To get the sum of leave an employee has taken
hi all
i have this query
SELECT dif.employee_number, dif.full_name employeename,
TO_CHAR (date_entray, 'DY') DAY, date_entray attendance_date,
TO_CHAR (start_date, 'dd-Mon-rrrr') doj, dif.dept_name, POSITION,
tran_name, insert_type, day_desc,
CASE
WHEN insert_type = 'AnLv'
THEN COUNT
(insert_type)
END days_anlv,
CASE
WHEN insert_type = 'SkLv'
THEN COUNT (insert_type)
END days_sklv,
CASE
WHEN insert_type = 'BTrp'
THEN COUNT (insert_type)
END days_btrp
FROM nap_punch_data_emp_list trn, nap_emp_def dif,
nap_punch_card_eleg ele
WHERE trn.employee_number = dif.employee_number
AND ele.employee_number = trn.employee_number
AND date_entray BETWEEN :p_from_date AND :p_to_date
AND trn.employee_number BETWEEN NVL (:p_emp_no, trn.employee_number)
AND NVL (:p_emp_no2, trn.employee_number)
GROUP BY dif.employee_number,
dif.full_name,
start_date,
dif.dept_name,
POSITION,
tran_name,
insert_type,
date_entray,
day_desc
ORDER BY date_entray
the output of which is
EMPLOYEE_NUMBER ATTENDANCE_DATE INSERT_TYPE DAYS_ANLV DAYS_SKLV DAYS_BTRP
686 04/18/2012 annual leave 1
688 04/18/2012 sick leave 1
689 04/18/2012 annual leave 1
686 04/19/2012 annual leave 1
69 04/19/2012 businesstrip 1
69 04/19/2012 businesstrip 1
is it possible to obtain
employee number days_anlv days_btrp
686 2
69 2the sum of the respective leaves each employee has taken
kindly guide
thanking in advance
Edited by: makdutakdu on Jun 24, 2012 2:59 PM
Edited by: makdutakdu on Jun 24, 2012 3:00 PM
Edited by: makdutakdu on Jun 24, 2012 3:01 PM
Edited by: makdutakdu on Jun 24, 2012 3:02 PM
Edited by: makdutakdu on Jun 24, 2012 3:03 PM
Edited by: makdutakdu on Jun 24, 2012 3:03 PM
Edited by: makdutakdu on Jun 24, 2012 3:04 PM
Edited by: makdutakdu on Jun 24, 2012 3:26 PM
Edited by: makdutakdu on Jun 24, 2012 3:27 PM
Edited by: makdutakdu on Jun 24, 2012 3:28 PM
Edited by: makdutakdu on Jun 25, 2012 9:05 AM
Hi,
makdutakdu wrote:
hi all
i have this query
SELECT dif.employee_number, dif.full_name employeename,
TO_CHAR (date_entray, 'DY') DAY, date_entray attendance_date,
TO_CHAR (start_date, 'dd-Mon-rrrr') doj, dif.dept_name, POSITION,
tran_name, insert_type, day_desc,
CASE
WHEN insert_type = 'AnLv'
THEN COUNT
(insert_type)
END days_anlv,
CASE
WHEN insert_type = 'SkLv'
THEN COUNT (insert_type)
END days_sklv,
CASE
WHEN insert_type = 'BTrp'
THEN COUNT (insert_type)
END days_btrp
FROM nap_punch_data_emp_list trn, nap_emp_def dif,
nap_punch_card_eleg ele
WHERE trn.employee_number = dif.employee_number
AND ele.employee_number = trn.employee_number
AND date_entray BETWEEN :p_from_date AND :p_to_date
AND trn.employee_number BETWEEN NVL (:p_emp_no, trn.employee_number)
AND NVL (:p_emp_no2, trn.employee_number)
GROUP BY dif.employee_number,
dif.full_name,
start_date,
dif.dept_name,
POSITION,
tran_name,
insert_type,
date_entray,
day_desc
ORDER BY date_entray
the output of which is
EMPLOYEE_NUMBER ATTENDANCE_DATE INSERT_TYPE DAYS_ANLV DAYS_SKLV DAYS_BTRP
686 04/18/2012 annual leave 1
688 04/18/2012 sick leave 1
689 04/18/2012 annual leave 1
686 04/19/2012 annual leave 1
69 04/19/2012 businesstrip 1
69 04/19/2012 businesstrip 1
When posting formatted code, make sure it appears on this site so that people can read and understand it. Does the output above look okay ih your browser? I can;t tell which numbers are supposed to be in which columns. Use the "Preview" tab and edit your message, if necessarry, before posting.
is it possible to obtain
employee number days_anlv days_btrp
686 2
69 2
the sum of the respective leaves each employee has takenIt's unclear what you want, but I'm sure you can do it.
Whenever you have a question, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all the tables involved, and the results you want from that data.
Explain, using specific examples, how you get those results from that data.
Always say what version of Oracle you're using.
See the forum FAQ {message:id=9360002}
If you only want one row of output for each employee_number, then employe_number should be the only thing in the GROUP BY clause.
You may need to do 2 GROUP BYs; one in a sub-query, and the the other (with employee_number alone in the GROUP BY clause) in the main query.
Why do the results not include employee_numbers 688 and 689?
Similar Messages
-
Getting cummulative sum of salaries of employees from emp table
Hi gurus,
Can any body tell me how to get cummulative sum of salaries of employees in emp table by using analytical functions.
thanks in advance....SeánMacGC wrote:
Hello,
Try:
SELECT empno,
SUM(SAL) OVER () cumulative_sal
FROM emp;
You need to order by to get the cumulative salary
SQL> SELECT empno,
2 SUM(SAL) OVER () cumulative_sal
3 FROM emp;
EMPNO CUMULATIVE_SAL
7369 29025
7499 29025
7521 29025
7566 29025
7654 29025
7698 29025
7782 29025
7788 29025
7839 29025
7844 29025
7876 29025
EMPNO CUMULATIVE_SAL
7900 29025
7902 29025
7934 29025
14 rows selected.
SQL> SELECT empno, sal,
2 SUM(SAL) OVER (Order by empno) cumulative_sal
3 FROM emp;
EMPNO SAL CUMULATIVE_SAL
7369 800 800
7499 1600 2400
7521 1250 3650
7566 2975 6625
7654 1250 7875
7698 2850 10725
7782 2450 13175
7788 3000 16175
7839 5000 21175
7844 1500 22675
7876 1100 23775
EMPNO SAL CUMULATIVE_SAL
7900 950 24725
7902 3000 27725
7934 1300 29025
14 rows selected. -
Get the sum/product of two UDF rows before adding A/R Invoice
Hi Everyone,
I am making some tests here where I am trying to get the sum or product of two UDF rows in a service type A/R invoice where I need to get the product before i even add the document.
The query goes like:
SELECT T0.[U_UDF1] * T0.[U_UDF2] FROM INV1 T0 WHERE T0.[U_UDF1] = $[INV1.U_UDF1]
It did not work. Is this possible?
Thanks,
DerrickBefore you add a transaction, the values you specify in the screen are not stored into the database. In an FS you can use SQL statements but in these statements you can refer only to the actual header or row level data with the special expressions starting with $. The system replaces these expressions with a constant containing the actual value before executing the SQL string.
So there is no possibility to sum the columns with FS before adding the document.
Sorry, I didnu2019t read carefully your question and probably misunderstood it.
Edited by: István K#rös on Jan 13, 2011 11:27 AM -
Getting the sum of all members in a hierarchy....
Hi,
I want to get the sum of each member in a hierarchy....
The hierarchy is defined in the table strdet:
create table strdet
(costcenterms varchar2(20), // parent
costcenterdet varchar2(20), // child
lev varchar2(1))The values for each object/material per costcenter(child) is defined in the table details_det:
create table details_det
(costcenterms varchar2(20),
eppid varchar2(30) ,
purchcontyear0 number(4,1) )Some sample data:
insert into strdet values ('1' , '1.1','2')
insert into strdet values ('1' , '1.2','2')
insert into strdet values ('1.1' , '1.1.1','3')
insert into strdet values ('1.1' , '1.1.2','3')
insert into strdet values ('1.2' , '1.2.1','3')
insert into strdet values ('1.2' , '1.2.2','3')
insert into strdet values ('1.2' , '1.2.3','3')
insert into strdet values ('1.1.1' , '1.1.1.1','4')
insert into strdet values ('1.1.1' , '1.1.1.2','4')
insert into strdet values ('1.1.2' , '1.1.2.1','4')
insert into strdet values ('1.2.1' , '1.2.1.1','4')
insert into strdet values ('1.2.1' , '1.2.1.2','4')
COMMIT;
insert into details_det values('1.1.1.1','epp1',10);
insert into details_det values('1.1.1.1','epp2',20);
insert into details_det values('1.1.1.1','epp3',0);
insert into details_det values('1.1.1.2','epp1',0);
insert into details_det values('1.1.2.1','epp2',5);
insert into details_det values('1.1.2.1','epp4',15);
insert into details_det values('1.2.1.1','epp1',65);
insert into details_det values('1.2.1.1','epp2',95);
insert into details_det values('1.2.1.2','epp1',5);
commit;The output of the desired sql stmt must be like this:
costcenter val
1 220
1.1 55
1.2 165
1.1.1 30
1.1.2 20
1.2.1 165I have written the following , so far.....
SQL> select distinct s.costcenterms , sum(purchcontyear0) over(partition by s.costcenterms order by s.costcenterms)
2 from details_det d , strdet s
3 where s.costcenterdet=d.costcenterms(+)
4 start with s.costcenterms='1'
5 connect by s.costcenterms = prior s.costcenterdet
6 order by s.costcenterms
7 /
COSTCENTERMS SUM(PURCHCONTYEAR0)OVER(PARTIT
1.2
1.2.1 165
1.1.1 30
1.1.2 20
1
1.1
6 rows selectedHow should i modify the above sql stmt to get the desired result...????
Note: I use OracleDB 10g. v.2
Thanks, a lot
SimI' m grateful to all.....!!!!
I connected as user SYS so as to give the appropriate privileges to SCOTT schema ....
SQL*Plus: Release 10.2.0.1.0 - Production on Êõñ Óåð 14 11:03:44 2008
Copyright (c) 1982, 2005, Oracle. All rights reserved.
SQL> connect sys/***@info as sysdba;
Connected
SQL> grant create materialized view to scott;
Grant succedded
SQL> grant alter any materialized view to scott with admin option;
Grant succedded
SQL> connect scott/tiger@info;
Connected
SQL> create materialized view mv
2 as
3 select s.costcenterms , sum(connect_by_root d.purchcontyear0) sum_cbr
4 from details_det d , strdet s
5 where s.costcenterdet = d.costcenterms(+)
6 connect by s.costcenterdet = prior s.costcenterms
7 group by s.costcenterms
8 order by length(s.costcenterms) , s.costcenterms ;
create materialized view mv
Error in line 1
ORA-30361: unrecognized string type
SQL> create materialized view x_mv
2 as
3 select grp, sum(purchcontyear0)
4 from (
5 select connect_by_root s.costcenterms grp, d.purchcontyear0
6 from strdet s, details_det d
7 where s.costcenterdet=d.costcenterms(+)
8 connect by s.costcenterms = prior s.costcenterdet
9 )
10 group by grp
11 /
Materialized view created
SQL> create materialized view mv
2 as
3 select s.costcenterms , sum(connect_by_root d.purchcontyear0) sum_cbr
4 from details_det d , strdet s
5 where s.costcenterdet = d.costcenterms(+)
6 connect by s.costcenterdet = prior s.costcenterms
7 group by s.costcenterms ;
create materialized view mv
Error in line 1
ORA-30361: unrecognized string typeTo sum up.....
Rob's version of definition of mv is unsuccessful... even when i omit the order by clause.... whereas SY's version is successful..... Can you imagine why since... as Rob posted above , it is successful in his environment......!!!!!
Note: As regards the ORA- error , the cause and action of Oracle is as follows:
Cause: An internal Oracle error occured.
Action: Report the problem through your normal support channels. Thanks again,
Sim -
Getting the sum of the elements in an array
Hello all,
Any ideas on how to easily get the sum of the elements of an array of floating points (or any data type for that matter ) this is to be part of a method.
arrayName (float [] floaters)
Thanksint total=0;
for(int a=0; a<array.length; a++){
total=total+array[a];
}now is that so hard?
or even as a method
public int addUp(int[] array){
int total=0;
for(int a=0; a<array.length; a++){
total=total+array[a];
return total;
}to be used as
int total=addUp(array);just write your own! -
How do you get the sum of two columns multipied together?
I can't seem to figure out how to get the sum of two columns multiplied together without having to manually type out each location (example: A1*B1+A2*B2+A3*B3, etc..). Though the idea seems to be rather simple, everything I have tried has only given me an error. I know there must be an easier way of doing this, but I get lost in the explanations given in 'help' area of numbers, can someone help me?
C3=SUMPRODUCT(A3:A18, B3:B18)
the function SUMPRODUCT() takes ranges and multiplies corresponding cells in the ranges, then adds them together.
I the case I show SUMPRODUCT() performs:
A3*B3 + A4*B4 + A5*B5 + A6*B6 + ... + A18*B18
If you want to perform the same operation on the whole column (s) you could modify the formula:
C3=SUMPRODUCT(A, B) -
How to get the sum total of just one row in the dashboard
How do I get the sum total of one row in the compound layer results. This is 11g
Does anyone know?
may be sales, I need the total at the bottom of the row..
thx
ChuckI fnd the answer,
in the table view, click edit then nxt to the columns and measures there is total sum icon. Click that, and choose after -
Function Module to get the Direct manager to an employee in a period?
Function Module to get the Direct manager to an employee in a period of time?
Hi,
try these FM
/MRSS/SQP_EMP_PROF_GET_API
/MRSS/SQP_EMP_PROF_GET_HISTORY
Thanks
Viquar Iqbal -
Count consecutive Workdays where employee has taken SICK leave
I am trying to identify a way within sql to count the number of consecutive workdays (Monday - Friday) an employee has taken SICK leave. My problem in the past has been trying to count days whereas we cross the weekend. Currently I have 4 queries identifying patterns around the weekend that I run and export into an Excel Spreadsheet and manipulate from there. My goal is to be able to list an EMPLID (employee id), EMPL_RCD ( employee record), Min(DUR) (Date of absence), Max(DUR), and count of consecutive workdays.
Any help or guidance would will be appreciated. I have attached my current query.
I run my current query 4 times using the patterns below one at a time.
SELECT DISTINCT A.EMPLID,A.EMPL_RCD, A.DUR,b.dur,c.dur,d.dur, A.TL_QUANTITY, A.TRC
FROM PS_TL_RPTD_TIME A, PS_TL_RPTD_TIME B, PS_TL_RPTD_TIME C,PS_TL_RPTD_TIME D
WHERE A.EMPLID = B.EMPLID
AND A.EMPL_RCD = B.EMPL_RCD
AND A.EMPLID = C.EMPLID
AND A.EMPL_RCD = C.EMPL_RCD
AND A.EMPLID = D.EMPLID
AND A.EMPL_RCD = D.EMPL_RCD
AND B.EMPLID = C.EMPLID
AND B.EMPL_RCD = C.EMPL_RCD
AND B.TRC = C.TRC
AND A.TRC = B.TRC
AND A.TRC = C.TRC
AND A.TRC = D.TRC
AND (B.DUR = A.DUR+3 AND C.DUR = A.DUR+4 AND D.DUR = A.DUR+5) Friday, Monday, Tuesday, Wednesday
AND (B.DUR = A.DUR+1 AND C.DUR = A.DUR+4 AND D.DUR = A.DUR+5) Thursday, Friday, Monday, Tuesday
AND (B.DUR = A.DUR+1 AND C.DUR = A.DUR+2 AND D.DUR = A.DUR+5) Wednesday, Thursday, Friday, Monday
AND (B.DUR = A.DUR+1 AND C.DUR = A.DUR+2 AND D.DUR = A.DUR+3) -- Same workweek
AND A.TRC LIKE 'SICK%'
AND NOT EXISTS ( SELECT 'x' FROM PS_JOB J
WHERE J.EMPLID = A.EMPLID
AND J.EMPL_RCD = A.EMPL_RCD
AND J.EMPL_STATUS IN ('P','L')
AND J.EFFDT = ( SELECT MAX(J1.EFFDT) FROM PS_JOB J1
WHERE J1.EMPLID = J.EMPLID
AND J1.EMPL_RCD = J.EMPL_RCD
AND J1.EFFDT <= D.DUR))You should consider a technique from data warehousing where you use a table to describe dates. To keep things simple, let's create a table that holds all your valid business days for the past 2 weeks...
create table business_dates (business_day date);
begin
insert into business_dates values (to_date('16-oct-2006'));
insert into business_dates values (to_date('17-oct-2006'));
insert into business_dates values (to_date('18-oct-2006'));
insert into business_dates values (to_date('19-oct-2006'));
insert into business_dates values (to_date('20-oct-2006'));
insert into business_dates values (to_date('23-oct-2006'));
insert into business_dates values (to_date('24-oct-2006'));
insert into business_dates values (to_date('25-oct-2006'));
insert into business_dates values (to_date('26-oct-2006'));
insert into business_dates values (to_date('27-oct-2006'));
insert into business_dates values (to_date('30-oct-2006'));
insert into business_dates values (to_date('31-oct-2006'));
insert into business_dates values (to_date('01-nov-2006'));
insert into business_dates values (to_date('02-nov-2006'));
insert into business_dates values (to_date('03-nov-2006'));
end;
now we create a table that shows whether each employee was sick or not for a given work day...
create table attendance (empid number, business_day date, sick char(1));
insert into attendance values (100, to_date('16-oct-2006'), 'N');
insert into attendance values (100, to_date('17-oct-2006'), 'Y');
insert into attendance values (100, to_date('18-oct-2006'), 'Y');
insert into attendance values (100, to_date('19-oct-2006'), 'N');
insert into attendance values (100, to_date('20-oct-2006'), 'N');
insert into attendance values (100, to_date('23-oct-2006'), 'Y');
insert into attendance values (100, to_date('24-oct-2006'), 'Y');
insert into attendance values (100, to_date('25-oct-2006'), 'Y');
insert into attendance values (100, to_date('26-oct-2006'), 'N');
insert into attendance values (100, to_date('27-oct-2006'), 'N');
insert into attendance values (100, to_date('30-oct-2006'), 'N');
insert into attendance values (100, to_date('31-oct-2006'), 'Y');
insert into attendance values (100, to_date('01-nov-2006'), 'N');
insert into attendance values (100, to_date('02-nov-2006'), 'N');
insert into attendance values (100, to_date('03-nov-2006'), 'N');
insert into attendance values (105, to_date('16-oct-2006'), 'Y');
insert into attendance values (105, to_date('17-oct-2006'), 'Y');
insert into attendance values (105, to_date('18-oct-2006'), 'N');
insert into attendance values (105, to_date('19-oct-2006'), 'N');
insert into attendance values (105, to_date('20-oct-2006'), 'Y');
insert into attendance values (105, to_date('23-oct-2006'), 'N');
insert into attendance values (105, to_date('24-oct-2006'), 'N');
insert into attendance values (105, to_date('25-oct-2006'), 'Y');
insert into attendance values (105, to_date('26-oct-2006'), 'Y');
insert into attendance values (105, to_date('27-oct-2006'), 'Y');
insert into attendance values (105, to_date('30-oct-2006'), 'Y');
insert into attendance values (105, to_date('31-oct-2006'), 'Y');
insert into attendance values (105, to_date('01-nov-2006'), 'N');
insert into attendance values (105, to_date('02-nov-2006'), 'N');
insert into attendance values (105, to_date('03-nov-2006'), 'Y');
Now the query to get each sick occurrence and the number of consecutive days for each employee is...
select empid, first_sick_day, sick_count from
(select empid,
first_value(business_day) over (partition by empid, groupno order by business_day) as first_sick_day,
row_number() over (partition by empid, groupno order by business_day) as rn,
count(*) over (partition by empid, groupno) as sick_count
from
(select empid, business_day, daynum-rownum groupno
from
(SELECT a.empid, a.business_day, d.day_num as daynum
FROM attendance a,
(select rownum as day_num, business_day
from (select business_day from business_dates order by business_day)) d
WHERE sick = 'Y' AND a.business_day = d.business_day
ORDER BY 1,2 )
where rn = 1;
The above query can be modified slightly to only give you the sick occurrence with the maximum number of consecutive days for each employee.
Having a separate date table is nice because you can take in account weekends, holidays or any other nonwork day by just removing that date from the table. Generating this table is easy as date dimension examples can be found on on the web, and the amount of rows is small (250 rows per year approx).
JR -
I'm getting the error message "Photos folder syncing has been disabled for the iPhone <my iPhone> because the folder "Pictures" cannot be found." lately.
Normally, all I do with photos is move them from my iPhone to my computer's (Windows 7) hard drive. I do this by connecting the iPhone with the cable, a box pops up on the screen asking me what I want to do, and I choose "Import pictures and videos". I've previously selected the "delete photos from the device after move" option (or however it's worded...), simply because I don't want this device to fill up with photos.
Lately, it has been importing the photos fine, but it won't delete them from the iPhone. This used to work just fine, now it doesn't work and I don't know what changed, if anything. In iTunes, I get the error message I list at the beginning of this message.
How do I fix this?Hi there scarbo59,
You mentioned that you are still able to import without issues, but you may still want to run through the troubleshooting steps outlined in the article below.
iOS: Unable to import photos to computer
-Griff W. -
iTunes is updated and works fine and I am able to log onto my account. When I go to purchase a song, I get the error message "Your Apple ID has been disabled". I've tried different methods: changing passwords, making a new account with another email address, and emailing itunes tech support. I am curious as to how many others have been experiencing the same issue. When I googled the error, it seemed like it was happening extremely often with many people.
We all love their products, but they always come with a lot of issues and horrible customer support.
My apple Id is [email protected]My Iphone 4 is telling me the same thing and I believe I figured out what the problem is. I had some fraudulent charges on my itunes account, so I call my bank and disputed the charges. Right after I did that, I started getting the message "Your apple ID has been disabled." I just realized today that the charges are not fraudulent, they are "in app purchases." One of my daughters downloaded the game Top Girl which is FREE, but in the game Top Girl you use money in the game to purchase things. It just so happens that the money you use to purchase things is real money MY Money!!!. My daughter thought she was using play money in the game and had no idea she was using real money. She spent $106.00 buying stuff. Now I have to call the bank and tell them to release the hold and pay Itunes. I'm hoping this solves the problem. Here is the link to learn how to disable "in app purchase" on your iphone or ipad.
http://www.ikidapps.com/2010/12/parents-avoid-accidental-app-purchases-how-to-tu rn-off-in-app-purchasing.html -
getting the error message"your apple ID has been disabled" . I reset my ID password last night and am still having the same issue.
If you are still unable to access your account after resetting your password, you will need to contact iTunes Store Customer Support via http://www.apple.com/support/itunes/contact/
-
I am running windows vista for business (32 bit), using firefox, when I try to play a sample from audible.co.uk the browser hangs and then I get the message, "adobe flash plug in has crashed". I have tried uninstalling the flash player and reinstalling to no avail. It also crashes using Internet Explorer and Google Chrome.
If you have the ClickToFlash extension installed, that can prevent Flash based video from streaming. Safari > Preferences > Extensions
It can also be installed as a plugin in /Library/Internet-Plug-Ins.
Try uninstalling the currently installled Flash plugin (required for most YouTube content) then reinstall new > Troubleshoot Flash Player | Mac OS
From your Safari menu bar top of your screen click Safari > Preferences then select the Advanced tab.
Select: Show Develop menu in menu bar
Now from the menu bar click Develop > Empty Caches -
TS4062 I keep getting the error message "apple outlook DAV has stopped working"
My phone and I pad all of the sudden just stopped syncing with my desktop. I have had my phone for over a year when 4s first came out and everything was syncing fine. Then all the sudden it stopped. I keep getting the error message "apple outlook DAV has stopped working". I have rebooted, checked for duplicates, signed in and out of the cloud and still nothing. Has anyone had this problem and know of a good way to handle it. Also, now my phone and Ipad don't sync with the cloud either. Please help.
Windows 7 Professional. I meant that when I open a word doc and want to turn it into a PDF, i get the same error message. In the mean time I paid the $40.00 and spoke to Adobe and after 40 minutes, they re-installed Reader X instead of XI so now it works but I am not overly thrilled that I had to pay for it.
-
I have Photoshop Elements 7.0 and when I go to sort the photos in order (from oldest date) I keep getting the message "Photoshop Elements 7.0 has stopped working" and then the program closes. Sometimes, eventually it has sorted as I request but today this has been rejected over 15 times. What is wrong?
Try the licensing service update:
http://helpx.adobe.com/creative-suite/kb/error-licensing-stopped-windows.html
EDIT I see that maybe you did (is that the patch you mean? ); if so, try the other suggestions there.
Maybe you are looking for
-
Safari lost tabs after iOS 8 upgrade
i have just updated my iPad Air to the lates iOS 8.02 and when I open Safari it appears to have lost the ability to have more than one website as tabs.Where has the tab faculty gone. Tony
-
hello Guru ji tell me below scenario PO Not Showing in 0001 Client (production ) Please open case to determine why the following transaction failed to create a PO in 0001. (prodution client) some body has(take it as sunil)entered the following data o
-
Problem in creating transaction variant
Hi all, I am trying to create transaction variant for F- 41 transaction . it's giving an error message . Variants are possible only for dialog transactions. Message no. MS417 Diagnosis You cannot create variants for variant or parameter trans
-
IPhoto won't open at all!
I'll click on the icon and nothing will happen, not even a pop up will show. I've restarted and it still will not work. What can I do to fix it? I have a Macbook Pro with OS X Yosemite. It's a 250 gb and has about 189 gigabytes left.
-
Need help on resetting an iphone 4
I recently tried to sync my wifes phone and update the OS. I must have selected an incorrect setting, because all of my apps appeared on her phone. I have deleted all of the apps but I would like to know how to reset her phone to get her apps back.