Use first row of table to determine calculation of rest of the rows of that table.

Question

I have time sheet table where the rows are employees names and the column is the dates in the calender
Name
01
02
03
04
05
06
07
08
09
Emp 1
8
8
8
8
8
0
0
8
8
Emp 2
8
7
8
9
8
0
0
8
7
Emp 3
6
8
8
8
8
0
0
8
8
I want to come up with this table - where '1' indicates the public holiday.
Name
01
02
03
04
05
06
07
08
09
1
Emp 1
8
8
8
16
8
0
0
8
8
Emp 2
8
7
8
18
8
0
0
8
7
Emp 3
6
8
8
16
8
0
0
8
8
** I have the public Holiday table with dates of public holidays. I can do UNION ALL with sheet table and Public Holiday table to get the first row. i.e. if there is a Public Holiday within that date range then it will have '1' in the corresponding field
of the first row.
** Now If the there is a '1' in a field of the first row, I want all values below it to be doubled as shown in the example.
Please point me in the right direction.
Marsh Narewec

Answer 1

create table test (Name varchar(20),[01] int,[02] int,[03] int,[04] int,[05] int,[06] int,[07] int,[08] int,[09] int)
insert into test values('Emp 1',8,8,8,8,8,0,0,8,8),('Emp 2',8,7,8,9,8,0,0,8,7),('Emp 3',6,8,8,8,8,0,0,8,8)
;with mycte as(
select name, val,col from (select * from test) src
cross apply (values([01],'01'),([02],'02'),([03],'03'),([04],'04'),([05],'05'),([06],'06'),([07],'07'),([08],'08'),([09],'09')) d(val,col)
Select name,[01],[02],[03],[04],[05],[06],[07],[08],[09] from
(select name, Case when col='04' then val*2 else val end val,col from mycte) src
PIVOT (max(val) For col In ([01],[02],[03],[04],[05],[06],[07],[08],[09])) pvt
drop table test