Using xml file in java application

How can i get the attribute name & value into my java application from a xml flie?

read the file
parse the contents
store attribute name & value pairs.
%

Similar Messages

  • Passing Parameters from XML file to Java Application

    Can any one help me to know the way of passing values from XML file to Java Application..
    Thanx in advance

    With the Processing Instructions <?name pidata?>
    Get the Nodes in a Document.
    Node node;
    if(node.getNodeType()==Node.PROCESSING_INSTRUCTION_NODE)
    //String param=node.getData();

  • Using XML file in Java script to create Google Map

    Hello,
    I work for a non-profit in San Diego as a GIS Specialist. I have had to teach myself about some scripting to create some dynamic maps, but I am still very limited in my skills, so I have had to explore the internet in order to discover various tutorials and examples that have led me on a positive path.
    Right now I am working on a Google Mash-Up that will incorporate over 14,000 records, which will appear as separate markers that will have pop-up info bubbles with additional info inside (using html), once the marker is clicked.
    Here is the XML script example that is used in the tutorial I am following:
    <markers>
    <marker lat="43.65654" lng="-79.90138" html="Some stuff to display in the<br>First Info Window"
    label="Marker One" />
    <marker lat="43.91892" lng="-78.89231" html="Some stuff to display in the<br>Second Info Window"
    label="Marker Two" />
    <marker lat="43.82589" lng="-79.10040" html="Some stuff to display in the<br>Third Info Window"
    label="Marker Three" />
    </markers>
    ...and this is how it looks when the file is retrieved by the java script and mapped: http://econym.googlepages.com/example_map3.htm
    This is the java script that creates the Google Map. I have emboldened the section of the script that retrieves the data and parses it to create the markers:
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <title>Google Maps</title>
    <script src="http://maps.google.com/maps?file=api&v=2&key=ABQIAAAA6GoL8P5zqjQlG5A5uM1ETBSUPozAscB0cY3RG8xEGnZyeom4axRySak889rVpvHYRsV4f9OZZzbboA"
    type="text/javascript"></script>
    </head>
    <body onunload="GUnload()">
    <!-- you can use tables or divs for the overall layout -->
    <table border=1>
    <tr>
    <td>
    <div id="map" style="width: 800px; height: 1200px"></div>
    </td>
    <td width = 200 valign="top" style="text-decoration: underline; color: #4444ff;">
    <div id="side_bar"></div>
    </td>
    </tr>
    </table>
    <noscript><b>JavaScript must be enabled in order for you to use Google Maps.</b>
    However, it seems JavaScript is either disabled or not supported by your browser.
    To view Google Maps, enable JavaScript by changing your browser options, and then
    try again.
    </noscript>
    <script type="text/javascript">
    //<![CDATA[
    if (GBrowserIsCompatible()) {
    // this variable will collect the html which will eventualkly be placed in the side_bar
    var side_bar_html = "";
    // arrays to hold copies of the markers used by the side_bar
    // because the function closure trick doesnt work there
    var gmarkers = [];
    var i = 0;
    // A function to create the marker and set up the event window
    function createMarker(point,name,html) {
    var marker = new GMarker(point);
    GEvent.addListener(marker, "click", function() {
    marker.openInfoWindowHtml(html);
    // save the info we need to use later for the side_bar
    gmarkers[i] = marker;
    // add a line to the side_bar html
    side_bar_html += '<a href="javascript:myclick(' + i + ')">' + name + '</a><br>';
    i++;
    return marker;
    // This function picks up the click and opens the corresponding info window
    function myclick(i) {
    GEvent.trigger(gmarkers, "click");
    // create the map
    var map = new GMap2(document.getElementById("map"));
    map.addControl(new GLargeMapControl());
    map.addControl(new GMapTypeControl());
    map.setCenter(new GLatLng( 37.251699,-119.604315), 7);
    *// Read the data from testXML2blackpoolformat.xml*
    var request = GXmlHttp.create();
    request.open("GET", "testXML2blackpoolformat.xml", true);
    *request.onreadystatechange = function() {*
    *if (request.readyState == 4) {*
    var xmlDoc = GXml.parse(request.responseText);
    *// obtain the array of markers and loop through it*
    var markers = xmlDoc.documentElement.getElementsByTagName("ConnectoryRecord");
    *for (var i = 0; i < markers.length; i++) {*
    *// obtain the attribues of each marker*
    *var lat = parseFloat(markers[i].getAttribute("lat"));*
    *var lng = parseFloat(markers[i].getAttribute("lng"));*
    var point = new GLatLng(lat,lng);
    *var html = markers[i].getAttribute("html");*
    *var label = markers[i].getAttribute("label");*
    *// create the marker*
    var marker = createMarker(point,label,html);
    map.addOverlay(marker);
    // put the assembled side_bar_html contents into the side_bar div
    document.getElementById("side_bar").innerHTML = side_bar_html;
    request.send(null);
    else {
    alert("Sorry, the Google Maps API is not compatible with this browser");
    // This Javascript is based on code provided by the
    // Blackpool Community Church Javascript Team
    // http://www.commchurch.freeserve.co.uk/
    // http://econym.googlepages.com/index.htm
    //]]>
    </script>
    </body>
    </html>
    Here is my delima--
    This is the xml format that I need to use because it can accept the rest of my excel file and loop it through the 14,000+ records to create a functioning xml file. This is just a sample (2 records) of the larger file:
    <?xml version="1.0" encoding="UTF-8" standalone="yes" ?>
    <ConnectoryAug2008>
    <ConnectoryRecord>
         <lng>-117.03683</lng>
         <lat>32.944505</lat>
         <ConnectoryID>1</ConnectoryID>
         <Name>$2.95 Guys</Name>
         <StreetAddress>13750 Stowe Drive</StreetAddress>
         <City>Poway</City>
         <State>CA</State>
         <Zip>92064</Zip>
    <Marker>White</Marker>
         <IndustryGroup>Technical Services</IndustryGroup>
         <ConnectoryProfileLink>http://connectory.com/search/profile_view.aspx?connectoryId=1</ConnectoryProfileLink>
    </ConnectoryRecord>
    <ConnectoryRecord>
         <lng>-117.272843</lng>
         <lat>33.13337</lat>
         <ConnectoryID>2</ConnectoryID>
         <Name>(GLDS) Great Lakes Data Systems</Name>
         <StreetAddress>5954 Priestly Drive</StreetAddress>
         <City>Carlsbad</City>
         <State>CA</State>
         <Zip>92008</Zip>
    <Marker>Orange</Marker>
         <IndustryGroup>Technology</IndustryGroup>
         <ConnectoryProfileLink>http://connectory.com/search/profile_view.aspx?connectoryId=2</ConnectoryProfileLink>
    </ConnectoryRecord>
    </ConnectoryAug2008>
    This is the tutorial where I found the formatting techniques to successfully create the large xml file that will format/convert my excel file properly: http://www.mrexcel.com/tip064.shtml
    These variables should appear as html in the info bubble:
    <ConnectoryID>2</ConnectoryID>
         <Name>(GLDS) Great Lakes Data Systems</Name>
         <StreetAddress>5954 Priestly Drive</StreetAddress>
         <City>Carlsbad</City>
         <State>CA</State>
         <Zip>92008</Zip>
    <IndustryGroup>Technology</IndustryGroup>
         <ConnectoryProfileLink>http://connectory.com/search/profile_view.aspx?connectoryId=2</ConnectoryProfileLink>
    The "Marker" variable instructs Google Maps to label the marker with a particular color. I will be so grateful to the person(s) that helps me get through this wall that I have been hitting for a long time. It's very difficult without having the luxury of peers who know about these types of issues.
    Thank you!!

    Here is the relationship: They both contain geographic coordinates that produce a point on a map. I will use the rest of the information in the second xml file (company name, address, link, etc.) to produce the information for the bubble that will pop up once the marker is clicked.
    My problem is that I need to try to keep the second xml file in a relatively similar format, so the rest of my records will still be accepted. If I had a smaller amount of records I could place them directly into the javascript, but because there are so many records, I need to use an xml file that can be retrieved by the java script. I chose to use the second type of xml file because I can easily copy and past the 14,000+ records that are now in excel document.
    After the xml issue is corrected I need to rework the javascript that is now emboldened so that it will read the new xml file correctly. I included the first xml file so that the readers will understand what type of xml format is currently being used to produce the markers in the tutorial map.

  • What the best way to create XML files from JAVA application?

    Hi to all,
    I need to edit and to create new filex in format of xml. I know to parse, but what would be the best way to do:
    1. - Create new file, create like simle text file, or there is some clases that know to do it in more simple way
    2.a - Edit XML file, to take some data and add it to the XML in the place I want to.
    2.b - Also Edit, but not to add fields, just update some of them.
    Code examples or links to samples woul be welcomed.
    Best regards, Nick.

    I have tried working with XML directly using the Java classes but this was a pain. I then looked at DOM4J and JDOM and found JDOM easier to use.

  • HOw to create a Batch file for java application and whats the use of this ?

    HI,
    How to create a Batch file for java application ?
    And whats the use of creating batch file ?
    Thanks in advance

    First of all, you're OT.
    Second, you can find this everywhere in the net.
    If you got a manifest declaring main class (an classpath if needed), just create a file named whatever.bat, within same directory of jar file, containing:
    javaw -jar ./WhateverTheNameOfYourJarIs.jar %*By the way, assuming a Windows OS, you can just double click the jar file (no batch is needed).
    Otherwise use:
    javaw -cp listOfJarsAndDirectoriesSeparedBySemiColon country/company/application/package/className %*Where 'country/company/application/package/' just stands for a package path using '/' as separator instead of '.'
    Don't specify the .class extension.
    Javaw only works on Windows (you asked for batch, I assumed .BAT, no .sh), in Linux please use java.exe (path may be needed, Windows doesn't need it 'cause java's executables are copied to system32 folder in order to be always available, see PATH environment variable if you don't know what I'm talking about) and use ':' as classpath (cp) separator.
    The '%***' tail is there in order to pass all parameters, it only works on Windows, refer to your shell docs for other OSs (something like $* may work).
    This way you have a command you can call to launch your code (instead of opening NetBeans just to see your app working). You could schedule tasks on it or just call it in any command prompt (hope you know what it is 'cause there have been people in this very same forum with no clue about it, if not just hold the 'Windows button' and press 'R', then type 'cmd' and run it).
    Finally add dukes and give 'hem away.
    Bye.

  • How to edit the existing data in the XML file from java programming.

    Hi all
    i am able to create XML file with the sample data as below from java programming.
    i need sample code on how to edit the existing data in the XML file?
    for example
    <?xml version="1.0"?>
       <mydata>
               <data1>
                         <key1>467</key1>
                        <name1>Paul</name1>
                        <id1>123</id1>
              </data1>
              <data2>
                         <key2>467</key2>
                        <name2>Paul</name2>
                        <id2>123</id2>
              </data2>
        </mydata>
    i am able to insert the data in the XML.
    now i need sample code on how to modify the data in the above XML file from the java programming for only key2,name2,id2 tags only. the remaining tags data in the XML file i want to keep same data except for key2,name2,id2 which are i want to modify from java code
    Regards
    Sunil
    [points will be always rewardable]

    hi
    u need a parser or validate the xml file for to read the xml file from java coding u need for this
    xml4j.jar u can download this file  from here
    http://www.alphaworks.ibm.com/tech/xml4j
    or we can use the SAX(simple API for XML)
    some sample applications for this
    http://www.java-tips.org/java-se-tips/javax.xml.parsers/how-to-read-xml-file-in-java.html
    http://www.developertutorials.com/tutorials/java/read-xml-file-in-java-050611/page1.html
    http://www.xml-training-guide.com/e-xml44.html
    let me know u need any other info
    bvr

  • Generation of xml file from java code

    hi,
    I want to manipulate data in a xml file with java code.I have read data from xml file and also changed it. But i am unable to covert it again in xml file from java code. Can you please tell me how i can do this?

    Let me know which parser are you using currently for reading xml files so that i assist you. For now, you can refer to STAX Parser API under this link
    http://java.sun.com/webservices/docs/1.6/tutorial/doc/SJSXP3.html

  • Creation of xml file in r3 application server (AL11)

    Hi All
    I need to create xml file in r3 application server (AL11) using PI.Can we achieve this using file adapter or we need to proceed with proxy. As I tried with file adapter with FTP transport protocol. Its giving the error as "Unable to create new pooled resource:FTPEx:Login incorrect".
    Thanks in advance
    Regards,
    Kartikeya

    Hi
    need to create xml file in r3 application server (AL11) using PI.Can we achieve this using file adapter or we need to proceed with proxy.
    To generate file at AL11 file directory use File adapter. Proxy is not required for this
    Its giving the error as "Unable to create new pooled resource:FTPEx:Login incorrect".
    1. Check with the Login credentials for the FTP service.
    2. FTP User you use in communication channel must have 777 access to FTP location.
    Thanks
    Gaurav

  • How to create a Batch file for java application  ?

    HI,
    How to create a Batch file for java application ?
    And whats the use of creating batch file ?
    Thanks in advance

    [http://static.springsource.org/spring-batch/]
    Assuming you want to develop a batch application rather than actually just create a .bat file ..

  • Error while extracting XML file from the application server

    Hi ,
    I am writing a XML file into the application server, after which when i try to extract the file to the local server using the report - RFASLDPC ,
    the file is extracted, but with a '#' symbol at the first position.
    Because of which the XML File does not open. But after i open the file in notepad and manually delete the '#' symbol and then reopen the file, it works fine.
    Is there any way to remove the '#' symbol while extracting itself ??
    Thanks in advance,
    Vikas.

    Select the option "No Character Set Conversion" in stead of Code page 1100.
    However, I still have troubles -> the downloaded xml file misses a space on several places. This causes errors too.

  • Issue: XML File Downloading to Application Server

    Hi All,
    I am experiencing an issue downloading an XML File to the Application Server.
    I'm using FM SAP_CONVERT_TO_XML_FORMAT to convert SAP data to XML Format.
    After getting the XML data into XMLTAB, I'm using:
    OPEN DATASET pfile_fs FOR OUTPUT IN BINARY MODE .
         LOOP AT xmltab INTO xmltab_w.
         TRANSFER xmltab_w TO pfile_fs.
          CLEAR xmltab_w.
         ENDLOOP.
       CLOSE DATASET pfile_fs.
    The xml file is downloaded show an Error in 'XML page cannot be displayed
    Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later.
    Invalid at the top level of the document. Error processing resource 'file:/shared/TEST/2009'
    But when i download xml file using the FM  WS_Download , the XML page has no errors .
    I am unable to figure out what could be the issue, If this issue is due to some characters like Chinese or Japanese then .. is there any solution for this .
    Please, give me your valuable suggestions.
    Thank you,
    Prasead

    Dear Prasead,
            Hope things are good at your end, i have got the same issue as well, could you please care to share the solution...Wud be of a gr8 help if you could do that, hope to have your response back.
    Regards,
    Abdul.

  • How to run ear file in java application server

    i want how to run .ear file in java application server
    1. i m created ear file
    2. i m created jar file (bean,home,remote)
    3.i m created war file(in the form of jsp)
    but till now i couldnt run ear file
    how to run
    please hel me

    You must create :
    1.Jar file
    2.War file
    And then put them into an ear file
    Exemple : myapp.ear contains
    myappEJB.jar
    myappWEB.war
    META-INF/application.xml
    and application.xml looks like this :
    <application xmlns="http://java.sun.com/xml/ns/j2ee" version="1.4"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xsi:schemaLocation="http://java.sun.com /xml/ns/j2ee
                            http://java.sun.com/xml/ns/j2ee/application_1_4.xsd">
        <display-name>myapp</display-name>
        <description>Demo application</description>
        <module>
            <ejb>myappEJB.jar</ejb>
        </module>
        <module>
          <web>
             <web-uri>myappWAR.war</web-uri>
             <context-root>/myapp</context-root>
          </web>
        </module>
    </application>Good luck

  • Loading an XML File in an Application!

    Hy Guys!
    I'm quite new on Java, so I'm missing some important knowledge, for example: how to load an XML file in an Application downloaded by Java WebStart:
    In Details:
    I'm downloading an Application which needs an XML File for setting up an Legend. As far as I know, the XMLParser needs a File as argument to parse. By Java WebStart/jnlp, I can't download the XML-File to the local machine, and trying to create an instance by the url (as String), doesn't work. So now I'm missing some information, and I hope you can help me:
    Is there a possiblility to download the XML file via the application explicitly,
    or is there a possibility to "convert" the ResourceInputStream into a "parseable" class?
    I'm happy for every suggestion ..
    some code:
    public class EvalXML extends org.xml.sax.helpers.DefaultHandler {
    /** Creates a new instance of EvalXML */
    public EvalXML() {
    * @param args the command line arguments
    public static int main(String[] args) {
    DefaultHandler handler = new EvalXML();
    SAXParserFactory factory = SAXParserFactory.newInstance();
    String url = new String();
    //String url = EvalXML.class.getClassLoader().getResource("com/msgis/res/Lcc_Test_XML_Addressen.xml").getPath();
    //String url= "msgis.jar!/com/msgis/res/Lcc_Test_XML_Addressen.xml";
    if (args[0] + "empty" != "empty") url = args[0];
    else{
    System.out.println("no argument");
    return 0;
    System.out.println("PATH: \n" + url + "\n");
    try{
    SAXParser saxParser = factory.newSAXParser();
    //saxParser.parse(new File(EvalXML.class.getClassLoader().getResource("com/msgis/res/Lcc_Test_XML_Addressen.xml").getPath()), handler);
    saxParser.parse(new File(url), handler);
    System.out.println("pascht");
    catch(Throwable t){
    System.out.println(t.getMessage());
    return 1;
    regards dominik

    Although nobody wrote back, it is the quality of a forum depends on soluted problems so:
    the following function loads the file from the server to the box:
    public boolean loadResource(String pURL){
    DownloadService ds;
    URL lURL;
    boolean lLoaded = true;
    try{
    lURL = new URL(pURL);
    try {
    ds = (DownloadService)ServiceManager.lookup("javax.jnlp.DownloadService");
    } catch (UnavailableServiceException e) {
    ds = null;
    lLoaded = false;
    if (ds != null) {
    try {
    // determine if a particular resource is cached
    //URL url = new URL("http://java.sun.com/products/javawebstart/lib/draw.jar");
    boolean cached = ds.isResourceCached(lURL, "1.0");
    // remove the resource from the cache
    if (cached) {
    ds.removeResource(lURL, "1.0");
    // reload the resource into the cache
    DownloadServiceListener dsl = ds.getDefaultProgressWindow();
    ds.loadResource(lURL, "1.0", dsl);
    } catch (Exception e) {
    e.printStackTrace();
    lLoaded = false;
    catch(MalformedURLException mue)
    System.out.println(mue.getMessage());
    lLoaded =false;
    return lLoaded;
    dominik

  • Not able to open XML file in the application server..........

    Hi,
    I have downloaded a XML file to the application server.....
    File is created but i am not able to open the file there....
    Plz advice ....how to open it.....
    Regards.

    Use Notepad. Drag and drop in notepad.
    Aman

  • How I can create a XML file from java Aplication

    How I can create a XML file from java Aplication
    whith have a the following structure
    <users>
    <user>
    <login>anyName</login>     
    <password>xxxx</password>
    </user>
    </users>
    the password label must be encripted
    accept any suggestion

    Let us assume you have all the data from the jsp form in an java bean object..
    Now you want a xml file. This can be acheived in 2 ways
    1. Write it into a file using java.io classes. Say you have a class with name
    write("<name>"+obj.getName+</name>);
    bingo you have a flat file with the xml
    2. Use data binding to do the trick
    will recommend JiBx and Castor for the 2nd option
    Regards,
    Rajagopal

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