Using Vlookup over several tables
Hi I have read the following link
https://discussions.apple.com/message/16992843#16992843
I am looking to do something similar. I have got five tables for 5 different classes.
Column A has names B-K has results of the kids athletics achievements.
What I would like to do is find the best person across all tables at each event. I'm not sure if I can do a direct vlookup as it will be referencing from different tables.
Is my best option to create a new table which will show the best person for each event from just one table.
So basically i will create a new table per class table once I have found out who is best in that single class create another table that has best of all classes and then lookup that way? Although i'm adding tables it seems an easier way of possibly getting the end result?
Table 1 = Class 1
Table 2 = Class 2
Table 3 = Class 3
New table = best of class,1,2&3
New table = best?
Here's an example of VLOOKUP operating across three tables to find the 'best' 'performance. examples are small, but scaleable. "Best' may be either 'largest' (distance or height events–row 2) or 'smallest' (timed events–row 4). Caveats below.
Formulas differ only in using MAX or MIN to determine the search value:
Bis::B2: =MAX(Class A :: A,Class B :: A,Class C :: A)
Bis::B4: =MIN(Class A :: A,Class B :: A,Class C :: A)
Lookup formulas are the same in both cases:
A2: =IFERROR(VLOOKUP(B,Class A :: A:B,2,FALSE),IFERROR(VLOOKUP(B,Class B :: A:B,2,FALSE),(VLOOKUP(B,Class C :: A:B,2,FALSE))))
A4: =IFERROR(VLOOKUP(B,Class A :: A:B,2,FALSE),IFERROR(VLOOKUP(B,Class B :: A:B,2,FALSE),VLOOKUP(B,Class C :: A:B,2,FALSE)))
Caveat: Like all Lookup formulas, this one will stop at the first occurrence of the value it is looking for. If more than one student has the 'best' score, only one name will be returned. That's not an insurmountable problem. but it is one that won't be solved using only LOOKUP or one of it's variations.
Regards,
Barry
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Both applications can coexist on your MBP, and you will need both to move back to Pages '09.
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Barry -
Hi gurus,
I have a question about buildings sql trees over several tables.
This is the Output I hope for:
0
- 10, 'Company Blue1', 0
-- 101, 'Part Blue1', 10
--- 1001, 'Accounting Blue', 101
---- 10001, 'Hans Mueller', 1001
--- 1002, 'Special Problems Blue', 101
---- 10002, 'Stephen Meyer', 1002
---- 10003, 'Carlos Anceto', 1002
-- 102, 'Part Blue2', 10
--- 1003, 'Information Technology Blue', 102
---- 10004, 'Tobias Tries', 1003
- 20, 'Company Red1', 0
-- 201, 'Part Red1', 20
--- 2001, 'Accounting Red', 201
---- 20001, 'Carl Van Deser', 2001
---- 20002, 'Geromel Boats', 2002
- 30, 'Company Green1', 0
-- 301, 'Part Green1', 30
--- 3001, 'Accounting Green', 301
---- 30002, 'Peter Finnighan', 3001
--- 3003, 'Special Problems Green', 301
---- 30001, 'Loui Van Ecke', 3003This is the situation: I have 4 table which can be constraint by foreign key and all toghether build up a tree.
Table1:
tbl_company (c_id, company_name)
Values:
10, 'Company Blue1'
20, 'Company Red1'
30, 'Company Green1'
Table2:
tbl_company_parts (cp_id, part_name, company_id)
Values:
101, 'Part Blue1', 10
102, 'Part Blue2', 10
201, 'Part Red1',20
301, 'Part Green1',30
Table3:
tbl_departments (d_id, dept_name, part_id)
Values:
1, 'Accounting Blue', 101
2, 'Special Problems Blue', 101
3, 'Information Technology Blue', 102
4, 'Accounting Red',201
5, 'Accounting Green',301
6, 'Special Problems Green',301
Tablemployees (e_id, dept_name, department_id)
Values:
1, 'Hans Mueller', 1
2, 'Stephen Meyer', 2
3, 'Carlos AncetoÄ, 2
4, 'Carl Van Deser',4
5, 'Geromel Boats', 4
6, 'Loui Van Ecke',5
7, 'Peter Finnighan',6
8, 'Tobias Tries',3The problem is that I don't know how to concate alle these values and using the connect by clause creating this tree viewHi Tobias,
It was not exactly clear how the id's had to be calculated, but this example will get you going:
SQL> create table tbl_company (c_id, company_name)
2 as
3 select 10, 'Company Blue1' from dual union all
4 select 20, 'Company Red1' from dual union all
5 select 30, 'Company Green1' from dual
6 /
Table created.
SQL> create table tbl_company_parts (cp_id, part_name, company_id)
2 as
3 select 101, 'Part Blue1', 10 from dual union all
4 select 102, 'Part Blue2', 10 from dual union all
5 select 201, 'Part Red1',20 from dual union all
6 select 301, 'Part Green1',30 from dual
7 /
Table created.
SQL> create table tbl_departments (d_id, dept_name, part_id)
2 as
3 select 1, 'Accounting Blue', 101 from dual union all
4 select 2, 'Special Problems Blue', 101 from dual union all
5 select 3, 'Information Technology Blue', 102 from dual union all
6 select 4, 'Accounting Red',201 from dual union all
7 select 5, 'Accounting Green',301 from dual union all
8 select 6, 'Special Problems Green',301 from dual
9 /
Table created.
SQL> create table tbl_employees (e_id, emp_name, department_id)
2 as
3 select 1, 'Hans Mueller', 1 from dual union all
4 select 2, 'Stephen Meyer', 2 from dual union all
5 select 3, 'Carlos Anceto', 2 from dual union all
6 select 4, 'Carl Van Deser',4 from dual union all
7 select 5, 'Geromel Boats', 4 from dual union all
8 select 6, 'Loui Van Ecke',5 from dual union all
9 select 7, 'Peter Finnighan',6 from dual union all
10 select 8, 'Tobias Tries',3 from dual
11 /
Table created.
SQL> select coalesce
2 ( case when e.department_id is null then null else
3 trunc(d.part_id,-2) * 100 + dense_rank() over (partition by d.part_id order by e.e_id)
4 end
5 , trunc(d.part_id,-2) * 10 + dense_rank() over (partition by d.part_id order by d.d_id)
6 , p.cp_id
7 , c.c_id
8 , 0
9 ) id
10 , coalesce
11 ( e.emp_name
12 , d.dept_name
13 , p.part_name
14 , c.company_name
15 ) name
16 , coalesce
17 ( trunc(d.part_id,-2) * 10 + dense_rank() over (partition by d.part_id order by d.d_id)
18 , d.part_id
19 , p.company_id
20 , case grouping(c.c_id) when 0 then 0 end
21 ) parent_id
22 from tbl_company c
23 , tbl_company_parts p
24 , tbl_departments d
25 , tbl_employees e
26 where c.c_id = p.company_id
27 and p.cp_id = d.part_id
28 and d.d_id = e.department_id
29 group by rollup
30 ( ( c.c_id,c.company_name)
31 , ( p.cp_id,p.part_name,p.company_id)
32 , ( d.d_id,d.dept_name,d.part_id)
33 , ( e.e_id,e.emp_name,e.department_id)
34 )
35 order by c.c_id nulls first
36 , p.cp_id nulls first
37 , d.d_id nulls first
38 , e.e_id nulls first
39 /
ID NAME PARENT_ID
0
10 Company Blue1 0
101 Part Blue1 10
1001 Accounting Blue 1001
10001 Hans Mueller 1001
1002 Special Problems Blue 1002
10002 Stephen Meyer 1002
10003 Carlos Anceto 1002
102 Part Blue2 10
1001 Information Technology Blue 1001
10001 Tobias Tries 1001
20 Company Red1 0
201 Part Red1 20
2001 Accounting Red 2001
20001 Carl Van Deser 2001
20002 Geromel Boats 2001
30 Company Green1 0
301 Part Green1 30
3001 Accounting Green 3001
30001 Loui Van Ecke 3001
3002 Special Problems Green 3002
30002 Peter Finnighan 3002
22 rows selected.Regards,
Rob. -
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When I want to print any email from Mail, for some odd reason the email gets spread out over several pages or more depending on the size of the email. The text is printed in one vertical line consisting of one letter per line, like this:
t
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(10.3.9)
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Creating a combined timeline based on several timelines in several tables
Hi,
I need to extract a timeline for a customer based on valid_from and valid_to dates in several tables.
For example: I have a table named customers with an id, a valid_from and a valid_to date and a table named contracts with an contrat_name, customer_id and valid_from and valid_to:
CUSTOMERS:
ID | VALID_FROM | VALID_TO
1 | 01.03.2010 | 01.01.4000
CONTRACTS:
CONTRACT_NAME | CUSTOMER_ID | VALID_FROM | VALID_TO
ContractA | 1 | 01.03.2010 | 01.10.2010
ContractB | 1 | 01.10.2010 | 01.01.4000
The following statement would now give me the correct timeline:
select cus.id customer, con.contract_name contract, greatest(cus.valid_from,con.valid_from) valid_from, least(cus.valid_to,con.valid_to) valid_to
from customers cus
inner join contracts con on cus.id = con.customer_id;
CUSTOMER | CONTRACT | VALID_FROM | VALID_TO
1 | ContractA | 01.03.2010 | 01.10.2010
1 | ContractB | 01.10.2010 | 01.01.4000
That works, but I get a problem as soon as I have a point of time where there is no contract for a customer but I still would like to have these periods in my timeline:
Let's assume the following data and the same select statement:
CUSTOMERS:
ID | VALID_FROM | VALID_TO
1 | 01.03.2010 | 01.01.4000
CONTRACTS:
CONTRACT_NAME | CUSTOMER_ID | VALID_FROM | VALID_TO
ContractA | 1 | 01.05.2010 | 01.10.2010
ContractB | 1 | 01.12.2010 | 01.03.2011
What I would now get would be:
CUSTOMER | CONTRACT | VALID_FROM | VALID_TO
1 | ContractA | 01.05.2010 | 01.10.2010
1 | ContractB | 01.12.2010 | 01.03.2011
But what I would like to get is the following:
CUSTOMER | CONTRACT | VALID_FROM | VALID_TO
1 | null | 01.03.2010 | 01.05.2010
1 | ContractA | 01.05.2010 | 01.10.2010
1 | null | 01.10.2010 | 01.12.2010
1 | ContractB | 01.12.2010 | 01.03.2011
1 | null | 01.03.2011 | 01.01.4000
What I do not want to do is to generate a result with contract = null any time there is no contract since I actually want to join the timeline of several different tables into one and it would therefore become very complicated to assume things based on what data can or can not be found in one specific table.
Thanks for any help or ideas,
Regards,
ThomasHi, Thomas,
Thomas Schenkeli wrote:
... Is this the way you meant? Because I actually didn't have to change anything about part (b) of the statement since non-matching results were excluded by the where-clause "OR valid_from < valid_to" in the final select anyway.You're absolutely right. Sorry about the mistakes in my last message. I'm glad you solved the problem anyway.
Beware of SELECT DISTINCT . Adding DISTINCT causes the system to do extra work, often because the query was doing something wrong and generating too many rows, so you pay for it twice. In this case, the join conditions in (b) are different from (a) and (c), so b is generating too many rows. The DISTINCT in the main query corrects that mistake, but it would be more efficient just to avoid the mikstake in the first place, and use the same join conditions in all 3 branches of the UNION. (You could also factor out the join, doing it once in another sub-query, and then referencing that result set in each branch of the UNION.)
You can get the same results a little more efficiently, with a little less code, this way:
WITH union_data AS
SELECT MIN (ua.customer_id) AS customer_id
, NULL AS contract_name
, MIN (ua.valid_from) AS valid_from
, MIN (oa.valid_from) AS valid_to
, 'A' AS origin
FROM tmp_customers ua
JOIN tmp_contracts oa ON oa.customer_id = ua.customer_id
AND oa.valid_from >= ua.valid_from
AND oa.valid_to <= ua.valid_to
GROUP BY ua.id
UNION ALL
SELECT ub.customer_id
, ob.contract_name
, ob.valid_from
, ob.valid_to
, 'B' AS origin
FROM tmp_customers ub
JOIN tmp_contracts ob ON ob.customer_id = ub.customer_id
AND ob.valid_from >= ub.valid_from
AND ob.valid_to <= ub.valid_to
UNION ALL
SELECT uc.customer_id
, NULL AS contract_name
, oc.valid_to AS valid_from
, LEAD ( oc.valid_from
, 1
, uc.valid_to
) OVER ( PARTITION BY uc.id
ORDER BY oc.valid_from
) AS valid_to
, 'C' AS origin
FROM tmp_customers uc
JOIN tmp_contracts oc ON oc.customer_id = uc.customer_id
AND oc.valid_from >= uc.valid_from
AND oc.valid_to <= uc.valid_to
SELECT *
FROM union_data
WHERE contract_name IS NOT NULL
OR valid_from < valid_to
ORDER BY customer_id
, valid_from
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How to generate row numbering over several pages in PAGES??
How can I generate row numbering over several pages in PAGES??
e.g. Page1 1-35
Page2 36-...Hi Labrat,
My suggestion would be to create a Template in the Page Layout mode. This template would have a 1-column Table to present the line numbers and a Text Box for the Body Text. If you want the Line Numbers to stay in alignment with the Body Text, set the spacing for both to Exactly. Set the Table Cell Borders to None. The faint cell borders that you see in the following example are there because I am in View Layout mode. They will not show when printed.
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Here's my example:
Regards,
Jerry
Message was edited by: Jerrold Green1 -
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I have one application, for example safari, open and running with multiple windows (with or without tabs) spread over several desktops.
How can I switch between the windows only via keyboard? CMD+> and CMD+< let me only swicht between windows open on the one desktop I am currently looking at.
thanks for your replies,
equiBarney,
many thanks for your efforts and your time (preparing and posting the screenshot, answering to this question,...).
Unfortunately, moving the focus to the next window only works with windows on the same desktop.
btw, using a german keyboard layout and german language settings the shortcut is "cmd+<".
I can switch with this shortcut between different windows of my Safari which reside on the same desktop, but I cannot swith between different safari windows distributed over several desktops.
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Thanks for the question. I understand that you are experiencing issues installing iTunes for Windows. The following article outlines the error message you are receiving and a potential resolution:
iTunes 11.1.4 for Windows: Unable to install or open
http://support.apple.com/kb/TS5376
Some Windows customers may experience installation issues while trying to install or open iTunes 11.1.4.
Symptoms may include:
"The program can't start because MSVCR80.dll is missing from your computer"
"iTunes was not installed correctly. Please reinstall iTunes. Error 7 (Windows Error 126)”
"Runtime Error: R6034 - An application has made an attempt to load the C runtime library incorrectly"
"Entry point not found: videoTracks@QTMovie@@QBE?AV?$Vector@V?$RefPtr@VQTTrack@@@***@@$0A@VCrashOnOverf low@@***@@XZ could not be located in the dynamic link library C:\Program Files(x86)\Common Files\Apple\Apple Application Support\WebKit.dll”
Resolution
Follow these steps to resolve the issue:
Check for .dll files
1. Go to C:\Program Files (x86)\iTunes and C:\Program Files\iTunes and look for .dll files.
2. If you find QTMovie.DLL, or any other .dll files, move them to the desktop.
3. Reboot your computer.
Note: Depending on your operating system, you may only have one of the listed paths.
Uninstall and reinstall iTunes
1. Uninstall iTunes and all of its related components.
2. Reboot your computer. If you can't uninstall a piece of Apple software, try using theMicrosoft Program Install and Uninstall Utility.
3. Re-download and reinstall iTunes 11.1.4.
Thanks,
Matt M. -
Proper use of a Lookup table and adaptations for NET
Hello,
I need to create a few lookup tables and I often see the following:
create table Languages
Id int identity not null primary key (Id),
Code nvarchar (4) not null,
Description nvarchar (120) not null,
create table Posts
Id int identity not null primary key (Id),
LanguageId int not null,
Title nvarchar (400) not null,
insert into Languages (Id, Code, Description)
values (1, "en", "English");
This way I am localizing Posts with language id ...
IMHO, this is not the best scheme for Languages table because in a Lookup table the PK should be meaningful, right?
So instead I would use the following:
create table Languages
Code nvarchar (4) not null primary key (Code),
Description nvarchar (120) not null,
create table Posts
Id int identity not null primary key (Id),
LanguageCode nvarchar (4) not null,
Title nvarchar (400) not null,
insert into Languages (Code, Description)
values ("en", "English");
The NET applications usually use language code so this way I can get a Post in English without using a Join.
And with this approach I am also maintaining the database data integrity ...
This could be applied to Genders table with codes "M", "F", countries table, transaction types table (should I?), ...
However I think it is common to use int as PK in lookup tables because it is easier to map to ENUMS.
And know it is even possible to map to Flag Enums so have a Many to Many relationship in an ENUM.
That helps in NET code but in fact has limitations. A Languages table could never be mapped to a FLags Enum ...
... An flags enum can't have more than 64 items (Int64) because the keys must be a power of two.
A SOLUTION
I decided to find an approach that enforces database data integrity and still makes possible to use enums so I tried:
create table Languages
Code nvarchar (4) not null primary key (Code),
Key int not null,
Description nvarchar (120) not null,
create table Posts
Id int identity not null primary key (Id),
LanguageCode nvarchar (4) not null,
Title nvarchar (400) not null,
insert into Languages (Code, Key, Description)
values ("en", 1, "English");
With this approach I have a meaningfully Language code, I avoid joins and I can create an enum by parsing the Key:
public enum LanguageEnum {
[Code("en")
English = 1
I can even preserve the code in an attribute. Or I can switch the code and description ...
What about Flag enums? Well, I will have not Flag enums but I can have List<LanguageEnum> ...
And when using List<LanguageEnum> I do not have the limitation of 64 items ...
To me all this makes sense but would I apply it to a Roles table, or a ProductsCategory table?
In my opinion I would apply only to tables that will rarely change over time ... So:
Languages, Countries, Genders, ... Any other example?
About the following I am not sure (They are intrinsic to the application):
PaymentsTypes, UserRoles
And to these I wouldn't apply (They can be managed by a CMS):
ProductsCategories, ProductsColors
What do you think about my approach for Lookup tables?
Thank You,
Miguel>>IMHO, this is not the best scheme for Languages table because in a Lookup table the PK should be meaningful, right?<<
Not necessarily. The choice to use, or not to use, a surrogate key in a table is a preference, not a rule. There are pros and cons to either method, but I tend to agree with you. When the values are set as programming terms, I usually use a textual value
for the key. But this is nothing to get hung up over.
Bear in mind however, that this:
create table Languages
Id int identity not
null primary key
(Id),
Code nvarchar (4)
not null, Description nvarchar
(120) not
null,
is not equivalent to
create table Languages
Code nvarchar (4)
not null primary
key (Code),
Description nvarchar (120)
not null,
The first table needs a UNIQUE constraint on Code to make these solutions semantically the same. The first table could have the value 'Klingon' in it 20 times while the second only once.
>>However I think it is common to use int as PK in lookup tables because it is easier to map to ENUMS.<<
This was going to be my next point. For that case, I would only change the first table to not have an identity assigned key value, as it would be easier to manage at the same time and manner as the enum.
>>. A Languages table could never be mapped to a FLags Enum ...<<
You could, but I would highly suggest to avoid any values encoded in a bitwise pattern in SQL as much as possible. Rule #1 (First Normal Form) is partially to have 1 value per column. It is how the optimizer thinks, and how it works best.
My rule of thumb for lookup (or I prefer the term "domain" tables, as really all tables are there to look up values :)), is all data should be self explanatory in the database, through data if at all possible. So if you have a color column,
and it contains the color "Vermillion", and all you will ever need is the name, and you feel like it is good enough to manage in the UI, then great. But bear in mind, the beauty of a table that is there for domain purposes, is that you can then store
the R, G, and B attributes of the vermillion color (254, 73, 2 respectively, based on
http://www.colorcombos.com/colors/FE4902) and you can then use that in coding. Alternate names for the color could be introduce, etc. And if UserRoles are 1, 2, 3, and 42 (I have seen worse), then
definitely add columns. I think you are basically on the right track.
Louis
Without good requirements, my advice is only guesses. Please don't hold it against me if my answer answers my interpretation of your questions. -
i clicked the download all button at the end of the list of my library iTunes which i believe is in the iCloud, i have iTunes match also, many downloads were reported as occurring over several hours and then received the warning startup disc is full (activity monitor shows 3.99 of 4 GB used) and then another stating the download had not occurred due to the disc being full. most of the tunes still appear to be in the cloud but the disc is said to be full, spent a good period of time trying to investigate what has happened but failed...I'm not well up on all of this as an old chap so any help would be wonderful.....
unclefossil wrote:
Thanks Michael, what is the best way of backing up, should buy a cheap standalone external hard drive rather than relying on the Time Capsule which is quite sensitive...
If you read the link I provided you'll get an idea of one way to maintain a backup of your music files, use Time Machine, and not take up as much room on the internal HDD/SSD.
unclefossil wrote:
i live in the Scottish Highlands where Broadband is frequently intermittent disrupting backups.
Your internet connection speed has no effect on Time Machine/Time Capsule backups. Since that is all done locally, over your wireless network you actually do not need an internet connection at all.
unclefossil wrote:
Also I wondered if I could increase the memory on the setup disk by replacing the 4GB card already in the MBP with 16GB cards, if I upgraded would that affect anything I have stored already like my iTunes?
You're asking about the computer's RAM. Increasing that will not increase the size of the internal storage available to the computer. You'd need to replace the HDD/SSD of the Mac, which, depending on what model you have may or may not be possible (with new models of Macs).
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