Transform Document to String

What is an easy way to transform the contents of a org.w3c.dom.Document to String and vice versa?

You can use xerces parser for getting the XML string from Document object. There are Classes to provide this functionality. I have pasted the code here. Let me know if you have any problems
import org.w3c.dom.Document;
import org.apache.xml.serialize.OutputFormat;
import org.apache.xml.serialize.XMLSerializer;
import java.io.StringWriter;
import java.io.FileReader;
import java.io.File;
import java.io.FileReader;
import org.xml.sax.InputSource;
import org.apache.xerces.parsers.DOMParser;
public class XmlString{
     public static void main(String a[]) throws Exception{
          try{
          File file = new File("root.xml");
          FileReader fileReader = new FileReader(file);
          InputSource     inputSource = new InputSource(fileReader);
          DOMParser domParser = new DOMParser();
          domParser.parse(inputSource);
          Document doc = domParser.getDocument();
          OutputFormat format = new OutputFormat(doc, "ISO-8859-1", true);
          format.setStandalone(true);
          format.setIndenting(true);
          StringWriter stringOut = new StringWriter();
          XMLSerializer serial = new XMLSerializer(stringOut, format);
          serial.asDOMSerializer();
          serial.serialize(doc.getDocumentElement());
          System.out.println("XML CONTENT "+stringOut.toString());
          catch(Exception e){
               System.out.println(" EXP "+e);
Have a nice day
regards
Paulraj C

Similar Messages

Conversion from document to string

I want to perform conversion from document to string for tht purpose i m doing sax parser but in the end i m getting null.The same thing if i do with DOM parser its working fine but some problem with sax parser.
I am attaching the code if anyone can find the problem it would be gr8.
Thanks in advance.
public String DocumentToString(Document doc) {
          StreamResult result = null;
          try {
          SAXParserFactory SAXpf = SAXParserFactory.newInstance();
SAXParser SAXparser = SAXpf.newSAXParser();
          XMLr = SAXparser.getXMLReader();
     Source sXML = new SAXSource((InputSource) doc);
result = new StreamResult(new StringWriter());
Transformer transformer = TransformerFactory.newInstance().newTransformer();
transformer.setOutputProperty(OutputKeys.INDENT, "yes");
transformer.transform(sXML, result);
catch (TransformerConfigurationException e) {
e.printStackTrace();
catch (TransformerException e) {
e.printStackTrace();
catch(Exception e)
     System.out.println(e);
return result.getWriter().toString();
}

Paddy,
There are a couple of ways to create a Word file. One is to use the Report Generation Toolkit which includes vi's to create and edit Word documents. Since you are associated with a university you may already have the toolkit. The other way is to use ActiveX. You should be able to find examples of both in the forums. There may also be an example that shipped with LV.
Here is one example to get you going http://zone.ni.com/devzone/cda/epd/p/id/992

How to transform DOM into String

Hi,
Can any one provide an example of transforming DOM into String using TransformationFactory or any other API of JAXP?
Regards...
Shamit

And for finer output:
      * Prints a textual representation of a DOM object into a text string..
      * @param document DOM object to parse.
      * @return String representation of <i>document</i>.
    static public String toString(Document document) {
        String result = null;
        if (document != null) {
            StringWriter strWtr = new StringWriter();
            StreamResult strResult = new StreamResult(strWtr);
            TransformerFactory tfac = TransformerFactory.newInstance();
            try {
                Transformer t = tfac.newTransformer();
                t.setOutputProperty(OutputKeys.ENCODING, "iso-8859-1");
                t.setOutputProperty(OutputKeys.INDENT, "yes");
                t.setOutputProperty(OutputKeys.METHOD, "xml"); //xml, html, text
                t.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
                t.transform(new DOMSource(document.getDocumentElement()), strResult);
            } catch (Exception e) {
                System.err.println("XML.toString(Document): " + e);
            result = strResult.getWriter().toString();
        return result;
    }//toString()

Convert document into string with unicode

I want to convert my document into string with all <,>,& to be converted into <, >, and &. When I am doing transformation, I am getting <,> etc.
Can anybody suggest me how to do that.
regards,
Ranjan

I don't know of any way to tell the parser to convert is for you, you'll have to replace the characters yourself after you got the string from the parser.
Aviran
http://www.aviransplace.com

Convert Document to String ? (Java 1.3 compatible)

Hi folks,
hope you can help me out. I'm trying to convert a Document to String and my code must be compatible with Java 1.3.
Using Java 1.5 this code is working:
public static String string_output(Document doc){
          String content = "";
          try{
               //Console output
               TransformerFactory tranFactory = TransformerFactory.newInstance();
               Transformer aTransformer = tranFactory.newTransformer();
               Source src = new DOMSource(doc);
               StringWriter stringWriterOutput=new StringWriter();
               Result dest = new StreamResult(stringWriterOutput);
               aTransformer.transform(src,dest);
               content = stringWriterOutput.toString();
          catch (Exception e){
               System.out.println(e.getMessage());
          return contenat;
     }     But I can't use this code in Java 1.3. What can I do (except using a higher Java version)

I think the default transform is the only standard way of converting a Document to a String.
Xerces has a class that does the job: org.apache.xml.serialize.DOMSerializer

Converting XML Document to String

Dear All,
I am quite new to Java Web Services. I have made a Java Class which calls all the web services . I am displaying the results on a Command prompt. Below is my sample code:
import javax.xml.rpc.Service;
import javax.xml.rpc.Stub;
import horusWS.Horus_x0020_Web_x0020_Services_Impl;
import horusWS.Horus_x0020_Web_x0020_ServicesSoap;
public class JavaClient {
public static void main(String[] args)
Horus_x0020_Web_x0020_Services_Impl service = new Horus_x0020_Web_x0020_Services_Impl();
Horus_x0020_Web_x0020_ServicesSoap port = service.getHorus_x0020_Web_x0020_ServicesSoap();
String str;
str = port.getTextFeedbackLearner(1,"P001",1);
//where getTextFeedbackLearner is the my Web Service.
System.out.println(str);
System.out.println returns the web service in string format. Now I want to compare this string to my actual getTextFeedbackLearner.xml file. But I think I need to convert getTextFeedbackLearner.xml to string first. Please let me know
how can I convert an XML Document to String.
Thanking you in Anticipation.
cheers,
Sunil Sabir

You can read the XML document as you read any other file.
Read it into a String variable.
Check java.io.FileReader, java.io.BufferReader, etc.

Using XSL or Keyword Transformation Document

I am attempting to modify an XML document within an IPCC Express script. I have attached the original XML document and what I would like the xml document to look like after it is transformed. I am thinking I could use either an XSL Transform Document or a Keyword Transform Document, but I am having a hard time finding documentation on how to use either of these items.
Thanks,
Brian Corbet

Search through here for "xml". You'll find what you seek.
But for clarity sake, use the key word transform stuff with a template file. What it does is compare the template file with an xml file that you create. And where you specify special keywords in the template, writes variables to your xml document in that place.
Confusing at first but works like champ when you understand it.

SQL - transform a date string

Hello,
I have scenario where I need to transform a date string in SQL (from "yyyy-mm-dd" to "dd/mm/yyyy"):
E.g My table EMPTABLE looks like this
EMPNO STARTDATE(string)
1111 2000-11-30
2222 1998-01-22
I need an output of
EMPNO STARTDATE(string)
1111 30/11/2000
2222 22/01/1998
I know that we can user "to_date" and "to_char" functions to do that. The query would look like:
SELECT EMPNO as EMPNO, to_char(to_date(STARTDATE,'yyyy-mm-dd'),'mm/yy/dddd') as STARTDATE from EMPTABLE;
Are there any other ways to achive this? Like just using string manipulation.
Why I'm asking with the above query if there is any data discrepancy (e.g for one record the month value is 25 by mistake), the query fails.
Any help is appreciated.
Thanks.
Edited by: kIDMan on Nov 20, 2009 7:29 AM

Hi,
Welcome to the forum!
A lot of folks store dates in DATE columns; then it just takes one TO_CHAR call to get them in any format, and invalid data is impossible.
You can use SUBSTR to extact parts of the string, and || to re-assemble them in a different order.
Starting in Oracle 10, you can also use regular expressions, like this:
,     REGEXP_REPLACE ( startdate
                        , '([0-9]{4})-'     ||     -- \1 = year
                              '([0-9]{2})-'     ||     -- \2 = month
                   '([0-9]{2})'          -- \3 = day
                        , '\3/\2/\1'
                        )          AS startdate_dmyIf startdate does not contain the pattern (4 digits, hyphen, 2 digits, hyphen, 2 digits), the the expression above will return startdate unchanged.
Edited by: Frank Kulash on Nov 20, 2009 1:11 PM

Problem in transforming XML to string using XSLT

Hi there,
I have a R/3 -> XI -> WebService scenario where the message from XI to webservice needs to be sent in document/wrapped mode (the message xml must be embedded in a string element) and this message needs to be digitally signed.
We are using another webservice to sign the messages, also with the message being sent in a string. To transform the XML's into string and vice-versa, we are using XSLT (/people/michal.krawczyk2/blog/2005/11/01/xi-xml-node-into-a-string-with-graphical-mapping).
The problem is that both the signer and the final webservice understand the special characters (like '<', '>', '&', '"' etc) in one way but the XSLT generates them in another way. For example, the character '<', in both webservices, is returned as "<" but the XSL Transformation results in "<".
The problem now is that our messages are always being rejected because the signature is not being recognized as true, though we are almost 100% sure that it's being done correctly. The only possibility to the error that we found is this character mapping being done differently.
So, it's like this:
XI sends string to signer as "<"
XI receives string from signer as "<"
XI processes the message
XI sends string to webservice as "<"
XI receives string from webservice (containing error message) as "<"
Is there a way of making the XSLT to return "<" instead of "<"?
Thanks in advace,
Henrique.

For Java Mapping, you can refer this-
/people/prasad.ulagappan2/blog/2005/06/29/java-mapping-part-i
/people/prasad.ulagappan2/blog/2005/06/29/java-mapping-part-ii
/people/prasad.ulagappan2/blog/2005/06/29/java-mapping-part-iii
In Java Mapping, in the startdocument event , you need to check for the specialchars, and just repalce the value required.
But, what i am thinking is , just try with Java functions inside the XSLT mapping instead of going for Java Mapping. You can call java functions from the XSLT. So before the document starts pasring, you need to replace the special characters. I did not try in XSLT like this.
For this , you can think with this e.g
/people/pooja.pandey/blog/2005/06/27/xslt-mapping-with-java-enhancement-for-beginners
Regards,
Moorthy

XSLT transformation of XML string

Hello Everyone,
This is my first endeavor to use XSLT and XML in our newly upgraded system. I can't for the life of me figure out what is wrong with my code and would appreciate someone just glancing over it and pointing out what is likely a realy dumb problem.
I have a program that reads a PEXR2002 IDoc. For testing purposes, I've hardcoded that IDoc number. It runs fine, creates the XML fine, the xslt in STRANS tests fine as well...but in the end my ls_table is blank. I've been fuddling with this for a while and would really appreciate another pair of eyes taking a look at it.
THANKS!!
Greg
My program. (xslt is below...really simple, but it's my first time).
TYPES: BEGIN OF ty_table,
        sndprn LIKE edidc-sndprn,
        bgmref TYPE edif1004_r,
        moabetr TYPE edif5004_a,
        credat TYPE edidat8,
        datum TYPE edidat8,
      END OF ty_table.
DATA: o_idoc TYPE REF TO cl_idoc_xml1, str type string, ls_table type ty_table.
CREATE OBJECT o_idoc
EXPORTING
    docnum = '0000000000211014'.
CALL METHOD o_idoc->get_xmldata_as_string
IMPORTING
    data_string = str.
CALL TRANSFORMATION ZUSL_PEXR2002_V1
SOURCE XML str
RESULT HEADER_DATA = ls_table.
My XSLT....
<xsl:transform
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:asx="http://www.sap.com/abapxml"
    xmlns:sap="http://www.sap.com/sapxsl" version="1.0">
<xsl:strip-space elements="*"/>
<xsl:template match="/">
    <asx:abap version="1.0">
      <asx:values>
        <HEADER_DATA>
          <SNDPRN>
            <xsl:value-of select="PEXR2002/IDOC/EDI_DC40/SNDPRN"/>
          </SNDPRN>
          <BGMREF>
            <xsl:value-of select="PEXR2002/IDOC/E1IDKU1/BGMREF"/>
          </BGMREF>
          <MOABETR>
            <xsl:value-of select="PEXR2002/IDOC/E1IDKU5/MOABETR"/>
          </MOABETR>
          <CREDAT>
            <xsl:value-of select="PEXR2002/IDOC/EDI_DC40/CREDAT"/>
          </CREDAT>
          <DATUM>
            <xsl:value-of select="PEXR2002/IDOC/E1EDK03/DATUM"/>
          </DATUM>
        </HEADER_DATA>
      </asx:values>
    </asx:abap>
</xsl:template>
</xsl:transform>

Hi Greg,
please try it with the following (just slightly) modified transformation (works fine for me):
<xsl:transform xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
               xmlns:asx="http://www.sap.com/abapxml"
               xmlns:sap="http://www.sap.com/sapxsl"
               version="1.0">
<xsl:strip-space elements="*"/>
<xsl:template match="/PEXR2002/IDOC">
    <asx:abap version="1.0">
      <asx:values>
        <HEADER_DATA>
          <SNDPRN>
            <xsl:value-of select="EDI_DC40/SNDPRN"/>
          </SNDPRN>
          <BGMREF>
            <xsl:value-of select="E1IDKU1/BGMREF"/>
          </BGMREF>
          <MOABETR>
            <xsl:value-of select="E1IDKU5/MOABETR"/>
          </MOABETR>
          <CREDAT>
            <xsl:value-of select="EDI_DC40/CREDAT"/>
          </CREDAT>
          <DATUM>
            <xsl:value-of select="E1EDK03/DATUM"/>
          </DATUM>
        </HEADER_DATA>
      </asx:values>
    </asx:abap>
</xsl:template>
</xsl:transform>
I recommend to test all transformations that you define on a sample source and check the output. If you apply your original transformation you would see that it basically doesn't select anything and therefore you just get an XML document with the field names but no values.
Cheers, harald

XML Document to String - Line Separator problem

I�m facing a problem with line separator while converting a Document object to String.
Scenario: I get an input XML having line separator say \n (hex: 0A).
When I create the output XML using Transformer, the line separator is still \n.
I have a requirement which makes me convert the transformed Stream into a Document.
When I try to get the String/bytes from the Document, my line separator is now �\r\n�(hex 0D0A), which is my system�s System property �line-separator�.
I want to keep the line separator same as that was in input string. So, if the input has the separator has \n, output should have the separator as �\n� and if the input has it as �\r\n�, output should have the same.
i.e. my hex output should match the hex input.
Any pointers in the direction are welcome.
Thanks in advance.

Can I infer that the parser has changed my document
line separators when I load it into a Document?
If yes, is there a way to prevent that from
happening?I don't really know. Since the XML recommendation says that a parser "MUST" do line-break normalization, I would expect that it does. And I wouldn't design systems that use specific non-XML-approved line endings as a feature, either.

Document to String

Hello all,
I need in my program create very simple xml-like document (1 node without any attributes, few childs without attributes only string values). The easiest way is String concatination, but I want more flexible sollution. So, I desided to use xml packages that are in standart 1.4 jdk, without using any libraries. I'm using now org.w3c.dom.Document
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document doc = db.newDocument();
Element body = doc.createElement("body");
body.appendChild(doc.createElement("elem1"));
Now I need to retrive this xml as String, but how? The only sample I found, is XMLUtils class from axis libs, which have method DocumentToString. But may be such functionality can be found in classes that are in standart jdk pacjkages? If not, how can I receive xml as string using this XMLUtils, without header "xml version="1.0" encoding="UTF-8""?
Thanks,
Stan

Hi Stan,
When I was using DOM, I remember having converted my document to a String simply with the "toString()" method ... I know it may sound a bit easy, but have you tried it ?
Else, I don't know if your application has to respect some performance rules, but DOM is one of the worst API in terms of memory consumption.
You should take a look at some other, like XMLBeans if you want a XSD strong related scheme.
Well, I hope you'll find a solution
See ya !

DOM Document to string output... HELP

Currently I am building an XML document using DOM and am requierd to output the generated document as text/String. Is there a method in the API to do this or do I need to parse the document and create the string manually? I'm surprised not to have found such a method, as XML is a text format, and displaying a document as text must be a common requirement.
Thanks in advance,
G Powell

Hi,
if you are using the Crimson implementation you have to cast you Document to a org.apache.crimson.tree.XmlDocument which has a write(OutputStream) method. Write the stream to a file.
If you are using Xerces implementation you have to wrap your Document in a org.apache.xml.serialize.OutputFormat object. Then follow these steps:
OutputFormat format = new OutputFormat((Document)doc);
serializer = new XMLSerializer(format);
serializer.reset();
serializer.setOutputByteStream(out);
serializer.serialize(((Document)doc).getDocumentElement());
Again you are using an OutputStream (out) to write to and then use that to write to file. I think there are other ways of doing this but those are the ones I know.
Hope that helps.

Dom Document to String

Hi!
I am looking for a method to create a String from a Dom Document. I have been searching on the internet but all the methods I have found so far contain some deprecated classes :( . Can anyone help me please?
Thanks in advanced

georgemc wrote:
When I saw [this cartoon|http://xkcd.com/763/], I instantly thought of some of the dancing about you have to do with JAXP sometimes
:-)

XML document - request string

Hi Experts,
Could you please tell me, how to pass XML document as a request string to the webservice scenario. Inside the service, I have to do the schema validation for the request . Please guide me, how to proceed further?
Regards
Sara

Hi SARA,
use following Code written in SAX parsing .this will fulfil your requirment.This handle Special character also.
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.Writer;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.GregorianCalendar;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.xml.parsers.FactoryConfigurationError;
import javax.xml.parsers.ParserConfigurationException;
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;
import org.xml.sax.Attributes;
import org.xml.sax.helpers.DefaultHandler;
import org.xml.sax.SAXException;
import com.sap.aii.mapping.api.StreamTransformation;
import com.sap.aii.mapping.api.StreamTransformationException;
public class SimpleForwardMappingString extends DefaultHandler implements StreamTransformation
     private List m_arlCurrent = new ArrayList();
     private List m_arlBOList = new ArrayList();
     private List m_arlObjectList = new ArrayList();
    public static int counter = 0;
     String listName = "newList";
     public StringBuffer m_totalElementsBuffer = new StringBuffer();
     String startData = "<inCanonStream>";
     String endData = "</inCanonStream>";
     private Map param = null;
     /** Constant Strings used in Forward Mapping */
     public static void main(String args[])
          try {
                  InputStream in = new FileInputStream(new File("C:
Documents and Settings
281152
Desktop
Cannonical12321.xml"));
               OutputStream out = new FileOutputStream(new File("C:
Documents and Settings
281152
Desktop
Cannonical21.xmlOut.xml"));
               SimpleForwardMappingString myMapping = new SimpleForwardMappingString();
          catch (Exception e)
               e.printStackTrace();
     public void execute(InputStream arg0, OutputStream arg1)
     throws StreamTransformationException
          Writer out;
          try
               out = new OutputStreamWriter(arg1, "UTF16");
               /** Building the SAX parser */
               getXMLDoc(arg0, arg1);
               arg1.write(m_totalElementsBuffer.toString().getBytes("UTF16"));
          catch (IOException e)
               System.out.println("Error : io" + e.getMessage());
          catch (Exception e)
               System.out.println("Error :" + e.getMessage());
     /* (non-Javadoc)
@see com.sap.aii.mapping.api.StreamTransformation#setParameter(java.util.Map)
     public void setParameter(Map arg0)
     public void getXMLDoc(InputStream inputStream, OutputStream outputStream)
Defines a factory API that enables applications to configure and
obtain a SAX based parser to parse XML documents. Once an application
has obtained a reference to a SAXParserFactory it can use the
factory to configure and obtain parser instances.
          SAXParserFactory factory = SAXParserFactory.newInstance();
          try
               factory.setNamespaceAware(true);
               factory.setValidating(true);
               SAXParser saxParser = factory.newSAXParser();
Parse the content of the given {@link java.io.InputStream}
instance as XML using the specified
{@link org.xml.sax.helpers.DefaultHandler}.
@param inputstream InputStream containing the content to be parsed.
@param cobject The SAX DefaultHandler to use.
@exception IOException If any IO errors occur.
@exception IllegalArgumentException If the given InputStream is null.
@exception SAXException If the underlying parser throws a
SAXException while parsing.
               saxParser.parse(inputStream, this);
          catch (FactoryConfigurationError e)
               System.out.println("Error");
          catch (ParserConfigurationException e)
               e.printStackTrace();
          catch (SAXException e)
               e.printStackTrace();
          catch (IOException e)
               e.printStackTrace();
     /** ===========================================================
                         Methods Overriding in SAX Default Handler
          ===========================================================
Receive notification of the beginning of the document.
By overriding this method in a subclass to take specific actions
at the beginning of a document (such as allocating the root node
of a tree or creating an output file)
     public void startDocument()throws SAXException
          if(m_totalElementsBuffer.length()>0)
                            m_totalElementsBuffer = new StringBuffer();
                            counter = 0;
          m_totalElementsBuffer.append(m_prologue);
          m_totalElementsBuffer.append(m_nameSpace);
          m_totalElementsBuffer.append(startData);     }
Receive notification of the end of the document.
By overriding this method in a subclass to take specific
actions at the end of a document (such as finalising a tree
or closing an output file)
     public void endDocument()throws SAXException
          m_totalElementsBuffer.append(endData);
          m_totalElementsBuffer.append(m_rootElementEnd);
Receive notification of the start of an element.
By overriding this method in a subclass to take specific
actions at the start of each element (such as allocating
a new tree node or writing output to a file)
     public void startElement(String namespaceURI, String name, String qName, Attributes attrs)
          throws SAXException
          /** If current List is not empty then append node to StringBuffer */
               m_totalElementsBuffer.append("<" + name + ">");
Receive notification of the end of an element.
By overriding this method in a subclass to take specific
actions at the end of each element (such as finalising
a tree node or writing output to a file)
     public void endElement(String uri, String name, String qName) throws SAXException
               m_totalElementsBuffer.append("</" + name + ">");
Receive notification of character data inside an element.
By overriding this method to take specific actions for each
chunk of character data (such as adding the data to a node
or buffer, or printing it to a file)
     public void characters(char buf[], int offset, int len)
          throws SAXException
          String s = new String(buf, offset, len);
          if (null != s && s.length() >0)
               if(s.equalsIgnoreCase("&"))
                     //System.out.println("FOUND AND SYMBOL");
                     String s1 = s.replaceAll("&","_-#_");
                     //System.out.println("s= " +s1);
                     s = s1;
               if(s.equalsIgnoreCase("<"))
                     //System.out.println("FOUND AND SYMBOL");
                     String s1 = s.replaceAll("<","_#-_");
                     //System.out.println("s= " +s1);
                     s = s1;
               m_totalElementsBuffer.append(s);
Thanks
Sunil Singh

Transform Document to String

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