Update a column in each row in my table that have similar values in another column

Hi All,
I have a table in my DB.
This table has values like this:
Name
Key
a
1
a
2
a
3
a
2
b
4
b
5
b
5
I need to change the name to a different name for keys that are different. For same keys, the name must be same.
Here I need to rename the 'a' to different name, but make sure that the 'a' that have 2 as the key have same name .
Similarly, i've to rename the 'b' to different name , but make sure that the 'b' that have 5 as the key have the same name.
How can I achieve this in sql? I dont know how to use cursor and complex queries, as i'm new to SQL.
Please help
Thanks,
Vid
Vidya Suryanarayana

Ok. The output should be like this:
Note here, that the names with same keys have same names.
name
key
a1
1
a2
2
a3
3
a2
2
b1
4
b2
5
b2
5
Thanks,
Vid
Vidya Suryanarayana

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Create a new column in a table that compares the value of one column with its previous value

The DDL:
DECLARE
@T TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
DECLARE
@K TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
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INTO @T
VALUES(22,'C_V_Harris','2014-01-02 10:23:49.0000000',
23.335,
23.347)
INSERT
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23.369)
INSERT
INTO @T
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VALUES(19,'C_V_Harris','2014-01-02 09:45:26.0000000',
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INSERT
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INSERT
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SELECT
ROW_NUMBER()
OVER (ORDER
by IDNO)
AS RN,*
FROM
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SELECT
* FROM
@K
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SELECT
a.RN,a.Price2
FROM
@K a
INNER
JOIN @K
b
ON
a.RN=b.RN-1
WHERE
a.Price2>b.Price2
I need to create a view with a column (say 'Comp' below) that compares the value of each row in Price2 with the previous Price2 row, and it is greater then +1, the
same 0, and less -1.
The processed table should be:
IDNO
name
Date
Price1
Price2
Comp
22
C_V_Harris
1/2/2014 10:23:49
23.335
23.347
0
21
C_V_Harris
1/2/2014 10:05:13
23.357
23.369
1
20
C_V_Harris
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23.377
1
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C_V_Harris
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-1
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23.396
1
17
C_V_Harris
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23.455
23.468
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16
C_V_Harris
1/2/2014 9:30:37
23.474
23.486
1
15
C_V_Harris
1/2/2014 9:18:12
23.419
23.431
-1
14
C_V_Harris
1/2/2014 9:16:06
23.36
23.374
-1
How can I structure the statement to get (the most recent - order by date ) result for Comp?

Satheesh Variath, I just had to make some corrections from your script to get the correct answer:
CREATE
VIEW vw_Comp
AS
SELECT
TOP 1 t.IDNO,t.name,t.[Date],t.Price1,t.Price2,
CASE
WHEN t.Price2
> LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNO)
THEN 1
WHEN t.Price2
< LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNo)
THEN -1
ELSE 0
END
AS Comp
FROM
@T t
ORDER
BY DATE
DESC
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Please post DDL, so that people do not have to guess what the keys, constraints, Declarative Referential Integrity, data types, etc. in your schema are. Learn how to follow ISO-11179 data element naming conventions and formatting rules. You have no idea,
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CREATE TABLE Foobar
(something_seq INTEGER NOT NULL PRIMARY KEY,
onhand_qty INTEGER NOT NULL);
Learn how to use the SUM()OVER() and LAG() aggregate functions, post what you tried for yourself and then we will help you.
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in Sets / Trees and Hierarchies in SQL

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