Using very long/large numbers

Question

Hi, I want to know how to "store" and use very large numbers.
For example, say I had:
double n = 1.23456789101112131415;
or:
double n = 123456789101112131415
I know that they are too big for using double, so how would I be able to store it; and even more importantly round it ,preferably using "Math.round," to 15 decimal places?
i.e. tell it to do this:
n = 1.23456789101112131415;
number = Math.round((1000000000000 * n) / 1000000000000 .0);
System.out.println(number);

Answer 1

As much as your "advice" helps, the java docs provide
only methods for the BigDecimal/Integer
objects. They don't show complete syntax, and don't
contain examples. Fortunately, I have avoided the
"35-years-old-and-still-living-in-my-mother's-basement
-and-aren't-even-professional-programmers" path and
have enough of a life that I try not to spend all day
reading about Java syntax.I don't believe this. Morgalr gave you genuine help. You spent more time criticizing him than conducting a very simple google search sucha as "BigInteger"+"example". I would suggest a little attitude adjustment if you still want people to help you next time.