To find the bonus amount
hi everybody,
i need to create column bonus in a table and to enter the value as bonus=(salary+10%) every time when i create it shows an error.
eg:
salary bonus
==== =====
500 550
1000 1100
which means we calculate the bonus from the salary and add 10% from the salary.
Hi,
1009262 wrote:
hi everybody,
i need to create column bonus in a table and to enter the value as bonus=(salary+10%) every time when i create it shows an error. What command are you using to create it, and what is the error message that it shows? Post them. It's very hard for me to say what you're doing wrong when I don't know what you're doing.
>
eg:
salary bonus
==== =====
500 550
1000 1100
which means we calculate the bonus from the salary and add 10% from the salary.Which is
1.1 * salaryAs the others have said, it sounds like a virtual column would be better than a regular column, assuming you're using Oracle 11, and that the bonus is always determined by the salary (or something in the same row), with no exceptions. You can find examples of how to declare and use virtual columns in the SQL Language manual
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Hi All,
I have this sample data:
create table sampleTable(
sample_id number,
sample_fy number,
sample_amt number
insert into sampleTable(sample_id, sample_fy, sample_amt)
values(1, 2003, 25);
insert into sampleTable(sample_id, sample_fy, sample_amt)
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insert into sampleTable(sample_id, sample_fy, sample_amt)
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insert into sampleTable(sample_id, sample_fy, sample_amt)
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insert into sampleTable(sample_id, sample_fy, sample_amt)
values(2, 2005, 10);
insert into sampleTable(sample_id, sample_fy, sample_amt)
values(2, 2006, 6);
insert into sampleTable(sample_id, sample_fy, sample_amt)
values(3, 2003, 75);
insert into sampleTable(sample_id, sample_fy, sample_amt)
values(3, 2004, 13);
insert into sampleTable(sample_id, sample_fy, sample_amt)
values(3, 2005, 13);
insert into sampleTable(sample_id, sample_fy, sample_amt)
values(3, 2006, 26);
How can I find the rows with same amounts (amt) for the same sample_id and years between 2004 and 2005?
The result should be:
sample_id
1
3
I try lead, but it is comparing rows from different sample_id as:
SELECT sample_id, sample_fy, sample_amt,
LEAD(sample_amt, 1, 0) OVER (ORDER BY sample_id, sample_fy) - sample_amt AS my_diff
FROM sampleTable
WHERE sample_fy between 2004 and 2005;
Any ideas?
Maybe is another function that I can use.
Thanks!Hi,
I would use GROUP BY:
SELECT sample_id
FROM sampletable
WHERE sample_fy IN (2004, 2005)
GROUP BY sample_id
HAVING COUNT (DISTINCT sample_fy) = 2
AND COUNT (DISTINCT sample_amt) = 1
This does not assume that there will be esxactly 1 row for each combination of sample_id and sample_fy. A given sample_id may be missing one year or the other (in which case it will not produce any output), or there may be multiple rows per year (in which case, the sample_id will be chosen only if all they are all equal. I assume sample_amt can not be NULL).
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PARTITION BY sample_id -- This line added
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) - sample_amt AS my_diff
FROM sampleTable
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I have spreadsheet in which 3 columns are in use A,B and C
Requirements
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On the Home tab of the ribbon, click Conditional Formatting > Highlight Cells Rules > Duplicate Values...
Click OK.
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Dim rng As Range
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With rng.FormatConditions
.Delete
With .AddUniqueValues
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.Interior.Color = 13551615
.Font.Color = -16383844
End With
End With
End Sub
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Apart from that: enter the following formula in C1:C23 and confirm it with Ctrl+Shift+Enter to make it an array formula:
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Dim rng As Range
Set rng = Range(Range("A1"), Range("A" & Rows.Count).End(xlUp))
With rng.Offset(0, 2)
.FormulaArray = "=VLOOKUP(" & rng.Address & "," & _
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