or another user has the GUI, then screencapture will not generate an output file. It does not output an error message or return an error status; it just silently fails, so you have to test for the file's existence.
For example:
#!/bin/bash
rm -f myscreen.png
screencapture -x myscreen.png
if test -f myscreen.png
then
echo "I have the screen."
rm -f myscreen.png
else
echo "I don't have the screen."
fi
It's not clean or efficient, but it works, except for the case where my screen saver is running. In that case, this test indicates that I have the screen, although my desktop is not visible. So in addition to the test above, I'd also have to test whether I have a ScreenSaverEngine process that does not have the -background flag.
All in all, it's probably not a practical solution, but at least it demonstrates what I am trying to accomplish.

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