Turning Upload script into multiple upload script

Question

Hi all,
I would like to change the following script so it is able to handle 2 file uploads. With a basic understanding of PHP, this is a bit beyond me and you may laugh and the initial attempt (found at the the bottom of the post).
Here is the original script for one upload:
<?php
//this is the directory where the images images will be saved
$target = "../IMAGES/books/";
$target = $target . basename( $_FILES['imageURL']['name']);
// this gets all the other info from the form
$name=$_POST['name'];
$publication=$_POST['publication'];
$year=$_POST['year'];
$desc=$_POST['description'];
$link=$_POST['linkToBuy'];
$price=$_POST['price'];
$pic=($_FILES['imageURL']['name']);
// Connects to your Database
mysql_connect("localhost:8889", "root", "root") or die(mysql_error()) ;
mysql_select_db("keithMcCarthy") or die(mysql_error()) ;
//Writes the information to the database
mysql_query("INSERT INTO books (name,publication,year,description,linkToBuy,price,imageURL)
VALUES ('$name', '$publication', '$year', '$desc', '$link', '$price', '$pic')") ;
//Writes the photo to the server
if(move_uploaded_file($_FILES['imageURL']['tmp_name'], $target))
          $note['success'] = 'The file '. basename( $_FILES['imageURL']['name']). ' has been uploaded, and your information has been added to the directory';
else {
          //Give an error if it's not
          $note['error'] = 'Sorry, there was a problem uploading your file.';
?>
Here is my attempt - it sends everything to the database but does not upload the file and gives an error "Sorry, there was a problem uploading your file." At leat that is working.
<?php
//this is the directory where the images images will be saved
$target = "../IMAGES/books/";
$targetTwo = "../IMAGES/books/";
$target = $target . basename( $_FILES['imageURL']['name']);
$targetTwo = $target . basename( $_FILES['imageURLtwo']['name']);
// this gets all the other info from the form
$name=$_POST['name'];
$publication=$_POST['publication'];
$year=$_POST['year'];
$desc=$_POST['description'];
$link=$_POST['linkToBuy'];
$price=$_POST['price'];
$pic=($_FILES['imageURL']['name']);
$picTwo=($_FILES['imageURLtwo']['nameTwo']);
// Connects to your Database
mysql_connect("localhost:8889", "root", "root") or die(mysql_error()) ;
mysql_select_db("keithMcCarthy") or die(mysql_error()) ;
//Writes the information to the database
mysql_query("INSERT INTO books (name,publication,year,description,linkToBuy,price,imageURL,imageURLtwo)
VALUES ('$name', '$publication', '$year', '$desc', '$link', '$price', '$pic', '$picTwo')") ;
//Writes the photo to the server
if(move_uploaded_file($_FILES['imageURL']['tmp_name'], $target))
  $note['success'] = 'The file '. basename( $_FILES['imageURL']['name']). ' has been uploaded, and your information has been added to the directory';
else {
  //Give an error if it's not
  $note['error'] = 'Sorry, there was a problem uploading your file.';
if(move_uploaded_file($_FILES['imageURLTwo']['tmp_name'], $targetTwo))
  $note['success'] = 'The file '. basename( $_FILES['imageURLTwo']['name']). ' has been uploaded, and your information has been added to the directory';
else {
  //Give an error if it's not
  $note['error'] = 'Sorry, there was a problem uploading your file.';
?>

Answer 1

Thank you for your help, trulfy!
However, I am so new to all this that I don't really even understand your reply or how to do it...
Maybe you could put it in more simplistic terms/steps?
Thank you anyway!