To get the File path dynamically

Hi all,
I am using the <b>Gui_upload function, and i want to get the file dynamically from the search help</b>,
So please help me in finding the answer.
Thanks,
Girish

Hai Girish
Check the following Code
DATA: I_FILETABLE TYPE FILETABLE,
      V_RC TYPE I.
PARAMETERS: P_FILE LIKE RLGRAP-FILENAME.     "local file with contracts
AT SELECTION-SCREEN ON VALUE-REQUEST FOR P_FILE.
CALL METHOD CL_GUI_FRONTEND_SERVICES=>FILE_OPEN_DIALOG
   EXPORTING
     WINDOW_TITLE            = 'Find File'
     DEFAULT_EXTENSION       = 'C:\'
     DEFAULT_FILENAME        = ''
     FILE_FILTER             = ',..'
   INITIAL_DIRECTORY       =
   MULTISELECTION          =
   WITH_ENCODING           =
CHANGING
    FILE_TABLE               = I_FILETABLE
    RC                       = V_RC
   USER_ACTION             =
   FILE_ENCODING           =
EXCEPTIONS
    FILE_OPEN_DIALOG_FAILED = 1
    CNTL_ERROR              = 2
    ERROR_NO_GUI            = 3
    NOT_SUPPORTED_BY_GUI    = 4
    others                  = 5
IF SY-SUBRC <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
           WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
READ TABLE I_FILETABLE INTO P_FILE INDEX 1.
Thanks & Regards
Sreenivasulu P
Message was edited by: Sreenivasulu Ponnadi

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