The order of elements in an array.

Hi
I have an array whose array.length is 3.
I need to add a new element at the the first position in the array.
For example the existing values in the array are
1,2,3.
Now I need to add 10 in the first position so that the array looks like : 10,1,2,3.
Is there any Java API that accomplishes this.
Any help is highly appreciated.
Thanks in advance.

You can use the new appendToBeginning method of the CrazyMadeUp Class. It's available in version 1.6 (codename Monkey) and above. Unfortunately it only works with Objects though.
public static Object[] appendToBeginning(Object[] originalArray, Object[] addToStart) {
Object[] tempArray = new Object[originalArray.length + addToStart.length];
System.arraycopy(originalArray, 0, tempArray, addToStart.length, originalArray.length);
for (int i = 0; i < addToStart.length; i++) tempArray[i] = addToStart;
return tempArray;

Similar Messages

Reverse the order of elements in an array

how would i go about Reverse the order of elements in an array??

I link to the javadocs can't be too bad. [url
http://java.sun.com/j2se/1.5.0/docs/api/java/util/Coll
>
ections.html#reverse(java.util.List)]Collections.rever
se(List)Of course I fortell the next question, but I wantan
Array not a List? So I provide the next link:[url
http://java.sun.com/j2se/1.5.0/docs/api/java/util/Arr
ys.html#asList(T...)]Arrays.asList(T...)Yeah but then you have to worry about the next
question which is more of a statement: "I can't use
Arrays".
Then I would as them: How would you do it in real life? Of course they could think a real world way of doing it. In that case, I'll give them an real life example.
Assumed List
1 2 3 4 5 6 7 8 9 10 11 12 13
Switch the first and the last elements
13 2 3 4 5 6 7 8 9 10 11 12 1
Then the second and second to the last
13 12 3 4 5 6 7 8 9 10 11 2 1
And repeat until your half way.
13 12 10 4 5 6 7 8 9 3 2 1
13 12 10 9 5 6 7 8 4 3 2 1
13 12 10 9 8 6 7 5 4 3 2 1
13 12 10 9 8 7 6 5 4 3 2 1
Done.

How can i change the order of elements in a JList ?

Hi,
i would like to know if it is possible to change the order of elements in a JList ? Maybe i could use drag and drop to do this ?
Thanks for answering.

The simplest way is probably to implement ur own listmodel and then supply the listitems in the order u want. Example:
class MyListModel
          extends AbstractListModel
          implements ContactListListener {
public int getSize() {
return listitemcount;
public Object getElementAt(int index) {
//here u return the item for the index at the list
//if u for example have an array of strings
//which u wanna have listed in reversed order (reversed to
//the order in the array, u could do
     return myarray[getSize()-index];
}

Will the order of elements stored in pl.sql table retains

Hello Friends,
I am having a record type and the for each element of record , i am having corresponding pl.sql table type .
If i am storing the values into the records from a query and also the individual elements in the pl.sql table type will the order of data is stored as it is . ..
example...
in a record type the data is stored as ( name1 , age1 , salary1) , (name2, age2, salary2)
if i store in corresponding pl sql table type name1 , name2
age1, age2
salary1, salary2
can i relate the index of record type with that of pl/sql table type ..
pls advice
thanks/kumar

Kumar,
Yes, the order of elements will be the same.
Any specific reason why you would want to create a collection for each individual attribute of the record ?
You can as well declare another variable of the same record and initialize it.
A few other suggestions for your code :
1) The 2nd FOR loop can be modified to accommodate the query of the first cursor there-by eliminating one extra iteration.
SELECT MINC.FAMID,
                     MINC.MEMBNO,
                     MEMB.AGE,
                     SALARYX,
                     SALARYBX,
                     NONFARMX,
                     NONFRMBX,
                     FARMINCX,
                     FRMINCBX,
                     CU_CODE
                FROM MINC, MEMB, FMLY
               WHERE MINC.FAMID = MEMB.FAMID
                 AND MINC.MEMBNO = MEMB.MEMBNO
                 AND MINC.FAMID = FMLY.FAMID
                 AND MEMB.FAMID = FMLY.FAMID
               ORDER BY MINC.FAMID2) The collections can be alternately initialized as follows :
   v_member_rec(v_member_rec.last).FAMID := j.FAMID;
   max_earnings_tab(max_earnings_tab.last) := v_max_earnings;The tried the below example for confirmation ...
declare
type emp_rec is record
(name emp.ename%TYPE,
dept emp.edept%TYPE,
sal emp.esal%TYPE
TYPE emp_rec_tab is table of emp_rec;
ert emp_rec_tab := emp_rec_tab();
TYPE ename_tab is table of varchar2(20);
ent ename_tab := ename_tab();
TYPE edept_tab is table of number;
edt edept_tab := edept_tab();
begin
for i in (select * from emp)
loop
     ert.extend;
     ent.extend;
     edt.extend;
     ert(ert.last).name := i.ename;
     ert(ert.last).dept := i.edept;
     ert(ert.last).sal := i.esal;
     ent(ent.last) := i.ename;
     edt(edt.last) := i.edept;
end loop;
for i in 1..ert.count
loop
     dbms_output.put_line(ert(i).name||','||ent(i));
     dbms_output.put_line(ert(i).dept||','||edt(i));
     dbms_output.put_line('');
end loop;
end;

Error in file export when order of elements in build array changes

Hi everyone,
A while ago I wrote a vi file which does the following:
At first it initializes a camera and chooses a region of interest (ROI). Data out of the ROI will be discarded.
Then it raster scans a motor stage in x and y direction, in bidirectional mode (meaning that x alternates between scanning from left to right and right to left as y is inreased).
For each point of the scan, the spectrum is collected, which is then integrated in lambda to give an idea of the total intensity.
Then the intensity is plotted, along with the spectrum at each point.
The final results are exported in a text file.
The problem:
If I flip the order of the wires in the "build array" before the file export, placing the Total Count (intensity) wire in place of the Spectrum wire, the file export fails. What I mean by "fails" is that the .txt file contains characters that look like chinese!
Why is that?
I attach my .vi as well as two screenshots which demostrate the problem.
Solved!
Go to Solution.
Attachments:
correct.png ‏182 KB
Wrong.png ‏180 KB
1.7z ‏119 KB

mikeporter wrote:
Hey Jeff... The changes you recommend are all good (and necessary) but the thing I'm stuck on is that regardless of what happens to the floating point data, there's that built-in VI that changes it to string representations of the numbers. And as I understand it, that is where the problem is.
Mike...
PS: Coming to NI Week?
Not this year
What scared me was the sgls on a SLs with no wire branch to force a data copy which, would force LabVIEW to preserve the sgls since the SL might need to be used again then, they get all mixed up building arrary out of mixed coerced sgls and dbls. With the potential of a miss-reussed buffer (not uncommon in 2011) confusing the string operations in the write to spreadsheet. The problem of course, must exist outside of write to spreadsheet file since it only exhibits with a build array element order change. Or, we all are halucinating (Possible alternate theory)
Jeff

Will Vector keep the order of elements?

I would like to quickly add lines of a file into a vector to get the size. I then create an array using that declaring that number of elements, then read each vector element into the array. I thought I read somewhere that a Vector may swap the order of the elements?

I thought I read
somewhere that a Vector may swap the order of the
elements?Well, if you did read that somewhere it might be true. If you write some serious code you cannot buy what people just say. You have to look into it for yourself and ESTABLISH what goes with your chosen data-structure.
PS. My advice to everybody is to look into this stuff and convince yourself you're doing the right thing.

How Do I Print the Number of Elements in An Array

How do I print: "There are ____ number of elements in the array?"

If you have a String holding a sentence, and if you split on non-empty sequences of whitespace (if the string has newlines in it, you'd probably need to pass the argument that makes \s match newlines, and for that you would probably need to use java.util.regex.Pattern -- see the docs and try some tests), when you'd get an array of Strings that were the non-whitespace parts of the original String. That makes for a reasonably good definition of the words in the sentence, although you could arguably get into some gray areas (does "isn't" count as one or two words? Does a sequence of numbers or punctuation qualify as a word?). In that case, counting the number of elements in the resulting array of String. using .length, would be a reasonable way to get the number of words in that sentence, yes.
But rather than asking for confirmation on forums, why don't run some tests?
import java.io.*;
public class TestWordCount {
public static void main(String[] argv) {
    try {
      BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
      String line;
      while((line = in.readLine()) != null) {
        int count = // your code here, to count the words
        System.out.println("I see " + count + " words.");
    } catch (IOException e) {
      e.printStackTrace();
}Put your word-counting code in there, then run it from the command line. Type in a sentence. See how many words it thinks it found. Does it match with your expectation, or the examples given (hopefully) with your homework assignment?

How to find the defference between elements in an array

hi guys,
this is probs an easy one for you but how can you find the diffence between all elements in an array?
e.g array = 1 2 3 4 5 6
so difference between 1 and two is 1, difference between 1 and 3 is 2. all the way to trough to the differece between 6 and x is x etc.
i have been trying to use shift registers but cant quite get it.
Thanks
Message Edited by adamkse on 09-02-2009 01:18 AM
Solved!
Go to Solution.

or maybe this:
Harold Timmis
[email protected]
Orlando,Fl
*Kudos always welcome
Attachments:
buildarraysubtract.JPG ‏58 KB

Reverse the order of elements in array?

Hi All,
i have elements of string[] aray = {one,two,three};i want the elements needs to be in reverse order..
ex : {three,two,one};how can we do this...
plz help on this...with example..
thanks in advance..
jags.

Melanie_Green wrote:
Eric-Fistons wrote:
int j = 0;
for (int i = array.length - 1; i >= 0; i--) {
newArray[j] = array;
j++;
Simplified
int j = 0;
for (int i = array.length; i > 0; i--){
newArray[j++] = array;
}Aka bored, Mel
package forums;
import java.util.Arrays;
class ArrayReverserator
public static void main(String[] args) {
    try {
      System.out.println(Arrays.toString(reverse(new Object[]{1,2,3})));
    } catch (Exception e) {
      e.printStackTrace();
public static Object[] reverse(Object[] a) {
    Object[] result = new Object[a.length];
    for ( int i=a.length-1,j=0; i>=0; --i ) {
      result[j++] = a;
return result;
I also am bored...
<tut-tut>for i=a.length; i>0; == you're slipping</tut-tut>
IMHO, java.util.Arrays could stand to have a reverse... it is, after all, just special case of sort... by index decending.
Cheers. Keith.

Get the number of elements in Array

Hi everyone,
Could anyone give me idea on how to get the number of elements in an Array (not number of rows) ?
I tried to find that in both property node and array functions but nothing.
Thanks,
-Kun

You are going to have to provide some proof that the Array Size does not work correctly. Right click on the input to it and select 'Create Indicator'. Run the VI. Go to the front panel and select 'Edit>Make Current Values Default'. Save the VI and attach it to your post.
You can also check the array size yourself. Right click on the index display of the array and select 'Advanced>Show Last Element'. I will bet you that number shown is equal to Array Size -1.
p.s. The number of elements in an array is equal to the number of rows in a 1D array. If you define the number of elements as anything else, you are mistaken.
Message Edited by Dennis Knutson on 04-21-2009 10:40 AM

How to find the elements of an array

I want to find the number of elements in an array, and I can't find the tutorial that shows how to find it. If anyone could point me in the right direction, it would be greatly appreciated.

warnerja wrote:
flounder wrote:
DrLaszloJamf wrote:
You mean x.length?<pbs>
Depends upon your interpretation of "number of elements in the array"
int[] numbers = new int[10];
numbers[0] = 42;
numbers[1] = 666;Number of elements in the array is 2 not 10.
</pbs>If you used something other than a primitive type for the array element type you could have a case. A value of integer zero for the other elements is still a value, so there are indeed 10 elements there.Even if it were not primitive, every element would have a value. That value would either be null or a reference.

Customizing the order of input tag variables?

How do you change the order of elements inside input tags?
Example :
<input value="A" name="B" type="checkbox" />
Instead of...
<input name="B" type="checkbox" value="A" />
etc.. (and will a code formatting fix all past instances?)

You're a stubborn one, aren't you?
The question, still quoted below by the way, was "*How* do
you change the
order of..." and not "*Does* changing the order of affect..."
I didn't ask if it would make a difference in the output. I
asked how I can
have DW automatically re-order the elements inside the tag.
Turns out I
can't, so the point is now moot.
And before you follow up by telling me it doesn't matter what
the order is
again like a broken record : it might not to you but it does
to me. Some of
these tags are 300 chrs long if you include CSS,
javascripting and other
optional attributes. So if I'm in the code view and I'm
looking for VALUE
and not ID -- or, as is the case, if I'm passing this code
onto other
programmers who are coding via text only, then I (and them)
appreciate
knowing if a tag will potentially be found at the beginning,
middle or end
of a 300-chr input string.
"xtra" <[email protected]> wrote in message
news:ekid9s$j2n$[email protected]..
> Yes, it did. You asked about changing the order of the
elements. And I
> answered that you don't have to for them to work.
>
> Good luck.
>
>
> "R. Jay" <[email protected]> wrote in message
> news:ekia6h$fjf$[email protected]..
>> Thanks, but that wasn't the question. :(
>>
>> "xtra" <[email protected]> wrote in message
>> news:ekhple$pbi$[email protected]..
>>> The order of the attributes doesn't matter.
>>>
>>>> "R. Jay" <[email protected]> wrote in
message
>>>> news:ekfqjn$efq$[email protected]..
>>>>> How do you change the order of elements
inside input tags?
>>>>>
>>>>> Example :
>>>>> <input value="A" name="B"
type="checkbox" />
>>>>>
>>>>> Instead of...
>>>>>
>>>>> <input name="B" type="checkbox"
value="A" />
>>>>>
>>>>> etc.. (and will a code formatting fix
all past instances?)

Sort an an arrayList by the first element of an array

Hi,
I am really struggling trying to sort an arratList of arrays. I have an arrayList
ArrayList<String[]> myArrayList = new ArrayList<String []>(100);
Within this array I have may arrays with 2 elements
String[] myArray1 = {"Peter", "London"};
String[] myArray2 = {"John", "London"};
String[] myArray3 = {"Tony", "Birmingham"};
I add all these arrays to the arrayList and want to sort by the first element of the array. Basically I expect the final arrayList to be in the order of:
"John", "London"
"Peter", "London"
"Tony", "London"
Thanks
Peter

Hi,
I am really struggling trying to sort an arratList of
arrays. I have an arrayList
ArrayList<String[]> myArrayList = new
ArrayList<String []>(100);
Within this array I have may arrays with 2 elements
String[] myArray1 = {"Peter", "London"};
String[] myArray2 = {"John", "London"};
String[] myArray3 = {"Tony", "Birmingham"};
I add all these arrays to the arrayList and want to
sort by the first element of the array. Basically I
expect the final arrayList to be in the order of:
"John", "London"
"Peter", "London"
"Tony", "London"
Thanks
PeterThis can be done by using
Collections.sort(myArrayList, new Comparator<String[]>() {
public int compare(String[] s1, String[] s2) {
if (s1.length() <1) {
return -1;
if (s2.length() <1) {
return 1;
return s1[0].compareTo(s2[0]);
});

How can I change the properties of only one element in an array of booleans?

I'm displaying an array of booleans to my operators, with each boolean in the array representing some system status check. Some of these checks are critical and some are not, therefore I want some of these booleans to have a different color when in the TRUE state (Red for the critical ones and Yellow for the non-critical ones). I can change the boolean colors with a property node, but that effects every element in the array. Is there any way to change a property of an individual element in an array? I know that I could take the incoming array and break it into two arrays - one for critical and one for non-critical, but this system is replacing an older system and the operators are accustomed to seeing their indicator lights a certain way and I'm trying to replicate what they had exactly.

Here's what I had in mind
Of course you can use as many colors as you want.
Message Edited by altenbach on 12-21-2005 04:53 PM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
LEDarray.png ‏7 KB
ColorArray3.vi ‏23 KB

How can i sort out the N lowiest elements from an 1D array faster than using the build in sort function (1D-array) in Labview?

I need an algorithm that is based on the same sorting-algorithm that Labview uses (or one that is just as fast) but it only needs to sort out the N lowiest elements (and the N-element output array don't need to be sorted).
/Jonas

I want all three zeros in the output. You can se the algorithm that I'm looking for as a soft version of Labviews own sort algorithm that only gives you the N (always less then the length of the array) lowiest values as output.If two elements contain the same small value both should be sorted out.
/Jonas

The order of elements in an array.

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