Ugent: Regarding Oracle 10g Analytic functions

Question

Hi,
EMP TABLE:
EMPNO     ENAME          JOB          MGR          HIREDATE          SAL          COMM     DEPTNO
==================================================================
7369          SMITH          CLERK          7902          12/17/1980     800                    20
7499          ALLEN          SALESMAN          7698          2/20/1981          1600          300          30
7521          WARD          SALESMAN          7698          2/22/1981          1250          500          30
7566          JONES          MANAGER          7839          4/2/1981          2975                    20
7654          MARTIN          SALESMAN          7698          9/28/1981          1250          1400          30
7698          BLAKE          MANAGER          7839          5/1/1981          2850                    30
7782          CLARK          MANAGER          7839          6/9/1981          2450                    
7788          SCOTT          ANALYST          7566          12/9/1982          3000                    20
7839          KING          PRESIDENT                    11/17/1981     5000                    
7844          TURNER          SALESMAN          7698          9/8/1981          1500          0          30
7876          ADAMS          CLERK          7788          1/12/1983          1100                    20
7900          JAMES          CLERK          7698          12/3/1981          950                    30
7902          FORD          ANALYST          7566          12/3/1981          3000                    20
7934          MILLER          CLERK          7782          1/23/1982          1300                    
================================================================
I would like the output group by manger and the employees under that manager using analytic functions.
Output should look like:
ManagerName EMPNAME
==========================================================
KING JONES,BLAKE,CLARK
JONES SCOTT,FORD
BLAKE ALLEN,WARD,MARTIN,TURNER,JAMES
CLARK MILLER
FORD SMITH
SCOTT ADAMS
Also I would like to run this query in unix shell script in order to create a folder structure like this:
Root Folder: King -> Jones -> SCOTT -> ADAMS
-> FORD -> SMITH
-> BLAKE -> ALLEN
-> WARD
-> MARTIN
-> TURNER
-> JAMES
-> CLARK -> MILLER
On a total 14 folders should be created.
Thanks in Advance
G.Vamsi Krishna
Edited by: user10733211 on Apr 20, 2009 11:30 PM

Answer 1

user10633982 wrote:
hey guys can you please give your personal opinions and remarks out of this thread.
this thread is supposed to be solving query and not for chit chattingNot chit chatting and not just personal opinions, just letting you know how it works around here...
Urgent is it?
Why? Have you forgotten to do your coursework and you'll get thrown off your course if you don't hand it in today?
What makes you believe that your request for help is more important than someone else who has requested help? It's very rude to assume you are more important than somebody else, and I'm sure they would like an answer to their issue as soon as they can get one too, but they've generally been polite and not demanded that it is urgent.
Also, you assume that people giving answers are all sitting here just waiting to answer your question for you. That's not so. We're all volunteers with our own jobs to do. How dare you presume to demand our attention with urgency.
If you want help and you want it answering quickly you simply just put your issue forward and provide as much valuable information as possible.
You will find if you post on here demanding your post is urgent then most people will just ignore it, some will tell you to get lost, and some will explain to you why you shouldn't post "urgent" requests. Occasionally you may find somebody who's got nothing better to do who will actually provide you with an answer, but you really are limiting your options by not asking properly.
How can something being run against the SCOTT schema be something that is "urgent"?
For the first part of your enquiry:
SQL> ed
Wrote file afiedt.buf
  1  with emps as (select ename, mgr, row_number() over (partition by mgr order by ename) as rn from emp)
  2  select ename as managername
  3        ,(select ltrim(sys_connect_by_path(emps.ename,','),',')
  4          from   emps
  5          where emps.mgr = emp.empno
  6          and connect_by_isleaf = 1
  7          connect by rn = prior rn + 1 and mgr = prior mgr
  8          start with rn = 1
  9         ) as empname
10  from emp
11* where empno in (select mgr from emp)
SQL> /
MANAGERNAM EMPNAME
JONES      FORD,SCOTT
BLAKE      ALLEN,JAMES,MARTIN,TURNER,WARD
CLARK      MILLER
SCOTT      ADAMS
KING       BLAKE,CLARK,JONES
FORD       SMITH
6 rows selected.
SQL>As for using that output in a unix shell script to create directory structures you should consider asking in a unix forum.