User to enter values and stored as array

Question

Hi,
I have some problem with my labs that I would like to clear by doubt.
I need a user to keyed in a list of age so to calculate the average age. The values entered is stored in into an Array (not arrayList) I have been using ArrayList rather than array. =(
So I have used a bufferedReader to capture the input the user keyed in. unlike arraylist, I could not create an array without knowing the size of it.
Also,
My following code has some proble, when I run the program and enter 99 as the first value input. The system would terminate. However, when I enter other values than 99, the system would not terminate. Do point out my brainless mistake. Thanks alot.
  public static void main(String[] args) {
         // TODO, add your application code
        int num =0;
         int j = 0;
  boolean stop = false;
          int[] arr = new int[200];
           BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
              while(stop == false){
           try {
         num =  Integer.parseInt(br.readLine());
      } catch (IOException ioe) {}
      if(num == 99){
      stop = true;
    arr[j] = num;
    j++;
    }

Answer 1

seah_ly wrote:
I need a user to keyed in a list of age so to calculate the average age. The values entered is stored in into an Array (not arrayList) I have been using ArrayList rather than array. =(Yes you are correct in using an ArrayList, however if arrays are required you could mimic the actions of a growing ArrayList by using an array and initializing a new array with double the size of the old array and copying the old elements to the new array. Note this is exactly what an ArrayList does.
My following code has some proble, when I run the program and enter 99 as the first value input. The system would terminate. However, when I enter other values than 99, the system would not terminate. Do point out my brainless mistake. Thanks alot.
if(num == 99){
  stop = true;
}What do you think this does to the while loop?
Mel