Create a new column in a table that compares the value of one column with its previous value

Question

The DDL:
DECLARE
@T TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
DECLARE
@K TABLE
IDNO
int,
name
varchar(40),
[Date]
datetime2,
Price1
float,
Price2
float
INSERT
INTO @T
VALUES(22,'C_V_Harris','2014-01-02 10:23:49.0000000',
23.335,      
23.347)
INSERT
INTO @T
VALUES(21,'C_V_Harris','2014-01-02 10:05:13.0000000',
23.357,      
23.369)
INSERT
INTO @T
VALUES(20,'C_V_Harris','2014-01-02 09:56:15.0000000',
23.364,      
23.377)
INSERT
INTO @T
VALUES(19,'C_V_Harris','2014-01-02 09:45:26.0000000',
23.351,      
23.367)
INSERT
INTO @T
VALUES(18,'C_V_Harris','2014-01-02 09:43:20.0000000',
23.380,      
23.396)
INSERT
INTO @T
VALUES(17,'C_V_Harris','2014-01-02 09:34:28.0000000',
23.455,      
23.468)
INSERT
INTO @T
VALUES(16,'C_V_Harris','2014-01-02 09:30:37.0000000',
23.474,      
23.486)
INSERT
INTO @T
VALUES(15,'C_V_Harris','2014-01-02 09:18:12.0000000',
23.419,      
23.431)
INSERT
INTO @T
VALUES(14,'C_V_Harris','2014-01-02 09:16:06.0000000',
23.360,      
23.374)
INSERT
INTO @K
SELECT
ROW_NUMBER()
OVER (ORDER
by IDNO)
AS RN,*
FROM
@T
SELECT
* FROM
@K
--not working:
SELECT
a.RN,a.Price2
FROM
@K a
INNER
JOIN @K
b
ON
a.RN=b.RN-1
WHERE
a.Price2>b.Price2
I need to create  a view with a column (say 'Comp' below) that compares the value of each row in Price2 with the previous Price2 row, and it is greater then +1, the
same 0, and less -1.
The processed table should be:
IDNO
name
Date
Price1
Price2
Comp
22
C_V_Harris
1/2/2014 10:23:49
23.335
23.347
0
21
C_V_Harris
1/2/2014 10:05:13
23.357
23.369
1
20
C_V_Harris
1/2/2014 9:56:15
23.364
23.377
1
19
C_V_Harris
1/2/2014 9:45:26
23.351
23.367
-1
18
C_V_Harris
1/2/2014 9:43:20
23.38
23.396
1
17
C_V_Harris
1/2/2014 9:34:28
23.455
23.468
1
16
C_V_Harris
1/2/2014 9:30:37
23.474
23.486
1
15
C_V_Harris
1/2/2014 9:18:12
23.419
23.431
-1
14
C_V_Harris
1/2/2014 9:16:06
23.36
23.374
-1
 How can I structure the statement to get (the most recent - order by date ) result for Comp?

Answer 1

Satheesh Variath, I just had to make some corrections from your script to get the correct answer:
CREATE
VIEW vw_Comp
AS
SELECT
TOP 1 t.IDNO,t.name,t.[Date],t.Price1,t.Price2,
CASE
WHEN t.Price2
> LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNO) 
THEN 1
WHEN t.Price2
< LAG(Price2,1)
OVER (PARTITION
BY name
ORDER BY IDNo) 
THEN -1
ELSE 0
END
AS Comp
FROM 
@T t
ORDER
BY DATE
DESC
The adjustments: the selection of the most recent comparison (Top 1) and the use of the function LAG (instead of LEAD) to get the previous value of the column.