Values in Colum as separate columns

Question

I have a table that looks like this:
Company (varchar),
FieldName (varchar)
Valuex (varchar)
Data may look like this:
Company Fieldname Valuex
123 Name John
123 MiddleName C
123 LastName Smith
I would like to write a query that comes out like this:
Company FirstName MiddleName LastName
123 John C Smith
Can it be one? Thanks in advance.

Answer 1

Hi,
Pivot is new in 11g is it not? I'm on 10g. Can it be done without the pivot function?Yes! You can do pivots in any version. I just said there was a newer, easier way that was introduced in Oracle 11; that's the only case in which the word PIVOT occurs in the code.
I just tried searching for "pivot", and I did find dozens of examples. Almost all of them said "Search for pivot", so I'll post an exmple here. The example below works in any version of Oracle, including 10.
--     How to Pivot a Result Set (Display Rows as Columns)
--     This example uses the scott.emp table.
--     Given a query that produces three rows for every department,
--     how can we show the same data in a query that has one row
--     per department, and three separate columns?
--     For example, the query below counts the number of employess
--     in each departent that have one of three given jobs:
PROMPT     ==========  0. Simple COUNT ... GROUP BY  ==========
SELECT     deptno
,     job
,     COUNT (*)     AS cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno
,          job;
Output:
    DEPTNO JOB              CNT
        20 CLERK              2
        20 MANAGER            1
        30 CLERK              1
        30 MANAGER            1
        10 CLERK              1
        10 MANAGER            1
        20 ANALYST            2
PROMPT     ==========  1. Pivot  ==========
SELECT     deptno
,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno;
--     Output:
    DEPTNO ANALYST_CNT  CLERK_CNT MANAGER_CNT
        30           0          1           1
        20           2          2           1
        10           0          1           1
--     Explanation
(1) Decide what you want the output to look like.
     (E.g. "I want a row for each department,
     and columns for deptno, analyst_cnt, clerk_cnt and manager_cnt)
(2) Get a result set where every row identifies which row
     and which column of the output will be affected.
     In the example above, deptno identifies the row, and
     job identifies the column.
     Both deptno and job happened to be in the original table.
     That is not always the case; sometimes you have to
     compute new columns based on the original data.
(3) Use aggregate functions and CASE (or DECODE) to produce
     the pivoted columns. 
     The CASE statement will pick
     only the rows of raw data that belong in the column.
     If each cell in the output corresponds to (at most)
     one row of input, then you can use MIN or MAX as the
     aggregate function.
     If many rows of input can be reflected in a single cell
     of output, then use SUM, COUNT, AVG, STRAGG, or some other
     aggregate function.
     GROUP BY the column that identifies rows.
{code}
Edited by: Frank Kulash on Sep 5, 2008 5:37 PM