Using regex in java

I need to get a name from the text box and store it in a String variable.And i should put a condition that the name that is stored in the stirng variable should not start with non alpha numeric characters or special characters.For this i want to use Regular expressions in java.I got a Regex or pattern for this purpose it is shown below
Pattern:
^([0-9a-zA-Z]([-.\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\w]*[0-9a-zA-Z]\.)+[a-zA-Z]{2,9})$
And my code is as follows:
JTextFeild reportnametext;
String name=reportnametext.getText();
//here i need to check whether the first charecter of the name is starting with a special character and if it starts with special charecter i need to popup a dialog box that name should not start with special characters.
Can u plz show me how to implement it in my code

If you'd have taken the time to go through the links I provided you would have seen [url http://javaalmanac.com/egs/java.util.regex/Case.html]Setting Case Sensitivity in a Regular Expression.
Pattern p = Pattern.compile("^[a-z0-9]", Pattern.CASE_INSENSITIVE);Regards

Similar Messages

  • Search given string array and replace with another string array using Regex

    Hi All,
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    any --> trip
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    One Single regular expression which matches the pattern and solve the issue.
    the output should be as:
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    Thanks In Advance,
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    As stated, no, it can't be done. But that doesn't mean you have to make a separate pass over the input for each word you want to replace. You can employ a regex that matches any word, then use the lower-level Matcher methods to replace the word or not depending on what was matched. Here's an example: import java.util.*;
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    Yes, did you notice it said something about incredibly vague functionality?
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    I am developing a java project to extract Table of
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    Neeraj Hans wrote:
    Hi
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