Unable to copy database with different name in the same instance

Question

I had a huge database and wanted to try some change optimization changes.
So wanted to make a copy of the database along with data in the same instance.
I have tried copy database wizard several times but always see the error as in attachment.
Can someone let me know how to troubleshoot further?
If this is not the correct way please suggest how do i copy a database with different name in the same instance along with data.

Answer 1

Hi Nandu,
From the screenshot, the error 1813 happens when corrupt database log is attempted to attach to the SQL Server. To work around this issue, please preform the following steps, for more details, please review this
blog.
1. Create a new database with same name which you want to recover. Make sure that the MDF file and LDF file have same name with previous database data and log file.
2. Stop SQL Server. Move original MDF file from old location to new location by replacing just created MDF file. Delete the LDF file of new location just created.
3. Start SQL Server. At this point, the database is in suspect status.
4. Make sure that system tables of Master database allows to update the values. Please note that you will be performing this in query window.
Use Master
go
sp_configure 'allow updates',1
reconfigure with override
go
5. Change database mode to emergency mode.
SELECT *
FROM sysdatabases
WHERE name = 'DatabaseName'
BEGIN
UPDATE sysdatabases
SET status = 32768
WHERE name = ' DatabaseName '
COMMIT TRAN
6. Restart SQL Server. Then execute the following DBCC command in query window to create new log file.
DBCC TRACEON (3604)
DBCC REBUILD_LOG(databasename,'c:\yourdatabasename_log.ldf')
GO
7. Reset the database status using following command.
sp_RESETSTATUS yourdatabasename
GO
8. Turn off the update to system tables of Master database running following script.
USE MASTER
GO
sp_CONFIGURE 'allow updates',0
RECONFIGURE WITH OVERRIDE
GO
9. Reset the database status to previous status.
BEGIN
UPDATE sysdatabases
SET status = (value retrieved in first query of step 5)
WHERE name = 'DatabaseName‘
COMMIT TRAN
GO
Make sure that you have done all the steps in order and restarted SQL Server where it is mentioned. Also run SQL Server Management Studio as administrator.(Right click-> Run as Administrator)
Thanks,
Lydia Zhang