Trying to displaying image in screen.

Question

Hi,
I'm new to this CLDC and MIDP coding. I'm working on this code right now, but I cannot seem to display a image in the screen. All I get is a blue background.
Can someone help me to make the image appear in the screen?
-I think it may have to do with the directories, but I am not sure. I have tried everything possible that I can think of.
Here's my code:
public class Character extends GameCanvas implements Runnable
    private Image image;
    private int xAxis_Image;
    private int yAxis_Image;
    public Character()
        super(true);
    public void gatherImageProperties()
        try
            image = Image.createImage("/example.gif");
        }catch(IOException e)
            System.out.println("e");
        finally{
            Thread thread = new Thread(this);
            thread.start();
    public void run()
        Graphics graphics = getGraphics();
        while(true)
            gameScreenRefresh(getGraphics());
            try{
                Thread.currentThread().sleep(45);
            }catch(Exception e)
                System.out.println(e);
    private void gameScreenRefresh(Graphics g)
        g.setColor(23, 200, 230);
        g.fillRect(0, 0, getWidth(), getHeight());
        g.drawImage(image, xAxis_Image, yAxis_Image, Graphics.HCENTER | Graphics.VCENTER );
        flushGraphics();
}Here's my midlet
public class my_Midlet extends MIDlet
    Character character;
    public my_Midlet()
    public void startApp()
        character = new Character();
        Display display = Display.getDisplay(this);
        character.gatherImageProperties();
        display.setCurrent(character);
    public void pauseApp()
    public void destroyApp(boolean unconditional)
}

Answer 1

image = Image.createImage("C:\Documents and Settings\Owner\Desktop\Graphics\src\graphic_Core\example.gif");{color:#000080}See the documentation for javax.microedition.lcdui.Image.createImage(String name){color}
Creates an immutable image from decoded image data obtained from the named resource. The name parameter is a resource name as defined by Class.getResourceAsStream(name). The rules for resolving resource names are defined in the Application Resource Files section of the java.lang package documentation.
{color:#000080}Refer to the documentation for java.lang{color}
<h5>Application Resource Files</h5>
Application resource files are accessed using getResourceAsStream(String name) in java.lang.Class . In the MIDP specification, getResourceAsStream is used to allow resource files to be retrieved from the MIDlet Suite's JAR file.
Resource names refer to the contents of the MIDlet Suite JAR file. Absolute pathnames, beginning with "/" are fully qualified file names within the jar file.
Relative pathnames, not beginning with "/" are relative to the class upon which getResourceAsStream is called. Relative names are converted to absolute by prepending a "/" followed by the fully qualified package with "." characters converted to "/" and a separator of "/". The resulting string is reduced to canonical form by applying as many times as possible the following:
All occurences of "/./" are replaced with "/".
All occurences of "/segment/../" are replaced with "/" where segment does not contain "/".
The canonical resource name is the absolute pathname of the resource within the JAR.
In no case can the path extend outside the JAR file, and resources outside the JAR file MUST NOT be accessible. For example, using "../../" does NOT point outside the JAR file. If there are any remaining "." or ".." characters they are treated literally in locating the resource. No resource can exist with that name so null is returned from Class.getResourceAsStream. Also, devices MUST NOT allow classfiles to be read from the JAR file as resources, but all other files MUST be accessible.
{color:#000080}Place your image file in the jar, and use it from there.
db{color}