Tokenizer - getting the third node from this format (800,PA,PAC,Package)

Question

Hi Folks,
I am trying to get the third node from the following format: 800,PA,PAC,Package
The correct output is PAC.
Your help is very much appreciated!
Just to add the code that I have is as follows:
Import com.sap.mw.jco.*;
//write your code here
String DBTABLE = a;
String WHERE_CLAUSE = b+" = "+"'"c"'" ;
//...some code in here...
// Create function
JCO.Function function = null;
IFunctionTemplate ft = mRepository.getFunctionTemplate("RFC_READ_TABLE");
function = ft.getFunction();
// Obtain parameter list for function
JCO.ParameterList input = function.getImportParameterList();
// Pass function parameters
input.setValue( DBTABLE, "QUERY_TABLE");
input.setValue( "," , "DELIMITER");
//Fill the where clause of the table
JCO.ParameterList tabInput = function.getTableParameterList();
JCO.Table inputTable = tabInput.getTable("OPTIONS");
inputTable.appendRow();
inputTable.setValue(WHERE_CLAUSE,"TEXT");
mConnection.execute( function );
//This is the part where the output is generated
JCO.Table valueSet = function.getTableParameterList().getTable("DATA");
String resultSet = valueSet.getString("WA"); //WA contains 800,PA,PAC,Package
mConnection.disconnect();
return resultSet;

Answer 1

Hi Morgalr,
Thank your for the tip.
I am not sure if there is a better way to do the coding. But what what I have come up is the following:
JCO.Table valueSet = function.getTableParameterList().getTable("DATA");
String resultSet []= valueSet.getString("WA").split("(double \ in here),");
mConnection.disconnect();
return resultSet[2];
Let me know if this works with you.
regards,
Lex