URL openStream problem. URL String length

Hi,
My problem is about length of the url string. I'm simply creating a URL and trying to call openStream() to get content. But if the length of url string exceeds 118 characters, I'm getting an exception. It says Server returned Http response code 505.
If I try the same url string in a browser it's working.
Thanks for all replies in advance...

the problem solved, it was about white space not length... I didn't notice the white space there sorry!

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URL.openStream() works in Windows but not in Linux

I am having a problem with this line:
BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
in the code sample further below.
A simple program using this line works when compiled in my Windows XP:
java version "1.6.0_03"
Java(TM) SE Runtime Environment (build 1.6.0_03-b05)
Java HotSpot(TM) Client VM (build 1.6.0_03-b05, mixed mode, sharing)
but not when compiled on my RedHat FC 4 server:
java version "1.4.2"
gij (GNU libgcj) version 4.0.2 20051125 (Red Hat 4.0.2-8)
The program (making using of a previous froum example and pared down to minimize tangent topics):
The code works for all 3 URLs in Windows. In Linux it only works for the 1st one (bbc.co site)
Error is listed below the code:
import java.net.*;
import java.io.*;
public class BBC {
public static void main(String[] args) throws Exception
//    URL url = new URL("http://news.bbc.co.uk/sport1/hi/football/eng_prem/6205747.stm");
//    URL url = new URL("http://www.weatherunderground.com/global/stations/71265.html");
    URL url = new URL("http://www.weatherunderground.com");
    BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream()));
    int nLineCnt = 0;
    String inputLine;
    while ((inputLine = in.readLine()) != null)
        nLineCnt++;
    System.out.println("nLineCnt=" + nLineCnt);
//--------------------------------------------------------------------------------------------------------------------------------------------Exception in thread "main" java.lang.StringIndexOutOfBoundsException
at java.lang.String.substring(int, int) (/usr/lib/libgcj.so.6.0.0)
at gnu.java.net.protocol.http.Request.readResponse(gnu.java.net.LineInputStream) (/usr/lib/libgcj.so.6.0.0)
at gnu.java.net.protocol.http.Request.dispatch() (/usr/lib/libgcj.so.6.0.0)
at gnu.java.net.protocol.http.HTTPURLConnection.connect() (/usr/lib/libgcj.so.6.0.0)
at gnu.java.net.protocol.http.HTTPURLConnection.getInputStream() (/usr/lib/libgcj.so.6.0.0)
at java.net.URL.openStream() (/usr/lib/libgcj.so.6.0.0)
at BBC.main(java.lang.String[]) (Unknown Source)
at gnu.java.lang.MainThread.call_main() (/usr/lib/libgcj.so.6.0.0)
at gnu.java.lang.MainThread.run() (/usr/lib/libgcj.so.6.0.0)
Can anyone please suggest what I can do to be able to process the weatherunderground URL?
Claude

To me it would suggest a bug in the VM that you are using.
Solutions
1. Use a different VM
2. Write your own code to process the http code. Depending on licensing for the VM in use and the VM itself. you might be
able to find the bug in that code, fix it yourself, and then use your fix (start up command line options for VM.) Otherwise
you have to duplicate the functionality. You might look to jakarta commons, there might be code there that does that.

JSP bug? url.openStream() = server redirected too many times

I tried something the other day that works in Java, so it should work as a JSP scriptlet, but I received an error message that others have posted elsewhere without a compete resolution. Specifically, given a URL, say u, one ought to be able to do u.openStream() and eventually read the remote page. Typically, one might want to try
URL u = new URL("http://someserver.com/path/file.xxx")
BufferedReader bfr = new BufferedReader(new InputStreamReader(u.openStream()))and then read bfr line-by-line. The problem that seems to be fairly common is that the openStream() call throws a ProtocolException claiming "server redirected too many times (20), ."
What I've seen is that this exception occurs whenever the URL is outside the Tomcat server whence the call is being made; in our case, we're running "out-of-the-box" Jakarta Tomcat 4.1.29 on port 8080 of a w2k server. The code works perfectly in native Java and in JSP for a URL of the form "/anotherpage.jsp"
Is this a bug in JSP, or in our version of Tomcat, or is there just some configuration parameter that needs to be changed from its default? As I said, I've seen similar posts (with less detailed analysis) in the Usenet newsgroups, but not one has generated a response that explains and resolves the matter.
Perhaps a JSP guru out there could set the record straight? Thanks.
P.S. I know that the use of scriptlets in JSP is being discouraged, but they are still supported AFAIK.

Sure scriptlets are still supported. Most times though you can do things better with a custom tag. Why reinvent the wheel?
Just as a suggestion, you might try the JSTL <c:import> tag.
It basically does just this behind the scenes.
However I don't think that will help you in the end - it will probably hit the same error message.
My guess would be that the problem is not caused by java/JSP as such, but by a firewall, or configuration somewhere.
The following works fine for me (ignoring broken images of course)
<%@ page import="java.net.*, java.io.*" %>
<%
URL u = new URL("http://www.google.com");
BufferedReader bfr = new BufferedReader(new InputStreamReader(u.openStream()));
String line = null;
while ((line = bfr.readLine()) != null){
out.println(line);
%>Hope this helps,
evnafets

URL.openstream doesn't work

Hi,
I run the demo program form java tutorial. Code as below:
import java.net.*;
import java.io.*;
public class urltest {
public static void main(String[] args) throws Exception {
     URL yahoo = new URL("http://www.yahoo.com/");
     BufferedReader in = new BufferedReader(
                    new InputStreamReader(
                    yahoo.openStream()));
     String inputLine;
     while ((inputLine = in.readLine()) != null)
     System.out.println(inputLine);
     in.close();
but it gives the follow output
Exception in thread "main" java.net.NoRouteToHostException: Operation timed out:
no further information
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(Unknown Source)
at java.net.PlainSocketImpl.connectToAddress(Unknown Source)
at java.net.PlainSocketImpl.connect(Unknown Source)
at java.net.Socket.<init>(Unknown Source)
at java.net.Socket.<init>(Unknown Source)
at sun.net.NetworkClient.doConnect(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.connect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown So
urce)
at java.net.URL.openStream(Unknown Source)
at urltest.main(urltest.java:30)
Plz advise.

Thx Jean, I modify the OS to Windows 95, but the program still don't work
code:
import java.net.*;
import java.io.*;
public class urltest {
public static void main(String[] args) throws Exception {
     URL yahoo = new URL("http://www.yahoo.com/");
     HttpURLConnection uc = (HttpURLConnection)yahoo.openConnection();
uc.setRequestProperty("User-Agent","Mozilla/4.0 (compatible; MSIE 5.5; Windows 95)");
uc.setRequestProperty("Connection","Keep-Alive");
uc.setDoOutput(true);
uc.setDoInput(true);
uc.setUseCaches(false);
uc.setRequestMethod("GET");
uc.setFollowRedirects(false);
uc.setInstanceFollowRedirects(false);
     BufferedReader in = new BufferedReader(
                    new InputStreamReader(
                    uc.getInputStream()));
     String inputLine=in.readLine();
     //while ((inputLine = in.readLine()) != null)
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     in.close();
The output is
Exception in thread "main" java.net.NoRouteToHostException: Operation timed out:
no further information
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(Unknown Source)
at java.net.PlainSocketImpl.connectToAddress(Unknown Source)
at java.net.PlainSocketImpl.connect(Unknown Source)
at java.net.Socket.<init>(Unknown Source)
at java.net.Socket.<init>(Unknown Source)
at sun.net.NetworkClient.doConnect(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.connect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown So
urce)
at urltest.main(urltest.java:39)
Plz advise

URL access problem

I have JDK1.5.0_06 (build 1.5.0_06-b05) on my PC with Windows 2000 OS and when I am running the following code
public class A
public static void main(String[] args)
try{
URL u = new URL("http://www.aaaa.com/xxxx%F3P%F3Rblabla");
ur = u.openConnection();
ur.getInputStream().close();
}catch(Exception e){
e.printStackTrace();
}finally{
the following exception appears:
java.lang.IllegalArgumentException
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     at sun.net.www.ParseUtil.toURI(ParseUtil.java:253)
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I think that the problem is using "%F3" in the URL. But, I have a site where this code appears in the URL and from IE it works fine.
If somebody knows how to solve please give me a sign.
If I use 1.5.0_02 (build 1.5.0_02-b09) it works fine.
Best regards,
Leo

Are regular users able to access Files? Is the user seeing the SSO Login page or do they just get a HTTP 500?
Please have the user delete all their cookies and temporary internet files and try it again.
In addition please see if the users request makes it to the Files server by checking the HTTP access_log and the Files servlet's application.log.
Hope that helps,
-sancho
I have a user who is having trouble accessing the
administrator and files URL. He is using the same URL
as other administrators but keeps getting HTTP 500
error or page can not be displayed.
The problem appears to be with his browser settings
in IE version 5.5. He has reinstalled IE and is still
getting this error. He can use someone else's PC and
is able to log in using the URLs but on his PC he
keeps getting an error.
Does anyone have any suggestions where to start
looking for a problem resolution?
Thanks for any help...

Help with URL.openStream

Hi,
This small Java program hangs if run on 1.3.1 but not 1.2.2 or some version of 1.4:
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public class V {
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Thanks,
Angel

what's it hanging after? does it print any of your lines out? You don't need to call connect() on the URLConnection, do you? Maybe not if using openStream().
BTW, is that script going to loop forever? The URL isn't working.

Extract URL from a href string

Greetings,
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* To change this template, choose Tools | Templates
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Passing user/pass by URL (url.openstream())

Hi guys,
I have a tough one for you...hehe
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You should have session variables attached to your page. Check Connection and Session, you should be able to use something like getProperties ("userid")

How to use "url.openStream()" . What this function does?

how to use "url.openStream()" . What this function does?
Edited by: sahil1287 on Apr 16, 2009 10:02 PM

http://java.sun.com/javase/6/docs/api/java/net/URL.html#openStream()
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Set "url" in HTTPService using String variable

Hi,
How can I set "url" in HTTPService using String variable (see below). I've tried different formats of string & variable concatenations.
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try following:
url="{myurl}test.php"

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That is definitely a limitation that each custom page name must be unique.
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Nevermind. The sound of chagrin.

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URL openStream problem. URL String length

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