Unzipping a .ruf file

I've been trying to download an update for the firmware on my Kenwood car stereo. The downloaded file has a .ruf extension and the instructions from Kenwood's website tell you to unzip the file then burn it to CD. Unfortunately, I am having difficulty opening or unzipping the file and being a newbie to all things Mac-related I'm not sure what to do! Any help or advice would be most appreciated.

The downloaded file has a .ruf extension and the instructions from Kenwood's website tell you to unzip the file then burn it to CD.
If you are seeing .ruf at the end of the file name instead of .zip, then it may have already been unzipped and you should go to the next step.

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Problem in unzipping the zip files

Hi,
I have created a program to unzip the zip files. But when i try to zip it is creating the zipped files outside the folder where it is to be zipped.
what is wrong with my code.
if the zip file is migration.zip
if the path inside the zip file shows
and the path inside says this
/codebase/scripts/
it would create migration folder and create codebase folder outside the migration folder
what is wrong with my code
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
          String ext;
          public zipper(String ext)
               this.ext="." + ext;
          public boolean accept(File dir,String name)
               return name.endsWith(ext);
public static void main(String args[]) throws IOException
          try
                    String dir = "D:/a/";
                    File f2 = new File(dir);
                    FilenameFilter fn= new zipper("zip");
                    String ss[]=f2.list(fn);
               for ( int j = 0; j < ss.length; j++)
                    System.out.println(" Extracting ...." + ss[j]) ;
                    String zipFile = dir + ss[j];
                    ZipFile zf = new ZipFile(zipFile);
                    Enumeration entries = zf.entries();
                    String directoryName = zf.getName();
                    directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
                         String folderName = zf.getName();
                         folderName = folderName.substring(0, folderName.lastIndexOf("."));
                         File file1 = new File(folderName);
                         //File file1 = new File(entries.getName());
                         file1.mkdir();
               while (entries.hasMoreElements())
                         ZipEntry ze = (ZipEntry) entries.nextElement();
                         String path = directoryName + ze.getName() ;
                         String path1 = folderName + ze.getName();
                         //System.out.println(" : " + path);
                         if (ze.getName().endsWith("/"))
                                   File file = new File(path);
                                   file.mkdir();
                                   continue;
                                   //break;
                    BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
     StringBuffer fileBuffer = new StringBuffer(" ");
     String line ;
                    while ((line = bReader.readLine()) != null)
                              fileBuffer.append(line);
                              fileBuffer.append("\r\n");
                              //line = line + "\r\n";
                              //byte[] b = new byte[line.length()];
                              //b =line.getBytes();
                              //out.write();
                    String fileData = fileBuffer.toString();
     File f1 = new File(path);
                    f1.createNewFile();
                    //FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
                    FileOutputStream out = new FileOutputStream(path);
                    long size = ze.getSize();
                    byte[] data1 = new byte[fileData.length()];
                    for (int i = 0; i < fileData.length(); i++)
                              data1[i] = (byte) fileData.charAt(i);
     out.write(data1);
     out.close();
                    bReader.close();
               } catch (Exception e)
                         e.printStackTrace();
Thanks in Advance
Avinash

String path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path

Problem in Unzipping the zip file

Hi
I have created a program to unzip the zip files in the folder named after the zip file
it is working well well when u try to zip zip files put in a directory
i.e u create a folder name contents and put files into that and then zip it
but when u directly create a zip file , without putting in a folder
it creates the folder and zip the files outside the folder
Another problem is that with the path
for e.g. suppose the zip file name is contents and path should show
contents/filename.txt but there are some other files whose path shows
res/file.txt. In this case it creates a folder of res and put it outside the
folder with the name of zip file
I have pasted my code :
//Unzip the zip files to the folder with their name
import java.io.BufferedReader;
import java.io.File;
import java.io.FileOutputStream;
import java.io.FilenameFilter;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.Enumeration;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
// Getting the path to find the type of files
public class zipper implements FilenameFilter{
          String ext;
          public zipper(String ext)
               this.ext="." + ext;
          public boolean accept(File dir,String name)
               return name.endsWith(ext);
public static void main(String args[]) throws IOException
          try
                    String dir = "D:/";
                    File f2 = new File(dir);
                    FilenameFilter fn= new zipper("zip");
                    String ss[]=f2.list(fn);
               for ( int j = 0; j < ss.length; j++)
                    System.out.println(" Extracting ...." + ss[j]) ;
                    String zipFile = dir + ss[j];
                    ZipFile zf = new ZipFile(zipFile);
                    Enumeration entries = zf.entries();
                    String directoryName = zf.getName();
                    directoryName = directoryName.substring(0, (directoryName.indexOf(":" + File.separator) + 2));
                         String folderName = zf.getName();
                         folderName = folderName.substring(0, folderName.lastIndexOf("."));
                         File file1 = new File(folderName);
                         //File file1 = new File(entries.getName());
                         file1.mkdir();
               while (entries.hasMoreElements())
                         ZipEntry ze = (ZipEntry) entries.nextElement();
                         String path = directoryName + ze.getName() ;
                         String path1 = folderName + ze.getName();
                         //System.out.println(" : " + path);
                         if (ze.getName().endsWith("/"))
                                   File file = new File(path);
                                   file.mkdir();
                                   continue;
                                   //break;
                    BufferedReader bReader = new BufferedReader(new InputStreamReader(zf.getInputStream(ze)));
     StringBuffer fileBuffer = new StringBuffer(" ");
     String line ;
                    while ((line = bReader.readLine()) != null)
                              fileBuffer.append(line);
                              fileBuffer.append("\r\n");
                              //line = line + "\r\n";
                              //byte[] b = new byte[line.length()];
                              //b =line.getBytes();
                              //out.write();
                    String fileData = fileBuffer.toString();
     File f1 = new File(path);
                    f1.createNewFile();
                    //FileOutputStream out = new FileOutputStream(folderName + "/" + ze.getName());
                    FileOutputStream out = new FileOutputStream(path);
                    long size = ze.getSize();
                    byte[] data1 = new byte[fileData.length()];
                    for (int i = 0; i < fileData.length(); i++)
                              data1[i] = (byte) fileData.charAt(i);
     out.write(data1);
     out.close();
                    bReader.close();
               } catch (Exception e)
                         e.printStackTrace();
Thanks in Advance
Avinash

String path = directoryName + ze.getName();
String path1 = folderName + File.separator+ ze.getName();
File f1 = new File(path); // pass path1 instead of path
f1.createNewFile();
FileOutputStream out = new FileOutputStream(path); // pass path1 instead of path

Unzipping a jar file

how do Unzip a jar file?

You can unjar a file giving
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Unzip multiple bzip files thru powershell

Hello there-
I have 50 directories. Each directory has 10 sub directories in which there are 300 bz2 files. I would like to unzip them thru bzip program. Is it possible to do so with powershell/batch/cmd line script?
Dir1>Subdir1>*.bz2
      >Subdir2>*.bz2
      >Subdir10>*.bz2
Dir2>Subdir1>*.bz2
      >Subdir2>*.bz2
      >Subdir10>*.bz2
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Hi,
To unzip files, I would like suggest you refer below code, those code is to find all current location zip files and unzip them to the current location:
$shell=new-object -com shell.application
$CurrentLocation=get-location
$CurrentPath=$CurrentLocation.path
$Location=$shell.namespace($CurrentPath)
$ZipFiles = get-childitem *.zip
$ZipFiles.count | out-default
foreach ($ZipFile in $ZipFiles)
$ZipFile.fullname | out-default
$ZipFolder =
$shell.namespace($ZipFile.fullname)
$Location.Copyhere($ZipFolder.items())
If you want to unzip many location files, we could use get-childitem to get all of them and saved in a variable.
For more details, please refer to the below link:
PowerShell script to unzip many files
http://www.techiebirdsnest.com/2009/01/powershell-script-to-unzip-many-files.html
Hope this helps.
Regards,
Yan Li
Yan Li
TechNet Community Support

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The UnArchiver
http://theunarchiver.googlecode.com/files/TheUnarchiver2.7.1.zip

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I can't unzip the zipped disk 1 files for the installation of Oracle 9i database. I find no programme for the unzip of the files with the file extention .cpio

Hi Hugo,
1) Create directories to extract the files { say
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2) cd Disk1
3) cpio -idmv < filename.cpio
or
cpio -idmv < filename.cpio.gz
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How to Unzip EBS software files into directory on linux

Hi,
I am trying to unzip the Software file which i 've downloaded from eDelivery on /u01 directory to /u01/Rstage/directroy
when i execute the command under /u01 directory in order to unzip all the zip under /u01 to /u01/Rstage directory. I get the following Error
unzip .zip -d Rstage/*
-bash: unzip: command not found
*[root@22 u01]# gunzip *.zip -d Rstage/*
gunzip: V32251-01.zip: unknown suffix -- ignored
gunzip: V32252-01.zip: unknown suffix -- ignored
gunzip: V32253-01.zip: unknown suffix -- ignored
gunzip: V32254-01.zip: unknown suffix -- ignored
gunzip: V32255-01.zip: unknown suffix -- ignored
gunzip: V32256-01.zip: unknown suffix -- ignored
gunzip: V32257-01.zip: unknown suffix -- ignored
gunzip: V32258-01.zip: unknown suffix -- ignored
gunzip: V32259-01.zip: unknown suffix -- ignored
gunzip: V32260-01.zip: unknown suffix -- ignored
gunzip: V32261-01.zip: unknown suffix -- ignored
gunzip: V32262-01.zip: unknown suffix -- ignored
gunzip: V32263-01.zip: unknown suffix -- ignored
gunzip: V32264-01.zip: unknown suffix -- ignored
gunzip: V32265-01.zip: unknown suffix -- ignored
gunzip: V32266-01.zip: unknown suffix -- ignored
gunzip: V32267-01.zip: unknown suffix -- ignored
gunzip: Rstage/ is a directory -- ignored
Does the above error mean the RPM of zip isn't there on linux or command syntax is wrong ?
Could you plz tell if its the right way to unzip all the files into /directory ?
Thanks & Regards
MZ

Try any of below two option:-
unzip ‘*.zip’ -- *.zip in single quotes.
or
through single shell command:-
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Thanks,
JD

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Stuffit Expander Mac

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Ensure that the file is a valid zip file and it is
accessible. Cause : java.util.zip.ZipException: error in opening
zip file
I can open the zip file through windows with no issue so this
has to do with what CF uses to open the file. I also extracted the
files in the zip file and then created a new zip file on my own and
CF can unzip that file fine as well.
Does ftp'ing a file cause some kind of change with the file
that would cause the exception?

jsg1000 wrote:
> When I try to unzip a zip file that was FTP'd to my
server I get an error:
>
> Ensure that the file is a valid zip file and it is
accessible. Cause :
> java.util.zip.ZipException: error in opening zip file
>
> I can open the zip file through windows with no issue
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file ? FTP files can be transferred in 2 modes: ascii and
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> Does ftp'ing a file cause some kind of change with the
file that would cause
> the exception?
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Mack

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It may help you to know how I add JARs
1. I open my Project (myProject)
2. I Mount the JAR to the FileSystem (like mypackages.jar = which includes com.mus.de.myClass.java)
3. I Mount the File to the FileSystem (like c:\..myfiles..\myProject)
3.1 I add the File to my Project
4. I select File | New -> Classes | Main
4.1 I typed "import com.mus.de.myClass.java" to refer to this package.
4.2 I called some of the public methods
thats it
Andreas

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thanking you

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Thanks & Regards
Bikash

this thread has some code
http://forum.java.sun.com/thread.jsp?forum=31&thread=417611
asjf

Unzipping a .ruf file

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