Using analytic function to get the right output.

Question

Dear all;
I have the following sample date below
create table temp_one
       id number(30),  
      placeid varchar2(400),
      issuedate  date,
      person varchar2(400),
      failures number(30),
      primary key(id)
insert into temp_one values (1, 'NY', to_date('03/04/2011', 'MM/DD/YYYY'), 'John', 3);
insert into temp_one values (2, 'NY', to_date('03/03/2011', 'MM/DD/YYYY'), 'Adam', 7);
insert into temp_one values (3, 'Mexico', to_date('03/04/2011', 'MM/DD/YYYY'), 'Wendy', 3);
insert into temp_one values (4, 'Mexico', to_date('03/14/2011', 'MM/DD/YYYY'), 'Gerry', 3);
insert into temp_one values (5, 'Mexico', to_date('03/15/2011', 'MM/DD/YYYY'), 'Zick', 9);
insert into temp_one values (6, 'London', to_date('03/16/2011', 'MM/DD/YYYY'), 'Mike', 8);this is output I desire
placeid       issueperiod                               failures
NY              02/28/2011 - 03/06/2011          10
Mexico       02/28/2011 - 03/06/2011           3
Mexico        03/14/2011 - 03/20/2011          12
London        03/14/2011 - 03/20/2011          8All help is appreciated. I will post my query as soon as I am able to think of a good logic for this...

Answer 1

hI,
user13328581 wrote:
... Kindly note, I am still learning how to use analytic functions.That doesn't matter; analytic functions won't help in this problem. The aggregate SUM function is all you need.
But what do you need to GROUP BY? What is each row of the result set going to represent? A placeid? Yes, each row will represent only one placedid, but it's going to be divided further. You want a separate row of output for every placeid and week, so you'll want to GROUP BY placeid and week. You don't want to GROUP BY the raw issuedate; that would put March 3 and March 4 into separate groups. And you don't want to GROUP BY failures; that would mean a row with 3 failures could never be in the same group as a row with 9 failures.
This gets the output you posted from the sample data you posted:
SELECT       placeid
,             TO_CHAR ( TRUNC (issuedate, 'IW')
              , 'MM/DD/YYYY'
            ) || ' - '|| TO_CHAR ( TRUNC (issuedate, 'IW') + 6
                                         , 'MM/DD/YYY'
                           )     AS issueperiod
,       SUM (failures)                  AS sumfailures
FROM        temp_one
GROUP BY  placeid
,            TRUNC (issuedate, 'IW')
;You could use a sub-query to compute TRUNC (issuedate, 'IW') once. The code would be about as complicated, efficiency probably won't improve noticeably, and the the results would be the same.