Variable call not working

Question

This script fetches users and their groups. I was trying to make a
function or something where I call groups $USER_ID instead of printing it out each time.
Here is how it is now:
cat myFile | while read LINE
do
USER_ID=`echo $LINE | awk -F: '{print $1}'`
REAL_NAME=`echo $LINE | awk -F: '{print $2}'`
i=`groups $USER_ID | awk '{print NF}'`
if (( $i == 1 ))
then
echo "$REAL_NAME is a member of $i group:"
groups $USER_ID
else
echo "$REAL_NAME is a member of $i groups:"
groups $USER_ID
fi
done
Here is my attempt at putting the groups $USER_ID in a variable:
cat myFile | while read LINE
do
USER_ID=`echo $LINE | awk -F: '{print $1}'`
var=`groups $USER_ID` #HERE IS MY VARIABLE DECLARATION ATTEMPT USING groups system command
REAL_NAME=`echo $LINE | awk -F: '{print $2}'`
i=`groups $USER_ID | awk '{print NF}'`
if (( $i == 1 ))
then
echo "$REAL_NAME is a member of $i group:"
$var #also tried echo "$var" but it still doesnt work.
else
echo "$REAL_NAME is a member of $i groups:"
$var
fi
done
I keep getting an error message with the $var variable. Please advise
the most proficient way of doing this?

Answer 1

The most proficient way to do this is to use the groups(1)
command instead.
-- richard