Using exceptions

Basically I have this
          for(int i=0; i<6; i++){
                guess=Integer.parseInt(JOptionPane.showInputDialog(null, "Please enter guess" + " " + (i+1) + " " + "(between 1 and 6)" ));
     do {
     if (guess[i]<1 || guess[i]>6){
               JOptionPane.showMessageDialog (null, "That's not between 1 and 6, try again", "Invalid", JOptionPane.WARNING_MESSAGE);
               guess[i]=Integer.parseInt(JOptionPane.showInputDialog(null, "Please enter guess" + " " + (i+1) + " " + "(between 1 and 6)"));
          }while (guess[i]<1 || guess[i]>6);
I want to make it so that it catches the NumberFormatException if the user accidentally inputs a character instead of a number. How do I go about this? I know I have to use "try" and "catch", but at what bit of the above piece of code would I user it?

Here's how NumberFormatException could be handled.
String str = null;
for(int i = 0; i < 6; i++) {
    do {
        str = JOptionPane.showInputDialog(null, "Please enter guess" +" " +(i+1)
                +" " +"(between 1 and 6)");
        // Handle the NumberFormatException.
        try {
            guess[i] = Integer.parseInt(str);
        } catch(NumberFormatException nfe) {
            nfe.printStackTrace();
            // Do something like setting the guess value
            // to a negative number and prompting for input again.
            guess[i] = -1;
        if (guess[i] < 1 || guess[i] > 6) {
            JOptionPane.showMessageDialog(null, "That's not between 1 and 6, try again",
                    "Invalid", JOptionPane.WARNING_MESSAGE);
        } else {
            break;
    } while(true);
}In your code snippet, you need not repeat the same lines again.

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    >
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