View source of AJAX content

Is there a way to view the source code of content that is included in an AJAX response?
For example, I load a page and click on a link that fetches content from another filed and loads that into a div of the loaded page. If I view source as normal, it only shows me the code of the original page loaded. Same thing with the web inspector.
My goal here is to validate my HTML markup, including that outputted by PHP scripts and requested via AJAX. Any ideas?

Safari -> Preferences -> Advanced -> Show Develop Menu In Toolbar
Develop -> Show Web Inspector

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View source of AJAX content

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