Updating table from stored procedure in TimesTen

Question

Hi experts,
I am unable to update table from procedure; here is what I did -
Created and populated table -
Command> create table test_table(key integer,value integer);
Command> insert into test_table values(1,10);
1 row inserted.
Command> insert into test_table values(2,20);
1 row inserted.
Command> insert into test_table values(3,30);
1 row inserted.
Command> select * from test_table
> ;
< 1, 10 >
< 2, 20 >
< 3, 30 >
created procedure -
Command> create or replace procedure testtable_update(key integer,value integer) as
> begin
> update test_table set test_table.value = value where test_table.key = key;
> end;
> /
Procedure created.
Executed procedure -
Command> begin
> testtable_update(3,60);
> end;
> /
PL/SQL procedure successfully completed.
Command> select * from test_table
> ;
< 1, 10 >
< 2, 20 >
< 3, 30 >
I am not seeing update, in underlying table. What could be the reason for this?
If I do following it works -
Command> update test_table set test_table.value = 60 where test_table.key = 3;
1 row updated.
Command> select * from test_table;
< 1, 10 >
< 2, 20 >
< 3, 60 >
3 rows found.
Am I missing something?
Any pointers or help will be greatly appreciated.
Thanks

Answer 1

The problem is that the parameter names in your procedure are the same as the column names, hence the columns are being updated with the same values. You have two options:
1. Change the names of the parameters by adding a prefix. For example:
create or replace procedure testtable_update( p_ key integer,*p_* value integer)
begin
update test_table set test_table.value = p_ value where test_table.key = p_ key;
end;
2. Qualiflying the parameters with the procedure name.
create or replace procedure testtable_update(key integer,value integer)
begin
update test_table set test_table.value = testtable_update. value where test_table.key = testtable_update. key;
end;
Simon