UTF-8 Regular Expression Whitelist

I'm trying to create a whitelist regular expression for form
input.
<cfset pattern_name = "^[\w]+[\w-\.,\s'""]*$"> works
for Ascii, but I need to include characters 192-255 in the ISO
8859-1 character set.
<cfset pattern_name =
"^[\wÀ-ÿ]+[\wÀ-ÿ-\.,\s'""]*$">
doesn't work. Österström, Garzón, and
Márquez are all rejected.
Does anyone know how to fix it?

Similar Messages

Rplacing space with &nbsb; in html using regular expressions

Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What number does this represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

sorry i missed some information in above,The modified information was in red color
Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADIN G="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What&nbsb;number&nbsb;does&nbsb;this&nbsb;represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

Regular Expressions and String variables

Hi,
I am attempting to implement a system for searching text files for regular expression matches (similar to something like TextPad, etc.).
Looking at the regular expression API, it appears that you can only match using string variables. I just wanted to make sure this is true. Some of these files might be large and I feel uneasy about loading them into ginormous Strings. Is this the only way to do it? Can I make a String as big as I want?
Thanks,
-Mike

Newlines are only a problem if you're reading the
text line-by-line and applying the regexp to each
line. It wouldn't catch expressions that span
lines.
@sabre150: your note re: CharSequence -- so what
you're suggesting is to implement a CharSequence that
wraps the file contents, and then use the regexps on
the whole thing? I like the idea but it seems like
it would only be easy to implement if the file uses a
fixed-width character set. Or am I missing
something...?You are correct for the most basic implementation. It is very easy to create a char sequence for fixed width character sets using RandomAccessFile. Once you go to character sets such as UTF-8 then more effort is required.
While ever the regex is moving forward thought the CharSequence one char at a time there is no problem because one can wrap a Reader but once it backtracks then one needs random access and one will need to have a buffer. I have used a ring buffer for this which seems to work OK but of course this will not allow the regex to move to any point in the CharSequence.
'uncle_alice' is the regex king round here so listen to him.
:-( I should read further ahead next time!
Message was edited by:
sabre150
Message was edited by:
sabre150

Regular Expression replacement not working

I am trying to use a regular expression to replace non-ascii characters on a file, and I'm afraid I've reached the end of my regex knowledge.
Here is the specific code
'Set the Regular Expression paramaters
Set RegEx = CreateObject("VBScript.Regexp")
RegEx.Global = True
RegEx.Pattern = "[^\u0000-\u007F]"
RegEx.IgnoreCase = True
'Replace the UTF-8 characters
ReplacedText = RegEx.Replace(FileText, "\u0020")
If I understand regular expressions correctly the pattern of "[^\u0000-\u007F]" should replace any character that is not an ascii character, and then replace it with a space (which I understand is "\u0020"). What am I doing wrong?

Simply use
ReplacedText = RegEx.Replace(FileText, " ")
Regards, Hans Vogelaar (http://www.eileenslounge.com)

Regular expressions and characters as č, �, ť ...

Hi. I have this problem with regular expressions. The next piece of code is work only with string without diacritics. If I use as pattern character with diacritic the matcher is not find any occurence of a character. The code:
String pat = "č"; // "a"
String text = "naj čalamada"
Pattern pattern = Pattern.compile(pat, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(text);
while (matcher.find()) { }If I uncomment character 'a' its occurence will be founded but occurence of 'č' is not found. :(
Can you tell me what is wrong ??
If I use flag Pattern.CASE_INSENSITIVE | Pattern.CANON_EQ nothing will be changed.
Thanks for all replays.

The file encoding is same as system encoding and it is utf-8.
How can I specify encoding as an inout parameter when I compile it?
Piece of code or concrete funcions help me more...

Best Regular expression ?

What is the best regular expression to represent the following string in java ?
<?xml version = '1.0' encoding = 'UTF-8'?>
Thanks in advance !

What about that exact same string? depending on your regular expression implementation you'll probably need to escape some characters.. So something like: <\?xml version = '1.0' encoding = 'UTF-8'\?>

Regular expression for html links

Hi, I'm trying to get text/link pairs from a string, accepted links
are like:
text1
text2
The expected result would be:
url: url1
Text: text1
url: url2
Text: text2
I use the following regular expression to catch the texts and the urls:
"<a href=\"*(.*)\"*.*>(.*)</a>"
group(1) should be the url and group(2) the text.
But it doesn't work ok, I got something like:
url: http://url1/" garbagetags
text: text1
url: utl2
text: text2
I'm trying to avoid links with " and without it and dinamic html
tags.
I think the problem is the Regular Expression string, I'm new using
them and I can't found the right one, if you know what's wrong with
my R.E. string, please help me.!
thanx

Had to break it in to two regular expressions:
import java.util.regex.*;
class B2 {
 public static void main(String[] args) {
 //String INPUT = "<a href=\"http://url1/\" garbagetags>text1</a>";
 //String INPUT = "<a href=url2>text2</a>";
 //String INPUT ="<a href=\"http://www.google.com\">Google search engine</a>";
 String INPUT="<a id=1a class=q href=\"/imghp?hl=en&tab=wi&ie=UTF-8&oe=UTF-8\" onClick=\"return c('www.google.com/imghp','wi',event);\">Images</a>";
 //String REGEX = "<a .*href=\\\"?h?t?t?p?:?/?/?([\\w\\.\\?\\&=\\-\\d]*)/?\\\"?.*>(.*)</a>";
 String REGEX = "<a .*href=\\\"?h?t?t?p?:?/?/?([\\w\\.\\?\\&=\\-\\d]*)/?\\\"?.*>";
 String REGEX2 = ">\\b([\\w\\s\\d]+)\\b<";
 Pattern p = Pattern.compile(REGEX);
 Matcher m = p.matcher(INPUT);
 StringBuffer sb = new StringBuffer();
 if ( m.find() ) {
 System.out.println(m.group(1) + " " ); }
 else { System.out.println("No MAtch found"); }
 Pattern p2 = Pattern.compile(REGEX2);
 Matcher m2 = p2.matcher(INPUT);
 if ( m2.find() ) {
 System.out.println(m2.group(1) + " " ); }
 else { System.out.println("No MAtch found"); }
} You do realize that you'll never get 100% accuracy with this. There are too many possible variations to account for them all.

Regular expression for http response/request

Hi. I need to use reg. ex. to parse a file that contains a list of http requests and responses. The requests and responses may or may not include a message body. My regular expression to detect a response is as follows:
RESPONSE_STATUS_LINE_REG_EX + CRLF +
"(" + HTTP_HEADER_REG_EX + CRLF + ")*" + CRLF +
"(?s:.(?!" + "(" + RESPONSE_STATUS_LINE_REG_EX + ")" + "|" + "(" + REQUEST_LINE_REG_EX + ")" + "))*";
The first two lines works perfectly to detect the response initial line and headers. The last line reads the message body, but does not work when the response has an empty message body. My logic is to read everything after the headers until the next response or request. This logic works when there is a message body.
As a result, the above reg. ex. produce the following result as one response, but should be two separate responses.
HTTP/1.0 200 OK
Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, application/vnd.ms-powerpoint, application/vnd.ms-excel, application/msword, */*
Referer: http://www.google.com/
Accept-Language: en-us
HTTP/1.0 200 OK
Connection: Close
Date: Tue, 15 Apr 2003 23:36:09 GMT
Cache-control: private
Content-type: text/html
Server: GWS/2.0
<html><head><meta HTTP-EQUIV="content-type" CONTENT="text/html; charset=UTF-8"><title>Google Search: burger </html>
Can anyone see what is wrong with my regular expression?
thanks,
Paul

It would help if we could see the actual regexes instead of those variable names. But you might try this:RESPONSE_STATUS_LINE_REG_EX + CRLF +
"(" + HTTP_HEADER_REG_EX + CRLF + ")*" + CRLF +
"(?:(?!(" + RESPONSE_STATUS_LINE_REG_EX + ")|(" + REQUEST_LINE_REG_EX + ")).*" + CRLF + ")*";This way, the negative lookahead is appied at the beginning of each line, then the whole line is consumed. Without knowing more, I can't tell if this will do what you want, but at least it should fail more efficiently. :P

How to display regular expression text

I cannot seem to get the text of a regular expression to display in a text input. The regex is defined as:
Bindable]
private var myRegExp:RegExp=/^.*(?=.{10,32})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[.!@#$%*^&()+]).*$/;
In my form, I want to display the actual expression. The code I am using to do so is:
<mx:FormItem label="regExpLabel">
 <mx:TextInput id="regExpTextInput" text="{myRegExp}" />
</mx:FormItem>
When I run the app, the data displayed in the regExpTextInput filed is /^.*(?=.{10,32})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[.!@#$%*^&()+]).*$/
What I want to display is only the regular expression, not including the slashes required by Flex at the beginning and end of the string. The data I want displayed is ^.*(?=.{10,32})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[.!@#$%*^&()+]).*$
I tried changing my variable type to String and leaving out the beginning and ending slashes, but that did not work either. Any thoughts?
Thanks!

Hi, I am unable to understand your requirement properly but here is one demo of the using regular expression. In this application I am allowing only those character to be enter in the Textbox which are taken as the valid filename. Hope this will help you.
I think In your requirement first of all you have to take it as string type. And the second is that use \\ before every special character if you are writing it in the script. As I have done. Pls let me know if you
Have any issue with the code below.
<?xml version="1.0" encoding="utf-8"?>
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute">
<mx:Script>
 <![CDATA[
 [Bindable]
 private var regExpForFile : String
 = "0-9A-Za-z\\&\\`\\~\\!\\@\\#\\$\\%\\^\$\$\\-\\_\\=\\+\\]\\}\[\\'\\;\\,\\.\\{ ";
 ]]>
</mx:Script>
 <mx:VBox horizontalAlign="center" width="350">
 <mx:Label text="Enter File Name"/>
 <mx:TextInput id="fileName" width="170" height="20" restrict="{regExpForFile}"/>
 </mx:VBox>
</mx:Application>
with Regards,
Shardul Singh Bartwal

Logical AND in Java Regular Expressions

I'm trying to implement logical AND using Java Regular Expressions.
I couldn't figure out how to do it after reading Java docs and textbooks. I can do something like "abc.*def", which means that I'm looking for strings which have "abc", then anything, then "def", but it is not "pure" logical AND - I will not find "def.*abc" this way.
Any ideas, how to do it ?
Baken

First off, looks like you're really talking about an "OR", not an "AND" - you want it to match abc.*def OR def.*abc right? If you tried to match abc.*def AND def.*abc nothing would ever match that, as no string can begin with both "abc" and "def", just like no numeric value can be both 2 and 5.
Anyway, maybe regex isn't the right tool for this job. Can you not simply programmatically match it yourself using String methods? You want it to match if the string "starts with" abc and "ends with" def, or vice-versa. Just write some simple code.

Help in Regular expression

Hello..
I wanted to write a regular expression to match the foll string..
 
 NEW ORLEANS, Louisiana (CNN) 
-- Two years after Hurricane Katrina devastated coastal areas of Louisiana and Mississippi, residents say much of America has forgotten their plight.
 
I tried doing..
Matcher matcher= Pattern.compile(" ([^<^>]+?)", Pattern.CASE_INSENSITIVE).matcher(story);
Its not working...
is there any other soln?

Theres probably a better way to do this but here's a way that works.
import java.util.regex.*;
public class RegexTester{
public static void main(String[] args){
 String text =
 " " +
 " NEW ORLEANS, Louisiana (CNN) " +
 "-- Two years after Hurricane Katrina devastated coastal areas of Louisiana and Mississippi," +
 "residents say much of America has forgotten their plight." +
 " ";
 String regex = ">((?:\\s*[\\S&&[^<>]]+\\s*)*?)<";
 Pattern p = Pattern.compile(regex);
 Matcher m = p.matcher(text);
 while(m.find()){
 System.out.println("Match: '" + m.group(1) + "'");
}

Help in regular expression matching

I have three expressions like
1) [(y2009)(y2011)]
2) [(y2008M5)(y2011M3)] or [(y2009M5)(y2010M12)]
3) [(y2009M1d20)(y2011M12d31)]
i want regular expression pattern for the above three expressions
I am using :
REGEXP_LIKE(timedomainexpression, '???[:digit:]{4}*[:digit:]{1,2}???[:digit:]{4}*[:digit:]{1,2}??', 'i');
but its giving results for all above expressions while i want different expression for each.
i hav used * after [:digit:]{4}, when i am using ? or . then its giving no results. Please help in this situation ASAP.
Thanks

I dont get your question Can you post your desired output? and also give some sample data.
Please consider the following when you post a question.
1. New features keep coming in every oracle version so please provide Your Oracle DB Version to get the best possible answer.
You can use the following query and do a copy past of the output.
select * from v$version 2. This forum has a very good Search Feature. Please use that before posting your question. Because for most of the questions
that are asked the answer is already there.
3. We dont know your DB structure or How your Data is. So you need to let us know. The best way would be to give some sample data like this.
I have the following table called sales
with sales
as
 select 1 sales_id, 1 prod_id, 1001 inv_num, 120 qty from dual
 union all
 select 2 sales_id, 1 prod_id, 1002 inv_num, 25 qty from dual
select *
from sales 4. Rather than telling what you want in words its more easier when you give your expected output.
For example in the above sales table, I want to know the total quantity and number of invoice for each product.
The output should look like this
Prod_id sum_qty count_inv
1 145 2 5. When ever you get an error message post the entire error message. With the Error Number, The message and the Line number.
6. Next thing is a very important thing to remember. Please post only well formatted code. Unformatted code is very hard to read.
Your code format gets lost when you post it in the Oracle Forum. So in order to preserve it you need to
use the {noformat}{noformat} tags.
The usage of the tag is like this.
<place your code here>\
7. If you are posting a *Performance Related Question*. Please read
 {thread:id=501834} and {thread:id=863295}.
 Following those guide will be very helpful.
8. Please keep in mind that this is a public forum. Here No question is URGENT.
 So use of words like *URGENT* or *ASAP* (As Soon As Possible) are considered to be rude.

Regular expression alphabets

Hi
I want to retrieve the data if the data contains a character or a space or '-' thru select query .
Please help me in writing the combination of 3 with regular expression.
Thanks!!

VT wrote:
Hi,
Try this
SELECT *
FROM <TABLE> WHERE REGEXP_LIKE(<COLUMN>, '[a-z -][A-Z -]');cheers
VTThat won't work as it's expecting at least two characters with the first having to be a-z (lower case) or space or "-" followed by A-Z (upper case) or space or "-".
The correct way is either:
[a-zA-Z -]or
[[:alpha:] -]using the alpha set is often preferable as it can work differently with different character sets/languages rather than restricting to just the a-zA-Z ranges.
Generating a reference for your own database characterset/language can be useful...
SQL> select level-1 as asc_code, decode(chr(level-1), regexp_substr(chr(level-1), '[[:print:]]'), CHR(level-1)) as chr,
2 decode(chr(level-1), regexp_substr(chr(level-1), '[[:graph:]]'), 1) is_graph,
3 decode(chr(level-1), regexp_substr(chr(level-1), '[[:blank:]]'), 1) is_blank,
4 decode(chr(level-1), regexp_substr(chr(level-1), '[[:alnum:]]'), 1) is_alnum,
5 decode(chr(level-1), regexp_substr(chr(level-1), '[[:alpha:]]'), 1) is_alpha,
6 decode(chr(level-1), regexp_substr(chr(level-1), '[[:digit:]]'), 1) is_digit,
7 decode(chr(level-1), regexp_substr(chr(level-1), '[[:cntrl:]]'), 1) is_cntrl,
8 decode(chr(level-1), regexp_substr(chr(level-1), '[[:lower:]]'), 1) is_lower,
9 decode(chr(level-1), regexp_substr(chr(level-1), '[[:upper:]]'), 1) is_upper,
10 decode(chr(level-1), regexp_substr(chr(level-1), '[[:print:]]'), 1) is_print,
11 decode(chr(level-1), regexp_substr(chr(level-1), '[[:punct:]]'), 1) is_punct,
12 decode(chr(level-1), regexp_substr(chr(level-1), '[[:space:]]'), 1) is_space,
13 decode(chr(level-1), regexp_substr(chr(level-1), '[[:xdigit:]]'), 1) is_xdigit
14 from dual
15 connect by level <= 256
16 /
ASC_CODE C IS_GRAPH IS_BLANK IS_ALNUM IS_ALPHA IS_DIGIT IS_CNTRL IS_LOWER IS_UPPER IS_PRINT IS_PUNCT IS_SPACE IS_XDIGIT
 0 1
 1 1
 2 1
 3 1
 4 1
 5 1
 6 1
 7 1
 8 1
 9 1 1
 10 1 1
 11 1 1
 12 1 1
 13 1 1
 14 1
 15 1
 16 1
 17 1
 18 1
 19 1
 20 1
 21 1
 22 1
 23 1
 24 1
 25 1
 26 1
 27 1
 28 1
 29 1
 30 1
 31 1
 32 1 1 1
 33 ! 1 1 1
 34 " 1 1 1
 35 # 1 1 1
 36 $ 1 1 1
 37 % 1 1 1
 38 & 1 1 1
 39 ' 1 1 1
 40 ( 1 1 1
 41 ) 1 1 1
 42 * 1 1 1
 43 + 1 1 1
 44 , 1 1 1
 45 - 1 1 1
 46 . 1 1 1
 47 / 1 1 1
 48 0 1 1 1 1 1
 49 1 1 1 1 1 1
 50 2 1 1 1 1 1
 51 3 1 1 1 1 1
 52 4 1 1 1 1 1
 53 5 1 1 1 1 1
 54 6 1 1 1 1 1
 55 7 1 1 1 1 1
 56 8 1 1 1 1 1
 57 9 1 1 1 1 1
 58 : 1 1 1
 59 ; 1 1 1
 60 < 1 1 1
 61 = 1 1 1
 62 > 1 1 1
 63 ? 1 1 1
 64 @ 1 1 1
 65 A 1 1 1 1 1 1
 66 B 1 1 1 1 1 1
 67 C 1 1 1 1 1 1
 68 D 1 1 1 1 1 1
 69 E 1 1 1 1 1 1
 70 F 1 1 1 1 1 1
 71 G 1 1 1 1 1
 72 H 1 1 1 1 1
 73 I 1 1 1 1 1
 74 J 1 1 1 1 1
 75 K 1 1 1 1 1
 76 L 1 1 1 1 1
 77 M 1 1 1 1 1
 78 N 1 1 1 1 1
 79 O 1 1 1 1 1
 80 P 1 1 1 1 1
 81 Q 1 1 1 1 1
 82 R 1 1 1 1 1
 83 S 1 1 1 1 1
 84 T 1 1 1 1 1
 85 U 1 1 1 1 1
 86 V 1 1 1 1 1
 87 W 1 1 1 1 1
 88 X 1 1 1 1 1
 89 Y 1 1 1 1 1
 90 Z 1 1 1 1 1
 91 [ 1 1 1
 92 \ 1 1 1
 93 ] 1 1 1
 94 ^ 1 1 1
 95 _ 1 1 1
 96 ` 1 1 1
 97 a 1 1 1 1 1 1
 98 b 1 1 1 1 1 1
 99 c 1 1 1 1 1 1
 100 d 1 1 1 1 1 1
 101 e 1 1 1 1 1 1
 102 f 1 1 1 1 1 1
 103 g 1 1 1 1 1
 104 h 1 1 1 1 1
 105 i 1 1 1 1 1
 106 j 1 1 1 1 1
 107 k 1 1 1 1 1
 108 l 1 1 1 1 1
 109 m 1 1 1 1 1
 110 n 1 1 1 1 1
 111 o 1 1 1 1 1
 112 p 1 1 1 1 1
 113 q 1 1 1 1 1
 114 r 1 1 1 1 1
 115 s 1 1 1 1 1
 116 t 1 1 1 1 1
 117 u 1 1 1 1 1
 118 v 1 1 1 1 1
 119 w 1 1 1 1 1
 120 x 1 1 1 1 1
 121 y 1 1 1 1 1
 122 z 1 1 1 1 1
 123 { 1 1 1
 124 | 1 1 1
 125 } 1 1 1
 126 ~ 1 1 1
 127 1
 128 Ç 1 1 1
etc.
{code}

Help in query using regular expression

HI,
I need a help to get the below output using regular expression query. Please help me.
SELECT REGEXP_SUBSTR ('PWRPKG(P/W+P/L+CC)', '[^+]+', 1, lvl) val, lvl
FROM DUAL,(SELECT LEVEL lvl FROM DUAL
CONNECT BY LEVEL <=(SELECT MAX ( LENGTH ('PWRPKG(P/W+P/L+CC)') - LENGTH (REPLACE ('PWRPKG(P/W+P/L+CC)','+',NULL))+ 1) FROM DUAL));
I need the output as
correct result:
==============
val lvl
P/W 1
P/L 2
CC 3
But i tried the above it is not coming the above result. Please help me where i did a mistake.
Thanks in advance

Frank gave you a solution in your other thread. You could simplify it if you are on 11g:
SQL> select * from table_x
2 /
TXT
TECHPKG(INTELLI CC+FRT SONAR)
PWRPKG(P/W+P/L+CC)
select txt,
 regexp_substr(
 txt,
 '(.*\()*([^+)]+)',
 1,
 column_value,
 null,
 2
 ) element,
 column_value element_number
from table_x,
 table(
 cast(
 multiset(
 select level
 from dual
 connect by level <= regexp_count(txt,'\+') + 1
 as sys.OdciNumberList
order by rowid,
 column_value
TXT ELEMENT ELEMENT_NUMBER
TECHPKG(INTELLI CC+FRT SONAR) INTELLI CC 1
TECHPKG(INTELLI CC+FRT SONAR) FRT SONAR 2
PWRPKG(P/W+P/L+CC) P/W 1
PWRPKG(P/W+P/L+CC) P/L 2
PWRPKG(P/W+P/L+CC) CC 3
SQL> SY.

Query help in regular expression

Hi all,
SELECT * FROM emp11
WHERE INSTR(ENAME,'A',1,2) >0;
Please let me know the equivalent query using regular expressions.
i have tried this after going through oracle regular expressions documentation.
SELECT * FROM emp11
WHERE regexp_LIKE(ename,'A{2}')
Any help in this regard would be highly appreciated .
Thanks,
P Prakash

please go here
Introduction to regular expressions ...
Thanks,
P Prakash

UTF-8 Regular Expression Whitelist

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